I have a table in SQL Server 2008 like:
Period Name Value
1 A 10
2 A 20
3 A 30
4 A 40
1 B 50
2 B 80
3 B 70
4 B 60
What I need to write a select query includes a new column MainValue which contains the value where period=4 for a name for each data.
Example:
Period Name Value MainValue
1 A 10 40
2 A 20 40
3 A 30 40
4 A 40 40
1 B 50 60
2 B 80 60
3 B 70 60
4 B 60 60
How can I provide this? I tried the one below, but it is not working as I want.
Select
*,
(select Value where Period = 4) as MainValue
from myTable;
Any help would be appreciated.
Try this:
SELECT Period, Name, Value,
MAX(CASE WHEN Period=4 THEN Value END) OVER (PARTITION BY Name) AS MainValue
FROM mytable
The query uses a window function with a condition applied over Name partitions: the function returns the Value corresponding to Period=4 inside each partition.
You can do this a number of ways. A correlated sub-query as the column, a cross apply to a correlated query, or a cte. I personally like the cte approach. It would look something like this.
with MainValues as
(
select Name
, Value
from SomeTable
where Period = 4
)
select st.*
, mv.Value as MainValue
from SomeTable st
join MainValues mv on st.Name = mv.Name
Related
Using TSQL 2012 here, essentially I have a dataset that looks like the following:
Period Values OtherValues SiteName MoreColumns
1 12 45 Site 1 34
2 34 6 Site 1 346
2 56 79 Site 1 345
3 3 78 Site 1 67
3 4 67 Site 1 8
What I would like to return is a dataset that groups on site and sums all the other columns based on the period they're against.
Site P1V P2v P3V P1OtherV P2OtherV P3OtherV
Site 1 12 90 7 45 85 145
I know I can do it with a case in the style of:
SELECT CASE WHEN Period = '1' THEN Sum(Values) As P1Values,
CASE WHEN Period = '2' THEN Sum(Values) As P2Values,
CASE WHEN Period = '3' THEN Sum(Values) As P3Values
.....
But surely there's a more elegant solution for this? The dataset should return three sums (for each period) for 7 columns, so in total 21 sums, with the potential to grow.
I would use UNPIVOT/PIVOT sequence:
SELECT * FROM
(
SELECT Period+Col Period, SiteName, Value FROM
Src UNPIVOT (Value FOR Col IN (SapValues,OtherValues)) U
) U
PIVOT (SUM(Value) FOR Period IN (P1SapValues,P2SapValues,P3SapValues,
P1OtherValues,P2OtherValues,P3OtherValues)) P
You can do it using PIVOT and making source table with UNION
WITH T1 AS
(
SELECT Period + 'SapValues' as Period, SapValues as Value, SiteName FROM T
UNION ALL
SELECT Period + 'OtherValues' as Period, OtherValues as Value, SiteName FROM T
)
SELECT *
FROM T1
PIVOT
(
Sum(Value)
FOR Period IN ([P1SapValues],[P2SapValues],[P3SapValues],
[P1OtherValues],[P2OtherValues],[P3OtherValues])
) AS PivotTable;
Consider the following table?
ID COL VALUE
1 A 10
2 B 10
3 C 10
4 D 10
5 E 10
Output:
ID COL VALUE
1 A 10
2 B 20
3 C 30
4 D 40
5 E 50
Based on your (deleted) comment in output it is taking up the sum of the upper values, it sounds like you're wanting a cumulative SUM().
You can do this with a windowed function:
Select Id, Col, Sum(Value) Over (Order By Id) As Value
From YourTable
Output
Id Col Value
1 A 10
2 B 20
3 C 30
4 D 40
5 E 50
Please make use of the the below code to obtain the cumulative sum. The code is working as expected with SQL Server 2012.
DECLARE #Table TABLE (ID int, COL CHAR(2), VALUE int)
INSERT #Table
(ID,COL,[VALUE])
VALUES
(1,'A',10),
(2,'B',10),
(3,'C',10),
(4,'D',10),
(5,'E',10)
SELECT t.ID,t.COL,SUM(VALUE) OVER (ORDER BY t.ID) AS VALUE
FROM #Table t
Not really sure what you are asking for. If my assumption is correct, you want to SUM the contents of a column and group it.
