Two dimensional rank using T-SQL - sql

Question

This is the data I'm dealing with:
I would like to find a way, in sql, of adding numbers to the yellow column which will rank the Names in such a way that I get the following.
note: This is the final pivoted result - in the sql table there is no need to pivot the data.
This ranking is decided via these rules:
The most recent week (ie Wk5 column) is the most important.
The next most recent week is next most important.
...so on to the left with the oldest week column "WK1" being the least important.
A data value that is small e.g. 1, is best. A data value that is high e.g. 7, is not good. A blank space is the worst and if at all possible should be located near the bottom of the page - but rules 1/2/3 always take precedence.
This is the data with a placeholder of 0 in the column Idx:
CREATE TABLE #values
(
Name varchar(5),
Idx int,
"Week" varchar(5),
Amount int
);
INSERT INTO #values
VALUES
('A',0,'WK1',3),
('T',0,'WK1',2),
('H',0,'WK1',1),
('P',0,'WK1',4),
('V',0,'WK1',6),
('N',0,'WK1',5),
('A',0,'WK2',2),
('F',0,'WK2',1),
('K',0,'WK2',3),
('P',0,'WK2',4),
('W',0,'WK2',7),
('V',0,'WK2',5),
('B',0,'WK2',6),
('A',0,'WK3',1),
('F',0,'WK3',2),
('T',0,'WK3',3),
('K',0,'WK3',4),
('W',0,'WK3',5),
('V',0,'WK3',6),
('N',0,'WK3',7),
('A',0,'WK4',2),
('F',0,'WK4',1),
('T',0,'WK4',5),
('K',0,'WK4',4),
('B',0,'WK4',6),
('A',0,'WK5',1),
('F',0,'WK5',2),
('T',0,'WK5',3),
('H',0,'WK5',4),
('K',0,'WK5',5);
This is my current attempt:
WITH
allData AS
(
SELECT Name,
"Week",
newRank = RANK() OVER (ORDER BY "Week" DESC,Amount)
FROM #values
)
,allData2 AS
(
SELECT *,
newRank2 = 1 / CONVERT(NUMERIC(18,10),newRank)
FROM allData
)
,allData3 AS
(
SELECT Name,
smRank = SUM(newRank2)
FROM allData2
GROUP BY Name
)
SELECT Name,
smRank,
rnk = RANK() OVER (ORDER BY smRank DESC)
INTO #RankA
FROM allData3;
UPDATE X
SET X.Idx = Y.rnk
FROM #values X
INNER JOIN #RankA Y ON
X.Name = Y.Name;
Unfortunately if I pivot the results, and then order by the Idx column it is not in the order I am aiming at.

Answer 1

This is based on two nested ROW_NUMBERs:
select *,
row_number()
over (order by "Week" desc, amount)
from
(
select *,
row_number()
over (partition by name
order by "Week" desc, amount) as rn
from #values
) as dt
where rn = 1 -- for each name find the latest week and it's lowest number
What if two names share the same week/amount? You might consider RANK or DENSE_RANK instead.

Answer 2

Using your #values table, here is how to pivot it (since the data you provided was not in the same table format) and then assign a value to the index based on your requirements.
select *
, ROW_NUMBER() OVER(ORDER BY CASE WHEN wk5 IS NULL THEN 1 ELSE 0 END, wk5, CASE WHEN wk4 IS NULL THEN 1 ELSE 0 END, wk4, CASE WHEN wk3 IS NULL THEN 1 ELSE 0 END,wk3, CASE WHEN wk2 IS NULL THEN 1 ELSE 0 END,wk2, CASE WHEN wk1 IS NULL THEN 1 ELSE 0 END, wk1) AS new_index
from (
select * from #values
) p
PIVOT (
MAX(Amount)
FOR [week] IN (wk1, wk2, wk3, wk4, wk5)) AS pvt
USING DYNAMIC FOR 52 WEEKS
DECLARE #COLS AS NVARCHAR(MAX),
#QUERY AS NVARCHAR(MAX)
SELECT #COLS = STUFF(( SELECT distinct ','+QUOTENAME(C.[week])
FROM #values AS C
FOR XML PATH('')), 1, 1, '')
SET #QUERY = '
select *
, ROW_NUMBER() OVER(ORDER BY CASE WHEN wk5 IS NULL THEN 1 ELSE 0 END, wk5, CASE WHEN wk4 IS NULL THEN 1 ELSE 0 END, wk4, CASE WHEN wk3 IS NULL THEN 1 ELSE 0 END,wk3, CASE WHEN wk2 IS NULL THEN 1 ELSE 0 END,wk2, CASE WHEN wk1 IS NULL THEN 1 ELSE 0 END, wk1) AS new_index
from (
select * from #values
) p
PIVOT (
MAX(Amount)
FOR [week] IN (' + #cols+ ')) AS pvt'
EXEC(#QUERY)