I have created few custom fields for products.Products appear in sales,purchase,warehouse and manufacturing module.I want to make my custom fields appear only in manufacturing module and hide everywhere else.So how to put condition on invisible attribute.I tried like this and got error as Unknown field _name in domain
attrs="{'invisible': [('_name', '!=', 'mrp.bom')]}"
Python file,
from openerp import fields,models, api
class product_template(models.Model):
_inherit = "product.template"
rim_weight = fields.Float(string='Rim Weight(KG)', readonly=True, compute='_compute_one_rim_weight')
width = fields.Float(string='Width(cm)',default='50')
length = fields.Float(string='Length(cm)',default='63')
gsm = fields.Float(string='Gram per square meter(gsm)',default='230')
Xml file,
<record id="product_template_form_view_dis_inherit" model="ir.ui.view">
<field name="name">product.template.common.form.dis.inherit</field>
<field name="model">product.template</field>
<field name="inherit_id" ref="product.product_template_form_view"/>
<field name="arch" type="xml">
<xpath expr="//page[#string='Accounting']" position='after'>
<page string='Cover Page Paper'>
<group>
<field name="width"/>
<field name="length"/>
<field name="gsm"/>
<field name="rim_weight"/>
</group>
</page>
</xpath>
</field>
</record>
There are many ways to do this, however I suggest following options to you.
Modify an existing action and set context inside that and based on that context just write condition in view. (Remember here you need to override an action, and if you want to create another then you need to redefine menu to assign new action to that menu).
Create new view and set this view reference in an action of that model in which you want to show these fields. In new view you need to visible those fields, no need to extend product template existing view.
However the 1st solution is easy to achieve and 2nd one is lengthy.
Example of 1st solution:
<record id="action_name" model="ir.actions.act_window">
<field name="name">Name</field>
<field name="res_model">product.template</field>
<field name="view_type">form</field>
<field name="view_mode">tree,form</field>
<field name="context" eval="{'is_manufacturing_model':True}" />
</record>
And then in view just write like this
<page string='Cover Page Paper'>
<group invisible="context.get('is_manufacturing_model',False)">
<field name="width"/>
<field name="length"/>
<field name="gsm"/>
<field name="rim_weight"/>
<group>
</page>
Related
I created custom fields in Odoo v15.
PROBLEM
Now I would like to add them to invoice template.
How I could do it?
You need to inherit the form view (account.invoice.form) and add your custom fields to the view. Or if you want to test the view you can enable debug mode and click "Edit FormView" at the top right of your form view to (temporarily) edit the form view directly.
See my example below:
<record id="account_invoice_form_custom" model="ir.ui.view">
<field name="name">account.invoice.form.custom</field>
<field name="model">account.invoice</field>
<field name="inherit_id" ref="account.invoice_form" />
<field name="arch" type="xml">
<field name="partner_id" position="after">
<field name="custom_field"/>
</field>
</field>
</record>
I have following QWeb element:
<record id="extended_res_partner" model="ir.ui.view">
<field name="name">Extended View</field>
<field name="inherit_id" ref="base.view_partner_form"/>
<field name="model">res.partner</field>
<field name="arch" type="xml">
<notebook position="inside">
<page string="Foo" name="foo" attrs="{'invisible': [('is_customer', '=', False),]}">
<field name="is_customer" invisible="1"/>
<span>Foo2</span>
</page>
</notebook>
</field>
</record>
But it does not work. I get:
Field `is_customer` does not exist
If I remove attrs=... it works fine.
Even that you didn't provide the error message but this will work only if the the form view if for res.partner but i'm assuming that the form is for another model that have a many2one relation with res.partner in this case you need to create a related field in the model.
partner_id = ......
is_customer = fields.Boolean(related='partner_id.is_customer', readonly=True)
Then you need to add this field to the form view because attrs is client side feature it need the value in form in order to work.
<page string="foo" name="foo" attrs="{'invisible': [('is_customer', '=', False),]}">
<field name="is_customer" invisible="1"/>
<span>Foo2</span>
</page>
Note: if the form view is for res.partner just add the field to the form view because as I said is a client side operation it will not call the server to know what is the value of that field you need to pass it.
How can I set my own form view to enter customer data into res.partner model without using base.view_partner_form form view of res_partner model?
First off, you will need the custom form view, of course.
And after that it depends, what you want to do.
Change the form view everywhere: Give your form view a lesser priority than "base.view_partner_form":
<record id="my_partner_form" model="ir.ui.view">
<field name="name">...</field>
<!-- other fields -->
<field name="priority">1</field>
<!-- arch -->
</record>
Or if you want to get a new menuitem for the users, just create one. Then create a ir.actions.act_window with your new form view as default view and link it to your new menuitem.
You can create new partner form and set priority.
By default system will load minimum priority form in odoo.
View default priority is 16 & if you give your view priority is 20 then default from view will be load.
