I am studying for an SQL test and the previous year has the final question:
Name the student who has studied the least number of papers. How many
papers have they studied?
So far, this is the select query that I have created:
select min(Full_Name), min(Amount)
from (select st.ST_F_Name & ' ' & st.ST_L_Name as Full_Name, count(*) as Amount
from (student_course as sc
inner join students as st
on st.ST_ID=sc.SC_ST_ID)
group by st.ST_F_Name & ' ' & st.ST_L_Name)
This works perfectly for returning the result I want but I'm not sure if this is the way I should be doing this query? I feel like calling min() on the Full_Name could potentially backfire on me under certain circumstances. Is there a better way to be doing this? (this is in MS Access for unknown reasons)
If you want only 1 of such students if there are multiple, this is probably the simplest:
select st.ST_F_Name, st.ST_L_Name, count(*) as Amount
from student_course as sc
inner join students as st
on st.ST_ID=sc.SC_ST_ID
group by st.ST_ID
order by Amount ASC LIMIT 1
However, if you want to find all stuch students, you follow a different approach. We use a WITH clause to simplify things, that defines a CTE (Common Table Expression) computing the number of courses per-student. And then we select students where their number equals to the minimum in that CTE:
with per_student as (
select st.ST_F_Name, st.ST_L_Name, count(*) as Amount
from student_course as sc
inner join students as st
on st.ST_ID=sc.SC_ST_ID
group by st.ST_ID
)
select * from per_student
where amount = (select min(amount) from per_student)
But the real trick in that question is that there might be students that didn't take ANY courses. But with approaches presented so far you'll never see them. You want something like this:
with per_student as (
select st.ST_F_Name, st.ST_L_Name, count(sc.SC_ST_ID) as Amount
from student_course as sc
right outer join students as st
on st.ST_ID=sc.SC_ST_ID
group by st.ST_ID
)
select * from per_student
where amount = (select min(amount) from per_student)
You can order by count(*) to get the student with the least # of papers:
i.e.
select * from students where st_id in (
select top 1 sc_st_id
from student_course
group by sc_st_id
order by count(*)
)
if you also need the # of papers studied, then join a derived table containing the min count:
select * from students s
left join (
select top 1 sc_st_id, count(*)
from student_course
group by sc_st_id
order by count(*)
) t on t.sc_st_id = s.st_id
Related
I am trying to query some data from SQL Server 2012 using sub query. I am trying to get first 3 records for each Id returned by Sub Query but I am not getting the idea how to do so for now I write this query:
Select * from Student Where TeacherId in (Select TeacherId from Teacher)
I am not sure if this is achievable by using such query or do I have to write a function or any thing else ?
Any Suggestions would be great and sorry for my bad explanation skills.
You should join the Teacher to Student table, and then use an analytic function to get the first there records for each teacher:
SELECT *
FROM
(
SELECT
s.*, t.TeacherId, t.TeacherName,
ROW_NUMBER() OVER (PARTITION BY t.TeacherId ORDER BY some_col) rn
FROM Teacher t
INNER JOIN Student s
ON t.TeacherId = s.TeacherId
) t
WHERE rn = 3;
I assume that there is a column in one of the two tables some_col which you want to use for ordering. It does not make much sense to speak of the first three records without also defining some ordering.
I guess you want the top 3 rows for each ids, not top 3 rows for entire result set
WITH CTE AS
(
SELECT *,
ROW_NUMBER() OVER (PARTITION BY t.TeacherId ORDER BY ?) Seq
FROM Student s
INNER JOIN Teacher t ON t.TeacherId = s.TeacherId
)
SELECT * FROM CTE
WHERE Seq between 1 AND 3
? placeholder requires column_name to generate the sequence_number to get the result with boundary of 1 to 3 .
