My macro is supposed to do the following:
Look for instances of double spaces.
Replace those instances of double spaces with single spaces.
Go through the document again to see if there are any more double spaces and to replace them, if there are. For instance, if there were originally 4 spaces in a row somewhere, there will still be double spaces, so, replace remaining double spaces with single spaces.
Repeat the previous step until there are no more double spaces.
The problem is that the macro works perfectly in debug mode but only runs one pass if run normally. What am I doing wrong? Please note that my code may not be the most compact, but that's not the point; what I'm really wondering is why the code only works in debug mode and not in normal run mode, and how this can be fixed.
Sub Test_for_doubles()
'
' Test_for_doubles Macro
'
Dim blnFoundDoubles As Boolean
blnFoundDoubles = True
Do While blnFoundDoubles = True
Selection.HomeKey Unit:=wdStory 'Go to the beginning of the document.
blnFoundDoubles = False 'Don't go through this loop again unless we find a double this time through
With Selection.Find
.Text = " "
.Replacement.Text = " "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
If .Found = True Then
blnFoundDoubles = True
End If
End With
Selection.Find.Execute Replace:=wdReplaceAll
Loop
End Sub
I've always found that testing the Found property is a bit hit-and-miss: sometimes it works, sometimes not. I prefer to declare a Boolean variable and assign it to Find.Execute since the method returns True if the find is successful, otherwise False.
The code you show has another problem: it's testing Found before the Find is executed. Try changing your code to something more like this:
Dim blnFoundDoubles As Boolean
Dim bFound as Boolean
blnFoundDoubles = True
bFound = False
Do While blnFoundDoubles = True
Selection.HomeKey Unit:=wdStory 'Go to the beginning of the document.
blnFoundDoubles = False 'Don't go through this loop again unless we find a double this time through
With Selection.Find
.Text = " "
.Replacement.Text = " "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
bFound = .Execute(Replace:=wdReplaceAll)
If bFound Then
blnFoundDoubles = True
End If
'OR
'blnFoundDoubles = bFound
End With
Loop
Related
I am using Word VBA. I want to find a specific keyword "MyTest" from the beginning of the document, and then repeat until all of occurrences are found. How to do so?
I use macro record, and get the following codes:
Selection.Find.ClearFormatting
With Selection.Find
.Text = "MyTest"
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchByte = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute
This seems only start the find from the current position and will return one instance of the keyword?
The macro recorder will not give you the best code as it can only record what you do on screen. This means that it always works with the Selection object, i.e. whatever you have selected on screen.
Instead you should use a Range object set to the the part of the document you want to work with. Unless you are using ReplaceAll you also need to repeatedly execute the Find until you have found all the matches.
Below is a generic routine that you can modify.
Sub FindSomeTextAndDoSomething(textToFind As String)
Dim findRange As Range
Set findRange = ActiveDocument.Content
With findRange.Find
.ClearFormatting
.Text = textToFind
.Replacement.Text = ""
.Wrap = wdFindStop
.Format = False
Do While .Execute = True
'add code here to do something with the found text
'collapse range to continue
findRange.Collapse wdCollapseEnd
Loop
End With
End Sub
I want change a word to superscript in macro.
word 2016.
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "7th of every month."
.Replacement.Text = "7^th of every month."
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchAllWordForms = False
.MatchWholeWord = True
.MatchWildcards = False
.MatchSoundsLike = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
when i run the macro instead of making "th" as supercript it just create space between "7" and "h"
Result is like this "The meeting is on 7 h of every month."enter image description here
The following code searches for one or two digits, immediately followed by th and superscripts the th. This makes it more flexible than searching the specific string.
It works with a Range rather than a Selection object which will make it faster. The search type is a "wildcard" search.
