I am trying to output a blank row after each row.
For example:
SELECT id,job,amount FROM table
+----+-----+--------+
| id | job | amount |
+----+-----+--------+
| 1 | 100 | 123 |
| 2 | 200 | 321 |
| 3 | 300 | 421 |
+----+-----+--------+
To the following:
+----+-----+--------+
| id | job | amount |
+----+-----+--------+
| 1 | 100 | 123 |
| | | |
| 2 | 200 | 321 |
| | | |
| 3 | 300 | 421 |
+----+-----+--------+
I know I can do similar things with a UNION like:
SELECT null AS id, null AS job, null AS amount
UNION
SELECT id,job,amount FROM table
Which would give me a blank row at the beginning, but for the life of me I can't figure out how to do it every second row. A nested SELECT/UNION? - Have tried but nothing seemed to work.
The DBMS is SQL Server 2016
This is an akward requirement, that would most probably better handled on application side. Here is, however, one way to do it:
select id, job, amount
from (
select id, job, amount, id order_by from mytable
union all
select null, null, null, id from mytable
) t
order by order_by, id desc
The trick is to add an additional column to the unioned query, that keeps track of the original id, and can be used to sort the records in the outer query. You can then use id desc as second sorting criteria, which will put null values in second position.
Demo on DB Fiddle:
with mytable as (
select 1 id, 100 job, 123 amount
union all select 2, 200, 321
union all select 3, 300, 421
)
select id, job, amount
from (
select id, job, amount, id order_by from mytable
union all
select null, null, null, id from mytable
) t
order by order_by, id desc;
id | job | amount
---: | ---: | -----:
1 | 100 | 123
null | null | null
2 | 200 | 321
null | null | null
3 | 300 | 421
null | null | null
In SQL Server, you can just use apply:
select v.id, v.job, v.amount
from t cross apply
(values (id, job, amount, id, 1),
(null, null, null, id, 2)
) v(id, job, amount, ord1, ord2)
order by ord1, ord2;
I wrote a pretty big sql query that joins (outer join) two similar queries. Each one of them returns a table in format:
date | value1(q1)
-----------+-----------
05-06-2010 | 10
05-07-2017 | 12
And the same for the second subquery. After i join them i get a following table:
date | value1(q1) | date | value(q2)
-----------+------------+------------+--------
05-06-2010 | 10 | NULL | NULL
05-07-2017 | 12 | NULL | NULL
NULL | NULL | 05-07-2010 | 15
NULL | NULL | 01-02-2008 | 17
I tried wrapping everything in a CONCAT, but it doesn't work.
How to get result in such a form:
date | value1(q1) | value(q2)
-----------+------------+-----------
05-06-2010 | 10 | 0
05-07-2017 | 12 | 10
07-08-2018 | 14 | 17
Try this below script-
SELECT [date],
SUM([value1(q1)]) AS 'value1(q1)',
SUM([value(q2)]) AS 'value(q2)'
FROM
(
SELECT [date],
[value1(q1)] AS 'value1(q1)',
0 AS 'value(q2)'
FROM your_table_1
UNION ALL
SELECT [date],
0 AS 'value1(q1)',
[value(q2)] AS 'value(q2)'
FROM your_table_2
)A
GROUP BY [date]
I think you want a full join:
select coalesce(q1.date, q2.date) as date,
coalesce(q1.value, 0) as value1,
coalesce(q2.value, 0) as value2
from q1 full join
q2
on q1.date = q2.date;
I am new to sql and need your help to achieve the below , I have tried using group and count functions but I am getting all the rows in the unique group which are duplicated.
Below is my source data.
