Can you help me answer these queries using max and min commands.
I've just started SQL and I am attempting to:
Find the lowest price of any CD
Find the number of CDs costing 11.99
Find the title of the most expensive rock CD
I'm using the min and max commands in my query but i cannot seem to get the correct queries. Below is a link to the tables that I'm referring to.
The code I have so far is:
1)SELECT cdPrice FROM `CD` order BY MIN(cdPrice)
2)
3)SELECT cdTitle FROM `CD` where cdGenre = 'Rock' AND order BY MAX(cdPrice)
Tables that I'm referring to:
#1
The lowest price of any CD is just a basic minimum select.
SELECT MIN(Price)
FROM CD
#2
We need to use a basic COUNT and where clause to get the count for that specific price.
SELECT COUNT(*)
FROM CD
WHERE Price = '11.99'
#3
With #3 we need to find the highest price. We can do this in multiple ways, the way that I would do it is with a subquery and where clause just off my head.
SELECT Title, Price
FROM CD
WHERE Price =
(
SELECT MAX(Price) FROM CD
)
1. select min(cdPrice) from CD;
2. select cdID from CD where Price=11.99;
3. select a.cdTitle, a.Price, a.cdId
from CD a
inner join (select cdId, MAX(Price) as max_p
from CD
group by Genre
having Genre = 'Rock'
) b a.cdId = b.cdId and a.Price = b.max_p;
It gets a bit complicated to get the title of the most expensive Rock CD. Here are my answers. Hope it helps.
SELECT MIN(column_name) FROM table_name
Try do homework by your self, its fast way to understand SQL.
Related
I have the following query:
SELECT DISTINCT
CAB.CODPARC,
PAR.RAZAOSOCIAL,
BAI.NOMEBAI,
SUM(VLRNOTA) AS AMOUNT
FROM TGFCAB CAB, TGFPAR PAR, TSIBAI BAI
WHERE CAB.CODPARC = PAR.CODPARC
AND PAR.CODBAI = BAI.CODBAI
AND CAB.TIPMOV = 'V'
AND STATUSNOTA = 'L'
AND PAR.CODCID = 5358
GROUP BY
CAB.CODPARC,
PAR.RAZAOSOCIAL,
BAI.NOMEBAI
Which the result is this. Company names and neighborhood hid for obvious reasons
The query at the moment, for those who don't understand Latin languages, is giving me clients, company name, company neighborhood, and the total value of movements.
in the WHERE clause it is only filtering sales movements of companies from an established city.
But if you notice in the Select statement, the column that is retuning the value that aggregates the total amount of value of sales is a SUM().
My goal is to return only the company that have the maximum value of this column, if its a tie, display both of em.
This is where i'm struggling, cause i can't seem to find a simple solution. I tried to use
WHERE AMOUNT = MAX(AMOUNT)
But as expected it didn't work
You tagged the question with the whole bunch of different databases; do you really use all of them?
Because, "PL/SQL" reads as "Oracle". If that's so, here's one option.
with temp as
-- this is your current query
(select columns,
sum(vrlnota) as amount
from ...
where ...
)
-- query that returns what you asked for
select *
from temp t
where t.amount = (select max(a.amount)
from temp a
);
You should be able to achieve the same without the need for a subquery using window over() function,
WITH T AS (
SELECT
CAB.CODPARC,
PAR.RAZAOSOCIAL,
BAI.NOMEBAI,
SUM(VLRNOTA) AS AMOUNT,
MAX(VLRNOTA) over() AS MAMOUNT
FROM TGFCAB CAB
JOIN TGFPAR PAR ON PAR.CODPARC = CAB.CODPARC
JOIN TSIBAI BAI ON BAI.CODBAI = PAR.CODBAI
WHERE CAB.TIPMOV = 'V'
AND STATUSNOTA = 'L'
AND PAR.CODCID = 5358
GROUP BY CAB.CODPARC, PAR.RAZAOSOCIAL, BAI.NOMEBAI
)
SELECT CODPARC, RAZAOSOCIAL, NOMEBAI, AMOUNT
FROM T
WHERE AMOUNT=MAMOUNT
Note it's usually (always) beneficial to join tables using clear explicit join syntax. This should be fine cross-platform between Oracle & SQL Server.
