I have a Dynamic query which fetch a row with 62 columns in sql
The query is like this
DECLARE #SQLQuery AS nvarchar(max)
DECLARE #columns nvarchar(max)
SELECT
#columns = ISNULL(#columns + ', ', '') + QUOTENAME(Column_name)
FROM (SELECT
Column_name
FROM
(SELECT
Column_name,
ROW_NUMBER() OVER (PARTITION BY Column_name ORDER BY Column_name) AS Rows
FROM information_Schema.Columns
WHERE Table_Name IN ('Parking', 'AIV_Parking')
AND column_name NOT IN ('IssueNo', 'Issuedate', 'Agency', 'OfficerName', 'OfficerId', 'Beat', 'UNITSERIAL', 'VEHLICNO', 'VEHLICSTATE', 'VEHLICEXPDATE', 'VEHLICTYPE', 'VEHMAKE',
'VEHMODEL', 'VEHBODYSTYLE', 'VEHVIN4', 'VEHVIN', 'ISSUENOCHKDGT', 'VEHCOLOR1', 'VEHCOLOR2', 'PERMITNO', 'VEHLABELNO', 'LOCBLOCK', 'LOCSTREET', 'LOCDESCRIPTOR', 'LOCTRAVELDIR', 'LOCSIDEOFSTREET',
'LOCSUBURB', 'LOCLOT', 'LOCCROSSSTREET1', 'LOCCROSSSTREET2', 'LOCSTATE', 'LOCPOSTALCODE', 'METERNO', 'METERBAYNO', 'REMARK1', 'REMARK2')) p
WHERE Rows = 2) RequiredColumns
EXEC ('SELECT ' + #columns + ' FROM AIV_Parking Where Issueno =''100000600''')
Which gives me below records
So result is Something like below where i get only 1 row at a time.
|ACTLINE1 | ACTLINE2 | AUTOPROC_UNIQUEKEY | COURTADDR| IssueNo|.......
|SUBIACO | LOCAL LAWS| NULL | NULL | 123 |
Now i want this to converted like:
|FieldName | FieldValue
|ACTLINE1 | SUBIACO
|ACTLINE2 | LOCAL LAWS
|ISSUENO | 123
While pivoting these column ,I want only those columns which has value i don't want those column whose value is null or ' '
You need to use UNION ALL and filter the result with a WHERE clause:
DECLARE #SQLQuery AS NVARCHAR(MAX) = ''
SELECT #SQLQuery = #SQLQuery +
'SELECT ''' + COLUMN_NAME + ''' AS FieldName, CAST(' + QUOTENAME(COLUMN_NAME) + ' AS NVARCHAR(MAX)) AS FieldValue
FROM AIV_Parking
WHERE Issueno =''100000600''
UNION ALL' + CHAR(10)
--QUERY HERE TO GET COLUMNS FROM INFORMATION_SCHEMA.COLUMNS
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME IN('Parking','AIV_Parking')
IF #SQLQuery <> '' BEGIN
-- Remove the last occurence of UNION ALL
SELECT #SQLQuery = LEFT(#SQLQuery, LEN(#SQLQuery) - 11)
SELECT #SQLQuery =
'SELECT * FROM (' + #SQLQuery + ') t WHERE FieldValue IS NOT NULL AND FieldValue <> '''''
EXEC(#SQLQuery)
END
Note that you need to CAST your FieldValue to a NVARCHAR(MAX) or whatever datatype that will not produce a conversion error. This is because when using UNION all columns must have the same datatype, if not, they will be converted to the one with the higher data type precedence.
Related
I have a table which has more than 30 columns(all are varchar). I need to list out all the columns which contains blank i.e.' ' values.
I tried using 'coalesce' but it is only for NULL.
The following query will give you all the columns in a table that might have null or '' values.
It is written so that you can run it for all tables in your database but you can limit it to a single table, as I have done for this specific example, checking a table called testingNulls:
--two variables needed for table name and column name, when looping through all tables
declare #table varchar(255), #col varchar(255), #sql varchar(max)
--this will be used to store the result, to have one result set instead of one row per each cursor cycle
if object_id('tempdb..#nullcolumns') is not null drop table #nullcolumns
create table #nullcolumns (tablename varchar(255), columnname varchar(255))
declare getinfo cursor for
select t.name tablename, c.name
from sys.tables t join sys.columns c on t.object_id = c.object_id
where t.name = 'testingnulls' --here the condition for the table name
open getinfo
fetch next from getinfo into #table, #col
while ##fetch_status = 0
begin
select #sql = 'if exists (select top 1 * from [' + #table + '] where [' + #col + '] is null or [' + #col + '] like '''' ) begin insert into #nullcolumns select ''' + #table + ''' as tablename, ''' + #col + ''' as all_nulls end'
print(#sql)
exec(#sql)
fetch next from getinfo into #table, #col
end
close getinfo
deallocate getinfo
--this should be the result you need:
select * from #nullcolumns
You can see a working example here. I hope this is what you need.
