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I have start date, end date and name of days. How can fetch all dates between those two dates of that specific days in sql?
example data:
start_date:4/11/2018
end_date: 5/11/2018
days: monday, thursday
expected output: all dates between start and end date which comes on monday and thursday and store them in table
updated
my present code(not working)
; WITH CTE(dt)
AS
(
SELECT #P_FROM_DATE
UNION ALL
SELECT DATEADD(dw, 1, dt) FROM CTE
WHERE dt < #P_TO_DATE
)
INSERT INTO Table_name
(
ID
,DATE_TIME
,STATUS
,CREATED_DATE
,CREATED_BY
)
SELECT #P_ID
,(SELECT dt FROM CTE WHERE DATENAME(dw, dt) In ('tuesday','friday',null))
,'NOT SENT'
,CAST(GETDATE() AS DATE)
,#USER_ID
Another approach for generating dates between ranges can be like following query. This will be faster compared to CTE or WHILE loop.
DECLARE #StartDate DATETIME = '2018-04-11'
DECLARE #EndDate DATETIME = '2018-05-15'
SELECT #StartDate + RN AS DATE FROM
(
SELECT (ROW_NUMBER() OVER (ORDER BY (SELECT NULL)))-1 RN
FROM master..[spt_values] T1
) T
WHERE RN <= DATEDIFF(DAY,#StartDate,#EndDate)
AND DATENAME(dw,#StartDate + RN) IN('Monday','Thursday')
Note:
If the row count present in master..[spt_values] is not sufficient for the provided range, you can make a cross join with the same to get a bigger range like following.
SELECT (ROW_NUMBER() OVER (ORDER BY (SELECT NULL)))-1 RN
FROM master..[spt_values] T1
CROSS JOIN master..[spt_values] T2
By this you will be able to generate date between a range with gap of 6436369 days.
You can use a recursive common table expression (CTE) to generate a list of days. With datepart(dw, ...) you can filter for specific days of the week.
An example that creates a list of Mondays and Thursdays between March 1st and today:
create table ListOfDates (dt date);
with cte as
(
select cast('2018-03-01' as date) as dt -- First day of interval
union all
select dateadd(day, 1, dt)
from cte
where dt < getdate() -- Last day of interval
)
insert into ListOfDates
(dt)
select dt
from cte
where datepart(dw, dt) in (2, 5) -- 2=Monday and 5=Thursday
option (maxrecursion 0)
See it working at SQL Fiddle.
This will work for you:
DECLARE #table TABLE(
ID INT IDENTITY(1,1),
Date DATETIME,
Day VARCHAR(50)
)
DECLARE #Days TABLE(
ID INT IDENTITY(1,1),
Day VARCHAR(50)
)
INSERT INTO #Days VALUES ('Monday')
INSERT INTO #Days VALUES ('Thursday')
DECLARE #StartDate DATETIME='2018-01-01';
DECLARE #EndDate DATETIME=GETDATE();
DECLARE #Day VARCHAR(50)='Friday';
DECLARE #TempDate DATETIME=#StartDate;
WHILE CAST(#TempDate AS DATE)<=CAST(#EndDate AS DATE)
BEGIN
IF EXISTS (SELECT 1 FROM #Days WHERE DAY IN (DATENAME(dw,#TempDate)))
BEGIN
INSERT INTO #table
VALUES (
#TempDate, -- Date - datetime
DATENAME(dw,#TempDate) -- Day - varchar(50)
)
END
SET #TempDate=DATEADD(DAY,1,#TempDate)
END
SELECT * FROM #table
INSERT INTO TargetTab(dateCOL)
SELECT dateCOL
FROM tab
WHERE dateCOL >= startdate AND dateCOL <= enddate
AND (DATENAME(dw,dateCOL) ='Thursday' OR DATENAME(dw,dateCOL) = 'Monday')
Try this query to get your result.
Use a recursive CTE to generate your dates, then filter by week day.
