Sed/Awk:How to remove Ctrl z characters at the last line, replace new line characters in between records to space - awk

I have a requirement where I need to perform following 3 things to a file in Linux:
Check if Ctrl-z character is present at the last line of the file and if present then delete the line.
Replace new line characters that appear in between the fields in all the records to a single space but it should not replace the last new line in every record which signifies record delimiter.
Delete the first line of the file.
I can not use any script.Can it be done with sed/awk. Any suggestion is highly appreciated.

Related

Intellij how to delete all line containing annotation?

I want to delete all lines that contains annotation. I see there is a shortcut to delete line/selection. But how do i pass regex to the delete line shortcut so that all line that starts with # gets deleted?
I want to use like this
^#
You have to use replace option.
Use Ctrl+R to open replace option, select regex(at the left side of search box there is a * sign). Enter #.*$ in replace box. Keep the replace with box empty.
The Regex means any line starting with # followed by zero or more characters(digit/non digit/letter etc) and ended by end line.

Deleting a line from a multiline flxText

How can I delete the first line from a flxText?
I have tried text.textField.replaceText(0, text.textField.getLineLength(0), ""); but it only works once. I have also tried keeping count of the line that's being deleted and it doesn't work either.
edit: I would like to reopen this question to specify that I want to take into account both newlines and word wrap.
Considering the text contains the line breaks why not just split the text on \n, remove the lines you no longer need, and then set the text to the joined lines.
var lines = flText.text.split("\n");
lines.shift(); // removes the first line
flText.text = lines.join("\n");

Visual Basic pulling a character from a certain line number

I am working on a macro that needs to be able to check and make sure that a character on a certain line is what it should be before it finishes the form.
Where or how do i find the information to do this?
I have tried using the command "Left(#of line ,1)" and am not getting it to return anything at this point.
I Assume that you have this text in a string. Comment to my answer if wrong.
You can use a Regex to compare to string with your character like so :
If Regex.IsMatch(MyString, *.{X}Y) Then
'You have to manually replace X for the number of characters before the character you scan for
'You have to manually replace Y for the-said character it is supposed to be
Look at http://www.codeproject.com/Articles/9099/The-Minute-Regex-Tutorial for more info on Regex.
If you want to only take one line in your string :
TheLine = split(MyString,Environnement.Newline)([Line Number])

write new line to file

I'm trying to write to file newline. I'm using WS_DOWNLOAD but have no idea how to write new line into text.
Anyone knows ?
Set a character type field to cl_abap_char_utilities=>cr_lf and insert that in the appropriate places (wherever you want a new line) to your output.
This contains the carriage return & linefeed characters.

how to break up lines of codes AND comments in VB.NET 2010?

everytime i try the space then underscore + enter it doesnt work and it lights up red
edit - like for example this is a comment:
'you must add such and such to this variable and then you must declare it'
say i have that for a comment and i want to break the comment after variable. when i do this
'you must add such and such to this variable _
and then you must declare it'
it gives me an error
The underscore at the end of the line trick doesn't work for comments. The underscores are treated as part of the comment.
To create a bunch of single line comments at once, select the lines you want to comment out and press CTRL+K then CTRL+C
A line continuation consists of at least one white-space character that immediately precedes a single underscore character as the last character (other than white space) in a text line.
Ref.
Doesn't apply to comments though; if you want multiple comment lines simply start a new comment for each subsequent line.