Comparing column by column between two rows in Oracle DB - sql

I need to write a query to compare column by column (ie: find differences) between two rows in the database. For example:
row1: 10 40 sometext 24
row2: 10 25 sometext 24
After the query executed, it should shows only the fields that have difference (ie: the second field)
Here's what I have done so far:
select table1.column1, table1.column2, table1.column3, table1.column4
from table1
where somefield in (field1, field2);
The above query will show me two rows one above another like this:
10 40 sometext 24
10 25 sometext 24
Then I have to manually do the comparison and it takes a lot of time b/c the row contains a lot of column.
So again my question is: How can I write a query that will show me only the columns that have differences??
Thanks

Use UNPIVOT clause (see http://www.oracle-developer.net/display.php?id=506) to turn columns into rows, then filter out the same rows (using GROUP BY HAVING COUNT and finally use PIVOT to get rows with different columns only.

To do this easily you need to query the metadata for the table to get each row. You can use the following code as a script.
Replace the define table_name with your table name and define yes_drop_it = NO. Put your raw WHERE syntax into the where_clause. The comparison logic always compares the first two rows returned for the where clause.
whenever sqlerror exit failure rollback;
set linesize 150
define test_tab_name = tst_cf_cols
define yes_drop_it = YES
define order_by = 1, 2
define where_clause = 1 = 1
define tab_owner = user
<<clearfirst>> begin
for clearout in (
select 'drop table ' || table_name as cmd
from all_tables
where owner = &&tab_owner and table_name = upper('&&test_tab_name')
and '&&yes_drop_it' = 'YES'
) loop
execute immediate clearout.cmd;
execute immediate '
create table &&test_tab_name as
select 10 as column1, 40 as column2, ''sometext'' as column3, 24 as column4 from dual
union all
select 10 as column1, 25 as column2, ''sometext'' as column3, 24 as column4 from dual
';
end loop;
end;
/
column cfsynt format a4000 word_wrap new_value comparison_syntax
with parms as (select 'parmquery' as cte_name, 'row_a' as corr_name_1, 'row_b' as corr_name_2 from dual)
select
'select * from (select ' || LISTAGG(cfcol || ' AS cf_' || trim (to_char (column_id, '000')) || '_' || column_name
, chr(13) || ', ') WITHIN GROUP (order by column_id)
|| chr(13) || ' from (select * from parmquery where row_number = 1) ' || corr_name_1
|| chr(13) || ', (select * from parmquery where row_number = 2) ' || corr_name_2
|| chr(13) || ') where ''DIFFERENT'' IN (' || LISTAGG ('cf_' || trim (to_char (column_id, '000')) || '_' || column_name, chr(13) || ', ') within group (order by column_id) || ')'
as cfsynt
from parms, (
select
'decode (' || corr_name_1 || '.' || column_name || ', ' || corr_name_2
|| '.' || column_name || ', ''SAME'', ''DIFFERENT'')'
as cfcol,
column_name,
column_id
from
parms,
all_tab_columns
where
owner = &&tab_owner and table_name = upper ('&&test_tab_name')
);
with parmquery as (select rownum as row_number, vals.* from (
select * from &&test_tab_name
where &&where_clause
order by &&order_by
) vals
) &&comparison_syntax
;

