I want to convert the decimal number 3562.45 to 356245, either as an int or a varchar. I am using cast(3562.45 as int), but it only returns 3562. How do I do it?
How about the obvious:
CAST(3562.45*100 as INTEGER)
This works for me
SELECT FLOOR(55.5999)
Or you can replace the decimal point.
select cast(replace('3562.45', '.','') as integer)
This way, it doesn't matter how many decimal places you have.
You can use also the CONVERT function:
SELECT CONVERT(INT, 3562.45 * 100)
Related
I want to convert my decimal SQL query result in percent. Example I have a 0.295333 I want it to be 30% and if I have a 0.090036 I want it to be 9%.
This is what I have so far.
(100 * (sample1/ sample2) ) as 'Percent'
I also tried this one but the problem is result comes with ".00" and I don't know how to remove the decimal.
cast (ROUND(100 * (sample1 / sample2),0) As int ) as 'Percent'
Try with the below script..
cast (100 * Round((sample1 / sample2),2) As int ) as 'Percent'
So as some of the comments pointed out you may need to pay attention to your datatype if one or both of the original columns that you get your decimal from are integer.
One easy way of dealing with that is something like this:
ColA * ColB * 1.0 which will make sure that your integers are treated as decimals
So if you have SQL Server 2012+ you can use Format and not mess with rounding at all. Like this FORMAT(YourDecimal,'#%'), yep that simple.
;WITH cteValues AS (
SELECT 0.295333 as OriginalValue
UNION ALL
SELECT 0.090036 as OriginalValue
)
SELECT
OriginalValue
,FORMAT(OriginalValue,'#%') as PercentFormat
FROm
cteValues
If you are pre 2012 and do not have format an easy way is to round to the 100th then times by 100 and cast as int CAST(ROUND(YourDecimal,2) * 100 AS INT)
;WITH cteValues AS (
SELECT 0.295333 as OriginalValue
UNION ALL
SELECT 0.090036 as OriginalValue
)
SELECT
OriginalValue
,CAST(ROUND(OriginalValue,2) * 100 AS INT) as PercentInt
FROm
cteValues
Because an INT cannot by definition have decimal places, if you are receiving .00 with the method similar to this or the one you have tried, I would ask the following.
Are you combining (multiplying etc.) the value after casting with another column or value that may be decimal, numeric, or float?
Are you looking at the query results in a program outside of SSMS that could be formatting the results automatically, e.g. Excel, Access?
Address your assumptions first.
How does ROUND work? Does it guarantee return values and if so, how? What is the precedence of the two columns? Does Arithmetic operators influence the results and how?
I only know what I do not know, and any doubt is worth an investigation.
THE DIVIDEND OPERATOR
Since ROUND always returns the higher precedence, this is not the problem. It is in fact the divide operator ( / ) that may be transforming your values to an integer.
Always verify the variables are consistently of one datatype or CAST if either unsure or unable to guarantee (such as insufficiently formatted. I.e. DECIMAL(4,2) instead of required DECIMAL(5,3) ).
DECLARE #Sample1 INT
, #Sample2 DECIMAL(4,2);
SET #Sample1 = 50;
SET #Sample2 =83.11;
SELECT ROUND( 100 * #Sample1 / #Sample2 , 0 )
Returns properly 60.
SELECT ROUND( 100 * #Sample2 / #Sample1 , 0)
Incorrectly turns variables into integers before rounding.
The reason is that DIVIDE - MSDN in SQL may return the higher precedence, but any dividend that is an integer returns another integer.
UPDATE
This also explains why the decimal remains after ROUND...it is of higher precedence. You can add another cast to transform the non-INT datatype to the preferred format.
SELECT CAST( ROUND( <expression>, <Length>) AS INT)
Note that in answering your question I learned something myself! :)
Hope this helps.
I am trying to use either Round or Ceiling method based on Thousandth decimal number.
How do I write condition in the T-SQL stored procedure?
Thanks in advance!
Example:
If I have this number:
1,793.5123611111
I would like to use Round( Variable ,2,1) so that it becomes 1,793.51
So that thousandth decimal does not round off.
If I have this number:
11,80620619333
I would like to use ceiling(Variable *100) / 100 so that it becomes 11,806.21
So that thousandth decimal rounds off.
Thanks.
What is the current data type? VARCHAR?