I have the following tables below and their schema:
INV
id, product code, name, ucost, tcost, desc, type, qoh
1,123,CPASS 700,1.00,5.00,CPASS 700 Lorem, COM,5
2,456,Shelf 5,2.00,6.00,Shelf 5 KJ, BR,3
GRP
id,type,desc
1,COM,COMPASS
2,BR,SHELF
Currently I have a query like this:
SELECT INV.*,GRP.DESCR AS CATEGORY
FROM INV LEFT JOIN GRP ON INV.TYPE = GRP.TYPE
WHERE INV.QOH = 0
There is no problems with that query.
Right now,I want to know the SUM of the TCOST of every INV record where their QOH is 0.
In this situation, does that I mean all I have to do is to write a separate query like the one below:
SELECT SUM(TCOST)
FROM INV
WHERE QOH = 0
Does it make any sense for me to try and combine those two queries as one ?
First understand that SUM is the aggregate function hence either you can run the Query like
(SELECT SUM(TCOST) FROM INV WHERE QOH=0) as total
This will return Sum of TCOST in INV Table for mentioned condition.
Another approach is finding the Sum based on the some column (e.g. Type)
you could write query like
SELECT Type , SUM(TCOST) FROM INV WHERE QOH=0 GROUP BY type ;
Its not clear on what criteria you want to sum . But I think above two approaches would provide you fare idea .
Mmm, you could maybe use a correlated query, though i'm not sure it's the best approach since I'm not sure I understand what your attempting to do:
SELECT INV.*,
GRP.DESCR AS CATEGORY ,
(SELECT SUM(TCOST) FROM INV WHERE QOH=0) as your_sum
FROM INV LEFT JOIN GRP ON INV.TYPE = GRP.TYPE
WHERE INV.QOH = 0
If you want only one value for the sum(), then your query is fine. If you want a new column with the sum, then use window functions:
SELECT INV.*, GRP.DESCR AS CATEGORY,
SUM(INV.TCOST) OVER () as sum_at_zero
FROM INV LEFT JOIN
GRP
ON INV.TYPE = GRP.TYPE
WHERE INV.QOH = 0;
It does not make sense to combine the queries by adding a row to the first one, because the columns are very different. A SQL result set requires that all rows have the same columns.
I have a table "Bed" and a table "Component". Between those two I have a m:n relation and the table "BedComponent", where I store the Bed-ID and the Component-ID.
Every Component has a price. And now I want to write a select-statement that gives me the sum of prices for a certain bed.
This is what I have:
SELECT Bed.idBed, Bed.name, SUM(src.price) AS summe, Bed.idCustomer
FROM Bed,
(SELECT price
FROM dbo.Component AS C
WHERE (C.idComponent IN
(SELECT idComponent
FROM dbo.BedComponent AS BC
WHERE 1 = BC.idBed))) AS src
GROUP BY dbo.Bed.idBed, dbo.Bed.name, dbo.Bed.idCustomer;
This statement works. But of course I don't want to write the bed-ID hard coded into my select as it will always calculate the price for bed 1. Instead of the "1" i want to have the current bed-id.
I work with MS SQL Server
Thanks for your help.
I think you want:
select b.idBed, b.name, SUM(src.price) AS summe, b.idCustomer
from bed b join
bedcomponent bc
on b.idBed = bc.idBed join
component c
on c.idComponent = bc.idComponent
group by b.idBed, b.name, b.idCustomer;
The idCustomer looks strange to me in the select and group by, but I don't know what you are trying to achieve.
Also note the use of table aliases, which make the query easier to write and to read.
In the query
cr is customers,
chh? ise customer_pays,
cari_kod is customer code,
cari_unvan1 is customer name
cha_tarihi is date of pay,
cha_meblag is pay amount
The purpose of query, the get the specisified list of customers and their last date for pay and amount of money...
Actually my manager needs more details but the query is very slow and that is why im using only 3 subquery.
The question is how to combine them ?
I have researched about Cte and "with clause" and "subquery in "where " but without luck.
Can anybody have a proposal.
Operating system is win2003 and sql server version is mssql 2005.