Related

ORA-01489 : result of string concatenation to long

I am creating a dynamic query from a list of tables which are their in my table called : get_table_names
My Query :
SELECT listagg('SELECT '
|| ''''
|| tbl_name
|| ''''
|| ' AS TBL , COUNT(*) as CNT FROM '
|| 'TGT_MB.'
|| tbl_name
|| ' union all'
|| CHAR(10) ) WITH GROUP ( ORDER BY tbl_name) AS sql_str
FROM get_table_names;
My get_table_names as lots of table , at least 70 table names.
The query works fine for 10 tables but more then that it throws the error like below
ORA-01489 : result of string concatenation to long
Their is some option called EXTEND that option I cannot touch as I have low level privileges.
cannot make changes to it until DBA.
Any other work around would be much appreciated like using some XMLAGG or CLOB , BLOB
Can I respectively suggest that when posting a code snippet, make it sure it runs so that people can help you more easily. eg your code above took the following debugging before we could even start to see what you want to do
SQL> SELECT listagg('SELECT '
2 || ''''
3 || table_name
4 || ''''
5 || ' AS TBL , COUNT(*) as CNT FROM '
6 || 'TGT_MB.'
7 || table_name
8 || ' union all'
9 || CHAR(10) ) WITH GROUP ( ORDER BY table_name) AS sql_str
10 FROM dba_tables
11 where owner = 'SCOTT';
|| CHAR(10) ) WITH GROUP ( ORDER BY table_name) AS sql_str
*
ERROR at line 9:
ORA-00936: missing expression
SQL> SELECT listagg('SELECT '
2 || ''''
3 || table_name
4 || ''''
5 || ' AS TBL , COUNT(*) as CNT FROM '
6 || 'TGT_MB.'
7 || table_name
8 || ' union all'
9 || chr(10) ) WITH GROUP ( ORDER BY table_name) AS sql_str
10 FROM dba_tables
11 where owner = 'SCOTT';
|| chr(10) ) WITH GROUP ( ORDER BY table_name) AS sql_str
*
ERROR at line 9:
ORA-00923: FROM keyword not found where expected
Once those fixes are done, we end up here
SQL> SELECT listagg('SELECT '
2 || ''''
3 || table_name
4 || ''''
5 || ' AS TBL , COUNT(*) as CNT FROM '
6 || 'TGT_MB.'
7 || table_name
8 || ' union all'
9 || chr(10),'' ) WITHIN GROUP ( ORDER BY table_name) AS sql_str
10 FROM dba_tables
11 where owner = 'SCOTT';
SQL_STR
-------------------------------------------------------------------------------------
SELECT 'BONUS' AS TBL , COUNT(*) as CNT FROM TGT_MB.BONUS union all
SELECT 'DEPT' AS TBL , COUNT(*) as CNT FROM TGT_MB.DEPT union all
SELECT 'EMP' AS TBL , COUNT(*) as CNT FROM TGT_MB.EMP union all
SELECT 'EMP2' AS TBL , COUNT(*) as CNT FROM TGT_MB.EMP2 union all
SELECT 'SALGRADE' AS TBL , COUNT(*) as CNT FROM TGT_MB.SALGRADE union all
which ultimately blows up when we get too many tables
SQL> SELECT listagg('SELECT '
2 || ''''
3 || table_name
4 || ''''
5 || ' AS TBL , COUNT(*) as CNT FROM '
6 || 'TGT_MB.'
7 || table_name
8 || ' union all'
9 || chr(10),'' ) WITHIN GROUP ( ORDER BY table_name) AS sql_str
10 FROM dba_tables;
FROM dba_tables
*
ERROR at line 10:
ORA-01489: result of string concatenation is too long
Now even if we use a tool (eg
https://github.com/connormcd/listagg_clob) to get the results as a clob, then I imagine you are just going to fire that SQL at the database to get a count of all tables. If that is the case, then why do you need to LISTAGG at all, just build a script to do it, ie
SELECT 'SELECT '
|| ''''
|| table_name
|| ''''
|| ' AS TBL , COUNT(*) as CNT FROM '
|| 'TGT_MB.'
|| table_name
|| ' union all'
FROM dba_tables
Spool that to a file, trim the last union all and run it as a script.
Or even better...think about what benefit the output gives you. Why does anyone need the exact row count? Querying NUM_ROWS from USER_TABLES is probably sufficient.

Get count of rows from multiple tables Redshift SQL?

