Query to count the frequence of many-to-many associations - sql

Question

I have two tables with a many-to-many association in postgresql. The first table contains activities, which may count zero or more reasons:
CREATE TABLE activity (
id integer NOT NULL,
-- other fields removed for readability
);
CREATE TABLE reason (
id varchar(1) NOT NULL,
-- other fields here
);
For performing the association, a join table exists between those two tables:
CREATE TABLE activity_reason (
activity_id integer NOT NULL, -- refers to activity.id
reason_id varchar(1) NOT NULL, -- refers to reason.id
CONSTRAINT activity_reason_activity FOREIGN KEY (activity_id) REFERENCES activity (id),
CONSTRAINT activity_reason_reason FOREIGN KEY (reason_id) REFERENCES reason (id)
);
I would like to count the possible association between activities and reasons. Supposing I have those records in the table activity_reason:
+--------------+------------+
| activity_id | reason_id |
+--------------+------------+
| 1 | A |
| 1 | B |
| 2 | A |
| 2 | B |
| 3 | A |
| 4 | C |
| 4 | D |
| 4 | E |
+--------------+------------+
I should have something like:
+-------+---+------+-------+
| count | | | |
+-------+---+------+-------+
| 2 | A | B | NULL |
| 1 | A | NULL | NULL |
| 1 | C | D | E |
+-------+---+------+-------+
Or, eventually, something like :
+-------+-------+
| count | |
+-------+-------+
| 2 | A,B |
| 1 | A |
| 1 | C,D,E |
+-------+-------+
I can't find the SQL query to do this.

Answer 1

I think you can get what you want using this query:
SELECT count(*) as count, reasons
FROM (
SELECT activity_id, array_agg(reason_id) AS reasons
FROM (
SELECT A.activity_id, AR.reason_id
FROM activity A
LEFT JOIN activity_reason AR ON AR.activity_id = A.activity_id
ORDER BY activity_id, reason_id
) AS ordered_reasons
GROUP BY activity_id
) reason_arrays
GROUP BY reasons
First you aggregate all the reasons for an activity into an array for each activity. You have to order the associations first, otherwise ['a','b'] and ['b','a'] will be considered different sets and will have individual counts. You also need to include the join or any activity that doesn't have any reasons won't show up in the result set. I'm not sure if that is desirable or not, I can take it back out if you want activities that don't have a reason to not be included. Then you count the number of activities that have the same sets of reasons.
Here is a sqlfiddle to demonstrate
As mentioned by Gordon Linoff you could also use a string instead of an array. I'm not sure which would be better for performance.

Answer 2

We need to compare sorted lists of reasons to identify equal sets.
SELECT count(*) AS ct, reason_list
FROM (
SELECT array_agg(reason_id) AS reason_list
FROM (SELECT * FROM activity_reason ORDER BY activity_id, reason_id) ar1
GROUP BY activity_id
) ar2
GROUP BY reason_list
ORDER BY ct DESC, reason_list;
ORDER BY reason_id in the innermost subquery would work, too, but adding activity_id is typically faster.
And we don't strictly need the innermost subquery at all. This works as well:
SELECT count(*) AS ct, reason_list
FROM (
SELECT array_agg(reason_id ORDER BY reason_id) AS reason_list
FROM activity_reason
GROUP BY activity_id
) ar2
GROUP BY reason_list
ORDER BY ct DESC, reason_list;
But it's typically slower for processing all or most of the table. Quoting the manual:
Alternatively, supplying the input values from a sorted subquery will usually work.
We could use string_agg() instead of array_agg(), and that would work for your example with varchar(1) (which might be more efficient with data type "char", btw). It can fail for longer strings, though. The aggregated value can be ambiguous.
If reason_id would be an integer (like it typically is), there is another, faster solution with sort() from the additional module intarray:
SELECT count(*) AS ct, reason_list
FROM (
SELECT sort(array_agg(reason_id)) AS reason_list
FROM activity_reason2
GROUP BY activity_id
) ar2
GROUP BY reason_list
ORDER BY ct DESC, reason_list;
Related, with more explanation:
Compare arrays for equality, ignoring order of elements
Storing and comparing unique combinations

Answer 3

You can do this using string_agg():
select reasons, count(*)
from (select activity_id, string_agg(reason_id, ',' order by reason_id) as reasons
from activity_reason
group by activity_id
) a
group by reasons
order by count(*) desc;