I am trying to convert a string of 4 bytes in a string to an integer number in LabView, currently I am using the string subset to break apart my string and then storing it into a String Indicator on the front panel, however, I need to convert that string to an int so I can show the decimal value as well as convert it from inches to mm. Here is what I'm doing now:
I've tried converting to double using the convert string to double functions as well as I've tried splitting it up using the index array...can't quite seem to get an int out ever. Thanks!
Do as Ton Plomp said and use the Scan From String block. However, in yours, you don't want to separate with commas and with spaces. Just do:
%x%x%x%x
And that should do it for ya. Don't forget to pull the scan down so you have 4 outputs.
You can use Scan from string with the following format string:
%x
You can expand the scan from string to scan multiple items at once.
Related
I have a mac string:
mac=7A2918D5434F
And I need to convert to this:
mac=7A:29:18:D5:43:4F
How can I do that in kotlin?
If you are sure that your initial string is correct you can do something like:
"7A2918D5434F".chunked(2).joinToString(":")
chunked(2) splits the string in chunks of size 2 (can be used for any Iterable).
jointToString(":") takes a list, joins the elements to string using : as delimiter
In labview I am trying to convert a hex string to ascii format. For example if I have a hexstring like: 09124E4F21CD0024FFFFFFFFFFFFFFFF the ascii version of this is : NO!Í or basically a bunch of illegible symbols. I tried using the labview functions of converting hexstring to number but they didn't work. How would I convert the ascii part to hexformatted ascii?
Hexadecimal String to Number works fine, but only for a hex string that represents a number that can be stored as a numeric data type:
If the input string represents a number outside the range of the
representation of number, number is set to the maximum value for that
data type.
Your example input is 128 bits long whereas the longest integer data type in current LabVIEW is 64 bits.
You can use this function, but you need to convert the input one byte at a time:
Create a While Loop and add a shift register. Initialise the shift register with your input string.
Inside the loop, wire the string from the shift register to the string input of a Search/Split String function
Wire a numeric constant of 2 to the offset input - i.e. split the string into the first two characters, and the rest
Wire the match + rest of string output to the right-hand shift register terminal
Wire the substring before match output to a Hexadecimal String to Number function
Wire the default input of this function to a numeric constant with value 0 and type U8
Wire the output of this function to the right-hand side of the While loop and make the terminal indexing (via right-click)
Use an Empty String/Path? function to exit the While loop when the string being passed back into the shift register is empty.
The output from the indexing terminal you created will now be a U8 (byte) array containing the data converted from the input string. If you want it in string form you can convert it using Byte Array to String.
This assumes that your input string is always a multiple of 2 characters in length. If you need it to handle an input such as "3F2" you'll need to check for this and do something to the input (I'll let you figure out what) before passing it into your loop.
I am using bro to read bytes directly of the payload of a packet.
I have a string value "\x10" and I want to get the decimal value of off that.
I know that bro support directly printing hex to decimal:
print 0x10;
Question is, how do I convert that string similarly to its integer version?
The best you can do is strip off the "\x" portion, and run it through 2 BIFs:
bytestring_to_count(hexstr_to_bytestring("10"));
I have an input string as follows: "ABC1134M001020000089".
I want to convert the string to integer format. One of the methods I thought of was by replacing A,B,C,M to its respective ASCII Values.
How can I achieve this in PostgreSQL?
So, I made a program that for the most part, converts numbers to letters. My problem before was it was converting each individual digit instead of each number e.g. (1-0-1 instead of 101). Someone suggested that I use the Split function:
Dim numbers As String() = DTB.Split(" ")
So now it's reading the number all the way through being that it will only the split if there's a space in between. My problem now is that it's translating for example: "[102, 103, 104]" as "[102", "103" and "104]" because it will only split if there's a space between. Obviously, you can't convert "[102" or "104]" because they aren't actual numbers.
Does anyone have a solution on what I should do to get this to convert no matter the spacing? Would Regex be the way to go?
use a regular expression with \d+ it will match numbers
so
12234abcsdf23434
will return two matches
12234
23434