How to use pivot and have 2 different aggregate functions? - sql

I have a table with 1 date column. I want to group the dates by year and month so that I have a matrix such as:
Year Jan Feb Mar...Dec Total
2015.....
2016 10 15 10... 10 115
2017.....
Is this possible to achieve using the PIVOT function, and how exactly do I use it to achieve the above?

You can achieve without PIVOT
SELECT
DATEPART(yyyy,t.the_date) as year,
SUM(CASE WHEN DATEPART(mm,t.the_date)=1 THEN 1 ELSE 0 END) as Jan,
SUM(CASE WHEN DATEPART(mm,t.the_date)=2 THEN 1 ELSE 0 END) as Feb,
...
SUM(CASE WHEN DATEPART(mm,t.the_date)=12 THEN 1 ELSE 0 END) as Dec,
COUNT(*) as Total
FROM the_table t
GROUP BY DATEPART(yyyy,t.the_date)

try using this query : -
SELECT *
FROM (
SELECT
year(yourDate) as [year],left(datename(month,yourDate),3)as [month],
Amount
FROM YourTableName
) as s
PIVOT
(
SUM(Amount)
FOR [month] IN (jan, feb, mar, apr,
may, jun, jul, aug, sep, oct, nov, dec)
)AS pvt

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How to count number of rows returned per month in oracle? [closed]

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I am creating a feature for my application where I need to generate a report for the whole 2018.
I need to count all the tickets for 2018. Each ticket has a category.
For example:
Change of name.
Senior Citizen etc.
I need to count the number of change name tickets, senior citizen tickets for 2018 per month
I tried to to this but I can't seem to get the result that I want.
I can't seem to break down the count per month.
This is the query that I have so far:
SELECT SUBCATEGORY,COUNT(ticket_no)
FROM CNR_TICKET
WHERE date_created >= TO_DATE('1/01/2018','MM/DD/YYYY')
AND date_created <= TO_DATE('12/31/2018','MM/DD/YYYY')
GROUP BY SUBCATEGORY;
This is the columns I want to see:
CATEGORY | JAN | FEB | MARCH | APRIL | MAY | JNE | JUL | AUG | SEPT | OCT| NOV| DEC
SENIOR 2 5 20 50 1 11 23 4 1 2 4 6
COAN 23 55 22 55 6 2 12 23 12 12 5 89
Something like this :
SELECT
SUBCATEGORY,
count( distinct case when EXTRACT(month FROM date_created) = 1 then ticket_no else null end) as JAN,
count( distinct case when EXTRACT(month FROM date_created) = 2 then ticket_no else null end) as FEB,
count( distinct case when EXTRACT(month FROM date_created) = 3 then ticket_no else null end) as MARCH,
count( distinct case when EXTRACT(month FROM date_created) = 4 then ticket_no else null end) as APRIL,
count( distinct case when EXTRACT(month FROM date_created) = 5 then ticket_no else null end) as MAY,
count( distinct case when EXTRACT(month FROM date_created) = 6 then ticket_no else null end) as JNE,
count( distinct case when EXTRACT(month FROM date_created) = 7 then ticket_no else null end) as JUL,
count( distinct case when EXTRACT(month FROM date_created) = 8 then ticket_no else null end) as AUG,
count( distinct case when EXTRACT(month FROM date_created) = 9 then ticket_no else null end) as SEPT,
count( distinct case when EXTRACT(month FROM date_created) = 10 then ticket_no else null end) as OCT,
count( distinct case when EXTRACT(month FROM date_created) = 11 then ticket_no else null end) as NOV,
count( distinct case when EXTRACT(month FROM date_created) = 12 then ticket_no else null end) as DEC
FROM
CNR_TICKET
WHERE
date_created >= to_date('1/01/2018','MM/DD/YYYY') and
date_created <= to_date('12/31/2018','MM/DD/YYYY')
GROUP BY
SUBCATEGORY
you can change your WHERE clause using :
EXTRACT(year FROM date_created ) = 2018
You may try PIVOT statement
select * from (
select SUBCATEGORY, month(date_created) mon
from CNR_TICKET
where date_created >= to_date('1/01/2018','MM/DD/YYYY') and date_created <= to_date('12/31/2018','MM/DD/YYYY')
)
pivot (
count(*)
for mon
in ( 1 Jan, 2 Feb, 3 MARCH, 4 APRIL, 5 MAY, 6 JNE, 7 JUL, 8 AUG, 9 SEPT, 10 OCT, 11 NOV, 12 DEC )
)
you can use Pivot keyword by using for month for the pivoting query as
select *
from
(
select subcategory, to_char(date_created,'mm') as month
from cnr_ticket
where to_char(date_created,'yyyy')='2018'
)
pivot(
count(*)
for (month)
in ('01' as jan ,'02' as feb, '03' as mar,
'04' as apr ,'05' as may, '06' as jun,
'07' as jul ,'08' as aug, '09' as sep,
'10' as oct ,'11' as nov, '12' as dec
)
)
or using conditional aggregation
select subcategory,
sum(case when to_char(date_created,'mm') = '01' then 1 else 0 end) as jan,
sum(case when to_char(date_created,'mm') = '02' then 1 else 0 end) as feb,
sum(case when to_char(date_created,'mm') = '03' then 1 else 0 end) as mar,
sum(case when to_char(date_created,'mm') = '04' then 1 else 0 end) as apr,
sum(case when to_char(date_created,'mm') = '05' then 1 else 0 end) as may,
sum(case when to_char(date_created,'mm') = '06' then 1 else 0 end) as jun,
sum(case when to_char(date_created,'mm') = '07' then 1 else 0 end) as jul,
sum(case when to_char(date_created,'mm') = '08' then 1 else 0 end) as aug,
sum(case when to_char(date_created,'mm') = '09' then 1 else 0 end) as sep,
sum(case when to_char(date_created,'mm') = '10' then 1 else 0 end) as oct,
sum(case when to_char(date_created,'mm') = '11' then 1 else 0 end) as nov,
sum(case when to_char(date_created,'mm') = '12' then 1 else 0 end) as dec
from cnr_ticket
where to_char(date_created,'yyyy')='2018'
group by subcategory
Rextester Demo

