I have a column (XID) that contains a varchar(20) sequence in the following format: xxxzzzzzz Where X is any letter or a dash and zzzzz is a number.
I want to write a query that will strip the xxx and evaluate and return which is the highest number in the table column.
For example:
aaa1234
bac8123
g-2391
After, I would get the result of 8123
Thanks!
A bit painful in SQL Server, but possible. Here is one method that assumes that only digits appear after the first digit (which you actually specify as being the case):
select max(cast(stuff(col, 1, patindex('%[0-9]%', col) - 1, '') as float))
from t;
Note: if the last four characters are always the number you are looking for, this is probably easier to do with right():
select max(right(col, 4))
Using Numbers table
declare #string varchar(max)
set #string='abc1234'
select top 1 substring(#string,n,len(#string))
from
numbers
where n<=len(#string)
and isnumeric(substring(#string,n,1))=1
order by n
Output:1234
Using PATINDEX you can achieve it, like this -
DECLARE #test table
(
id INT,
player varchar(100)
)
INSERT #test
VALUES (1,'aaa1234'),
(2,'bac8123'),
(3,'g-2391')
SELECT
MAX(CONVERT(INT, LTRIM(SUBSTRING(player, PATINDEX('%[0-9]%', player), LEN(player)))))
FROM #test
Try:
Select MAX(RIGHT(XID,17))
from table
You can also use this method
CREATE TABLE #Tmp
(
XID VARCHAR(20)
)
INSERT INTO #Tmp(XID)
VALUES ('aaa1234'), ('bac8123'), ('g-2391')
SELECT MAX(RIGHT(XID, LEN(XID) - 3))
FROM #Tmp
Related
Values in Column are in format Name_city_age_ID (underscore separated).
Age was always blank. Other values may or not be blank. So values in column are like:
John_London__1223,
Mary_Paris__,
Dave____,
Smith____1012,
___2334
Now I have the age as 22 for all rows & I want to replace all values in the column, So the new columns should be:
John_London_22_1223,
Mary_Paris_22_,
Dave__22_,
Smith__22_1012,
__22_2334,
How to write the update query for this?
Using STUFF, but you should really normalize your data. This looks for the second instance of _ and adds 22.
declare #table table(col varchar(64))
insert into #table
values
('John_London__1223'),
('Mary_Paris__'),
('Dave____'),
('Smith____1012'),
('___2334')
select * from #table
--update the column
update #table
set col = stuff(col,charindex('_',col) + charindex('_',right(col,len(col) - charindex('_',col))) + 1,0,'22')
--see the results
select * from #table
Calling CHARINDEX function twice should do it. The following is the SELECT query for reviewing results, convert to UPDATE:
SELECT
str,
STUFF(str, CHARINDEX('_', str, CHARINDEX('_', str) + 1) + 1, 0, '22') AS newstr
FROM testdata
SQL Fiddle
I have a conundrum....
There is a table with one NVARCHAR(50) Float column that has many rows with many numbers of various decimal lengths:
'3304.063'
'3304.0625'
'39.53'
'39.2'
I need to write a query to find only numbers with decimal places >= 4
First the query I wrote was:
SELECT
Column
FROM Tablename
WHERE Column LIKE '%.[0-9][0-9]%'
The above code finds all numbers with decimal places >= 2:
'3304.063'
'3304.0625'
'39.53'
Perfect! Now, I just need to increase the [0-9] by 2...
SELECT
Column
FROM Tablename
WHERE Column LIKE '%.[0-9][0-9][0-9][0-9]%'
this returned nothing! What?
Does anyone have an explanation as to what went wrong as well and/or a possible solution? I'm kind of stumped and my hunch is that it is some sort of 'LIKE' limitation..
Any help would be appreciated!
Thanks.
After your edit, you stated you are using FLOAT which is an approximate value stored as 4 or 8 bytes, or 7 or 15 digits of precision. The documents explicitly state that not all values in the data type range can be represented exactly. It also states you can use the STR() function when converting it which you'll need to get your formatting right. Here is how:
declare #table table (columnName float)
insert into #table
values
('3304.063'),
('3304.0625'),
('39.53'),
('39.2')
--see the conversion
select * , str(columnName,20,4)
from #table
--now use it in a where clause.
