Suppose I have the following table 'player' in oracle database:
P_ID P_NAME C_ID DEBUT MATCH RUNS
101 amla 204 2003 190 5000
102 mushi 200 2001 240 7500
103 sakib 200 1999 150 5000
104 ricky 205 1993 180 7000
105 sachin 203 1990 250 8000
106 yuvi 203 1999 150 6900
I need a query to display the c_id, total runs done by all batsmen of the country which has the maximum run scorer. (in this case maximum run scorer is
sachin. so the query should return : c_id = 203, runs = 14900).
I have only been able to find the maximum run scorer and the country which he belongs to. the query:
select c_id, runs from player where runs = (select max(runs) from player);
does that. However, I am not been able to proceed further.
When you need condition on aggregate function, you must use sub-query or having clause.
This return always one row, but it's wrong when more then one groups have same total:
SELECT *
FROM (
SELECT c_id, Sum(runs) total
FROM player
GROUP BY c_id
ORDER BY total DESC
) WHERE ROWNUM =1;
But you can get all using this:
SELECT c_id, Sum(runs) total
FROM player
GROUP BY c_id
HAVING Sum(runs) = (
SELECT Max(t) from (
SELECT Sum(runs) t
FROM player
GROUP BY c_id))
;
Related
I was hoping to find the sum from two tables with columns ID and Amount, grouping by ID.
My first attempt was to UNION the two tables first and then conduct a sum and group by, but I was hoping to know of a better way.
Inputs:
Table 1
ID Amount
123 100
123 100
145 500
167 600
Table 2
ID Amount
123 100
123 100
145 500
199 600
Output
ID Amount
123 400
145 1000
167 600
199 600
You can do:
select id, sum(amount) as amount
from (
select id, amount from table_1
union all
select id, amount from table_2
) x
group by id
Below is the table where I have customer_id and different phones they have.
customer_id phone_number
101 123456789
102 234567891
103 345678912
102 456789123
101 567891234
104 678912345
105 789123456
106 891234567
106 912345678
106 456457234
101 655435664
107 453426782
Now, I want to find customer_id and distinct phone number count.
So I used this query:
select distinct customer_id ,count(distinct phone_number)
from customer_phone;
customer_id no of phones
101 3
102 2
103 1
104 1
105 1
106 3
107 1
And, from the above table my final goal is to achieve the below output which takes the counts and puts in different buckets and then count number of consumers that fall in those buckets.
Buckets no of consumers
3 2
2 1
1 4
There are close to 200 million records. Can you please explain an efficient way to work on this?
You can use width_bucket for that:
select bucket, count(*)
from (
select width_bucket(count(distinct phone_number), 1, 10, 10) as bucket
from customer_phone
group by customer_id
) t
group by bucket;
width_bucket(..., 1, 10, 10) creates ten buckets for the values 1 through 10.
Online Example: http://dbfiddle.uk/?rdbms=oracle_11.2&fiddle=1e6d55305570499f363837aba21bdc7e
Use two aggregations:
select cnt, count(*), min(customer_id), max(customer_id)
from (select customer_id, count(distinct phone_number) as cnt
from customer_phone
group by customer_id
) c
group by cnt
order by cnt;
I have a requirement to calculate rolling compound interest on several accounts in pl/sql. I was looking for help/advice on how to script calculate these calculations. The calculations I need are in the last two columns of the output below (INTERESTAMOUNT AND RUNNING TOTAL). I found similar examples of this on here, but nothing specifically fitting these requirements in pl/sql. I am also new to CTE/Recursive Techniques and the Model technique I found required a specific iteration which would be variable in this case. Please see my problem below:
Calculations:
INTERESTAMOUNT = (Previous Year RUNNING TOTAL+ Current Year AMOUNT) * INTEREST_RATE
RUNNINGTOTAL = (Previous Year RUNNING TOTAL+ Current Year AMOUNT) * (1 + INTEREST_RATE) - CURRENT YEAR EXPENSES
Input Table:
YEAR ACCT_ID AMOUNT INTEREST_RATE EXPENSES
2002 1 1000 0.05315 70
2003 1 1500 0.04213 80
2004 1 800 0.03215 75
2005 1 950 0.02563 78
2000 2 750 0.07532 79
2001 2 600 0.06251 75
2002 2 300 0.05315 70
Desired Output:
YEAR ACCT_ID AMOUNT INTEREST_RATE EXPENSES INTERESTAMOUNT RUNNINGTOTAL
2002 1 1000 0.05315 70 53.15 983.15
2003 1 1500 0.04213 80 104.62 2507.77
2004 1 800 0.03215 75 106.34 3339.11
2005 1 950 0.02563 78 109.93 4321.04
2000 2 750 0.07532 79 56.49 727.49
2001 2 600 0.06251 75 82.98 1335.47
2002 2 300 0.05315 70 86.93 1652.4
One way to do it is with a recursive cte.