How do I combine both in order to show the student name (sname) and section number (sectno) for a class that has more than 6 student? So far I have this
SELECT student.sname, enroll.sectno,
FROM student
INNER JOIN enroll
ON student.sid=enroll.sid
with
SELECT grade,
COUNT(grade)AS Frequency
FROM enroll
GROUP BY grade
HAVING COUNT(grade)>6
looks like you were very close. I think the below should work for you:
SELECT
student.sname,
enroll.sectno,
COUNT(enroll.grade) AS Frequency
FROM student
INNER JOIN enroll ON student.sid=enroll.sid
GROUP BY student.sname, enroll.sectno
HAVING COUNT(enroll.grade)>6
In your 2md Select there's no relation to a class that has more than 6 student, IMHO the GROUP BY should be based on column like classid. And then you can simply combine both using a Windowed Aggregate:
with cte as
(
SELECT student.sname, enroll.sectno,
-- get the count per class, might be a different column than sectno
count(*) over (partition by enroll.sectno) as cnt
FROM student
INNER JOIN enroll
ON student.sid=enroll.sid
)
select * from cte
where cnt > 6
So i woud like to find the department name or department id(dpmid) for the group that has the max average of age among the other group and this is my query:
select
MAX(avg_age) as 'Max average age' FROM (
SELECT
AVG(userage) AS avg_age FROM user_data GROUP BY
(select dpmid from department_branch where
(select dpmbid from user_department_branch where
user_data.userid = user_department_branch.userid)=department_branch.dpmbid)
) AS query1
this code show only the max value of average age and when i try to show the name of the group it will show the wrong group name.
So, How to show the name of max group that has subquery from another table???
You may try this..
select MAX(avg_age) as max_avg, SUBSTRING_INDEX(MAX(avg_age_dep),'##',-1) as max_age_dep from
(
SELECT
AVG(userage) as avg_age, CONCAT( AVG(userage), CONCAT('##' ,department_name)) as avg_age_dep
FROM user_data
inner join user_department_branch
on user_data.userid = user_department_branch.userid
inner join department_branch
on department_branch.dpmbid = user_department_branch.dpmbid
inner join department
on department.dpmid = department_branch.dpmid
group by department_branch.dpmid
) tab_avg_age_by_dep
;
I've done some change on ipothesys that the department name is placed in a "department" anagraphical table.. so, as it needed put in join a table in plus, then I changed your query, eventually if the department name is placed (but I don't thing so) in the branch_department table you can add the field and its treatment to your query
update
In adjunct to as said, if you wanto to avoid identical average cases you can furtherly make univocal the averages by appending a rownum id in this way:
select MAX(avg_age) as max_avg, SUBSTRING_INDEX(MAX(avg_age_dep),'##',-1) as max_age_dep from
(
SELECT
AVG(userage) as avg_age, CONCAT( AVG(userage), CONCAT('##', CONCAT( #rownum:=#rownum+1, CONCAT('##' ,department_name)))) as avg_age_dep
FROM user_data
inner join user_department_branch
on user_data.userid = user_department_branch.userid
inner join department_branch
on department_branch.dpmbid = user_department_branch.dpmbid
inner join department
on department.dpmid = department_branch.dpmid
,(SELECT #rownum:=0) r
group by department_branch.dpmid
) tab_avg_age_by_dep
;
I took a shot at what I think you are looking for. The following will give you the department branch with the highest average age. I assumed the department_branch table had a department_name field. You may need an additional join to get the department.
SELECT db.department_name, udb.dpmid, AVG(userage) as `Average age`
FROM user_data as ud
JOIN user_department_branch as udb
ON udb.userid = ud.userid
JOIN department_branch as db
ON db.dpmbid = udb.dpmbid
GROUP BY udb.dpmid
ORDER BY `Average age` DESC
LIMIT 1
I'm seriously stuck. Please bear with me though because I'm new to databases.:)
Anyway, I need to display the StudentID, the subject where the student has the highest grade in, and the grade of that subject.
Here's the code I have:
SELECT
Grades.Student_ID,
Subject.Subject_Code,
MAX(Grades.Grade)
FROM
Grades
LEFT JOIN
Subject ON Grades.Subject_ID = Subject.Subject_ID
GROUP BY
Grades.Student_ID
But it has this error:
'Subject.Subject_Code' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.'