Ex:
<record id="view_partner_title_form" model="ir.ui.view">
<field name="name">res.partner.title.form</field>
<field name="model">res.partner.title</field>
<field name="priority">20</field>
<field name="arch" type="xml">
<form string="Partner Titles">
<group col="4">
<field name="name"/>
<field name="shortcut"/>
</group>
</form>
</field>
</record>
Now your new form view priority is 20, so system will load default form view because default form view priority is 16.
You can create ir.actions.act_window.view
Based on that system will load any sequence form/tree view based on your requirement.
<record id="action_portal_partner_form" model="ir.actions.act_window">
<field name="name">Customers</field>
<field name="type">ir.actions.act_window</field>
<field name="res_model">res.partner</field>
<field name="domain">[('customer','=',True)]</field>
<field name="view_type">form</field>
<field name="view_mode">kanban,tree,form</field>
<field name="context">{"search_default_customer":1}</field>
<field name="search_view_id" ref="base.view_res_partner_filter"/>
</record>
<record id="action_portal_form_view2" model="ir.actions.act_window.view">
<field eval="23" name="sequence"/>
<field name="view_mode">form</field>
<field name="view_id" ref="view_partner_title_form"/>
<field name="act_window_id" ref="action_portal_partner_form"/>
</record>
View_mode : tree/form/..
View Id : your view id
Action : You must write correct action id
I am trying to inherit the Website settings menu and have two views. website.config.settings is a models.TransientModel
When I am inheriting that and viewing with a new menuitem it overwrites the previous view. Like - There are two views now, the new record I defined named Website Event Settings . When I click on that it loads the new modified view but when I click on existing Settings menu, it shows nothing.
In summary, the existing website settings menu not working and new menu does. I need both of them.
The py code and record view I used are following -
class cofair_website_design_config(models.TransientModel):
_name = 'website.config.settings'
_inherit = 'website.config.settings'
event_title = fields.Char(related='website_id.event_title', string='Event Title')
XML:
<record id="view_website_event_config_settings" model="ir.ui.view">
<field name="name">Website Event Settings</field>
<field name="model">website.config.settings</field>
<field name="arch" type="xml">
<form class="oe_form_configuration">
<header>
<button string="Apply" type="object" name="execute" class="oe_highlight"/>
<button string="Cancel" type="object" name="cancel" class="oe_link"/>
</header>
<div>
<group string="Event Page Section">
<group>
<field name="event_title_color"/>
</group>
</group>
</div>
</form>
</field>
</record>
<record id="action_website_event_configuration" model="ir.actions.act_window">
<field name="name">Website Event Settings</field>
<field name="res_model">website.config.settings</field>
<field name="view_mode">form</field>
<field name="target">inline</field>
<field name="view_id" ref="view_website_event_config_settings"/>
</record>
<menuitem id="menu_website_event_settings" parent="website.menu_website_configuration" name="Website Event Settings" action="action_website_event_configuration"/>
Instead of renaming the modules (which causes relational error), I found a workaround. I have inherited the main settings and put a view id there and called it with menuitem -
<!-- Bring settings menu out -->
<record id="website.action_website_configuration" model="ir.actions.act_window">
<field name="name">Website Settings</field>
<field name="res_model">website.config.settings</field>
<field name="view_mode">form</field>
<field name="target">inline</field>
<field name="view_id" ref="website.view_website_config_settings"/>
</record>
<menuitem id="website.menu_website_website_settings" parent="website.menu_website_configuration" name="Website Admin" action="website.action_website_configuration"/>
Then I called my record action and it loaded the view and action. Another catch point is I had to show website_id to show the values of specific websites or the transient model will always be empty.
Change the _name attribute in your model definition to something else and also modify the xml appropraitely.
class cofair_website_design_config(models.TransientModel):
_name = 'something.else'
_inherit = 'website.config.settings'
event_title = fields.Char(related='website_id.event_title', string='Event Title')
ir.ui.view
<field name="model">something.else</field>
and ir.actions.act_window
<field name="res_model">something.else</field>
That should copy all the fields and methods from website.config.settings to the new model something.else and keep it separate from website.config.settings
In the Account and Finance module i want to add a new field but do not want to change the current form view and also I don't want to override it. I know to create a new class and declare _inherit attribute, declare new fields there, but i think it will override the original form view.
I want both(original and inherited) form view to appear so that i can choose them based on my requirements. Is it possible?
(I desire to add discounts field in my inherited form view)
<?xml version="1.0"?>
<openerp>
<data>
<!-- 1st part of the sim_view start -->
<record model="ir.ui.view" id="account.partner_view_buttons">
<field name="name">partner.view.buttons</field>
<field name="model">res.partner</field>
<field name="inherit_id" ref="base.view_partner_form" />
<field name="type">form</field>
<field name="arch" type="xml">
<xpath expr="//div[#name='buttons']" position="inside">
<button type="action" class="oe_stat_button" id="invoice_button" icon="fa-pencil-square-o" name="464" attrs="{'invisible': [('customer', '=', False)]}" context="{'search_default_partner_id': active_id,'default_partner_id': active_id}">
<div><strong><field name="total_invoiced" widget="monetary"/></strong><br/>Invoiced</div>
</button>
</xpath>
</field>