--Return all values where the last digit isn't 0 from STR() the conversion
select *
from #table
where right(str(columnName,20,4),1) != 0
OLD ANSWER
Your LIKE statement would do it, and here is another way just to show they both work.
declare #table table (columnName varchar(64))
insert into #table
values
('3304.063'),
('3304.0625'),
('39.53'),
('39.2')
select *
from #table
where len(right(columnName,len(columnName) - charindex('.',columnName))) >= 4
select *
from #table
where columnName like '%.[0-9][0-9][0-9][0-9]%'
One thing that could be causing this is a space in the number somewhere... since you said the column type was VARCHAR this is a possibility, and could be avoided by storing the value as DECIMAL
declare #table table (columnName varchar(64))
insert into #table
values
('3304.063'),
('3304. 0625'), --notice the space here
('39.53'),
('39.2')
--this would return nothing
select *
from #table
where columnName like '%.[0-9][0-9][0-9][0-9]%'
How to find out if this is the case?
select *
from #table
where columnName like '% %'
Or, anything but numbers and decimals:
select *
from #table
where columnName like '%[^.0-9]%'
The following is working fine for me:
declare #tab table (val varchar(50))
insert into #tab
select '3304.063'
union select '3304.0625'
union select '39.53'
union select '39.2'
select * from #tab
where val like '%.[0-9][0-9][0-9][0-9]%'
Assuming your table only has numerical data, you can cast them to decimal and then compare:
SELECT COLUMN
FROM tablename
WHERE CAST(COLUMN AS DECIMAL(19,4)) <> CAST(COLUMN AS DECIMAL(19,3))
You'd want to test the performance of this against using the character data type solutions that others have already suggested.
You can use REVERSE:
declare #vals table ([Val] nvarchar(50))
insert into #vals values ('3304.063'), ('3304.0625'), ('39.53'), ('39.2')
select [Val]
from #Vals
where charindex('.',reverse([Val]))>4
i have written a query in which i am fetching an amount which is a number like '50,000','80,000'.
select Price_amount
from per_prices
As these values contain ',' these are considered to be varchar.Requirement is to to print these as 'number' with ','
that is how can '50,000' be considered as number and not varchar
If a value has anything other than numbers in it, it is not an integer it is string containing characters. in your case you have a string containing character 5, 0 and ,.
If this is what is stored in your database and this is what you want to display then go ahead you do not need to change it to Integer or anything else. But if you are doing some calculations on these values before displaying them, Yes then you need to change them to an Integer values. do the calculation. Change them back to the varchar datatype to show , between thousands and hundred thousands and display/select them.
Example
DECLARE #TABLE TABLE (ID INT, VALUE VARCHAR(100))
INSERT INTO #TABLE VALUES
(1, '100,000'),(2, '200,000'),(3, '300,000'),(4, '400,000'),
(1, '100,000'),(2, '200,000'),(3, '300,000'),(4, '400,000')
SELECT ID, SUM(
CAST(
REPLACE(VALUE, ',','') --<-- Replace , with empty string
AS INT) --<-- Cast as INT
) AS Total --<-- Now SUM up Integer values
FROM #TABLE
GROUP BY ID
SQL Fiddle
you could combine the Replace and cast function
SELECT CAST(REPLACE(Price_amount, ',', '') AS int) AS Price_Number FROM per_prices
for more information visit 'replace', 'cast'
SQLFiddle
I am trying to match data from an external source to an in house source. For example one table would have a field with a value of "black blue" and another table would have a field with a value of "blue black". I am trying to figure out how to check if all individual words in the first table are contained in a record the 2nd table in any order. It's not always two words that need to be compared it could be 3 or 4 as well. I know I could use a cursor and build dynamic sql substituting the space with the AND keywod and using the contains function but I'm hoping not to have to do that.
Any help would be much appreciated.
Try doing something like this: Split the data from the first table on the space into a temporary table variable. Then use CHARINDEX to determine if each word is contained in the second table's record. Then just do this for each word in the first record and if the count is the same as the successful checks then you know every word from the first record is used in the second.
Edit: Use a Split function such as:
CREATE FUNCTION dbo.Split (#sep char(1), #s varchar(512))
RETURNS table
AS
RETURN (
WITH Pieces(pn, start, stop) AS (
SELECT 1, 1, CHARINDEX(#sep, #s)
UNION ALL
SELECT pn + 1, stop + 1, CHARINDEX(#sep, #s, stop + 1)
FROM Pieces
WHERE stop > 0
)
SELECT pn,
SUBSTRING(#s, start, CASE WHEN stop > 0 THEN stop-start ELSE 512 END) AS s
FROM Pieces
)
Here's another method you could try, you could sample some simple attributes of your strings such as, length, number of spaces, etc.; then you could use a cross-join to create all of the possible string match combinations.