But I can't include Subject_Code in GROUP BY because the results will be different.
What can I do to only show the
Student_ID || (subject with highest grade) || (grade of that subject)
How can I work around this error?
It seems you are looking for a group wise maximum. Here's one approach joining back to a derived table containing the top grade for each student (This approach should work on most RDBMS, including MySql):
SELECT X.Student_ID,
s.Subject_Code,
x.TopGrade
FROM
(
SELECT
Grades.Student_ID,
MAX(Grades.Grade) AS TopGrade
FROM Grades
GROUP BY Grades.Student_ID
) x
INNER JOIN Grades g
ON g.Student_ID = x.Student_ID AND g.Grade = x.TopGrade
LEFT JOIN Subject s
ON g.Subject_ID = s.Subject_ID
If the same student has two or more marks with exactly the same grade, it will return all Subjects.
Here's my original answer, which will work on SQL Server
SELECT x.Student_ID, x.Subject_Code, x.Grade
FROM
(
SELECT
Grades.Student_ID,
Subject.Subject_Code,
RANK() OVER (PARTITION BY Grades.Student_ID ORDER BY Grades.Grade DESC) AS [Rank],
Grades.Grade
FROM Grades
LEFT JOIN Subject
ON Grades.Subject_ID = Subject.Subject_ID
) x
WHERE x.[Rank] = 1;
SqlFiddle of both the above queries here. In addition, there is an example with ROW_NUMBER with an additional arbitrary ORDER BY to pick one top subject when the student has equal marks in two or more subjects.
I have ran a query to give me the total number of students within each school but now I need to know the name of those students within each school while keeping the top result by total number at the top. How can I add to this query to show me the names of the students?
Here is what I have to show me the total number of students at each school:
SELECT
dbo_Schools.Schools,
Count(dbo_tStudent.Student) AS NumberOfStudents
FROM
dbo_tStudent
INNER JOIN dbo_tSchools ON dbo_tStudent.SchoolID=dbo_tSchool.SchoolID
GROUP BY dbo_tSchool.School
ORDER BY Count(dbo_tStudent.Student) DESC;
Its important that I keep the schools in order from top number of students while listing the students
In this case you could use a Sub Query to achieve your resultset.
To use order by inside a subquery, you will also need a top or limit operator.
SELECT sc.schoolname
,st.columns...
FROM dbo_tStudent st
INNER JOIN (
SELECT TOP 1000 dbo_Schools.SchoolID
,min(schoolname) schoolname
,Count(dbo_tStudent.Student) AS NumberOfStudents
FROM dbo_tStudent
INNER JOIN dbo_tSchools ON dbo_tStudent.SchoolID = dbo_tSchools.SchoolID
GROUP BY dbo_tSchool.School
ORDER BY Count(dbo_tStudent.Student) DESC
) sc ON st.SchoolID = sc.SchoolID
Assuming that you are using SQL Server, you can use a CTE to join the first aggregate with the details like this:
;WITH cte as (
SELECT TOP 1000 dbo_Schools.SchoolID, Count(dbo_tStudent.Student) AS NumberOfStudents
FROM
dbo_tStudent
INNER JOIN dbo_tSchools ON dbo_tStudent.SchoolID = dbo_tSchools.SchoolID
GROUP BY dbo_tSchool.School
ORDER BY Count(dbo_tStudent.Student) DESC
)
SELECT
sc.<your school name column>,
st.<your student columns>
from
dbo_tStudent st
INNER JOIN cte ON st.SchoolID = cte.SchoolID
INNER JOIN dbo_tSchools sc on cte.SchoolID = sc.SchoolID
More generally speaking: you need a derived table (your aggregation containing the group by clause) that is joined with the select statement for the student details. In this example, the CTE basically is a SQL Server feature that facilitates the use of derived tables.