Hello I want to update table2 if the data does not match table 1. If there are results in the below query I would like table2 to be updated
Select id, name, desc
From table1
Minus
Select id, name, desc
From table2
Table1
Id, name, desc
1 bob green
2 Sam Blue
Table2
Id, name, desc
1 bob yellow
2 sam b Red
I want table2 to have the same data as table1
Table2
Id, name, desc
1 bob Green
2 Sam Blue
If you want Table2 to have the same data as Table1 then I would recommend truncating it and re-inserting the data:
truncate table table2;
insert into table2(id, name, desc)
select id, name, desc
from table1;
This operation is usually going to be faster than a bunch of updates.
EDIT:
In Oracle, you can use merge or set the fields as:
update table2
set (name, desc) = (select name, desc from table1 where table1.id = table2.id);
If you like, you can add:
where (name, desc) <> (select name, desc from table1 where table1.id = table2.id)
Related
I want to join two tables and remove duplicates from both the tables but keeping any duplicate value found in the first table.
T1
Name
-----
A
A
B
C
T2
Name
----
A
D
E
Expected result
A - > FROM T1
A - > FROM T1
B
C
D
E
I tried union but removes all duplicates of 'A' from both tables.
How can I achieve this?
Filter T2 before UNION ALL
select col
from T1
union all
select col
from T2
where not exists (select 1 from T1 where T1.col = T2.col)
Assuming you want the number of duplicates from the table with the most repetitions for each value, you can do it with the ROW_NUMBER() windowing function, to eliminate duplicates by their sequence with the set of repetitions in each table.
SELECT Name FROM (
SELECT Name, ROW_NUMBER() OVER ( PARTITION BY Name ORDER BY Name ) AS Row
FROM T1
UNION
SELECT Name, ROW_NUMBER() OVER ( PARTITION BY Name ORDER BY Name ) AS Row
FROM T2
) x
ORDER BY Name
To see how this works out, we add two B rows to T2 then do this:
SELECT Name, ROW_NUMBER() OVER ( PARTITION BY Name ORDER BY Name ) AS Row
FROM T1
Name Row
A 1
A 2
B 1
C 1
SELECT Name, ROW_NUMBER() OVER ( PARTITION BY Name ORDER BY Name ) AS Row
FROM T2
Name Row
A 1
B 1
B 2
D 1
E 1
Now UNION them without ALL to combine and eliminate duplicates:
SELECT Name, ROW_NUMBER() OVER ( PARTITION BY Name ORDER BY Name ) AS Row
FROM T1
UNION
SELECT Name, ROW_NUMBER() OVER ( PARTITION BY Name ORDER BY Name ) AS Row
FROM T2
Name Row
A 1
A 2
B 1
B 2
C 1
D 1
E 1
The final query up top is then just eliminating the Row column and sorting the result, to ensure ascending order.
See SQL Fiddle for demo.
select * from T1
union all
select * from T2 where name not in (select distinct name from T1)
Sql Fiddle Demo
you should use "union all" instead of "union".
"union" remove other duplicated records while "union all" gives all of them.
for you result,because of we filtered intersects from table 2 in "where",we don't need "UNION ALL"
select col1 from t1
union
select col1 from t2 where t2.col1 not in(select t1.col1 from t1)
I D'not know the following code is good practice or not But it's working
select name from T1
UNION
select name from T2 Where name not in (select name from T1)
The Above Query Filter the value based on T1 value and then join two tables values and show the result.
I hope it's helps you thanks.
Note : It's not better way to get result it's affect your performance.
I sure i update the better solution after my research
You want all names from T1 and all names from T2 except the names that are in T1.
So you can use UNION ALL for the 2 cases and the operator EXCEPT to filter the rows of T2:
SELECT Name FROM T1
UNION ALL
(
SELECT Name FROM T2
EXCEPT
SELECT Name FROM T1
)
See the demo.
Results:
> | Name |
> | :--- |
> | A |
> | A |
> | B |
> | C |
> | D |
> | E |
I have 2 tables containing different data, linked by a column "id", except the id is repeated multiple times
For example,
Table 1:
id grade
1 A
1 C
Table 2:
Id company
1 Alpha
1 Beta
1 Charlie
The number of rows would be inconsistent, table 1 may sometimes have more/less/equal rows compared to table 2. How am I able to combine/merge them into this outcome:
id grade company
1 A Alpha
1 C Beta
1 Charlie
I am using Microsoft access' query.