You may try this
DECLARE #a VARCHAR(100) = '11,806.20619333'
PRINT CONVERT(VARCHAR(100),CAST(#a AS MONEY),1)
Use ROUND() without a third argument. When the third argument is not specified, it defaults to 0, which means rounding (any other value means truncating):
SELECT ROUND(Value, 2)
FROM (
SELECT 1793.5123611111
UNION ALL
SELECT 11806.20619333
) AS s (Value)
;
The above will yield these results:
--------
1793.51
11806.21
I have a table with numbers in a varchar(255) field. They're all greater than one and have multiple decimal places. I'd like to convert them to integers. According to every web site I've consulted, including this one on StackOverflow, either of these should work:
SELECT CAST(VarcharCol AS INT) FROM MyTable
SELECT CONVERT(INT, VarcharCol) FROM MyTable
These both work for me for every kind of numeric value but integer - I can convert to float, decimal, etc. just fine, but trying to convert to integer gives me the following error:
Conversion failed when converting the varchar value '7082.7758172'
to data type int.
I've worked around the problem by converting to data type Decimal(6,0), which works fine. But just for my education, can anyone tell me why converting to data type int (or integer) gives me an error? Thanks.
Converting a varchar value into an int fails when the value includes a decimal point to prevent loss of data.
If you convert to a decimal or float value first, then convert to int, the conversion works.
Either example below will return 7082:
SELECT CONVERT(int, CONVERT(decimal(12,7), '7082.7758172'));
SELECT CAST(CAST('7082.7758172' as float) as int);
Be aware that converting to a float value may result, in rare circumstances, in a loss of precision. I would tend towards using a decimal value, however you'll need to specify precision and scale values that make sense for the varchar data you're converting.
Actually whether there are digits or not is irrelevant. The . (dot) is forbidden if you want to cast to int. Dot can't - logically - be part of Integer definition, so even:
select cast ('7.0' as int)
select cast ('7.' as int)
will fail but both are fine for floats.
Presumably, you want to convert values before the decimal place to an integer. If so, use case and check for the right format:
SELECT (case when varcharcol not like '%.%' then cast(varcharcol as int)
else cast(left(varcharcol, chardindex('.', varcharcol) - 1) as int)
end) IntVal
FROM MyTable;
Try this
declare #v varchar(20)
set #v = 'Number'
select case when isnumeric(#v) = 1 then #v
else #v end
and
declare #v varchar(20)
set #v = '7082.7758172'
select case when isnumeric(#v) = 1 then #v
else convert(numeric(18,0),#v) end
Try this query:
SELECT cast(column_name as type) as col_identifier FROM tableName WHERE 1=1
Before comparing, the cast function will convert varchar type value to integer type.
SELECT
convert(numeric(18,5),Col1), Col2
FROM DBname.dbo.TableName
WHERE isnumeric(isnull(Col1,1)) <> 0
I want to add 2 zero to the right of the next function: UNIX_TIMESTAMP (NOW()),
So instead of: 1369047810, I would get: 136904781000
I try this:
SELECT (UNIX_TIMESTAMP (NOW()) + RIGHT(REPLICATE('0', 2))))
but it doesn't help.
SELECT UNIX_TIMESTAMP (NOW()) * 100
If you want it as a string, then you want to convert it to a string and then add the zeros. Something like:
SELECT (cast(UNIX_TIMESTAMP (NOW()) as varchar(255) + RIGHT(REPLICATE('0', 2))))
I think the string conversion is safer than doing arithmetic, if you want a string in the end. Multiplying values might cause arithmetic overflow.
Also, I associate the syntax UNIX_TIMESTAMP (NOW()) with MySQL (as I write this, there is no database tag on the question). The right syntax in that database would be:
select concat(cast(UNIX_TIMESTAMP (NOW()) as varchar(255), '00')
I have alphanumeric values like. XYZ1,XYZ2......XYZ11, XYZ12 and so on, now I want to select only the Max numeric value, i.e. 12 here.
I tried-
select max(REPLACE(ID,'XYZ','')) from myTable;
but this is returning 9. why?
Try converting to INT before max
select max(cast(REPLACE(ID,'XYZ','') as int)) from myTable;
It's still treating your value as a string instead of a number. Try:
select max(CAST(REPLACE(ID,'XYZ','') AS INT) from myTable;
Because you're still comparing strings. The fact that they contain only numeric digits doesn't mean that they're not strings. You need to convert them:
SELECT MAX(CAST(REPLACE(id, 'XYZ', '') AS INT)) FROM My_Table
Another method is
select max(REPLACE(ID,'XYZ','')*1) from myTable