SET DATEFIRST 1 -- 1: Monday, 7 Sunday
DECLARE #StartDate DATE = '2018-04-11'
DECLARE #EndDate DATE = '2018-05-15'
DECLARE #WeekDays TABLE (WeekDayNumber INT)
INSERT INTO #WeekDays (
WeekDayNumber)
VALUES
(1), -- Monday
(4) -- Thursday
;WITH GeneratingDates AS
(
SELECT
GeneratedDate = #StartDate,
WeekDay = DATEPART(WEEKDAY, #StartDate)
UNION ALL
SELECT
GeneratedDate = DATEADD(DAY, 1, G.GeneratedDate),
WeekDay = DATEPART(WEEKDAY, DATEADD(DAY, 1, G.GeneratedDate))
FROM
GeneratingDates AS G -- Notice that we are referencing a CTE that we are also declaring
WHERE
G.GeneratedDate < #EndDate
)
SELECT
G.GeneratedDate
FROM
GeneratingDates AS G
INNER JOIN #WeekDays AS W ON G.WeekDay = W.WeekDayNumber
OPTION
(MAXRECURSION 30000)
Try this:
declare #start date = '04-11-2018'
declare #end date = '05-11-2018'
declare #P_ID int = 1
declare #USER_ID int = 11
;with cte as(
select #start [date]
union all
select dateadd(DAY, 1, [date]) from cte
where [date] < #end
)
--if MY_TABLE doesn't exist
select #P_ID,
[date],
'NOT SENT',
cast(getdate() as date),
#USER_ID
into MY_TABLE
from cte
--here you can specify days: 1 - Sunday, 2 - Monday, etc.
where DATEPART(dw,[date]) in (2, 5)
option (maxrecursion 0)
--if MY_TABLE does exist
--insert into MY_TABLE
--select #P_ID,
-- [date],
-- 'NOT SENT',
-- cast(getdate() as date),
-- #USER_ID
--from cte
--where DATEPART(dw,[date]) in (2, 5)
--option (maxrecursion 0)
Is it possible to do in SQL: for example I have period where #s_date = '20130101' and #e_date = '20130601' and I want to select all last days of months in this period.
This is example of result:
20130131
20130228
20130331
20130430
20130531
Thanks.
The easiest option is to have a calendar table, with a last day of the month flag, so your query would simply be:
SELECT *
FROM dbo.Calendar
WHERE Date >= #StartDate
AND Date <= #EndDate
AND EndOfMonth = 1;
Assuming of course that you don't have a calendar table you can generate a list of dates on the fly:'
DECLARE #s_date DATE = '20130101',
#e_date DATE = '20130601';
SELECT Date = DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY Object_ID) - 1, #s_date)
FROM sys.all_objects;
Then once you have your dates you can limit them to where the date is the last day of the month (where adding one day makes it the first of the month):
DECLARE #s_date DATE = '20130101',
#e_date DATE = '20130601';
WITH Dates AS
( SELECT Date = DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY Object_ID) - 1, #s_date)
FROM sys.all_objects
)
SELECT *
FROM Dates
WHERE Date <= #e_Date
AND DATEPART(DAY, DATEADD(DAY, 1, Date)) = 1;
Example on SQL Fiddle
You can run the following query and then adjust it by using your table details:
declare #s_date as datetime= '20130101'
declare #e_date as datetime= '20131020'
SELECT DateAdd(m, number, '1990-01-31')
FROM master.dbo.spt_values
WHERE 'P' = type
AND DateAdd(m, number, #s_date) < #e_date
example for 20130101 :
select CONVERT(VARCHAR(8),
dateadd(day, -1, dateadd(month, 1,
convert(datetime, '20130101',112))), 112)
result :
20130131
Try this query
WITH sample
AS (SELECT Cast('2013-04-01' AS DATETIME) Date
UNION ALL
SELECT Dateadd(day, 1, date) dt
FROM sample
WHERE date < Cast('2013-05-05' AS DATETIME))
SELECT *
FROM sample
Fiddle
EOMONTH(#date) is the function you need.
Here is the help page https://learn.microsoft.com/en-us/sql/t-sql/functions/eomonth-transact-sql?view=sql-server-2017
This query gets the las 50 End Of Months.
