Insert XML Node into a SQL column in a table - sql

Question

I have an XML file that I am passing into a stored procedure.
I also have a table. The table has the columns VehicleReg | XML | ProcessedDate
My XML comes in like so:
<vehicles>
<vehicle>
<vehiclereg>AB12CBE</vehiclereg>
<anotherprop>BLAH</anotherprop>
</vehicle>
<vehicle>
<vehiclereg>AB12CBE</vehiclereg>
<anotherprop>BLAH</anotherprop>
</vehicle>
</vehicles>
What I need to do is read the xml and insert the vehiclereg and the full vehicle xml string into each row (the dateprocessed is a getdate() so not a problem).
I was working on something like below but had no luck:
DECLARE #XmlData XML
Set #XmlData = EXAMPLE XML
SELECT T.Vehicle.value('(vehiclereg)[1]', 'NVARCHAR(10)') AS vehiclereg,
T.Vehicle.value('.', 'NVARCHAR(MAX)'),
GETDATE()
FROM #XmlData.nodes('Vehicles/Vehicle') AS T(Vehicle)
I was wondering if someone could point me in the right direction?
Regards

Answer 1

Full query as you want:
DECLARE #XmlData XML
Set #XmlData = '<vehicles>
<vehicle>
<vehiclereg>AB12CBE</vehiclereg>
<anotherprop>BLAH</anotherprop>
</vehicle>
<vehicle>
<vehiclereg>AB12CBE</vehiclereg>
<anotherprop>BLAH</anotherprop>
</vehicle>
</vehicles>'
SELECT T.Vehicle.value('./vehiclereg[1]', 'NVARCHAR(10)') AS vehiclereg,
T.Vehicle.query('.'),
GETDATE()
FROM #XmlData.nodes('/vehicles/vehicle') AS T(Vehicle)

Answer 2

Just need to remember XML is case sensitive. You had:
FROM #XmlData.nodes('Vehicles/Vehicle') AS T(Vehicle)
but you should have had:
FROM #XmlData.nodes('/vehicles/vehicle') AS T(Vehicle)
Also as TT pointed out there was no column named Registration
This should do it:
DECLARE #XmlData XML
Set #XmlData = '<vehicles>
<vehicle>
<vehiclereg>AB12CBE</vehiclereg>
<anotherprop>BLAH</anotherprop>
</vehicle>
<vehicle>
<vehiclereg>AB12CBE</vehiclereg>
<anotherprop>BLAH</anotherprop>
</vehicle>
</vehicles>'
SELECT Vehicle.value('(vehiclereg)[1]', 'NVARCHAR(10)') AS vehiclereg,
Vehicle.value('.', 'NVARCHAR(MAX)'),
GETDATE()
FROM #XmlData.nodes('/vehicles/vehicle') AS T(Vehicle)
Result:
This would return XML:
DECLARE #XmlData XML
Set #XmlData = '<vehicles>
<vehicle>
<vehiclereg>AB12CBE</vehiclereg>
<anotherprop>BLAH</anotherprop>
</vehicle>
<vehicle>
<vehiclereg>AB12CBE</vehiclereg>
<anotherprop>BLAH</anotherprop>
</vehicle>
</vehicles>'
SELECT T.Vehicle.value('(vehiclereg)[1]', 'NVARCHAR(10)') AS vehiclereg,
T.Vehicle.query('.'),
GETDATE()
FROM #XmlData.nodes('vehicles/vehicle') AS T(Vehicle)
Result:

Answer 3

You can get the XML by XML.query(), in this case query('.') on the vehicles/vehicle node to get the inner XML.
DECLARE #x XML=
'<vehicles>
<vehicle>
<vehiclereg>AB12CBE</vehiclereg>
<anotherprop>BLAH</anotherprop>
</vehicle>
<vehicle>
<vehiclereg>AB13QQT</vehiclereg>
<anotherprop>BLAH</anotherprop>
</vehicle>
</vehicles>';
DECLARE #t TABLE(VehicleReg VARCHAR(128),[XML] XML,ProcessedDate DATETIME);
INSERT INTO #t(VehicleReg,[XML],ProcessedDate)
SELECT VehicleReg=n.v.value('(vehiclereg)[1]','VARCHAR(128)'),
[XML]=n.v.query('.'),
ProcessedDate=GETDATE()
FROM #x.nodes('vehicles/vehicle') AS n(v);
SELECT * FROM #t;
Result:
+------------+------------------------------------------------------------------------------------+-------------------------+
| VehicleReg | XML | ProcessedDate |
+------------+------------------------------------------------------------------------------------+-------------------------+
| AB12CBE | <vehicle><vehiclereg>AB12CBE</vehiclereg><anotherprop>BLAH</anotherprop></vehicle> | 2016-03-01 15:21:37.640 |
| AB13QQT | <vehicle><vehiclereg>AB13QQT</vehiclereg><anotherprop>BLAH</anotherprop></vehicle> | 2016-03-01 15:21:37.640 |
+------------+------------------------------------------------------------------------------------+-------------------------+