Sub SuperScript_th_()
Dim rngFind As Word.Range
Dim searchText As String
Dim found As Boolean
Set rngFind = ActiveDocument.content
searchText = "[0-9]{1;2}th"
'searchText = "7th"
With rngFind.Find
.Text = searchText
.MatchWildcards = True
.wrap = wdFindStop
found = .Execute
Do While found
rngFind.Collapse wdCollapseEnd
rngFind.MoveStart wdCharacter, -2
rngFind.Font.Superscript = True
rngFind.End = ActiveDocument.content.End
found = .Execute
Loop
End With
End Sub
The ^t is the instruction in Word's Find to insert a TAB (like pressing the Tab-key on the keyboard). That's why the code in the quesiton is inserting space between the 7 the h in the Replacement.Text.
While Word's Find/Replace is able to format text as part of the Replacement, the difficulty here is that
Not all the text being found should be formatted
The entire text needs to be retained
It's not possible to tell Find/Replace to find text, then format only part of it. That's why the Find needs to be separate from the formatting action. If the entire found text needed to be formatted, then Find/Replace alone would work.
There are also no commands in Word's Find/Replace to apply formatting as a "code" in the Replacement.Text string.
Why don't simply try like this
With Selection.Find
.Text = "7th of every month."
'.Replacement.Text = "7^th of every month."
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchAllWordForms = False
.MatchWholeWord = True
.MatchWildcards = False
.MatchSoundsLike = False
Do While .Execute
ActiveDocument.Range(Selection.Range.Start + 1, Selection.Range.Start + 3).Font.Superscript = True
Loop
End With
Edit: With turning off some word options etc the 8 sec time to process 60 pages and 1240 replacement may be reduced to around 2 seconds. the test code
Sub test2()
Dim Rng As Range, tm As Double
tm = Timer
TurnOnOff False
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "7th of every month."
X = 0
Do While .Execute
ActiveDocument.Range(Selection.Range.Start + 1, Selection.Range.Start + 3).Font.Superscript = True
X = X + 1
Loop
End With
Debug.Print X, Timer - tm
TurnOnOff True
End Sub
Sub TurnOnOff(OnOff As Boolean)
Application.ScreenUpdating = OnOff
With Options
.Pagination = OnOff
.CheckSpellingAsYouType = OnOff
.CheckGrammarAsYouType = OnOff
End With
End Sub
I am trying to create VBA to insert before and after Supercript and subscript. My code is below.
Public Sub MySubscriptSuperscript()
Dim myRange As Word.Range, myChr
For Each myRange In ActiveDocument.StoryRanges
Do
For Each myChr In myRange.Characters
If myChr.Font.Superscript = True Then
myChr.Font.Superscript = False
myChr.InsertBefore "<sup>"
myChr.InsertAfter "</sup>"
End If
If myChr.Font.Subscript = True Then
myChr.Font.Subscript = False
myChr.InsertBefore "<sub>"
myChr.InsertAfter "</sub>"
End If
Next
Set myRange = myRange.NextStoryRange
Loop Until myRange Is Nothing
Next
End Sub
This code is working good for each character of superscript and subscript.
But, I am looking for VBA which insert tags before and after complete superscript/subscript word/letters.
Example
C12H22O11 and x23 + y397 + x67
Above VBA is giving following Output
C<sub>1</sub><sub>2</sub>H<sub>2</sub><sub>2</sub>O<sub>1</sub><sub>1</sub><sub> </sub><sub> </sub> and x<sup>2</sup><sup>3</sup> + y<sup>3</sup><sup>9</sup><sup>7</sup> + x<sup>6</sup><sup>7</sup>
But I am looking for this output
C<sub>12</sub>H<sub>22</sub>O<sub>11</sub> and x<sup>23</sup> + y<sup>397</sup> + x<sup>67</sup>
Pls guide, how this can be achieved.
I would be tempted to go for easiest way to get the end result - at the end, simply do a replace of </sub><sub> and </sup><sup> with an empty string "".
But then, I am lazy this way...