The original query used as an example is from here.
https://dba.stackexchange.com/a/186829
WITH cte AS
(
SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) - 1 AS [Incrementor]
FROM [master].[sys].[columns] sc1
CROSS JOIN [master].[sys].[columns] sc2
)
SELECT top 50 EOMONTH(DATEADD(Month, -1 * cte.[Incrementor], GETDATE()))
FROM cte
WHERE EOMONTH(DATEADD(Month, -1 * cte.[Incrementor], GETDATE())) < GETDATE();
I tried but could not get the right solution. I want an SQL query that lists all the weekend dates of the current year.
I tried this SQL query:
WITH hier(num, lvl) AS (
SELECT 0, 1
UNION ALL
SELECT 100, 1
UNION ALL
SELECT num + 1, lvl + 1
FROM hier
WHERE lvl < 100
)
SELECT lvl [Week],
convert(date,DATEADD(dw, -DATEPART(dw, DATEADD(wk,DATEDIFF(wk,0,'12/31/'+convert(nvarchar,YEAR(getdate()))), 0)+6 ),
DATEADD(wk, DATEDIFF(wk,0,'12/31/'+convert(nvarchar,YEAR(getdate()))), 0)+6 ) - num * 7,101) [End Date]
FROM hier a
where num < 52
ORDER BY [End Date] asc
Its output is like this:
Week End date
52 2012-01-14
51 2012-01-21
50 2012-01-28
49 2012-02-04
I want the dates to start from the beginning – so, the above is missing one weekend, which is 2012-07-01. Also, I want the week numbers to show as 1, 2, 3... instead of 52, 51....
Check out this blog post.
Your question is explained in detail.
DECLARE #Year AS INT,
#FirstDateOfYear DATETIME,
#LastDateOfYear DATETIME
-- You can change #year to any year you desire
SELECT #year = 2010
SELECT #FirstDateOfYear = DATEADD(yyyy, #Year - 1900, 0)
SELECT #LastDateOfYear = DATEADD(yyyy, #Year - 1900 + 1, 0)
-- Creating Query to Prepare Year Data
;WITH cte AS (
SELECT 1 AS DayID,
#FirstDateOfYear AS FromDate,
DATENAME(dw, #FirstDateOfYear) AS Dayname
UNION ALL
SELECT cte.DayID + 1 AS DayID,
DATEADD(d, 1 ,cte.FromDate),
DATENAME(dw, DATEADD(d, 1 ,cte.FromDate)) AS Dayname
FROM cte
WHERE DATEADD(d,1,cte.FromDate) < #LastDateOfYear
)
SELECT FromDate AS Date, Dayname
FROM CTE
WHERE DayName IN ('Saturday','Sunday') -- For Weekend
/*
WHERE DayName LIKE 'Sunday'
WHERE DayName NOT IN ('Saturday','Sunday') -- For Weekday
WHERE DayName LIKE 'Monday' -- For Monday
WHERE DayName LIKE 'Sunday' -- For Sunday
*/
OPTION (MaxRecursion 370)
Will this help
DECLARE #startDate DATETIME, #endDate DATETIME
SELECT #startDate = '2012-01-01', #endDate = '2012-12-31'
;WITH Calender AS (
SELECT #startDate AS dt
UNION ALL
SELECT dt + 1 FROM Calender
WHERE dt + 1 <= #endDate
)
SELECT
dt
,NameMonth = DATENAME(Month, dt)
,NameDay = DATENAME (Weekday,dt)
,WeekofYr = DATEPART(WEEK, dt) FROM Calender
WHERE DATENAME (Weekday,dt) IN ('Sunday')
Option(MaxRecursion 0)
Result(Partial)
dt NameMonth NameDay WeekofYr
2012-01-01 00:00:00.000 January Sunday 1
2012-01-08 00:00:00.000 January Sunday 2
...............................................
...............................................
