Check address voor 2 properties and display in same row - sql

Question

From the Persons table I would like to get the following output:
Number FirstName AddressAvenue AddressFloor
----------------------------------------------
1 David Long Avenue 5th Floor
2 Bob Short Avenue NULL
3 Peter Middle Avenue 1st Floor
(Apparently, Bob his address does not contain a Floor number).
I thought I would get this by running the following query:
select
p.Number
p.FirstName
, case when (p.Street like '%Avenue%') then p.Street end as AddressAvenue
, case when (p.Street like '%Floor%') then p.Street end as AddressFloor
from
#persons
;
However, the output is as follows:
Number FirstName AddressAvenue AddressFloor
----------------------------------------------
1 David Long Avenue NULL
2 Bob Short Avenue NULL
3 Peter Middle Avenue NULL
1 David NULL 5th Floor
3 Peter NULL 1st Floor
Question How can I get both Address and Floor on the same line?
Any help is greatly appreciated!

Answer 1

Try this bad boy
CREATE TABLE #persons
(
Number INT
,FirstName VARCHAR(10)
,Street VARCHAR(50)
)
INSERT #persons
VALUES
(1, 'David', 'Long Avenue'),
(2, 'Bob', 'Short Avenue'),
(3, 'Peter', 'Middle Avenue'),
(1, 'David', '5th Floor'),
(3, 'Peter', '1st Floor')
--This is the code you really want, I just needed the rest to test it and make sure it worked
SELECT DISTINCT
z.Number
,z.FirstName
,(SELECT p.Street FROM #persons p where p.Street LIKE '%Avenue%' AND p.Number = z.Number)
,(SELECT p.Street FROM #persons p where p.Street LIKE '%Floor%' AND p.Number = z.Number)
FROM #persons z
DROP TABLE #persons
Results in the following: