How I can move value of a column to upper row where banakaccount is null
Below is my table data of two creditor TABLE1
UniqueDatabaseNo Creditor BankAccountNo
882370 300020 NULL
NULL 300020 NULL
NULL 300020 NULL
0 300020 NL21SOGE0946
NULL 300020 NULL
NULL 380910 NULL
0 380910 1432981
0 380910 NL98RABO0181
NULL 380910 NULL
2293483 380910 NULL
I NEED BELOW OUT PUT WHERE UniqueDatabaseNo > 0 AND ON SAME ROW BANK ACCOUNT SHOULD ON SAME ROW
Here is desired output
UniqueDatabaseNo Creditor BankAccountNo
882370 300020 NL21SOGE0946
2293483 380910 NL98RABO0181
I tried below query but it is not working correctly
select * from TABLE1
where uniquedatabaseno >0
union all
select * from TABLE1
where BankAccountNo LIKE '[a-Z][a-Z]%'
Thanks,
You can do what you want using aggregation:
select max(UniqueDatabaseNo) as UniqueDatabaseNo, Creditor,
max(case when BankAccountNo like '[a-Z][a-Z]%' then BankAccountNo end) as BankAccountNo
from t
group by Creditor;
Edit:
You might was conditional logic for UniqueDatabaseNo as well:
select max(case when UniqueDatabaseNo > 0 then UniqueDatabaseNo end) as UniqueDatabaseNo
This is not necessary for your sample data.
Try this
select UniqueDatabaseNo,Creditor,TT.BankAccountNo
from TABLE1 T1
OUTER APPLY(
SELECT BankAccountNo as 'BankAccountNo'
FROM TABLE1 T2
WHERE T1.Creditor=T2.Creditor AND T2.BankAccountNo IS NOT NULL
)TT
where T1.uniquedatabaseno >0 AND T1.UniqueDatabaseNo IS NOT NULL
You need to filter out NULL values:
SELECT * FROM TABLE1
WHERE
UniqueDatabaseNo > 0
AND BankAccountNo IS NOT NULL
Related
I can find the count of non null values by typing each column name, but is there a way to write it without manually typing the column names as I have 100+ columns in my table.
select 'col1Name', count(col1Name) from table where col1Name is null
union
select 'col2Name', count(col2Name) from table where col2Name is null
union ...
select 'col20Name', count(col20Name) from table where col20Name is null
You can use a case operation here
select
sum(case when a is null then 1 else 0 end) A,
sum(case when b is null then 1 else 0 end) B,
sum(case when c is null then 1 else 0 end) C
from T
I have a large data set with duplicate reference numbers (reference duplications range from 0 to 37 times). I want to count the number of references only where all instances are null in two columns. So using the table below, the code should return 1 because only Reference Code 3 has all null values, and the duplicates should only be counted once.
I would be grateful for any help.
This involves two steps: (1) isolate all the distinct pairs of values that only have null; (2) count each one once. One way to express this in a query is:
SELECT COUNT(*) FROM
(
SELECT refnum FROM #ref
GROUP BY refnum
HAVING MIN(colA) IS NULL
AND MIN(colB) IS NULL;
) AS x;
Use aggregation to get the codes:
select code
from t
group by code
having max(a) is null and max(b) is null;
If you want the count, use a subquery:
select count(*)
from (select code
from t
group by code
having max(a) is null and max(b) is null
) t;
With conditional aggregation:
select
refcode
from referencecodes
group by refcode
having sum(case when (a is null and b is null) then 0 else 1 end) = 0
The above will return the codes with only null values in a and b.
If you want the number of codes:
select count(r.refcode) from (
select
refcode
from referencecodes
group by refcode
having sum(case when (a is null and b is null) then 0 else 1 end) = 0
) r
Or with EXISTS:
select
count(distinct r.refcode)
from referencecodes r
where not exists (
select 1 from referencecodes
where (refcode = r.refcode) and (a is not null or b is not null)
)
See the demo
e.g. If I get 2 null data in a column for same id, then pass null.
ii) If I get 2 same not null data in a column for same id, then pass not null.
ii) If I get 1 null and 1 not null data in a column for same id, then pass not null.
ii) If I get 2 different not null data in a column for same id, then pass '?'.
Sample data
Please find the sample data in the image.
Thanks in advance.