2012-12-30 00:00:00.000 December Sunday 53
you can try this
DECLARE #FirstDateOfYear DATETIME
SET #FirstDateOfYear = ’2010-01-01′
SELECT DISTINCT DATEADD(d, number, #FirstDateOfYear),
CASE DATEPART(dw, DATEADD(d, number, #FirstDateOfYear))
WHEN 7 THEN ‘Saturday’
WHEN 1 THEN ‘Sunday’
ELSE ‘Work Day’
END
FROM master..spt_values
WHERE number BETWEEN 0 AND 364
AND (DATEPART(dw, DATEADD(d, number, #FirstDateOfYear)) = 1 OR DATEPART(dw, DATEADD(d, number, #FirstDateOfYear)) = 7)
ORDER BY DATEADD(d, number, #FirstDateOfYear)
Try to find the first Saturday by doing this:
Start on 2012-01-01
If it's not a Saturday, add a day
Goto 2
Then, into a temporary table, add that date and the following date (Sunday).
After that, loop the following:
Add 7 and 8 days to the last Saturday you found (you get the following Saturday and Sunday)
Check whether they are still in 2012
If they are, store them in temp table and goto 1
There may be more elegant ways, but that's my quick & dirty solution. As you didn't post any code of what you've tried, I'll leave the implementation up to you.
this also works
declare #dat datetime, #add int
set #dat = '20120101'
set #add = datepart(w,#dat)
set #add = 5 - #add -- friday
set #dat = dateadd(d,#add,#dat)
while #dat <= '20121231'
begin
print #dat
set #dat = dateadd(d,7,#dat)
end
;with AllDaysOfYear (Day) as (
select DATEADD(year,DATEDIFF(year,0,CURRENT_TIMESTAMP),0) --Jan 1st
union all
select DATEADD(day,1,Day) from AllDaysOfYear
where DATEPART(year,DATEADD(day,1,Day)) = DATEPART(year,CURRENT_TIMESTAMP)
)
select
ROW_NUMBER() OVER (ORDER BY Day) as WeekNo,
Day
from
AllDaysOfYear
where
DATEPART(weekday,Day) = DATEPART(weekday,'20120714')
option (maxrecursion 0)
First, generate a set of all of the days in the current year (AllDaysInYear). Then, select those whose weekday is a saturday. The value I've used ('20120714') isn't terribly important - it just has to be any saturday, from any year. I'm just using it to avoid needing to have particular DATEFIRST or language settings.
This query shows how to get the first day of this year and the first day of the next year in the first part. The first day of the next year is calculated once so as not to keep getting and comparing the year parts.
;WITH cte(TheDate,NextYear) AS
(
SELECT CAST(CONVERT(CHAR(4),GETDATE(),112)+'0101' AS DATETIME),
CAST(YEAR(GETDATE())*10000+10101 AS CHAR(8))
UNION ALL
SELECT DateAdd(d,1,TheDate),NextYear
FROM cte
WHERE DateAdd(d,1,TheDate)<NextYear
)
SELECT Week = DatePart(wk,TheDate),
TheDate
FROM cte
WHERE DateName(dw,TheDate) in ('Saturday')
ORDER BY TheDate
OPTION (MAXRECURSION 366)
with t as
(
select 1 b
union all
select 1 b
union all
select 1 b
union all
select 1 b
union all
select 1 b
union all
select 1 b
union all
select 1 b
union all
select 1 b
)
select * from
(
select
current_timestamp
-datepart(dy,current_timestamp)
+row_number() over (order by t.b) d
from t, t t1, t t2
) tmp
where datepart(yyyy,d)=datepart(yyyy,current_timestamp)
and
DATENAME(dw,d)='sunday'
DECLARE #Year AS INT
SELECT #Year = 2020
;WITH weekends AS (
SELECT DATEFROMPARTS(#Year, 1, 1) AS dt
UNION ALL
SELECT DATEADD(DAY, 1, dt)
FROM weekends
WHERE dt < DATEFROMPARTS(#Year, 12, 31)
)
SELECT dt, DATENAME(MONTH, dt), DATENAME(DW, dt)
FROM weekends
WHERE DATEPART(DW, dt) IN (1, 7)
OPTION(MaxRecursion 366)
I am after a view which will look like my first attached picture however with right hand column populated and not blank. The logic is as follows:
The data must be for current financial period. Therfore April will be 2011 and March will be 2012 and so on.
The calculation for Days Available for the single months will be:
Total number of working days (Monday-Friday) minus any bank holidays that fall into that particular month, for that particular financial year (Which we have saved in a table - see second image).
