select average of top 3 for each specific sql job - sql

Question

SELECT jobs.Job_ID AS JobID ,
jobs.NAME AS JobName ,
act.start_execution_date AS StartExecutionDate ,
AVG(FLOOR(run_duration / 100)) AS AvgDurationMin ,
CASE
--If job average less than 5 minutes then limit is avg+10 minutes
WHEN AVG(FLOOR(run_duration / 100)) <= 5
THEN ( AVG(FLOOR(run_duration / 100)) ) + 2
--If job average greater than 5 minutes then limit is avg*limit percentage
ELSE ( AVG(FLOOR(run_duration / 100))
)
END AS DurationLimit ,
DATEDIFF(MI, act.start_execution_date, GETDATE()) AS [CurrentDuration]
FROM #currently_running_jobs crj
INNER JOIN msdb..sysjobs AS jobs ON crj.job_id = jobs.job_id
INNER JOIN msdb..sysjobactivity AS act ON act.job_id = crj.job_id
AND act.stop_execution_date IS NULL
AND act.start_execution_date IS NOT NULL
INNER JOIN msdb..sysjobhistory AS hist ON hist.job_id = crj.job_id
AND hist.step_id = 0
WHERE crj.job_state = 1 --and jobs.NAME = 'long_running_testing'
GROUP BY jobs.job_ID ,
jobs.NAME ,
act.start_execution_date ,
DATEDIFF(MI, act.start_execution_date, GETDATE())
HAVING CASE WHEN AVG(FLOOR(run_duration / 100)) <= 5
THEN (AVG(FLOOR(run_duration / 100))) + 2
--THEN ( AVG(FLOOR(run_duration / 100)) ) + 1
ELSE ( AVG(FLOOR(run_duration / 100))
)
END < DATEDIFF(MI, act.start_execution_date, GETDATE())
Can someone please help me to extract the average run_duration of recent three entries of job's partitioned by job_name?
Please find the below script which I used to extract information
of recent three run_duration partitioned by job_name, but it
calculates the average of all run_duration .
Here I need only the recent three run_duration average count.
SELECT top 1 with ties jobs.Job_ID AS JobID , AVG(FLOOR(run_duration/100%100 )),
jobs.NAME AS JobName ,
act.start_execution_date AS StartExecutionDate
from msdb..sysjobs AS jobs
inner join msdb..sysjobactivity AS act ON act.job_id = jobs.job_id
INNER JOIN msdb..sysjobhistory AS hist ON hist.job_id = jobs.job_id AND hist.step_id = 0
GROUP BY jobs.job_ID ,
jobs.NAME
, act.start_execution_date ,hist.run_duration,
DATEDIFF(MI, act.start_execution_date, GETDATE())
order by case when row_number() over (partition by jobs.NAME order by hist.run_duration desc) <= 3 then 0 else 1 end;

Answer 1

Perhaps a CTE would simplify it.
with SeqByJob_cte as ( SELECT jobs.NAME AS JobName
,hist.run_duration
,row_number() over(partition by jobs.NAME order by act.start_execution_date desc) as seq
from msdb..sysjobs AS jobs
inner join msdb..sysjobactivity AS act ON act.job_id = jobs.job_id
INNER JOIN msdb..sysjobhistory AS hist ON hist.job_id = jobs.job_id AND hist.step_id = 0)
select avg(run_duration) as AvgOf3MostRecentRuns
,CASE
--If job average less than 5 minutes then limit is avg+10 minutes
WHEN AVG(FLOOR(run_duration / 100)) <= 5
THEN ( AVG(FLOOR(run_duration / 100)) ) + 2
--If job average greater than 5 minutes then limit is avg*limit percentage
ELSE ( AVG(FLOOR(run_duration / 100))
)
END AS DurationLimit
,JobName
from SeqByJob_cte
where seq <= 3
group by JobName