CDR_ID,TelephoneNo,Call_ID,call_Duration,Call_Plan
543,xxx-23,12,12,500
543,xxx-23,12,12,501
543,xxx-23,12,12,510
643,xxx-33,11,17,700
343,xxx-33,11,17,700
766,xxx-74,32,1,300
766,xxx-74,32,1,300
877,xxx-32,12,2,300
877,xxx-32,12,2,300
877,xxx-32,12,2,301
Please note :-the source has multiple combinations of unique records, so when I do the count the unique set is not appearing as count =1
example :- the below data in source have 60 records for each combination
877,xxx-32,12,2,300 -- 60 records
877,xxx-32,12,2,301 -- 60 records
I am trying to get the unique unique records, but the duplicate records are also getting in
Below are the rows which should come up in the unique group. i.e. there will be multiple call_Plans for the same combinations of CDR_ID,TelephoneNo,Call_ID,call_Duration. I want to read records for which there is only one call plan for each unique combination of CDR_ID,TelephoneNo,Call_ID,call_Duration,
CDR_ID,TelephoneNo,Call_ID,call_Duration,Call_Plan
643,xxx-33,11,17,700
343,xxx-33,11,17,700
766,xxx-74,32,1,300
Please advice on this.
Thanks and Regards
To do more complex groupings you could also use a Common Table Expression/Derived Table along with windowed functions:
declare #t table(CDR_ID int,TelephoneNo nvarchar(20),Call_ID int,call_Duration int,Call_Plan int);
insert into #t values (543,'xxx-23',12,12,500),(543,'xxx-23',12,12,501),(543,'xxx-23',12,12,510),(643,'xxx-33',11,17,700),(343,'xxx-33',11,17,700),(766,'xxx-74',32,1,300),(766,'xxx-74',32,1,300),(877,'xxx-32',12,2,300),(877,'xxx-32',12,2,300),(877,'xxx-32',12,2,301);
with cte as
(
select CDR_ID
,TelephoneNo
,Call_ID
,call_Duration
,Call_Plan
,count(*) over (partition by CDR_ID,TelephoneNo,Call_ID,call_Duration) as c
from (select distinct * from #t) a
)
select *
from cte
where c = 1;
Output:
+--------+-------------+---------+---------------+-----------+---+
| CDR_ID | TelephoneNo | Call_ID | call_Duration | Call_Plan | c |
+--------+-------------+---------+---------------+-----------+---+
| 343 | xxx-33 | 11 | 17 | 700 | 1 |
| 643 | xxx-33 | 11 | 17 | 700 | 1 |
| 766 | xxx-74 | 32 | 1 | 300 | 1 |
+--------+-------------+---------+---------------+-----------+---+
using not exists()
select distinct *
from t
where not exists (
select 1
from t as i
where i.cdr_id = t.cdr_id
and i.telephoneno = t.telephoneno
and i.call_id = t.call_id
and i.call_duration = t.call_duration
and i.call_plan <> t.call_plan
)
rextester demo: http://rextester.com/RRNNE20636
returns:
+--------+-------------+---------+---------------+-----------+-----+
| cdr_id | TelephoneNo | Call_id | call_Duration | Call_Plan | cnt |
+--------+-------------+---------+---------------+-----------+-----+
| 343 | xxx-33 | 11 | 17 | 700 | 1 |
| 643 | xxx-33 | 11 | 17 | 700 | 1 |
| 766 | xxx-74 | 32 | 1 | 300 | 1 |
+--------+-------------+---------+---------------+-----------+-----+
Basically you should try this:
SELECT A.CDR_ID, A.TelephoneNo, A.Call_ID, A.call_Duration, A.Call_Plan
FROM YOUR_TABLE A
INNER JOIN (SELECT CDR_ID,TelephoneNo,Call_ID,call_Duration
FROM YOUR_TABLE
GROUP BY CDR_ID,TelephoneNo,Call_ID,call_Duration
HAVING COUNT(*)=1
) B ON A.CDR_ID= B.CDR_ID AND A.TelephoneNo=B.TelephoneNo AND A.Call_ID=B.Call_ID AND A.call_Duration=B.call_Duration
You can do a shorter query using Windows Function COUNT(*) OVER ...
Below query will provide you the result
SELECT CDR_ID,TelephoneNo,Call_ID,call_Duration,Call_Plan, COUNT(*)
FROM TABLE_NAME GROUP BY CDR_ID,TelephoneNo,Call_ID,call_Duration,Call_Plan
HAVING COUNT(*) < 2;
It gives you with the count as well. If not required you can remove it.
