Searching and returning all occurences of keyword in a Postgres text column - sql

Question

About database
Database table for content of an Confluence page is named bodycontent and the HTML content is stored in column named body, which is a text field. Im using Postgres database. Primary key is named bodycontentid
Result I need
For each row in the table I need to find all occurence of <image> tag where src attribute starts with "http://images.mydomain.com/allImages/%" in the body column
Example
Let say that body with bodycontentid = 12345 contains following text:
<h1>Chapter 1</h1>
<image src="http://www.google.com/image/111.jpg"/>
<h1>Chapter 2</h1>
<image src="http://images.mydomain.com/allImages/222.jpg"/>
<h1>Chapter 3</h1>
<image src="http://images.mydomain.com/allImages/333.jpg"/>
Result after running this query should return:
bodycontentid: 12345
body: http://images.mydomain.com/allImages/222.jpg
bodycontentid: 12345
body: http://images.mydomain.com/allImages/333.jpg
What I have tried
Im able to find all rows that has at least one occurence of the keyword Im searching for (see below), but what I need is to get list of all keywords per row that is matching my query.
SELECT *
FROM bodycontent
WHERE body LIKE '%http://images.mydomain.com/allImages/%'

Answer 1

One method is to use regexp_split_to_table() and then some string manipulation:
select bc.bodycontentid,
left(rst.s, position('"' in rst.s) - 1) as domain
from bodycontent bc, lateral
regexp_split_to_table(bc.body, E'srce="') rst(s)
where rst.s like 'http://images.mydomain.com/allImages/%';