Regards
select cr.cari_kod,cr.cari_unvan1, cr.cari_temsilci_kodu,
(select top 1
chh1.cha_tarihi
from dbo.CARI_HESAP_HAREKETLERI chh1 where chh1.cha_kod=cr.cari_kod order by chh1.cha_RECno) as sontar,
(select top 1
chh2.cha_meblag
from dbo.CARI_HESAP_HAREKETLERI chh2 where chh2.cha_kod=cr.cari_kod order by chh2.cha_RECno) as sontutar
from dbo.CARI_HESAPLAR cr
where (select top 1
chh3.cha_tarihi
from dbo.CARI_HESAP_HAREKETLERI chh3 where chh3.cha_kod=cr.cari_kod order by chh3.cha_RECno) >'20130314'
and
cr.cari_bolge_kodu='322'
or
cr.cari_bolge_kodu='324'
order by cr.cari_kod
You will probably speed up the query by changing your last where clause to:
where (select top 1 chh3.cha_tarihi
from dbo.CARI_HESAP_HAREKETLERI chh3 where chh3.cha_kod=cr.cari_kod
order by chh3.cha_RECno
) >'20130314' and
cr.cari_bolge_kodu in ('322', '324')
order by cr.cari_kod
Assuming that you want both the date condition met and one of the two codes. Your original logic is the (date and code = 322) OR (code = 324).
The overall query can be improved by finding the record in the chh table and then just using that. For this, you want to use the window function row_number(). I think this is the query that you want:
select cari_kod, cari_unvan1, cari_temsilci_kodu,
cha_tarihi, cha_meblag
from (select cr.*, chh.*,
ROW_NUMBER() over (partition by chh.cha_kod order by chh.cha_recno) as seqnum
from dbo.CARI_HESAPLAR cr join
dbo.CARI_HESAP_HAREKETLERI chh
on chh.cha_kod=cr.cari_kod
where cr.cari_bolge_kodu in ('322', '324')
) t
where chh3.cha_tarihi > '20130314' and seqnum = 1
order by cr.cari_kod;
This version assumes the revised logic date/code logic.
The inner subquery select might generate an error if there are two columns with the same name in both tables. If so, then just list the columns instead of using *.
I need to get a max of the values from two columns from different tables.
eg the max of suburbs from schoolorder and platterorder. platterorder has clientnumbers that links to normalclient, and schoolorder has clientnumbers that links to school.
I have this:
SELECT MAX (NC.SUBURB) AS SUBURB
FROM normalClient NC
WHERE NC.CLIENTNO IN
(SELECT PO.CLIENTNO
FROM platterOrder PO
WHERE NC.CLIENTNO = PO.CLIENTNO)
GROUP BY NC.SUBURB
UNION
SELECT MAX (S.SUBURB) AS SCHOOLSUBURB
FROM school S
WHERE S.CLIENTNO IN
(SELECT S.CLIENTNO
FROM schoolOrder SO
WHERE S.CLIENTNO = SO.CLIENTNO)
GROUP BY S.SUBURB)
However that gets the max from platter order and joins it with the max of school. what I need is the max of both of them together.
=================================================
sorry for making this so confusing!
the output should only be one row.
it should be the suburb where the maxmimum orders have come from for both normal client and school clients. the orders are listed in platter order for normal clients, and school order for school clients. so it's the maximum value for two table's that don't have a direct relation.
hope that clears it up a bit !
If I'm understanding your question correctly, you don't need to use a GROUP BY since you're wanting the MAX of the field. I've also changed your syntax to use a JOIN instead of IN, but the IN should work just the same:
SELECT MAX (NC.SUBURB) AS SUBURB
FROM normalClient NC
JOIN platterOrder PO ON NC.ClientNo = PO.ClientNo
UNION
SELECT MAX (S.SUBURB) AS SCHOOLSUBURB
FROM school S
JOIN schoolOrder SO ON S.CLIENTNO = SO.CLIENTNO
Withouth knowing your table structures and seeing sample data, the best way I can recommend getting the MAX of results from the UNION is to use a subquery. There may be a better way with JOINs, but it's difficult to infer from your question:
SELECT MAX(Suburb)
FROM (
SELECT MAX (NC.SUBURB) AS SUBURB
FROM normalClient NC
JOIN platterOrder PO ON NC.ClientNo = PO.ClientNo
UNION
SELECT MAX (S.SUBURB)
FROM school S
JOIN schoolOrder SO ON S.CLIENTNO = SO.CLIENTNO
) T