List all columns that contain a blank in some record? You'd use a query per column and collect the results with UNION ALL:
select 'COL1' where exists (select * from mytable where col1 like '% %')
union all
select 'COL2' where exists (select * from mytable where col2 like '% %')
union all
...
union all
select 'COL30' where exists (select * from mytable where col30 like '% %');
If you want like select * from [your_table_name] where [col1] = '' and [col2] = ''....., then use dynamic sql query like below.
Query
declare #sql as varchar(max);
select #sql = 'select * from [your_table_name] where '
+ stuff((
select ' and [' + [column_name] + '] = ' + char(39) + char(39)
from information_schema.columns
where table_name = 'your_table_name'
for xml path('')
)
, 1, 5, ''
);
exec(#sql);
Update
Or else if you want to list the column names which have a blank value, then you can use the below dynamic sql query.
Query
declare #sql as varchar(max);
select #sql = stuff((
select ' union all select ' + [column_name] + ' as [col1], '
+ char(39) + [column_name] + char(39) + ' as [col2]'
+ ' from your_table_name'
from information_schema.columns
where table_name = 'your_table_name'
for xml path('')
)
, 1, 11, ''
);
set #sql = 'select distinct t.col2 as [blank_cols] from(' + #sql
+ ')t
where coalesce(ltrim(rtrim(t.col1)), ' + char(39) + char(39) + ') = '
+ char(39) + char(39) + ';';
exec(#sql);
Find a demo here
But still I'm not sure that this is what you are looking out for.
you have not many choices but to specify all the columns in your where clause
WHERE COL1 = '' AND COL2 = '' AND COL3 = '' AND . . .
or you can use Dynamic SQL to form your query, but that is not an easy path to go
If you want to count number of columns having '' value in a table (not for each row) then use the following
SELECT max(CASE WHEN col1 = '' THEN 1 ELSE 0 END) +
max(CASE WHEN col2 = '' THEN 1 ELSE 0 END) +
max(CASE WHEN col3 = '' THEN 1 ELSE 0 END) +
...
FROM t
demo
I created a dynamic SQL script that you can use by providing the table name only
Here it is
declare #sql nvarchar(max)
declare #table sysname = 'ProductAttributes'
select #sql =
'select * from ' + #table + ' where ' +
string_agg('[' + name + '] = '' '' ', ' and ')
from sys.columns
where object_id = OBJECT_ID(#table)
select #sql
exec sp_executesql #sql
Unfortunately, for SQL string concatenation String_Agg function is new with SQL Server 2017
But it is also possible to use SQL XML Path to concatenate WHERE clause fragments
SELECT #sql = 'select * from ' + #table + ' where ' +
STUFF(
(
SELECT
' and ' + '[' + [name] + '] = '' '' '
from sys.columns
where object_id = OBJECT_ID(#table)
FOR XML PATH(''),TYPE
).value('.','VARCHAR(MAX)'
), 1, 5, ''
)
select #sql as sqlscript
exec sp_executesql #sql
Could you please advise how to find the number of rows in the table which have 1 or more missing values? The missing values are represented in my table by question marks = '?'. The table has 15 columns and ~50k rows. When I run the following query for some of the columns I can receive some results:
SELECT
COUNT(*)
FROM table_name
WHERE column_name ='?'
However I have also columns which bring me result: "Error converting data type varchar to float"
I would like to be able to find the number of rows in the table which have 1 or more missing values using 1 query/not run separately for each column.
Thank you in advance for your support!
Select Count(*)
From mySchema.myTable
Where Cast(Col1 As NVarChar(128)) +
Cast(Col2 As NVarChar(128)) +
Cast(Coln As NVarChar(128)) Like '%?%'
It's ugly and WILL be slow and you may need to modify the Casts accordingly, but should do the trick.
This should work for any column:
select count(*)
from table_name
where column_name is null or cast(column_name as varchar(255)) = '?';
Try following query:
Just set table name and it will get all columns
Also you can give value_to_match like '?' in your case or any other if you want.