with rownums as (select t.*
,row_number() over(partition by acct_id order by yr) as rn
from t) -- t is your tablename
,cte(rn,yr,acct_id,amount,interest_rate,expenses,running_total,interest_amount) as
(select rn,yr,acct_id,amount,interest_rate,expenses
,(amount*(1+interest_rate))-expenses
,amount*interest_rate
from rownums
where rn=1
union all
select t.rn,t.yr,t.acct_id,t.amount,t.interest_rate,t.expenses
,((c.running_total+t.amount)*(1+t.interest_rate))-t.expenses
,(c.running_total+t.amount)*t.interest_rate
from cte c
join rownums t on t.acct_id=c.acct_id and t.rn=c.rn+1
)
select * from cte
Sample Demo
Generate row numbers using row_number function
Calculate the interest and running total of the first row for each acct_id (anchor in the recursive cte).
Join every row to the next one (ordered by ascending order of year column) for each account_id and compute the running total and interest for the subsequent rows.
The following is the code snippet.
Just design purpose I have added.
Here The user will be assigned multiple group.
So I want to select the person details alone.
Here Person id 103 have two different persmission for the same Product.
But the higher permission only be selected for the person.
But if he is not assinged to multiple group, the default permission should be selected.
Sample data
ProdId PersonId GroupId Permission
10103 78 55 15
10103 99 33 15
10103 100 33 0
10103 103 33 15
10103 103 40 0
10103 112 33 15
Result data should be
ProdId PersonId Permission
10103 78 15
10103 99 15
10103 100 0
10103 103 15
10103 112 15
You should use ROW_NUMBER() :
SELECT * FROM (
SELECT t.*,
ROW_NUMBER() OVER(PARTITION BY t.prodid,t.personID ORDER BY t.permission DESC) as rnk
FROM YourTable t) s
WHERE s.rnk = 1
I assumed you want the highest number on permission by your example? If not, change the ORDER BY clause to what you want.
Right now it will select all columns, specify the ones you want.
If you are using Oracle, try the below query..
select * from (
select ProdID, PersonID, Permission, row_number() over (partition by PersonID order by Permission Desc) as column1 from table1)
where column1 = 1;
Here is the code:
SELECT * FROM COMPANY WHERE SALARY > 40000;
4 Mark 25 Rich-Mond 65000.0
5 David 27 Texas 85000.0
6 Kim 22 South-Hall 45000.0
8 Kitos 31 90000.0
SELECT * FROM COMPANY
WHERE AGE < (SELECT AGE FROM COMPANY WHERE SALARY > 40000);
3 Teddy 23 Norway 20000.0
6 Kim 22 South-Hall 45000.0
7 James 24 Houston 10000.0
How does this work when there are multiple row returned from the sub-query? In this example I would expect the last query to produce employees younger than 22 (minimum from the sub-query), apparently it doesn't work that way.
Most databases will raise an error if the subquery does not return exactly one result. SQLite doesn't, but just uses the first returned row (or NULL) (there is an implied LIMIT 1).
The order of SELECT results is not guaranteed without an ORDER BY, so the result will be random.
If you want to use some specific record, you must ensure that you SELECT returns exactly that record, typically using MIN/MAX, or with ORDER BY:
SELECT ...
FROM Company
WHERE Age < (SELECT MIN(Age)
FROM Company
WHERE Salary > 40000);
SELECT ...
FROM Company
WHERE Age < (SELECT Age
FROM Company
WHERE Salary > 40000
ORDER BY Age
LIMIT 1);
It is also possible to use a correlated subquery, which can return a different result for each row in the outer query:
SELECT ...
FROM Company
WHERE Age < (SELECT Age
FROM Company AS C2
WHERE C2.ID = Company.ManagerID);