Column names for holiday table left to right: holidaytypeid, name, holstart, holend.
Table name: holidaytable
To work out the cumulative months 'Days Available' it will be a case of summing already populated data for the single months. E.g April-May will be April and May's data SUMMED and so on and so forth.
I need the SQL query in perfect format so that this can be pasted straight in and will work (i.e with the correct column names and table names)
Thanks for looking.
DECLARE #StartDate DATETIME, #EndDate DATETIME
SELECT #StartDate = '01/04/2011',
#EndDate = '31/03/2012'
CREATE TABLE #Data (FirstDay DATETIME NOT NULL PRIMARY KEY, WorkingDays INT NOT NULL)
;WITH DaysCTE ([Date]) AS
( SELECT #StartDate
UNION ALL
SELECT DATEADD(DAY, 1, [Date])
FROM DaysCTE
WHERE [Date] <= #Enddate
)
INSERT INTO #Data
SELECT MIN([Date]),
COUNT(*) [Day]
FROM DaysCTE
LEFT JOIN HolidayTable
ON [Date] BETWEEN HolStart AND HolEnd
WHERE HolidayTypeID IS NULL
AND DATENAME(WEEKDAY, [Date]) NOT IN ('Saturday', 'Sunday')
GROUP BY DATEPART(MONTH, [Date]), DATEPART(YEAR, [Date])
OPTION (MAXRECURSION 366)
DECLARE #Date DATETIME
SET #Date = (SELECT MIN(FirstDay) FROM #Data)
SELECT Period,
WorkingDays [Days Available (Minus the Holidays)]
FROM ( SELECT DATENAME(MONTH, Firstday) [Period],
WorkingDays,
0 [SortField],
FirstDay
FROM #Data
UNION
SELECT DATENAME(MONTH, #Date) + ' - ' + DATENAME(MONTH, Firstday),
( SELECT SUM(WorkingDays)
FROM #Data b
WHERE b.FirstDay <= a.FirstDay
) [WorkingDays],
1 [SortField],
FirstDay
FROM #Data a
WHERE FirstDay > #Date
) data
ORDER BY SortField, FirstDay
DROP TABLE #Data
If you do this for more than 1 year you will need to change the line:
OPTION (MAXRECURSION 366)
Otherwise you'll get an error - The number needs to be higher than the number of days you are querying.
EDIT
I have just come accross this old answer of mine and really don't like it, there are so many things that I now consider bad practise, so am going to correct all the issues:
I did not terminate statements with a semi colon properly
Used a recursive CTE to generate a list of dates
Generate a set or sequence without loops – part 1
Generate a set or sequence without loops – part 2
Generate a set or sequence without loops – part 3
Did not include the column list for an insert
Used DATENAME to elimiate weekends, which is language specific, much better to explicitly set DATEFIRST and use DATEPART
Used LEFT JOIN/IS NULL instead of NOT EXISTS to elimiate records from the holiday table. In SQL Server LEFT JOIN/IS NULL is less efficient than NOT EXISTS
These are all minor things, but they are things I would critique (at least in my head if not outloud) when reviewing someone else's query, so can't really not correct my own work! Rewriting the query would give.