I have a redshift database that is being updated with new tables so I can't just manually list the tables I want. I want to get a count of the rows of all the tables from my query. So far I have:
select 'SELECT ''' || table_name || ''' as table_name, count(*) As con ' ||
'FROM ' || table_name ||
CASE WHEN lead(table_name) OVER (order by table_name ) IS NOT NULL
THEN ' UNION ALL ' END
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME LIKE '%results%'
but when I do this I get the error:
Specified types or functions (one per INFO message) not supported on Redshift tables.
I've searched a lot but I can't seem to find a solution for my problem. Any help would be greatly appreciated. Thanks!
EDIT:
I've changed my approach to this and decided to use a for loop in R to get the row counts of each but I'm running into the issue that 'row_counts' is only saving one number, not the count of each row like I want. Here is the code:
schema <- "x"
table_prefix <- "results"
geos <- ad_districts %>% filter(geo != "geo")
row_count <- list()
i = 1
for (geo in geos){
table_name <- paste0(schema, ".", table_prefix, geo)
row_count[[i]] <- dbGetQuery(con,
paste("SELECT COUNT(*) FROM", table_name))
i = i + 1
}
Your query is doing a select * for all tables, this will take a lot of time and resources. Instead use a system table to get the same info
select name, sum(rows) as rows
from stv_tbl_perm
where name like '%results%'
group by 1
[EDIT] - I think this is the root cause - some sql functions are only supported on the leader node. Try connecting to that node and re-run your SQL.
https://docs.aws.amazon.com/redshift/latest/dg/c_sql-functions-leader-node.html
Hope this helps.
select 'select count(*) as "' || table_schema || '.' || table_name || '" from ' || table_schema || '.' || table_name || ' ;' as sql_text
from information_schema.tables
;
[EDIT - refined this a bit to generate a series of statements that can be run at once]
select rownum, case when rownum > 1 then sql_text else replace(sql_text, 'union all', '') end as sql_text
from
(
select rank() over (order by sql_text DESC) as rownum,
sql_text
from
(
select 'select ''' || table_schema || ' ' || table_name || ''' , count(*) as "' || table_schema || '.' || table_name || '" from ' || table_schema || '.' || table_name || ' union all ' as sql_text
from information_schema.tables
where table_schema = 'public'
order by table_schema, table_name
)X
)Y
order by rownum desc ;
SELECT ' Select count(*) , '''+ tablename + ''' from '+'"' + tablename +'"' +' Union ALL '
FROM pg_table_def
GROUP BY tablename
Above query eliminates any table name with space. Remove UNION ALL at the end of the query and query will be ready to be executed.