SQL - Calculate Customer's Percentage of Total Orders by Month

I'm practicing SQL on this site: https://www.w3schools.com/sql/trysqlserver.asp?filename=trysql_func_sqlserver_substring
, and am trying to calculate the % of total monthly orders by customer ID. So for example, if customer 10 had 3 orders in January, and there were 33 orders total in January, then customer 10's result in January would be 3/33 = 9.09%. I want each row to be a customer ID, and a column for each month.
Basically, I want to convert this:
Into this:
I can get the totals by month, but am having trouble getting the percentages.
I'm using this code:
SELECT d.CustomerID,
SUM(CASE WHEN Month = 01 THEN NumOrders ELSE 0 END) AS Jan,
SUM(CASE WHEN Month = 02 THEN NumOrders ELSE 0 END) AS Feb,
SUM(CASE WHEN Month = 03 THEN NumOrders ELSE 0 END) AS Mar,
SUM(CASE WHEN Month = 04 THEN NumOrders ELSE 0 END) AS Apr,
SUM(CASE WHEN Month = 05 THEN NumOrders ELSE 0 END) AS May,
SUM(CASE WHEN Month = 06 THEN NumOrders ELSE 0 END) AS Jun,
SUM(CASE WHEN Month = 07 THEN NumOrders ELSE 0 END) AS Jul,
SUM(CASE WHEN Month = 08 THEN NumOrders ELSE 0 END) AS Aug,
SUM(CASE WHEN Month = 09 THEN NumOrders ELSE 0 END) AS Sep,
SUM(CASE WHEN Month = 10 THEN NumOrders ELSE 0 END) AS Oct,
SUM(CASE WHEN Month = 11 THEN NumOrders ELSE 0 END) AS Nov,
SUM(CASE WHEN Month = 12 THEN NumOrders ELSE 0 END) AS [Dec],
SUM(NumOrders) AS Total
FROM(
SELECT CustomerID,
DATEPART(mm,OrderDate) AS Month,
COUNT(OrderID) AS NumOrders
FROM Orders
GROUP BY CustomerID,
DATEPART(mm,OrderDate)
) d
GROUP BY d.CustomerID
WITH ROLLUP
I've tried using this code like this to calculate the percentages, but am not getting it to work out.
SUM(CASE WHEN Month = 01 THEN NumOrders ELSE 0 END) / CAST( SUM(NumOrders) OVER (PARTITION BY Month) AS FLOAT) AS JanPct,
This is pretty basic in Excel, and seems like it should be in SQL too, so I feel like I'm missing something obvious.
Try this
Create table #tmp (CustId INT, Jan int, Feb Int, March int)
insert into #tmp VALUES
(10,4,3,5),
(11,3,1,7),
(12,6,2,6),
(13,5,4,4);
Select * from #tmp
select CustId,
CEILING(CAST(Jan As FLOAT)/CAST(SUM(Jan) OVER() AS FLOAT)*100) As Jan,
CEILING(CAST(Feb As FLOAT)/CAST(SUM(Feb) OVER() AS FLOAT)*100) As Feb,
CEILING(CAST(March As FLOAT)/CAST(SUM(March) OVER() AS FLOAT)*100) As March
from #tmp
drop table #tmp
if you want % symbol, convert to varchar and append %
Eg:
CONVERT(VARCHAR(5),CEILING(CAST(Jan As FLOAT)/CAST(SUM(Jan) OVER() AS FLOAT)*100))+'%'
I wasn't able to make rollup work with PIVOT, so here is the long solution.
DECLARE #t table(OrderId INT identity(1,1), OrderDate date, CustomerID INT)
INSERT #t values('2017-01-01', 1),('2017-01-01', 1),('2017-02-01', 1),('2017-01-01', 2)
;WITH CTE as
(
SELECT DISTINCT
CAST(ROUND(count(*) over(partition by CustomerID, Month(OrderDate))*100./ count(*)
over(partition by month(OrderDate)), 0) as INT) Pct,
Month(OrderDate) Mon,
CustomerID
FROM #t
)
SELECT
CustomerID,
SUM(CASE WHEN Mon = 1 THEN Pct ELSE 0 END) AS Jan,
SUM(CASE WHEN Mon = 2 THEN Pct ELSE 0 END) AS Feb,
SUM(CASE WHEN Mon = 3 THEN Pct ELSE 0 END) AS Mar,
SUM(CASE WHEN Mon = 4 THEN Pct ELSE 0 END) AS Apr,
SUM(CASE WHEN Mon = 5 THEN Pct ELSE 0 END) AS May,
SUM(CASE WHEN Mon = 6 THEN Pct ELSE 0 END) AS Jun,
SUM(CASE WHEN Mon = 7 THEN Pct ELSE 0 END) AS Jul,
SUM(CASE WHEN Mon = 8 THEN Pct ELSE 0 END) AS Aug,
SUM(CASE WHEN Mon = 9 THEN Pct ELSE 0 END) AS Sep,
SUM(CASE WHEN Mon = 10 THEN Pct ELSE 0 END) AS Oct,
SUM(CASE WHEN Mon = 11 THEN Pct ELSE 0 END) AS Nov,
SUM(CASE WHEN Mon = 12 THEN Pct ELSE 0 END) AS [Dec]
FROM CTE
GROUP BY ROLLUP (CustomerID)
Just Use below code instead of selecting COUNT(OrderID) AS NumOrders in your below subquery
CONVERT(numeric(10,2), count(Orderid) * 100.0/ (select count(Orderid) from [Orders])) as NumOrders