SET DATEFIRST 1;
DECLARE #StartDate DATETIME = '20110401',
#EndDate DATETIME = '20120331';
CREATE TABLE #Data (FirstDay DATETIME NOT NULL PRIMARY KEY, WorkingDays INT NOT NULL);
WITH DaysCTE ([Date]) AS
( SELECT TOP (DATEDIFF(DAY, #StartDate, #EndDate) + 1)
DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY a.object_id) - 1, #StartDate)
FROM sys.all_objects a
)
INSERT INTO #Data (FirstDay, WorkingDays)
SELECT FirstDay = MIN([Date]),
WorkingDays = COUNT(*)
FROM DaysCTE d
WHERE DATEPART(WEEKDAY, [Date]) NOT IN (6, 7)
AND NOT EXISTS
( SELECT 1
FROM dbo.HolidayTable ht
WHERE d.[Date] BETWEEN ht.HolStart AND ht.HolEnd
)
GROUP BY DATEPART(MONTH, [Date]), DATEPART(YEAR, [Date]);
DECLARE #Date DATETIME = (SELECT MIN(FirstDay) FROM #Data);
SELECT Period,
[Days Available (Minus the Holidays)] = WorkingDays
FROM ( SELECT DATENAME(MONTH, Firstday) [Period],
WorkingDays,
0 [SortField],
FirstDay
FROM #Data
UNION
SELECT DATENAME(MONTH, #Date) + ' - ' + DATENAME(MONTH, Firstday),
( SELECT SUM(WorkingDays)
FROM #Data b
WHERE b.FirstDay <= a.FirstDay
) [WorkingDays],
1 [SortField],
FirstDay
FROM #Data a
WHERE FirstDay > #Date
) data
ORDER BY SortField, FirstDay;
DROP TABLE #Data;
As a final point, this query becomes much simpler with a calendar table that stores all dates, and has flags for working days, holidays etc, rather than using a holiday table that just stores holidays.
Let me add few cents to this post. Just got assignment to calculate difference between planned hours and actual hour. The code below was converted to a function. So far no issue with the logic:
declare #date datetime = '11/07/2012'
declare #t table (HolidayID int IDENTITY(1,1) primary key,
HolidayYear int,
HolidayName varchar(50),
HolidayDate datetime)
INSERT #t
VALUES(2012, 'New Years Day', '01/02/2012'),
(2012,'Martin Luther King Day', '01/16/2012'),
(2012,'Presidents Day', '02/20/2012'),
(2012,'Memorial Day', '05/28/2012'),
(2012,'Independence Day', '07/04/2012'),
(2012,'Labor Day', '09/03/2012'),
(2012,'Thanksgiving Day', '11/22/2012'),
(2012,'Day After Thanksgiving', '11/23/2012'),
(2012,'Christmas Eve', '12/24/2012'),
(2012,'Christmas Day', '12/25/2012'),
(2013, 'New Years Day', '01/01/2013'),
(2013,'Martin Luther King Day', '01/21/2013'),
(2013,'Presidents Day', '02/18/2013'),
(2013,'Good Friday', '03/29/2013'),
(2013,'Memorial Day', '05/27/2013'),
(2013,'Independence Day', '07/04/2013'),
(2013,'Day After Independence Day', '07/05/2013'),
(2013,'Labor Day', '09/02/2013'),
(2013,'Thanksgiving Day', '11/28/2013'),
(2013,'Day After Thanksgiving', '11/29/2013'),
(2013,'Christmas Eve', NULL),
(2013,'Christmas Day', '12/25/2013')
DECLARE #START_DATE DATETIME,
#END_DATE DATETIME,
#Days int
SELECT #START_DATE = DATEADD(MONTH, DATEDIFF(MONTH, 0, #date), 0)
SELECT #END_DATE = DATEADD(month, 1,#START_DATE)
;WITH CTE AS
(
SELECT DATEADD(DAY, number, (DATEADD(MONTH, DATEDIFF(MONTH, 0, #date), 0) )) CDate
FROM master.dbo.spt_values where type = 'p' and number between 0 and 365
EXCEPT
SELECT HolidayDate FROM #t WHERE HolidayYear = YEAR(#START_DATE)
)
SELECT #Days = COUNT(CDate) --, datepart(dw, CDate) WDay
FROM CTE
WHERE (CDate >=#START_DATE and CDate < #END_DATE) AND DATEPART(dw, CDate) NOT IN(1,7)
SELECT #Days
I need a select to return Month and year Within a specified date range where I would input the start year and month and the select would return month and year from the date I input till today.
I know I can do this in a loop but I was wondering if it is possible to do this in a series selects?
Year Month
---- -----
2010 1
2010 2
2010 3
2010 4
2010 5
2010 6
2010 7
and so on.
Gosh folks... using a "counting recursive CTE" or "rCTE" is as bad or worse than using a loop. Please see the following article for why I say that.
http://www.sqlservercentral.com/articles/T-SQL/74118/
Here's one way to do it without any RBAR including the "hidden RBAR" of a counting rCTE.