DECLARE #table_name nvarchar(max) = 'table_name'
DECLARE #value_to_match nvarchar(max) = '1'
DECLARE #query nvarchar(max) = ''
DECLARE #Condition nvarchar(max) = ' OR ' -- 1 OR when you want to count row if any column has that value -- 2 when you want all all columns to have same value
SELECT #query = #query + ' cast(' + COLUMN_NAME + ' as nvarchar(500)) = ''' + #value_to_match + '''' + #Condition FROM informatioN_schema.columns WHERE table_name = #table_name
if ##rowcount = 0
BEGIN
SELECT 'Table doesn''t Exists'
RETURN
END
SELECT #query = LEFT(#query,LEN(#query)-3)
PRINT ('select count(9) FROM ' + #table_name + ' WHERE ' + #query)
EXEC ('select count(9) FROM ' + #table_name + ' WHERE ' + #query)
How to select columns in a table that only contain a specific value for all the rows? I am trying to find these columns to do an update on those values with a NULL value. In my columns I have varied range of values including NA
I am using SQL Server 2012.
I've tried doing: thsi only gives me column names. Can i add to this condition for columns with value 'NA'?
SELECT COLUMN_NAME AS NAMES,COLUMN_DEFAULT
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_SCHEMA = 'dbo'
AND TABLE_NAME = 'ABC'
I am a beginner in SQL. Trying to figure out how to do this.
If min of column equals to max then that column contains same values:
Select
case when min(col1) = max(col1) then 1 else 0 end as Col1IsSame,
case when min(col2) = max(col2) then 1 else 0 end as Col2IsSame,
...
from Table
With dynamic query:
declare #s nvarchar(max) = 'select '
select #s = #s + 'case when min(' + COLUMN_NAME + ') = max(' +
COLUMN_NAME + ') then 1 else 0 end as ' + COLUMN_NAME + ','
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_SCHEMA = 'dbo'
AND TABLE_NAME = 'Table'
Set #s = substring(#s, 1, len(#s) - 1) + ' from Table'
exec(#s)
TRY THIS QUERY
DECLARE #SQLQUERY NVARCHAR(MAX)
declare #tableName varchar(50)
DECLARE #NAME VARCHAR(50)
Declare #ParamDefinition AS NVarchar(2000)
Set #ParamDefinition = '#OIM VARCHAR(20)'
SELECT NAME
FROM sys.objects
WHERE [object_id]=#OIM
set #tableName= (SELECT NAME
FROM sys.objects
WHERE [object_id]=#OIM)
SET #NAME=(SELECT C.NAME
FROM sys.columns c
JOIN
sys.tables t ON c.object_id = t.object_id
WHERE c.name in (select distinct name
from sys.columns
where object_id=#OIM))
SET #SQLQUERY = ''
SELECT #SQLQUERY = #SQLQUERY + 'UPDATE ' + #tableName + ' SET ' + #NAME + ' = NULL WHERE ' + #NAME + ' = NA ; '
PRINT #SQLQUERY
Execute sp_Executesql #SQLQUERY , #ParamDefinition, #OIM
end
The following query returns the values of the table for each field in terms of null percentage . What I want is to get the sum of those percentages for a specific ProductID. Also, I would like to get a percentage (in an extra column) of the fields do not have value i.e. ="". Any ideas?
use AdventureWorks
DECLARE #TotalCount decimal(10,2), #SQL NVARCHAR(MAX)
SELECT #TotalCount = COUNT(*) FROM [AdventureWorks].[Production].[Product]
SELECT #SQL =
COALESCE(#SQL + ', ','SELECT ') +
'cast(sum (case when ' + QUOTENAME(column_Name) +
' IS NULL then 1 else 0 end)/#TotalCount*100.00 as decimal(10,2)) as [' +
column_Name + ' NULL %]
'
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = 'Product' and TABLE_SCHEMA = 'Production'
SET #SQL = 'set #TotalCount = NULLIF(#TotalCount,0)
' + #SQL + '
FROM [AdventureWorks].Production.Product'
print #SQL
EXECUTE SP_EXECUTESQL #SQL, N'#TotalCount decimal(10,2)', #TotalCount
You can use the following:
use AdventureWorks
DECLARE #colCount int;
DECLARE #nullCheck nvarchar(max) = N'';
DECLARE #emptyCheck nvarchar(max) = N'';
DECLARE #SQL NVARCHAR(MAX);
DECLARE #KeyToCheck int = 123; -- adapt as necessary
SELECT
#nullCheck += '
+ ' + 'count(' + QUOTENAME(column_Name) + ')'
,#emptyCheck += '
+ ' +
CASE
WHEN DATA_TYPE IN('bigint', 'int', 'smallint', 'tinyint', 'bit', 'money', 'smallmoney', 'numeric', 'decimal', 'float', 'real') THEN
-- check numeric data for zero
'sum(case when coalesce(' + QUOTENAME(column_Name) + ', 0) = 0 then 1 else 0 end)'
WHEN DATA_TYPE like '%char' or DATA_TYPE like '%text' THEN
--check character data types for empty string
'sum(case when coalesce(' + QUOTENAME(column_Name) + ', '''') = '''' then 1 else 0 end)'
ELSE -- otherwise, only check for null
'sum(case when ' + QUOTENAME(column_Name) + ' IS NULL then 1 else 0 end)'
END
,#colCount =
count(*) over()
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = 'Product' and TABLE_SCHEMA = 'Production'
;
SET #SQL = 'SELECT case when count(*) > 0 then 100.00 - (' + #nullCheck + '
) * 100.00 / ' + cast(#colCount as nvarchar(max)) + '.00 / count(*) end as null_percent
, case when count(*) > 0 then (' + #emptyCheck + '
) * 100.00 / ' + cast(#colCount as nvarchar(max)) + '.00 / count(*) end as empty_percent
FROM Production.Product
WHERE ProductID = ' + cast(#KeyToCheck as nvarchar(max))
;
print #SQL;
EXECUTE (#SQL)
I simplified one of your expressions: Instead of sum (case when <column> IS NULL then 1 else 0 end), you can just use count(<column>). When using count with an expression instead of *, it counts the rows where this expression is non-null. As this is the opposite from what you need, I added the 100.00 - as the start of the SELECT.