This is a real pain in MS Access. But you can do it by using a subquery to generate sequence numbers. Here is one method assuming that the rows are unique:
select id, max(grade) as grade, max(company) as company
from ((select id, grade, null as company,
(select count(*)
from table1 as tt1
where tt1.id = t1.id and tt1.grade <= t1.grade
) as seqnum
from table1 as tt1
) union all
(select id, null as grade, company,
(select count(*)
from table2 as tt2
where tt2.id = t2.id and tt2.company <= t1.company
) as seqnum
from table2 as tt2
)
) t12
group by id, seqnum;
This would be much simpler in almost any other database.
I have two tables having same columns.I want to get those columns whose values are distinct in both tables.How Can I achieve this?please help.Iam stuck.
imageid is primary key in both tables.Its not necessary that imageids present in first table should be present
on second table.
First table:
imageid name id
1 priya 001
2 neha 002
3 divya 003
4 santo 004
Second table:
imageid name id
1 priy 001
2 neha 003
4 santo 004
Result
imageid firstdata seconddata columnname
1 priy priya name
2 002 003 id
Assuming you have no duplicates, then you can do this with a basic inner join with union all:
select t1.imageid, t1.name as firstdata, t2.name as seconddata, 'name' as colname
from t1 join
t2
on t1.imageid = t2.imageid
where t1.name <> t2.name
union all
select t1.imageid, t1.id as firstdata, t2.id as seconddata, 'id'
from t1 join
t2
on t1.imageid = t2.imageid
where t1.id <> t2.id;
Depending on types and on the database, you might need to cast the ids to a string.
I found the following method on AskTom.com years ago and have kept it as a code template ever since. I find it's reasonably fast and I use it frequently.
SELECT COUNT(src1) AS in_first_table, COUNT(src2) AS in_second_table, imageid, name, id
FROM (SELECT imageid, name, id,
1 AS src1,
to_number(NULL) AS src2
FROM first_table
UNION ALL
SELECT imageid, name, id,
to_number(NULL) AS src1,
2 AS src2
FROM second_table
)
GROUP BY imageid, name, id
HAVING COUNT(src1) <> COUNT(src2)
ORDER BY 3, 1 DESC;
The first two columns (counts) indicate how many records found in that table, which can identify rows where the tables have multiple matching records.
I've also used this to compare very complex queries by putting them in a WITH clause, so the main query is easier to read.
For example:
WITH first_t AS
(SELECT imageid, NAME, id
FROM first_table),
second_t AS
(SELECT imageid, NAME, id
FROM second_table)
SELECT COUNT(src1) AS in_first_table,
COUNT(src2) AS in_second_table,
imageid, NAME, id
FROM (SELECT first_t.*,
1 AS src1,
to_number(NULL) AS src2
FROM first_t
UNION ALL
SELECT second_t.*,
to_number(NULL) AS src1,
2 AS src2
FROM second_t)
GROUP BY imageid,
NAME,
id
HAVING COUNT (src1) <> COUNT (src2)
UNION will return unique records on the result. If you specify ALL (UNION ALL) will keep duplicates on the result set.
SELECT column1 column2 FROM first_table
UNION
SELECT column1 column2 FROM second_table
Is there a way to union two tables, but keep the rows from the first table appearing first in the result set? However orderby column is not in select query
For example:
Table 1
name surname
-------------------
John Doe
Bob Marley
Ras Tafari
Table 2
name surname
------------------
Lucky Dube
Abby Arnold
Result
Expected Result:
name surname
-------------------
John Doe
Bob Marley
Ras Tafari
Lucky Dube
Abby Arnold
I am bringing Data by following query
SELECT name,surname FROM TABLE 1 ORDER BY ID
UNION
SELECT name,surname FROM TABLE 2
The above query is not keeping track of order by after union.