Output obtained after new code:
Result
You can try following :
SELECT (CASE WHEN PRTY_KEY_ID_NN= 0 THEN NULL /* IF BOTH/ALL VALUES ARE NULL */)
WHEN PRTY_KEY_ID_NN <> TOTAL_COUNT THEN PRTY_KEY_ID_NN_MX
ELSE
CASE WHEN TOTAL_COUNT=PRTY_KEY_ID_NN_DIST THEN NULL /* IF BOTH HAVING DIFFERENT NOT NULL VALUE */
CASE WHEN TOTAL_COUNT<>PRTY_KEY_ID_NN_DIST THEN PRTY_KEY_ID_NN_MX
END
END)PRTY_KEY_ID_VAL,
(CASE WHEN TOTAL_ASSET_A_NN= 0 THEN NULL /* IF BOTH/ALL VALUES ARE NULL */)
WHEN TOTAL_ASSET_A_NN <> TOTAL_COUNT THEN TOTAL_ASSET_A_MX
ELSE
CASE WHEN TOTAL_COUNT=TOTAL_ASSET_A_DIST THEN NULL /* IF BOTH HAVING DIFFERENT NOT NULL VALUE */
CASE WHEN TOTAL_COUNT<>TOTAL_ASSET_A_DIST THEN TOTAL_ASSET_A_MX
END
END)TOTAL_ASSET_VAL,
(CASE WHEN DBUS_NUM_NN= 0 THEN NULL /* IF BOTH/ALL VALUES ARE NULL */)
WHEN DBUS_NUM_NN <> TOTAL_COUNT THEN DBUS_NUM_MX
ELSE
CASE WHEN TOTAL_COUNT=DBUS_NUM_DIST THEN NULL /* IF BOTH HAVING DIFFERENT NOT NULL VALUE */
CASE WHEN TOTAL_COUNT<>DBUS_NUM_DIST THEN DBUS_NUM_MX
END
END)DBUS_NUM_DIST_VAL,
(CASE WHEN BUS_NATURE_DE_NN= 0 THEN NULL /* IF BOTH/ALL VALUES ARE NULL */)
WHEN BUS_NATURE_DE_NN <> TOTAL_COUNT THEN BUS_NATURE_DE_MX
ELSE
CASE WHEN TOTAL_COUNT=BUS_NATURE_DE_DIST THEN NULL /* IF BOTH HAVING DIFFERENT NOT NULL VALUE */
CASE WHEN TOTAL_COUNT<>BUS_NATURE_DE_DIST THEN BUS_NATURE_DE_MX
END
END)BUS_NATURE_DE_VAL
FROM
(SELECT COUNT(*)TOTAL_COUNT,
SUM(CASE WHEN PRTY_KEY_ID IS NULL THEN 0 ELSE 1 END)PRTY_KEY_ID_NN,
SUM(CASE WHEN TOTAL_ASSET_A IS NULL THEN 0 ELSE 1 END)TOTAL_ASSET_A_NN,
SUM(CASE WHEN TOTAL_LIAB_A IS NULL THEN 0 ELSE 1 END)TOTAL_LIAB_A_NN,
SUM(CASE WHEN DBUS_NUM IS NULL THEN 0 ELSE 1 END)DBUS_NUM_NN,
SUM(CASE WHEN BUS_NATURE_DE IS NULL THEN 0 ELSE 1 END)BUS_NATURE_DE_NN,
MAX(PRTY_KEY_ID_NN)PRTY_KEY_ID_NN_MX,
MAX(TOTAL_ASSET_A)TOTAL_ASSET_A_MX,
MAX(TOTAL_LIAB_A)TOTAL_LIAB_A_MX,
MAX(DBUS_NUM)DBUS_NUM_MX,
MAX(BUS_NATURE_DE)BUS_NATURE_DE_MX,
COUNT(DISTINCT PRTY_KEY_ID_NN) PRTY_KEY_ID_NN_DIST,
COUNT(DISTINCT TOTAL_ASSET_A)TOTAL_ASSET_A_DIST,
COUNT(DISTINCT TOTAL_LIAB_A)TOTAL_LIAB_A_DIST,
COUNT(DISTINCT DBUS_NUM)DBUS_NUM_DIST,
COUNT(DISTINCT BUS_NATURE_DE)BUS_NATURE_DE_DIST
FROM YOUR_TABLE)
You can find out the sample data like image in below SQL.If the column data type is varchar(char) please delete the TO_CHAR expression, and replace the table name TEST_TABLE to your table's.
WITH TEST_TABLE AS (
SELECT 1056059 AS PRTY_KEY_ID, NULL AS TOT_ASSET_AM, NULL AS TOT_LIABILITIES_AM, NULL AS DBUS_NM, 'Pediatrics' AS BUS_NATURE_DE FROM DUAL
UNION ALL
SELECT 1056059 AS PRTY_KEY_ID, 5000 AS TOT_ASSET_AM, '300000' AS TOT_LIABILITIES_AM, NULL AS DBUS_NM, 'Medicine' AS BUS_NATURE_DE FROM DUAL
)
SELECT
PRTY_KEY_ID,
MIN(CASE WHEN TOT_ASSET_AM_CNT > 1 THEN '?' ELSE TO_CHAR(TOT_ASSET_AM) END) AS TOT_ASSET_AM,
MIN(CASE WHEN TOT_LIABILITIES_AM_CNT > 1 THEN '?' ELSE TO_CHAR(TOT_LIABILITIES_AM) END) AS TOT_LIABILITIES_AM,
MIN(CASE WHEN DBUS_NM_CNT > 1 THEN '?' ELSE TO_CHAR(DBUS_NM) END) AS DBUS_NM,
MIN(CASE WHEN BUS_NATURE_DE_CNT > 1 THEN '?' ELSE TO_CHAR(BUS_NATURE_DE) END) AS BUS_NATURE_DE
FROM (
SELECT
TEST_TABLE.*,
COUNT(TOT_ASSET_AM) OVER(PARTITION BY PRTY_KEY_ID) AS TOT_ASSET_AM_CNT,
COUNT(TOT_LIABILITIES_AM) OVER(PARTITION BY PRTY_KEY_ID) AS TOT_LIABILITIES_AM_CNT,
COUNT(DBUS_NM) OVER(PARTITION BY PRTY_KEY_ID) AS DBUS_NM_CNT,
COUNT(BUS_NATURE_DE) OVER(PARTITION BY PRTY_KEY_ID) AS BUS_NATURE_DE_CNT
FROM TEST_TABLE
)
GROUP BY PRTY_KEY_ID
I want to add the below queries as the column values without creating a table.