How to maintain a running balance in a month wise report

SELECT *
FROM
(SELECT
YEAR (DateOfTransaction) AS year,
LEFT(DATENAME(MONTH, DateOfTransaction), 3) AS month,
SUM(CASE WHEN TransTypeName LIKE 'credit%' THEN amount ELSE 0 END) -
SUM(CASE WHEN TransTypeName LIKE 'Debit%' THEN amount ELSE 0 END) AS Balance
FROM
.............) AS t
PIVOT (SUM(balance) FOR month IN (jan, feb, march, ...., Dec)) AS pvt
This query returns a month-wise report account balance. I want a result is running balance.
Example:
January month I credit 5000, February month I credit 2000
My query result is
year jan feb march...dec
2014 5000 2000 null ..null
I want a result like this:
year jan feb march...dec
2014 5000 7000 null ..null
(5000+2000)
Try this
SELECT year,Jan = Jan, Feb = isnull(Jan,0)+isnull(Feb,0),....
FROM
(SELECT
YEAR (DateOfTransaction) AS year,
LEFT(DATENAME(MONTH, DateOfTransaction), 3) AS month,
SUM(CASE WHEN TransTypeName LIKE 'credit%' THEN amount ELSE 0 END) -
SUM(CASE WHEN TransTypeName LIKE 'Debit%' THEN amount ELSE 0 END) AS Balance
FROM
.............) AS t
PIVOT (SUM(balance) FOR month IN (jan, feb, march, ...., Dec)) AS pvt)t
Or you can simply add a temp table which stores numbers from 1 to 12
inner join #temp on n>=datepart(mm,DateofTransaction) group by year(transaction), n

