Recursive query with time difference - sql

Question

This is my first post here even though I am a daily reader. :)
I need to produce an MS SQL Server 2014 report that shows the clients that come back to do business with me in less than or equal to 3 days. I tried with INNER JOINS but I wasn't successful.
The way I thought of the solution is using the below Logic:
If product is same
and if userId is same
and if action was donedeal but now is new
and if date diff <= 3 days
and if type is NOT same
then show results
e.g of my Data:
id orderId userId type product date action
1 1001 654 ordered apple 01/05/2016 new
2 1002 889 ordered peach 01/05/2016 new
3 1001 654 paid apple 01/05/2016 donedeal
4 1002 889 paid peach 03/05/2016 donedeal
5 1003 654 ordered apple 03/05/2016 new
6 1004 889 ordered peach 04/05/2016 new
7 1005 122 ordered apple 04/05/2016 new
8 1006 978 ordered peach 04/05/2016 new
9 1005 122 paid apple 04/05/2016 donedeal
10 1007 122 ordered apple 10/05/2016 new
Desired results:
id orderId userId type product date Diff
3 1001 654 paid apple 01/05/2016 2 days
4 1002 889 paid peach 03/05/2016 1 day
5 1003 654 ordered apple 03/05/2016 2 days
6 1004 889 ordered peach 04/05/2016 1 day
Could you please direct me to the functions that can be useful for me to solve this?
Thanks in advance.
#
Update
Gordon Linoff gave me the suggested code below but since the Type had to be different I replicated the code and run it as per below and it worked:
select t.*
from (select t.*,
max(case when action = 'donedeal' and type='paid' then date end) over
(partition by user, product order by date) as last_donedealdate
from t
) t
where action = 'new' and type='ordered' date < dateadd(day, 3, last_donedealdate)
UNION ALL
select t.*
from (select t.*,
max(case when action = 'donedeal' and type='ordered' then date end) over
(partition by user, product order by date) as last_donedealdate
from t
) t
where action = 'new' and type='paid' date < dateadd(day, 3, last_donedealdate)

Answer 1

You can use window functions for this. To get the last done deal date, use max() with partition by and order by. The rest is just where clause logic:
select t.*
from (select t.*,
max(case when action = 'donedeal' then date end) over
(partition by user, product order by date) as last_donedealdate
from t
) t
where action = 'new' and date < dateadd(day, 3, last_donedealdate);