How to validate Web element if xpath locator is dynamic in selenium webdriver - selenium

Question

ID and Xpath is changing for "OK" button every time while saving(Account).
HTML Code:
<div class="modal-footer" style="display: block;">
<div class="bootstrap-dialog-footer">
<div class="bootstrap-dialog-footer-buttons">
<button id="fe02d6bd-6058-4871-b0e1-c1e914f64a6a" class="btn btn- default">Ok</button>
</div>
</div>
</div>
</div>
Xpath:.//*[#id='fe02d6bd-6058-4871-b0e1-c1e914f64a6a']
"ID"/XPath is not constant and it is varying while saving.

Answer 1

use the below code:
driver.findElement(By.cssSelector("div.bootstrap-dialog-footer-buttons>button.btn.btn-default"));

Answer 2

You can devise your own XPath locator to find the OK button by it's text content like so:
//button[.='Ok']
The first part of the XPath expression - //button - will select all <button> WebElements within the currently focused content.
The second part - [.='Ok'] - is a predicate that will filter out any WebElements whose exact text content is not equal to 'Ok'.

Answer 3

If it is the only OK button available on the page then you can probably use below code.
driver.findElement(By.xpath("//button[contains(.,'Ok')]"));
Else you can take a reference of parent window and locate a button on it as below
WebElement modalWin = driver.findElement(By.id("modal-window-id"));
modalWin.findElement(By.xpath("//button[contains(.,'Ok')]"));

Answer 4

This below code helps to click OK button in any page.
just call this method with parameter saying OK
public void buttonClick(String buttonname){
WebElemennt button = driver.findelement(by.xpath("//button[text(),'Ok']"))
or
WebElemennt button = driver.findelement(by.cssselector(".btn btn- default"))
for(int i=0; i<button.size;i++)
{
if(button.get(i).gettext().equalIgnorecase(buttonname))
{
button.get(i).click
}
}
}
Let me know result..