For the "empty check", this would make the logic more complex to understand, hence I left the original logic there and extended it. There, I implemented an check for emptiness for numeric and character/text data types. You can easily extend that for date, binary data etc. with whichever logic you use to determine if a column is empty.
I also found it more simple to leave first + in the two variables #nullCheck and #emptyCheck, as it is valid SQL to start an expression wit this.
I also extended the statement so that if there would potentially be more than one record with ProductId = 123, it shows the average across all records, i. e. the total sum divided by the count of rows. And the outermost case expressions just avoid an division by zero error if count(*) would be zero, i. e. no record with ProductId = 123 found. In that case the return value is null.
You could use AVG function:
SELECT AVG(CASE WHEN value IS NULL THEN 100 ELSE 0 END) AS Percents
FROM Table
UPDATE:
Here is your script:
DECLARE #SQL NVARCHAR(MAX), #TABLE_NAME NVARCHAR(MAX), #TABLE_SCHEMA NVARCHAR(MAX), #PK NVARCHAR(MAX)
SET #TABLE_NAME = 'tblBigTable'
SET #TABLE_SCHEMA = 'dbo'
SET #PK = '8'
SELECT
#SQL = COALESCE(#SQL + ', ', 'SELECT ') +'AVG(CASE WHEN ' + COLUMN_NAME + ' IS NULL THEN 100 ELSE 0 END) AS [' + COLUMN_NAME +' NULL %]'
FROM
INFORMATION_SCHEMA.COLUMNS
WHERE
TABLE_SCHEMA = #TABLE_SCHEMA AND
TABLE_NAME = #TABLE_NAME
SET #SQL = #SQL + ' FROM ' + #TABLE_NAME + ' WHERE pkId = ''' + #PK + ''''
print #SQL
EXECUTE SP_EXECUTESQL #SQL
I would like to ask for help.
As I have 500 plus tables, and I need to search those table's column having some similar words. Is it possible to search and list those tables?
E.g
Table 1 - Name, age, height
Table 2 - Result, Name, Score
Table 3 - Name, Pic, Parent1, Parent2
I wan to do a query to select all the table that any of the column contain the word "%Name%", is this possible?
Just run following query in your db and replace your search string with string and it will work.
SQL for find particular word/value from all columns and tables in a database
DECLARE #SQL VARCHAR(MAX)
DECLARE #valueToFind VARCHAR(1000)
DECLARE #columnName VARCHAR(1000)
SET #valueToFind = 'string'
SET #columnName = '%%'
CREATE TABLE #TMP
(Clmn VARCHAR(500),
CNT INT)
SELECT #SQL=COALESCE(#SQL,'')+CAST('INSERT INTO #TMP Select ''' + TABLE_SCHEMA + '.' + TABLE_NAME + '.' + COLUMN_NAME + ''' AS Clmn, count(*) CNT FROM '
+ TABLE_SCHEMA + '.[' + TABLE_NAME +
'] WHERE [' + COLUMN_NAME + '] LIKE ''%' + #valueToFind + '%'' ;' AS VARCHAR(8000))
FROM INFORMATION_SCHEMA.COLUMNS
JOIN sysobjects B
ON INFORMATION_SCHEMA.COLUMNS.TABLE_NAME = B.NAME
WHERE COLUMN_NAME LIKE #columnName AND xtype = 'U'
AND DATA_TYPE IN ('char','nchar','ntext','nvarchar','text','varchar')
--PRINT (#SQL)
EXEC(#SQL)
SELECT * FROM #TMP WHERE CNT > 0
DROP TABLE #TMP
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