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I want to assign one unique number for each repeated row in select statement.
table
Name | Position
Mark Wol 1
Mark wol 1
MArtha 1
Martha 1
and I want this
1 Mark Wl 1
2 Martha 1
You can use as few or as many rows as you want. If you want to use all of the rows, list them all.
SELECT Row1, Row2, Row3,
ROW_NUMBER() OVER (
PARTITION BY Row1, Row2, Row3,
ORDER BY Row1
)
FROM Table
The best solution is to already have a unique ID for each record and then you are choosing to show that (which will come from the first found record)...
SELECT name,COUNT(*),id
FROM test_table
GROUP BY name
HAVING COUNT(*) > 1
Related
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I have a table with column name No, which have duplicate values (which is necessary). I need to add an incrementing value in another column sub_no
For Example:
No
sub_no
1
0
1
1
1
2
2
0
2
1
3
0
3
1
3
2
3
3
I have tried update and select queries.
A window function will give you the results you want:
SELECT [No], ROW_NUMBER() OVER(PARTITION BY [No] ORDER BY [No]) - 1 AS
[sub_no]
FROM <table_name>;
You can find more information on window functions in T-SQL here.
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I know how to do running sum but can't figure out how to do running subtract.
Example: we have single column of data and a new column will be formed for running subtraction.
Value
------
10
1
3
4
Output needs to be:
10
9
6
2
I need both these columns next to each other
Any suggestion please.
Your question only makes sense if you have a column that specifies the ordering. In that case:
select (case when row_number() over (order by <ordercol>) = 1
then col
else 2 * first_value(col) over (<ordercol>) - sum(col) over (order by <ordercol>)
end) as output
from t;
That is, return the column value on the first row. Otherwise, the math is a little tricky. But you want the first value minus the sum of the rest of the column. Arithmetically, this is the same as twice the first value minus the cumulative sum.
EDIT:
As Shawn points out, this can be simplified to:
select 2 * first_value(col) over (<ordercol>) - sum(col) over (order by <ordercol>) as output
from t;
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Need a query to check ids with multiple revisionnums
id reviionnum
1 0
2 0
1 1
3 1
2 1
The query should result
id revisionnum
3 1
Please help
If you want ids with only one revision number, you can use aggregation:
select id, min(revissionnum)
from t
group by id
having count(*) = 1;
The min() is the value if there is only one row.
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I am looking for a way to exclude a single column from being sorted using SQL select statement.
Lets say a table has 10 columns and when an ORDER BY is done on a specific column using select statement, all the 10 columns are sorted. Is it possible to exclude any specific column (say column 6) from being sorted? If so how.
**
Before
ID name
-----------
1 papaya
2 apple
3 strawberry
4 banana
Required
ID name
-----------
1 apple
2 banana
3 papaya
4 strawberry
Appreciate your help
This will generate the ids and they will be always shown in order but that won't be the actual id, you might need that as well
SELECT #a:=#a+1 id,name from tableName order by name
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I have a table (for the sake of the exercise let's call it Persons)
I am trying to create a query that will generate the CrDRN number.
The CrDRN column should contain the DRN number of the last record that has a VoucherType = 80
In this instance the CrDRN column would have the values 1 1 1 5 5
Any help would be greatly appreciated.
The CrDRN column should contain the DRN number of the last record that
has a VoucherType = 80
Another way of saying that would be to get the max value of DRN where DRN is less than or equal to the current DRN and where VoucherType is 80.
You can formulate just that in a subquery that returns CrDRN.
select T1.DRN,
T1.VoucherType,
(
select max(T2.DRN)
from T as T2
where T2.DRN <= T1.DRN and
T2.VoucherType = 80
) as CrDRN
from T as T1