Select sum(value), col
from table
group by col
------------------------------------------
ID Name C D
------------------------------------------
1 AK-47 10 5
2 RPG 10 20
3 Mp5 20 15
4 Sniper 20 18
5 Tank 90 80
6 Space12 90 20
7 Rifle 90 110
8 Knife 90 85
Consider 1,2 ; 3,4 ; 5,6,7,8 are as separate groups
So i need to get the row group wise that which's D column holds the nearest lower number to the C column
So the Expected Result is :
------------------------------------------
ID Name C D
------------------------------------------
1 AK-47 10 5
4 Sniper 20 18
8 Knife 90 85
How can I achieve this ?
select t1.*
from your_table t1
join
(
select c, min(abs(c-d)) as near
from your_table
group by c
) t2 on t1.c = t2.c and abs(t1.c-t1.d) = t2.near
Here is the syntax for another way of doing this. This uses a cte and will only hit the base table once.
with MySortedData as
(
select ID, Name, C, D, ROW_NUMBER() over(PARTITION BY C order by ABS(C - D)) as RowNum
from Something
)
select *
from MySortedData
where RowNum = 1
Here's the case: I have one table myTable which contains 3 columns:
ID int, identity
Group varchar(2), not null
value decimal(18,0), not null
Table looks like this:
ID GROUP VALUE Prev_Value Result
------------------------------------------
1 A 20 0 20
2 A 30 20 10
3 A 35 30 5
4 B 100 0 100
5 B 150 100 50
6 B 300 200 100
7 C 40 0 40
8 C 60 40 20
9 A 50 35 15
10 A 70 50 20
Prev_Value and Result columns should be custom columns. I need to make it on view. Anyone can help? please... Thank you so much.
The gist of what you need to do here is to join the table to itself, where part of the join condition is that the value column of the joined copy of the table is less than value column of the original. Then you can group by the columns from the original table and select the max value from the joined table to get your results:
SELECT t1.id, t1.[Group], t1.Value
, coalesce(MAX(t2.Value),0) As Prev_Value
, t1.Value - coalesce(MAX(t2.Value),0) As Result
FROM MyTable t1
LEFT JOIN MyTable t2 ON t2.[Group] = t1.[Group] and t2.Value < t1.Value
GROUP BY t1.id, t1.[Group], t1.Value
Once you can update to Sql Server 2012 you'll also be able to take advantage of the new LAG keyword.
id Name claim priority
1 yatin 70 5
6 yatin 1 10
2 hiren 30 3
3 pankaj 40 2
4 kavin 50 1
5 jigo 10 4
7 jigo 1 10
this is my table and i want to arrange this table as shown below
id Name claim priority AlternateFlag
1 yatin 70 5 0
6 yatin 1 10 0
2 hiren 30 3 1
3 pankaj 40 2 0
4 kavin 50 1 1
5 jigo 10 4 0
7 jigo 1 10 0
It is sorted as alternate group of same row.
I am Using sql server 2005. Alternate flag starts with '0'. In my example First record with name "yatin" so set AlternateFlag as '0'.
Now second record has a same name as "yatin" so alternate flag would be '0'
Now Third record with name "hiren" is single record, so assign '1' to it
In short i want identify alternate group with same name...
Hope you understand my problem
Thanks in advance
Try
SELECT t.*, f.AlternateFlag
FROM tbl t
JOIN (
SELECT [name],
AlternateFlag = ~CAST(ROW_NUMBER() OVER(ORDER BY MIN(ID)) % 2 AS BIT)
FROM tbl
GROUP BY name
) f ON f.name = t.name
demo
You could use probably an aggregate function COUNT() and then HAVING() and then UNION both Table, like:
SELECT id, A.Name, Claim, Priority, 0 as AlternateFlag
FROM YourTable
INNER JOIN (
SELECT Name, COUNT(*) as NameCount
FROM YourTable
GROUP BY Name
HAVING COUNT(*) > 1 ) A
ON YourTable.Name = A.Name
UNION ALL
SELECT id, B.Name, Claim, Priority, 1 as AlternateFlag
FROM YourTable
INNER JOIN (
SELECT Name, COUNT(*) as NameCount
FROM YourTable
GROUP BY Name
HAVING COUNT(*) = 1 ) B
ON YourTable.Name = B.Name
Now, this assumes that the Names are unique meaning the names like Yatin for example although has two counts is only associated to one person.
See my SqlFiddle Demo
You can use Row_Number() function with OVER that will give you enumeration, than use the reminder of integer division it by 2 - so you'll get 1s and 0s in your SELECT or in the view.