--===== Declare and preset some obviously named variables
DECLARE #StartDate DATETIME,
#EndDate DATETIME
;
SELECT #StartDate = '2010-01-14', --We'll get the month for both of these
#EndDate = '2020-12-05' --dates and everything in between
;
WITH
cteDates AS
(--==== Creates a "Tally Table" structure for months to add to start date
-- calulated by the difference in months between the start and end date.
-- Then adds those numbers to the start of the month of the start date.
SELECT TOP (DATEDIFF(mm,#StartDate,#EndDate) + 1)
MonthDate = DATEADD(mm,DATEDIFF(mm,0,#StartDate)
+ (ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) -1),0)
FROM sys.all_columns ac1
CROSS JOIN sys.all_columns ac2
)
--===== Slice each "whole month" date into the desired display values.
SELECT [Year] = YEAR(MonthDate),
[Month] = MONTH(MonthDate)
FROM cteDates
;
I know this is an old question, but I'm mildly horrified at the complexity of some of the answers. Using a CTE is definitely the simplest way to go for selecting these values:
WITH months(dt) AS
(SELECT getdate() dt
UNION ALL
SELECT dateadd(month, -1, dt)
FROM months)
SELECT
top (datediff(month, '2017-07-01' /* start date */, getdate()) + 1)
YEAR(months.dt) yr, MONTH(months.dt) mnth
FROM months
OPTION (maxrecursion 0);
Just slap in whichever start date you'd like in place of the '2017-07-01' above and you're good to go with an efficient and easily-integrated solution.
Edit: Jeff Moden's answer quite effectively advocates against using rCTEs. However, in this case it appears to be a case of premature optimization - we're talking about 10's of records in all likelihood, and even if you span back to 1900 from today, it's still a minuscule hit. Using rCTEs to achieve code maintainability seems to be worth the trade if the expected result set is small.
You can use something like this: Link
To generate the equivalent of a numbers table using date ranges.
But could you please clarify your inputs and outputs?
Do you want to input a start date, for example, '2010-5-1' and end date, for example, '2010-8-1' and have it return every month between the two? Do you want to include the start month and end month, or exclude them?
Here's some code that I wrote that will quickly generate an inclusive result of every month between two dates.
--Inputs here:
DECLARE #StartDate datetime;
DECLARE #EndDate datetime;
SET #StartDate = '2010-1-5 5:00PM';
SET #EndDate = GETDATE();
--Procedure here:
WITH RecursiveRowGenerator (Row#, Iteration) AS (
SELECT 1, 1
UNION ALL
SELECT Row# + Iteration, Iteration * 2
FROM RecursiveRowGenerator
WHERE Iteration * 2 < CEILING(SQRT(DATEDIFF(MONTH, #StartDate, #EndDate)+1))
UNION ALL
SELECT Row# + (Iteration * 2), Iteration * 2
FROM RecursiveRowGenerator
WHERE Iteration * 2 < CEILING(SQRT(DATEDIFF(MONTH, #StartDate, #EndDate)+1))
)
, SqrtNRows AS (
SELECT *
FROM RecursiveRowGenerator
UNION ALL
SELECT 0, 0
)
SELECT TOP(DATEDIFF(MONTH, #StartDate, #EndDate)+1)
DATEADD(month, DATEDIFF(month, 0, #StartDate) + A.Row# * POWER(2,CEILING(LOG(SQRT(DATEDIFF(MONTH, #StartDate, #EndDate)+1))/LOG(2))) + B.Row#, 0) Row#
FROM SqrtNRows A, SqrtNRows B
ORDER BY A.Row#, B.Row#;
Code below generates the values for the range between 21 Jul 2013 and 15 Jan 2014.