P.S - I dont want to show ID in my select query
I am getting ORDER BY Column by joining tables. Following is my real query
SELECT tbl_Event_Type_Sort_Orders.Appraisal_Event_Type_ID AS Appraisal_Event_Type_ID , ISNULL(tbl_Appraisal_Event_Types.Appraisal_Event_Type_Display_Name, 'UnCategorized') AS Appraisal_Event_Type_Display_Name
INTO #temptbl
FROM tbl_Event_Type_Sort_Orders
INNER JOIN tbl_Appraisal_Event_Types
ON tbl_Event_Type_Sort_Orders.Appraisal_Event_Type_ID = tbl_Appraisal_Event_Types.Appraisal_Event_Type_ID
WHERE 1=1
AND User_Name='abc'
ORDER BY tbl_Event_Type_Sort_Orders.Sort_Order
SELECT * FROM #temptbl
UNION
SELECT DISTINCT (tbl_Appraisal_Event_Types.Appraisal_Event_Type_ID) AS Appraisal_Event_Type_ID , ISNULL(tbl_Appraisal_Event_Types.Appraisal_Event_Type_Display_Name, 'UnCategorized') AS Appraisal_Event_Type_Display_Name
FROM tbl_Appraisal_Event_Types
INNER JOIN tbl_Appraisal_Events
ON tbl_Appraisal_Event_Types.Appraisal_Event_Type_ID = tbl_Appraisal_Events.Event_Type_ID
INNER JOIN tbl_Appraisals
ON tbl_Appraisal_Events.Appraisal_ID = tbl_Appraisal_Events.Appraisal_ID
WHERE 1=1
AND ((tbl_Appraisals.Assigned_To_Staff_User) = 'abc' OR (tbl_Appraisals.Assigned_To_Staff_User2) = 'abc' OR (tbl_Appraisals.Assigned_To_Staff_User3) = 'abc')
Put a UNION ALL in a derived table. To keep duplicate elimination, do select distinct and also add a NOT EXISTS to second select to avoid returning same person twice if found in both tables:
select name, surname
from
(
select distinct name, surname, 1 as tno
from table1
union all
select distinct name, surname, 2 as tno
from table2 t2
where not exists (select * from table1 t1
where t2.name = t1.name
and t2.surname = t1.surname)
) dt
order by tno, surname, name
You can use a column for the table and one for the ID to order by:
SELECT x.name, x.surname FROM (
SELECT ID, TableID = 1, name, surname
FROM table1
UNION ALL
SELECT ID = -1, TableID = 2, name, surname
FROM table2
) x
ORDER BY x.TableID, x.ID
You can write as below, if you are ok with duplicate data then please use UNION ALL it will be faster:
SELECT NAME, surname FROM (
SELECT ID,name,surname FROM TABLE 1
UNION
SELECT ID,name,surname FROM TABLE 2 ) t ORDER BY ID
this will order the first row sets first then by anything you need
(haven't tested the code)
;with cte_1
as
(SELECT ID,name,surname,1 as table_id FROM TABLE 1
UNION
SELECT ID,name,surname,2 as table_id FROM TABLE 2 )
SELECT name, surname
FROM cte_1
ORDER BY table_id,ID
simply use a UNION clause with out order by.
SELECT name,surname FROM TABLE 1
UNION
SELECT name,surname FROM TABLE 2
if you wanted to order first table use the below query.
;WITH cte_1
AS
(SELECT name,surname,ROW_NUMBER()OVER(ORDER BY Id)b FROM TABLE 1 )
SELECT name,surname
FROM cte_1
UNION
SELECT name,surname
FROM TABLE 2
How can I filter my results in a Query? example
I have 5 Records
John,Smith,apple
Jane,Doe,apple
Fred,James,apple
Bill,evans,orange
Willma,Jones,grape
Now I want a query that would bring me back 3 records with the DISTINCT FRUIT, BUT... and here is the tricky part, I still want the columns for First Name , Last Name. PS I do not care which of the 3 it returns mind you, but I need it to only return 3 (or what ever how many DISTINCT fruit there are.
ex return would be
John,Smith,apple
Bill,evans,orange
Willma,Jones,grape
Thanks in advance I've been banging my head on this all day.
Oddly enough, the best solution doesn't involve GROUP BY.
WITH DistinctFruit AS (
SELECT
ROW_NUMBER() OVER (PARTITION BY Fruit ORDER BY LastName) AS FruitNo,
LastName,
FirstName,
Fruit
FROM table)
SELECT FirstName, LastName, Fruit
FROM DistinctFruit
WHERE FruitNo = 1;
If you have a small amount of data (not tens of thousands of rows), you can do sub-queries.
select distinct t1.fruit as Fruit,
(select top 1 t2.lastname
from t1 as t2
where t1.fruit = t2.fruit
order by t2.lastname) as LastName,
(select top 1 t2.firstname
from t1 as t2
where t1.fruit = t2.fruit
order by t2.lastname, t2.firstname) as FirstName
from t1
Note the FirstName column is sorted the same as the LastName column. This will give you a matching last name with the correct first name.
Here is my test data:
create table t1
(firstname varchar(20),
lastname varchar(20),
fruit varchar(20))
insert into t1
values ('John','Smith','apple')
insert into t1
values ('Jane','Doe','apple')
insert into t1
values ('Fred','James','apple')
insert into t1
values ('Bill','evans','orange')
insert into t1
values ('Willma','Jones','grape')
Just another solution
select distinct x.*,fruit from t1
cross apply
(select top 1 firstname, lastname from t1 t2 where t1.fruit=t2.fruit) x
SELECT DISTINCT x.*,fruit FROM peopleFruit pf
CROSS APPLY
(SELECT TOP 1 firstname, lastname FROM peopleFruit pf1 WHERE pf.fruit=pf1.fruit) x