Query which converts rows into columns

I have something like
ZoneNumber AverageSpeed
1 20
2 30
3 50
4 60
5 70
And I want to have a view like
AverageSpeed 1 AverageSpeed 2 AverageSpeed 3 AverageSpeed 4 AverageSpeed 5
20 30 50 60 70
Does anyone have any ideas what my query need to be written like?
You need to use Pivot.
Pivot rotates a table-valued expression by turning the unique values from one column in the expression into multiple columns in the output, and performs aggregations where they are required on any remaining column values that are wanted in the final output.
Basic example:
SELECT *
FROM (
SELECT year(invoiceDate) as [year], left(datename(month,invoicedate),3) as [month], InvoiceAmount as Amount
FROM Invoice
) as s
PIVOT
(
SUM(Amount)
FOR [month] IN (jan, feb, mar, apr, may, jun, jul, aug, sep, oct, nov, dec)
)AS pivot

SQL Server 2005 GROUP BY and COUNT query for each month

I have a SQL Server 2005 table named Rentals:
RentalID
Book
Date
I want to return, using a query, for each book, how many rentals were in each month for a given year.
The results should look something like this:
+--------------------------------+-----+-----+-----+
| Book | Jan | Feb | Mar |
+--------------------------------+-----+-----+-----+
| Isaac Asimov - Foundation | 2 | 5 | 3 |
| H.G. Wells - War of the Worlds | 4 | 3 | 1 |
| Frank Herbert - Dune | 7 | 4 | 6 |
+--------------------------------+-----+-----+-----+
My query so far:
SELECT
Book,
(SELECT COUNT(*) FROM Rentals WHERE month(Date)=1 AND year(Date)=2011),
(SELECT COUNT(*) FROM Rentals WHERE month(Date)=2 AND year(Date)=2011),
(SELECT COUNT(*) FROM Rentals WHERE month(Date)=3 AND year(Date)=2011),
(SELECT COUNT(*) FROM Rentals WHERE month(Date)=4 AND year(Date)=2011),
(SELECT COUNT(*) FROM Rentals WHERE month(Date)=5 AND year(Date)=2011),
(SELECT COUNT(*) FROM Rentals WHERE month(Date)=6 AND year(Date)=2011),
(SELECT COUNT(*) FROM Rentals WHERE month(Date)=7 AND year(Date)=2011),
(SELECT COUNT(*) FROM Rentals WHERE month(Date)=8 AND year(Date)=2011),
(SELECT COUNT(*) FROM Rentals WHERE month(Date)=9 AND year(Date)=2011),
(SELECT COUNT(*) FROM Rentals WHERE month(Date)=10 AND year(Date)=2011),
(SELECT COUNT(*) FROM Rentals WHERE month(Date)=11 AND year(Date)=2011),
(SELECT COUNT(*) FROM Rentals WHERE month(Date)=12 AND year(Date)=2011)
FROM Rentals
GROUP BY Book
This can be written much simpler by using a CASE expression inside of an aggregate function. This process is called PIVOT:
select book,
sum(case when month(Date) = 1 then 1 else 0 end) Jan,
sum(case when month(Date) = 2 then 1 else 0 end) Feb,
sum(case when month(Date) = 3 then 1 else 0 end) Mar,
sum(case when month(Date) = 4 then 1 else 0 end) Apr,
sum(case when month(Date) = 5 then 1 else 0 end) May,
sum(case when month(Date) = 6 then 1 else 0 end) Jun,
sum(case when month(Date) = 7 then 1 else 0 end) Jul,
sum(case when month(Date) = 8 then 1 else 0 end) Aug,
sum(case when month(Date) = 9 then 1 else 0 end) Sep,
sum(case when month(Date) = 10 then 1 else 0 end) Oct,
sum(case when month(Date) = 11 then 1 else 0 end) Nov,
sum(case when month(Date) = 12 then 1 else 0 end) Dec
from Rentals
where year(date) = 2011
group by book;
See SQL Fiddle with Demo. Instead of querying the table multiple times for each column, you use conditional aggregation to get the count for each book during the month and year.
If you use pivot the code is much easier to maintain,
SELECT
BOOK,
[1] as Jan ,
[2] as Feb,
[3] as Mar,
[4] as Apr,
[5] as May,
[6] as Jun,
[7] as Jul,
[8] as Aug,
[9] as Sep,
[10] as Oct,
[11] as Nov,
[12] as Dec
FROM
(
SELECT
BOOK ,
DATEPART(MONTH,[DATE]) AS PER
FROM
Rentals
WHERE
DATEPART(YEAR,[DATE]) = 2014
) AS P PIVOT
(
COUNT(PER) FOR PER IN ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12])
) AS DATA
Simple.