Edit - just an idea:
wouldn't it be faster to do the whole thing with replace? You wouldn't have to check every character. Here is what Word does record for the replacement, it would need a bit of polishing:
Selection.Find.Replacement.ClearFormatting
With Selection.Find.Replacement.Font
.Superscript = False
.Subscript = False
End With
With Selection.Find
.Text = "^?"
.Replacement.Text = "<sup>^&</sup>"
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
So, at the end, you would run search&replace 4 times:
replace superscript
delete the closing and opening tags for superscript
replace subscript
delete the closing and opening tags for subscript
Try:
Sub Demo()
Application.ScreenUpdating = False
With ActiveDocument.Range
With .Find
.ClearFormatting
.Replacement.ClearFormatting
.Forward = True
.Text = ""
.Wrap = wdFindContinue
.Font.Subscript = True
.Replacement.Text = "<sub>^&<\sub>"
.Execute Replace:=wdReplaceAll
.Font.Superscript = True
.Replacement.Text = "<sup>^&<\sup>"
.Execute Replace:=wdReplaceAll
End With
End With
Application.ScreenUpdating = True
End Sub
It's not apparent why you'd be looping through all storyranges, as such content would ordinarily only be in the document body. That said, it's easy enough to modify the code to work with all storyranges.
I have a document that contains the following text format that occurs throughout:
5:43-64
I want to search and replace so that the text reads like so:
5:43-64 indicates:
Fortunately, the - only appears in this type of text. The numbers change in each instance. So I don´t think I have to worry about some complicated search pattern. I can just search for the - character.
I want to then take whatever is after the the - and then save it as a variable then insert the text indicates afterward. I need this to loop through the whole document making these changes at any occurrence of the -.
Here is the code that I have up to this point that kind of half works:
Sub placeWordAfterDash()
Selection.Find.ClearFormatting
With Selection.Find
.Text = "-"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
If Selection.Find.Execute Then
Dim selectedString As String
Selection.Select
selectedString = Selection.Next(Unit:=wdWord, Count:=1).Text
Selection.Text = "-" & selectedString & " indicates: "
End If
End Sub
This code only makes the change in one instance and also leaves me with:
5:43-64 indicates: 64
Which isn´t quite what I want.
You don't need to use vba to do this find-replace, you can do it with a simple wildcard find-replace.
press CTRL+H, find (-<*>), Replace with \1 indicates: (make sure to check "Use Wildcards")
If you do want to use vba:
Selection.Find.ClearFormatting
With Selection.Find
.Text = "(-<*>)"
.Replacement.Text = "\1 indicates:"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
I'm trying to create a macro in word to find particular cells in a table and replace certain strings there. For example:
(word1 or word2 or word3).ab,ti.
Should be replaced by
word1[TIAB] or word2[TIAB] or word3[TIAB]
So, what I've done so far is a simple replaceAll to delete the initial brackets and replace the suffix ").ab,ti." by "[TIAB]. But that doesn't append the endings to word1 and word2, of course.
Sub Makro6()
'
' Makro6 Makro
'
'
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = ".ab,ti."
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
I guess what I need is to embed a loop in the replaceAll sub, which runs from the first position to the end of the current row and replaces the string " or " by "[TIAB] or ". However, I'm completely new to VBA so I somehow can't figure out how to do this. Any suggestions?
Thanks for your help!
Leni
This code performs the actions you want:
Sub Makro6()
Dim maxCount, curCount As Integer
maxCount = 3
curCount = 0
Do
curCount = curCount + 1
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = Chr(40) & "word" & curCount & Chr(41) & ".ab,ti."
.Replacement.Text = "word" & curCount & "[TIAB]"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = False
.Execute Replace:=wdReplaceAll
End With
Loop While (curCount < maxCount)
End Sub
Note that I had to rely on ASCII codes (Chr(40) & Chr(41)) to account for the parenthesis because surprisingly (at least, for me), the macro wasn't able to find the target string. I did some tests and the problem only happens with parenthesis followed by another character (?!).