Select *, count(CDR_ID)
from table
group by CDR_ID, TelephoneNo, Call_ID, call_Duration, Call_Plan
having count(CDR_ID) = 1
I have a table like the following:
+-------+--------------+
| Value | Date |
+-------+--------------+
| 14 | 10/11/2010 |
| 12 | 10/12/2010 |
| 12 | 10/13/2010 |
| 10 | 10/14/2010 |
| 8 | 10/15/2010 |
| 6 | 10/16/2010 |
| 4 | 10/17/2010 |
| 2 | 10/18/2010 |
+-------+--------------+
I would like to calculate the return (the quotient) between every row and the last row (which is with the latest date). e.g for the row with date "10/16/2010", the result should be 6/2=3
Hence, the resulting table should be
+-------+--------------+
| result| Date |
+-------+--------------+
| 7 | 10/11/2010 |
| 6 | 10/12/2010 |
| 6 | 10/13/2010 |
| 5 | 10/14/2010 |
| 4 | 10/15/2010 |
| 3 | 10/16/2010 |
| 2 | 10/17/2010 |
| 1 | 10/18/2010 |
+-------+--------------+
Is it possible to complete this? thanks you!
You can get the value you want to divide by. Since that's always going to be a single row, you can just use a cross join to join to that and perform your division. SQL Fiddle
with maxdate as
(select max([Date]) as maxdate from table1),
divby as
(select
value as divby
from
table1
inner join maxdate md
on md.maxdate = table1.[date])
select
value / divby
,[date]
from
table1
cross join divby
To break it down a bit, the first CTE (cleverly named maxdate) gets the maximum date for the whole thing. The second CTE (divby) get the value (that you will be dividing by) for that max date. As long as you only get one row back from that, you can safely use a cross join, resulting in each row in your table being divided by that one value.
Another possible solution JOIN the the table to itself.
SQL Fiddle Example
select (t1b.value / t1a.value) as result,
t1b.date from table1 t1a
join table1 t1b on t1a.date = (select max(date) from table1)
Thanks for the fiddle, Andrew! Can be accomplished like this as well if 2008 and above (fiddle: http://sqlfiddle.com/#!3/ecda1/11):
SELECT [Value] / MIN([Value]) OVER () AS result,
[Date]
FROM Table1
Running this query,
select * from table;
Returns the following
|branch | number |
-------------------
| 1 | 123 |
| 1 | 001 |
| 2 | 123 |
| 3 | 123 |
| 4 | 123 |
| 1 | 123 |
| 1 | 789 |
| 2 | 123 |
| 3 | 123 |
| 4 | 009 |
I want to find values that are unique to ONLY branch 1
| 1 | 001 |
| 1 | 789 |
Can this be done without the data being stored in separate tables? I've tried a few "select distinct" queries & don't seem to get the results I'm expecting.
SELECT branch, number
FROM table
WHERE branch = 1
GROUP BY branch, number
If you do not need any aggregates, you can use distinct instead of group by:
select distinct branch
, number
from YourTable
where branch = 1
I guess what I'm trying to say is that I want to find all numbers that are unique to ONLY branch 1. If they are found in any other branch, I don't want to see them.
I guess this is what you want.
SELECT distinct number
FROM MyTable
WHERE branch=1 and number not in
( SELECT distinct number
FROM MyTable
WHERE branch != 1 )
Try this:
SELECT branch, number
FROM table
GROUP BY branch, number
Here is a SQLFiddle for you to have a look at
If you want to limit it to only branch 1, then just add a where clause.
SELECT branch, number
FROM table
WHERE branch = 1
GROUP BY branch, number
To select all values that are unique in column number and have a branch value of 1 you can use the following code:
SELECT branch, number
FROM table1
WHERE number IN (
SELECT number
FROM table1
GROUP BY number
HAVING (COUNT(number ) = 1)
)
AND branch = 1
For a demo see http://sqlfiddle.com/#!2/97145/62