Then within your where-clause you can sort by matches, the final piece of which in this example is a check using the patindex() function to see if the sampled piece of the first string is in the second string.
-- begin sample table variable set up
declare #s table(
id int identity(1,1)
,string varchar(255)
,numSpace int
,numWord int
,lenString int
,firstPatt varchar(255)
);
declare #t table(
id int identity(1,1)
,string varchar(255)
,numSpace int
,numWord int
,lenString int
);
insert into #t(string)
values ('my name');
insert into #t(string)
values ('your name');
insert into #t(string)
values ('run and jump');
insert into #t(string)
values ('hello my name is');
insert into #s(string)
values ('name my');
insert into #s(string)
values ('name your');
insert into #s(string)
values ('jump and run');
insert into #s(string)
values ('my name is hello');
update #s
set numSpace = len(string)-len(replace(string,' ',''));
update #s
set numWord = len(string)-len(replace(string,' ',''))+1;
update #s
set lenString = len(string);
update #s
set firstPatt = rtrim(substring(string,1,charindex(' ',string,0)));
update #t
set numSpace = len(string)-len(replace(string,' ',''));
update #t
set numWord = len(string)-len(replace(string,' ',''))+1;
update #t
set lenString = len(string);
-- end sample table variable set up
-- select all combinations of strings using a cross join
-- and sort the entries in your where clause
-- the pattern index checks to see if the sampled string
-- from the first table variable is in the second table variable
select *
from
#s s cross join #t t
where
s.numSpace = t.numspace
and s.numWord = t.numWord
and s.lenString = t.lenString
and patindex('%'+s.firstPatt+'%',t.string)>0;
I have a row of strings that are in the following format:
'Order was assigned to lastname,firsname'
I need to cut this string down into just the last and first name but it is always a different name for each record.
The 'Order was assigned to' part is always the same.......
Thanks
I am using SQL Server. It is multiple records with different names in each record.
In your specific case you can use something like:
SELECT SUBSTRING(str, 23) FROM table
However, this is not very scalable, should the format of your strings ever change.
If you are using an Oracle database, you would want to use SUBSTR instead.
Edit:
For databases where the third parameter is not optional, you could use SUBSTRING(str, 23, LEN(str))
Somebody would have to test to see if this is better or worse than subtraction, as in Martin Smith's solution but gives you the same result in the end.
In addition to the SUBSTRING methods, you could also use a REPLACE function. I don't know which would have better performance over millions of rows, although I suspect that it would be the SUBSTRING - especially if you were working with CHAR instead of VARCHAR.
SELECT REPLACE(my_column, 'Order was assigned to ', '')
For SQL Server
WITH testData AS
(
SELECT 'Order was assigned to lastname,firsname' as Col1 UNION ALL
SELECT 'Order was assigned to Bloggs, Jo' as Col1
)
SELECT SUBSTRING(Col1,23,LEN(Col1)-22) AS Name
from testData
Returns
Name
---------------------------------------
lastname,firsname
Bloggs, Jo
on MS SQL Server:
declare #str varchar(100) = 'Order was assigned to lastname,firsname'
declare #strLen1 int = DATALENGTH('Order was assigned to ')
declare #strLen2 int = len(#str)
select #strlen1, #strLen2, substring(#str,#strLen1,#strLen2),
RIGHT(#str, #strlen2-#strlen1)
I would require that a colon or some other delimiter be between the message and the name.
Then you could just search for the index of that character and know that anything after it was the data you need...
Example with format changing over time:
CREATE TABLE #Temp (OrderInfo NVARCHAR(MAX))
INSERT INTO #Temp VALUES ('Order was assigned to :Smith,Mary')
INSERT INTO #Temp VALUES ('Order was assigned to :Holmes,Larry')
INSERT INTO #Temp VALUES ('New Format over time :LootAt,Me')
SELECT SUBSTRING(OrderInfo, CHARINDEX(':',OrderInfo)+1, LEN(OrderInfo))
FROM #Temp
DROP TABLE #Temp