I just want to convert the const char * argv[] in main method to NSArray or NSMutableArray. But I am really stuck and couldn't find any solution.
Any help will be appreciated.
You have a C-array of char * (C strings). You need to convert each C string into an NSString. Then you can add each NSString to your NSMutableArray.
int main(int argc, char *argv[]) {
NSMutableArray *results = [NSMutableArray array];
for (int i = 0; i < argc; i++) {
NSString *str = [[NSString alloc] initWithCString:argv[i] encoding:NSUTF8StringEncoding];
[results addObject:str];
}
}
Related
#import <Foundation/Foundation.h>
int main(int argc, const char * argv[]) {
#autoreleasepool {
NSMutableArray *groceries;
NSString *a = (#"loaf of bread");
NSString *b = (#"stick of butter");
NSString *c = (#"big ass cookie");
[groceries addObject:a];
[groceries addObject:b];
[groceries addObject:c];
for (NSString *d in groceries){
NSLog(#"%#", d);
}
}
return 0;
}
Why is this not working? What is wrong? Thanks.
I cannot seem to figure it out at this moment, the for loop defiantly seems to be the hangup.
While you didn't initialize NSMutableArray, it's is nil. Adding object to non-initialized mutable array always give nil.
Firstly you need to initialize groceries:
NSMutableArray *groceries = [NSMutableArray new];
or more liked by me way:
NSMutableArray *groceries = #[].mutableCopy;
In your case, for example, you can declare so:
NSMutableArray *groceries = #[#"loaf of bread", #"stick of butter", #"big ass cookie"].mutableCopy;
i am trying to get input from user and want to store it in an array.
int main(int argc, const char * argv[]) {
#autoreleasepool
{
int i;
char name[10];
NSMutableArray *myarray=[[NSMutableArray alloc]init];
for (i=0; i<10; i++)
{
scanf("%c",name);
[myarray addObject:i];
}
}
return 0;
}
You are trying to insert a non Object in NSMutableArray.
NSMutableArray can store objects only,
char and int are data types of c language which are not treated as objects in Objective C.
First you need to convert them into objects then You can insert.
Try with this:
[myarray addObject:#(i)]; or
[myarray addObject:[NSNumber numberWithInt:i]];
for name:
[NSString stringWithFormat:#"%c",name]
A textfield will hold user input. Fetch value from the textfield and add it to the array.
arryData = [[NSMutableArray alloc] initWithObjects:#"#&", textFieldinput.text, nil];
This will work better.
Hi I trying to convert string to int array in objective C its running fine in xcode but give some error in editor http://ideone.com
I have input like = {1,2,3,4,5} and want to convert it into int array or NSARRAY in and print....
#import <Foundation/Foundation.h>
NSArray* sampleMethod(NSString*val){
NSString *stringWithoutbracketstart = [val stringByReplacingOccurrencesOfString:#"{" withString:#""];
NSString *stringWithoutbracketend = [stringWithoutbracketstart
stringByReplacingOccurrencesOfString:#"}" withString:#""];
NSLog(#"%#",stringWithoutbracketend);
NSArray *items=[[NSArray alloc]init];
items = [stringWithoutbracketend componentsSeparatedByString:#","];
//NSLog(#"%#",items);
return items;
}
int main(int argc, const char * argv[]) {
NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init];
NSString *value =#"{1,2,3}";
NSArray* ip1= sampleMethod(value);
NSLog(#"%#",ip1);
[pool drain];
return 0;
}
Why not make the input string valid JSON and then it can be arbitrarily extended with little coding effort (no effort at all with respect to parsing):
int main(int argc, const char **argv)
{
int retval = 0;
#autoreleasepool {
if (argc == 2) {
NSString *str = #(argv[1]);
NSData *data = [str dataUsingEncoding:NSUTF8StringEncoding];
NSError *error = nil;
NSArray *array = [NSJSONSerialization JSONObjectWithData:data
options:0
error:&error];
if ([array isKindOfClass:[NSArray class]]) {
// Done
} else if (!array) {
NSLog(#"Input data is invalid: %#", [error localizedDescription]);
retval = 2;
} else {
NSLog(#"Input data is invalid");
retval = 3;
}
} else {
NSLog(#"Provide a JSON-list");
retval = 1;
}
}
return retval;
}
This means you would need to supply the list in JSON format:
$ ./myprog '[ 1, 2, 3 ]'
(quotes are necessary)
I found the solution easily by using your advice....
#import <Foundation/Foundation.h>
NSArray*sampleMethod(NSString*val){
NSString *newStr = [val substringFromIndex:1];
NSString *newStr1 = [newStr substringToIndex:[newStr length]-1];
NSArray *yourWords = [newStr1 componentsSeparatedByString:#","];
return yourWords;
}
int main(int argc, const char * argv[]) {
NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init];
NSString *value =#"{1,2,3}";
NSArray* ip1= sampleMethod(value);
NSLog(#"%#",ip1);
[pool drain];
return 0;
}
I have this:
NSString *string1 = ...;
NSString *string2 = ...;
NSMutableArray *array = [NSMutableArray alloc]inithWithObjects:string1, string2]autorelease];
How do I calculate the MD5 hash (or other more appropriate hash) for each content of the array, for further comparisons?
Thanks!
You can use this method on every string of your array:
- (NSString*)md5HexDigest:(NSString*)input {
const char* str = [input UTF8String];
unsigned char result[CC_MD5_DIGEST_LENGTH];
CC_MD5(str, strlen(str), result);
NSMutableString *ret = [NSMutableString stringWithCapacity:CC_MD5_DIGEST_LENGTH*2];
for(int i = 0; i<CC_MD5_DIGEST_LENGTH; i++) {
[ret appendFormat:#"%02x",result[i]];
}
return ret;
}
Do not forget to include:
#import <CommonCrypto/CommonDigest.h>
I want to get the characters of an NSString. Like this:
NSString *data;
const char * typein = [[data characters] UTF8String];
But obviously NSString won't respond to -characters. How do I get the characters of NSString?
thanks,
Elijah
You can use this function:
for(int i =0 ;i<[myString length]; i++) {
char character = [myString characterAtIndex:i];
}
or
NSString *str = #"astring";
const char *cString = [str UTF8String];
If you just want to get a cString from the NSString just call UTF8String as you are already doing and then iterate the array.