Select 'NetworkKey' as AuthKey
Select count(NetworkSK) as Totalcount from EDW.Fact.AuthorizationRequest
Select count(*) as NUllcount from EDW.Fact.AuthorizationRequest where NetworkSK is NULL
Select count(*) as NotNullcount from EDW.Fact.AuthorizationRequest where NetworkSK is Not NULL
My result should look like this without creating a table physically...
AuthKey Totalcount Nullcount NotNullCount
NetworkKey 100 5 95
YOU WANT TO DO IT LIKE THIS BECAUSE THIS WILL WORK TO SOLVE YOUR PROBLEM.
SELECT 'NetworkKey' AS AuthKey,
COUNT(*) AS TotalCount,
SUM(CASE WHEN NetworkSK IS NULL THEN 1 ELSE 0 END) AS NUllcount,
SUM(CASE WHEN NetworkSK IS NOT NULL THEN 1 ELSE 0 END) AS NotNullcount
FROM EDW.Fact.AuthorizationRequest
Happy holidays.
The table contains an ID column, valueHeading column and a value column. I want to separate the value column into two new columns called valueHeading1 and valueHeading2 depending on which type of valueHeading the value has.
So I want to join this select:
Edit: Full join
SELECT ID
,valueHeading
,value as 'valueHeading1'
FROM table1
WHERE valueHeading = 'valueHeading1'
With This select:
SELECT ID
,value as 'valueHeading2'
FROM table1
WHERE valueHeading = 'valueHeading2'
on their respective ID's. How do I do this?
Edit to illustrate what I want to do:
Original table:
ID valueHeading value
0 valueHeading1 a
0 valueHeading2 a
1 valueHeading1 ab
1 valueHeading2 NULL
2 valueHeading1 abcd
2 valueHeading2 abc
New Table:
ID valueHeading1 valueHeading2
0 a a
1 ab NULL
2 abcd abc
If you need only join use this. Using case when is elegant way if you don't need join.
SELECT * FROM
(SELECT ID
,valueHeading
,value as 'valueHeading1'
FROM table1
WHERE valueHeading = 'valueHeading1') AS TAB_1,
(SELECT ID
,value as 'valueHeading2'
FROM table1
WHERE valueHeading = 'valueHeading2') AS TAB_2
WHERE TAB_1.ID = TAB_2.ID
Try something like :
SELECT ID
, CASE WHEN valueHeading = 'valueHeading1' THEN value ELSE NULL END AS valueHeading1
, CASE WHEN valueHeading = 'valueHeading2' THEN value ELSE NULL END AS valueHeading2
FROM table1
WHERE valueHeading IN ('valueHeading1', 'valueHeading2')
If you want to regroup all values on one row for each ID, you can try :
SELECT ID
, MAX(CASE WHEN valueHeading = 'valueHeading1' THEN value ELSE NULL END) AS valueHeading1
, MAX(CASE WHEN valueHeading = 'valueHeading2' THEN value ELSE NULL END) AS valueHeading2
FROM table1
WHERE valueHeading IN ('valueHeading1', 'valueHeading2')
GROUP BY ID
HAVING MAX(CASE WHEN valueHeading = 'valueHeading1' THEN value ELSE NULL END) IS NOT NULL
OR MAX(CASE WHEN valueHeading = 'valueHeading2' THEN value ELSE NULL END) IS NOT NULL
See SQLFiddle. I also tried on Oracle 11g and MSSQL 2012, and it works each time.
In SQLServer2005+ possible use PIVOT
SELECT ID, valueHeading1, valueHeading2
FROM
(
SELECT *
FROM dbo.test28
WHERE valueHeading IN ('valueHeading1', 'valueHeading2')
) x
PIVOT
(
MAX(value)
FOR valueHeading IN ([valueHeading1], [valueHeading2])
) p
Demo on SQLFiddle
self join could be a simple solution
SELECT DISTINCT t1.ID, t1.value as valueHeading1, t2.value as valueHeading2,
FROM table1 t1
INNER JOIN table1 t2 ON t1.ID = t2.ID
WHERE t1.valueHeading <> t2.valueHeading