I usually use it in SSRS reports for generating lookup values for the Month parameter.
declare
#from date = '20130721',
#to date = '20140115';
with m as (
select * from (values ('Jan', '01'), ('Feb', '02'),('Mar', '03'),('Apr', '04'),('May', '05'),('Jun', '06'),('Jul', '07'),('Aug', '08'),('Sep', '09'),('Oct', '10'),('Nov', '11'),('Dec', '12')) as t(v, c)),
y as (select cast(YEAR(getdate()) as nvarchar(4)) [v] union all select cast(YEAR(getdate())-1 as nvarchar(4)))
select m.v + ' ' + y.v [value_field], y.v + m.c [label_field]
from m
cross join y
where y.v + m.c between left(convert(nvarchar, #from, 112),6) and left(convert(nvarchar, #to, 112),6)
order by y.v + m.c desc
Results:
value_field label_field
---------------------------
Jan 2014 201401
Dec 2013 201312
Nov 2013 201311
Oct 2013 201310
Sep 2013 201309
Aug 2013 201308
Jul 2013 201307
you can do the following
SELECT DISTINCT YEAR(myDate) as [Year], MONTH(myDate) as [Month]
FROM myTable
WHERE <<appropriate criteria>>
ORDER BY [Year], [Month]
---Here is a version that gets the month end dates typically used for accounting purposes
DECLARE #StartDate datetime;
DECLARE #EndDate datetime;
SET #StartDate = '2010-1-1';
SET #EndDate = '2020-12-31';
--Procedure here:
WITH RecursiveRowGenerator (Row#, Iteration)
AS ( SELECT 1, 1
UNION ALL
SELECT Row# + Iteration, Iteration * 2
FROM RecursiveRowGenerator
WHERE Iteration * 2 < CEILING(SQRT(DATEDIFF(MONTH, #StartDate, #EndDate)+1))
UNION ALL SELECT Row# + (Iteration * 2), Iteration * 2
FROM RecursiveRowGenerator
WHERE Iteration * 2 < CEILING(SQRT(DATEDIFF(MONTH, #StartDate, #EndDate)+1)) )
, SqrtNRows AS ( SELECT * FROM RecursiveRowGenerator
UNION ALL SELECT 0, 0 )
SELECT TOP(DATEDIFF(MONTH, #StartDate, #EndDate)+1)
DateAdd(d,-1,DateAdd(m,1, DATEADD(month, DATEDIFF(month, 0, #StartDate) + A.Row# * POWER(2,CEILING(LOG(SQRT(DATEDIFF(MONTH, #StartDate, #EndDate)+1))/LOG(2))) + B.Row#, 0) ))
Row# FROM SqrtNRows A, SqrtNRows B ORDER BY A.Row#, B.Row#;
DECLARE #Date1 DATE
DECLARE #Date2 DATE
SET #Date1 = '20130401'
SET #Date2 = DATEADD(MONTH, 83, #Date1)
SELECT DATENAME(MONTH, #Date1) "Month", MONTH(#Date1) "Month Number", YEAR(#Date1) "Year"
INTO #Month
WHILE (#Date1 < #Date2)
BEGIN
SET #Date1 = DATEADD(MONTH, 1, #Date1)
INSERT INTO #Month
SELECT DATENAME(MONTH, #Date1) "Month", MONTH(#Date1) "Month Number", YEAR(#Date1) "Year"
END
SELECT * FROM #Month
ORDER BY [Year], [Month Number]
DROP TABLE #Month
declare #date1 datetime,
#date2 datetime,
#date datetime,
#month integer,
#nm_bulan varchar(20)
create table #month_tmp
( bulan integer null, keterangan varchar(20) null )
select #date1 = '2000-01-01',
#date2 = '2000-12-31'
select #month = month(#date1)
while (#month < 13)
Begin
IF #month = 1
Begin
SELECT #date = CAST( CONVERT(VARCHAR(25),DATEADD(dd,-(DAY(DATEADD(mm,0,#date1))-1),DATEADD(mm,0,#date1)),111) + ' 00:00:00' as DATETIME )
End
ELSE
Begin
SELECT #date = CAST( CONVERT(VARCHAR(25),DATEADD(dd,-(DAY(DATEADD(mm,#month -1,#date1))-1),DATEADD(mm,#month -1,#date1)),111) + ' 00:00:00' as DATETIME )
End
select #nm_bulan = DATENAME(MM, #date)
insert into #month_tmp
select #month as nilai, #nm_bulan as nama
select #month = #month + 1
End
select * from #month_tmp
drop table #month_tmp
go