Oracle: Count non-null fields for each column in a table

I need a query to count the total number of non-null values for each column in a table. Since my table has hundreds of columns I'm looking for a solution that only requires me to input the table name.
Perhaps using the result of:
select COLUMN_NAME from ALL_TAB_COLUMNS where TABLE_NAME='ORDERS';
to get the column names and then a subquery to put counts against each column name? The additional complication is that I only have read-only access to the DB so I can't create any temp tables.
Slightly out of my league with this one so any help is appreciated.
Construct the query in SQL or using a spreadsheet. Then run the query.
For instance, assuming that your column names are simple and don't have special characters:
select replace('select ''[col]'', count([col]) from orders union all ',
'[col]', COLUMN_NAME
) as sql
from ALL_TAB_COLUMNS
where TABLE_NAME = 'ORDERS';
(Of course, this can be adapted for more complex column names, but I'm trying to show the idea.)
Then copy the code, remove the final union all and run it.
You can put this in one string if there are not too many columns:
select listagg(replace('select ''[col]'', count([col]) from orders',
'[col]', COLUMN_NAME
), ' union all '
) within group (order by column_name) as sql
from ALL_TAB_COLUMNS
where TABLE_NAME = 'ORDERS';
You can also use execute immediate using the same query, but that seems like overkill.
If you're happy with the results row-ar rather than column-ar:
SELECT 'SELECT ''dummy'', 0 FROM DUAL' FROM DUAL
UNION ALL
SELECT
' UNION ALL SELECT ''' ||
column_name ||
''', COUNT(' ||
column_name ||
') FROM ' ||
TABLE_NAME
FROM
all_tab_columns
WHERE
table_name = 'ORDERS'
This is an "SQL that writes an SQL" that you can then copy and run to get your answers. Should make a resultset that looks like:
SELECT 'dummy', 0 FROM dual
UNION ALL SELECT 'col1', COUNT(col1) FROM ORDERS
UNION ALL SELECT 'col2', COUNT(col2) FROM ORDERS
...
If you want your results column-ar:
SELECT 'SELECT '
UNION ALL
SELECT
'COUNT(' ||
column_name ||
') as count_' ||
column_name ||
', ' ||
TABLE_NAME
FROM
all_tab_columns
WHERE
table_name = 'ORDERS'
UNION ALL
SELECT 'null as dummy_column FROM ORDERS'
Should make a resultset that looks like:
SELECT
COUNT(col1) as count_col1,
COUNT(col2) as count_col2,
...
null as dummycoll FROM orders
Caveat: I don't have oracle installed anywhere I can test these, it's written from memory and may need some debugging
This will generate the SQL to get the counts in columns and will handle case sensitive column names and column names with non-alpha-numeric characters:
SELECT 'SELECT '
|| LISTAGG(
'COUNT("' || column_name || '") AS "' || column_name || '"',
', '
) WITHIN GROUP ( ORDER BY column_id )
|| ' FROM "' || table_name || '"' AS sql
FROM ALL_TAB_COLUMNS
WHERE TABLE_NAME = 'ORDERS'
GROUP BY TABLE_NAME;
or, if you have a large number of columns that is generating a string longer than 4000 characters you can use a custom aggregation function to aggregate VARCHAR2s into a CLOB and then do:
SELECT 'SELECT '
|| CLOBAgg( 'COUNT("' || column_name || '") AS "' || column_name || '"' )
|| ' FROM "' || table_name || '"' AS sql
FROM ALL_TAB_COLUMNS
WHERE TABLE_NAME = 'ORDERS'
GROUP BY TABLE_NAME;
In Oracle 19 (I used similar code in Ora 12, maybe that works too), this works without generating another select to execute:
select * from
(
select table_name, column_name,
to_number( extractvalue( xmltype(dbms_xmlgen.getxml('select count(to_char(substr('||column_name||',1,1))) c from '||table_name)) ,'/ROWSET/ROW/C')) count
from all_tab_columns where owner = user
)
--where table_name = 'MY_TABLE'
;
It will create XML with count, from which it extracts the current count. The substr and to_char functions here are used to extract first character, so it will works with CLOB columns also

Vertica. Count of Null and Not-Null of all columns of a Table

How can we get null and non-null counts of all columns of a Table in Vertica? Table can have n number of columns and for each column we need to get count of nulls and non-nulls values of that table.
For Example.
Below Table has two columns
column1 Column2
1 abc
pqr
3
asd
5
If its a specific column then we can check like
SELECT COUNT(*) FROM table where column1 is null;
SELECT COUNT(*) FROM table where column1 is not null;
Same query for column2
I checked system tables like projection_storage and others but I cant figure out a generic query which gives details by hard coding only TABLE NAME in the query.
Hello #user2452689: Here is a dynamically generated VSQL statement which meets your requirement of counting nulls & not nulls in N columns. Notice that this writes a temporary SQL file out to your working directory, and then execute it via the \i command. You only need to change the first two variables per table. Hope this helps - good luck! :-D
--CHANGE SCHEMA AND TABLE PARAMETERS ONLY:
\set table_schema '\'public\''
\set table_name '\'dim_promotion\''
---------
\o temp_sql_file
\pset tuples_only
select e'select \'' || :table_schema || e'\.' || :table_name || e'\' as table_source' as txt
union all
select * from (
select
', sum(case when ' || column_name || ' is not null then 1 else 0 end) as ' || column_name || '_NOT_NULL
, sum(case when ' || column_name || ' is null then 1 else 0 end) as ' || column_name || '_NULL' as txt
from columns
where table_schema = :table_schema
and table_name = :table_name
order by ordinal_position
) x
union all
select ' from ' || :table_schema || e'.' || :table_name || ';' as txt ;
\o
\pset tuples_only
\i temp_sql_file
You can use:
select count(*) as cnt,
count(column1) as cnt_column1,
count(column2) as cnt_column2
from t;
count() with a column name or expression counts the number of non-NULL values in the column/expression.
(Obviously, the number of NULL values is cnt - cnt_columnX.)
select column1_not_null
,column2_not_null
,column3_not_null
,cnt - column1_not_null as column1_null
,cnt - column2_not_null as column2_null
,cnt - column3_not_null as column3_null
from (select count(*) as cnt
,count (column1) as column1_not_null
,count (column2) as column2_not_null
,count (column3) as column3_not_null
from mytable
) t

SQL scripts to generate SQL scripts

Assume that the DBA_TAB_COLUMNS looks like this:
I'd like to write a SQL or PL/SQL script to generate following text:
select 'NULL' as A1, B1, QUERY, RECORD_KEY from SMHIST.probsummarym1
union all
select 'NULL' as A1, 'NULL' as B1, QUERY, RECORD_KEY from SMHIST_EIT200.probsummarym1
union all
select A1, 'NULL' as B1, QUERY, RECORD_KEY from SMHIST_EIT300.probsummarym1
the requirements are:
If the table under any of the SMHIST% schemas do not have that column, then insert a default NULL alias for that columns.
the column list is in alphabetical order.
so can anybody tell me how to write this script?
EDIT: Added better alias names and en explicit CROSS JOIN. Added XMLAGG version.
NB: LISTAGG exists from Oracle version 11.2 and onwards and returns VARCHAR2. If the output string is larger than 4000K or if on a prior version you can use XMLAGG which is a bit more cumbersome to work with (eg. http://psoug.org/definition/xmlagg.htm).
With LISTAGG (returning VARCHAR2):
SELECT LISTAGG (line,
CHR (13) || CHR (10) || 'union all' || CHR (13) || CHR (10))
WITHIN GROUP (ORDER BY sortorder)
script
FROM (SELECT line, ROWNUM sortorder
FROM ( SELECT 'select '
|| LISTAGG (
CASE
WHEN tc.column_name IS NULL
THEN
'''NULL'' as '
END
|| col_join.column_name,
', ')
WITHIN GROUP (ORDER BY col_join.column_name)
|| ' from '
|| col_join.owner
|| '.'
|| col_join.table_name
line
FROM dba_tab_columns tc
RIGHT OUTER JOIN
(SELECT DISTINCT
owner, table_name, col_list.column_name
FROM dba_tab_columns
CROSS JOIN
(SELECT DISTINCT column_name
FROM dba_tab_columns
WHERE owner LIKE 'SMHIST%') col_list
WHERE owner LIKE 'SMHIST%') col_join
ON tc.owner = col_join.owner
AND tc.table_name = col_join.table_name
AND tc.column_name = col_join.column_name
GROUP BY col_join.owner, col_join.table_name
ORDER BY col_join.owner, col_join.table_name))
With XMLAGG (returning CLOB by adding .getclobval (), note: RTRIM works here because table names cannot include ',' and ' ' (space)):
SELECT REPLACE (SUBSTR (script, 1, LENGTH (script) - 12),
'&' || 'apos;',
'''')
FROM (SELECT XMLAGG (
XMLELEMENT (
e,
line,
CHR (13)
|| CHR (10)
|| 'union all'
|| CHR (13)
|| CHR (10))).EXTRACT ('//text()').getclobval ()
script
FROM (SELECT line, ROWNUM sortorder
FROM ( SELECT 'select '
|| RTRIM (
REPLACE (
XMLAGG (XMLELEMENT (
e,
CASE
WHEN tc.column_name
IS NULL
THEN
'''NULL'' as '
END
|| col_join.column_name,
', ') ORDER BY
col_join.column_name).EXTRACT (
'//text()').getclobval (),
'&' || 'apos;',
''''),
', ')
|| ' from '
|| col_join.owner
|| '.'
|| col_join.table_name
line
FROM dba_tab_columns tc
RIGHT OUTER JOIN
(SELECT DISTINCT
owner,
table_name,
col_list.column_name
FROM dba_tab_columns
CROSS JOIN
(SELECT DISTINCT column_name
FROM dba_tab_columns
WHERE owner LIKE 'SMHIST%') col_list
WHERE owner LIKE 'SMHIST%') col_join
ON tc.owner = col_join.owner
AND tc.table_name = col_join.table_name
AND tc.column_name = col_join.column_name
GROUP BY col_join.owner, col_join.table_name
ORDER BY col_join.owner, col_join.table_name)))