I wanted to try to build and modify Chromium in order to try and learn a few things. When I first built it and ran it (without any changes), it worked perfectly fine, however I tried changes some of the branding in order to tinker with it and it gave me an error message. I referred to two places when rebranding to see where I could change the branding:
First link
Second link
When I ran the modified version, it gave me an error message when running:
[0808/205916.858263:FATAL:bundle_locations.mm(62)] Check failed: new_bundle. Failed to load the bundle at /path/to/src/out/buildTwo/RebrandName.app/Contents/Frameworks/Chromium Framework.framework/Versions/94.0.4601.0
0 libbase.dylib 0x000000010a123638 base::debug::CollectStackTrace(void**, unsigned long) + 12
1 libbase.dylib 0x000000010a00e774 base::debug::StackTrace::StackTrace() + 24
2 libbase.dylib 0x000000010a032c1c logging::LogMessage::~LogMessage() + 184
3 libbase.dylib 0x000000010a033914 logging::LogMessage::~LogMessage() + 12
4 libbase.dylib 0x0000000109ffa0f0 logging::CheckError::~CheckError() + 36
5 libbase.dylib 0x000000010a139d5c base::mac::AssignOverridePath(base::FilePath const&, NSBundle**) + 176
6 libchrome_dll.dylib 0x0000000104ceb5d0 SetUpBundleOverrides() + 40
7 libchrome_dll.dylib 0x0000000104ce8f44 ChromeMain + 156
8 RebrandName 0x00000001049b7cc0 main + 284
9 libdyld.dylib 0x000000018efcd450 start + 4
zsh: trace trap out/buildTwo/RebrandName.app/Contents/MacOS/RebrandName
I tried to investigate to see what might have happened and saw that /path/to/src/out/buildTwo/RebrandName.app/Contents/Frameworks/Chromium Framework.framework but in it's place is /path/to/src/out/buildTwo/RebrandName.app/Contents/Frameworks/RebrandName Framework.framework
I ran out/buildTwo/RebrandName.app/Contents/MacOS/RebrandName and this error popped up.
This is currently running on an M1 Macbook Pro on MacOS Big Sur.
I have tried searching for the fix with no luck. Please understand that I have little to no idea of what I'm doing, so if more clarification is required, please let me know and I will try to edit my question as best as I can.
The file:
chrome/common/chrome_constants.cc
Change PRODUCT_STRING constant
I am trying to understand how PDF objects are encoded.
Example - PDF doc with 1 page of text in english has following objects (this PDF was created using PDFLaTex tool):
obj 3 0
obj 8 0
obj 11 0
obj 5 0
obj 12 0
Could someone explain me the concept behind the object ID generation, it doesn't have an order and I am not able to figure out the concept behind it.
Let consider the code given below, may I know why CBMC is unwinding more than the upper bound limit while we have assumed the initial value of io is greater then 2.
#include<assert.h>
void main()
{
int i0;
int o1;
__CPROVER_assume(i0>=2);
//assert(i0>=0);
while(i0<=10)
{
i0=i0+1;
}
o1=i0+1;
assert((o1 <= 1));
}
CBMC Output:
CBMC version 5.8 64-bit x86_64 linux
Parsing /tmp/in1_1524461553_1936466587.c
Converting
Type-checking in1_1524461553_1936466587
Generating GOTO Program
Adding CPROVER library (x86_64)
Removal of function pointers and virtual functions
Partial Inlining
Generic Property Instrumentation
Starting Bounded Model Checking
Unwinding loop main.0 iteration 1 file /tmp/in1_1524461553_1936466587.c line 9 function main thread 0
Unwinding loop main.0 iteration 2 file /tmp/in1_1524461553_1936466587.c line 9 function main thread 0
Unwinding loop main.0 iteration 3 file /tmp/in1_1524461553_1936466587.c line 9 function main thread 0
Unwinding loop main.0 iteration 4 file /tmp/in1_1524461553_1936466587.c line 9 function main thread 0
Unwinding loop main.0 iteration 5 file /tmp/in1_1524461553_1936466587.c line 9 function main thread 0
Unwinding loop main.0 iteration 6 file /tmp/in1_1524461553_1936466587.c line 9 function main thread 0
Unwinding loop main.0 iteration 7 file /tmp/in1_1524461553_1936466587.c line 9 function main thread 0
Unwinding loop main.0 iteration 8 file /tmp/in1_1524461553_1936466587.c line 9 function main thread 0
Unwinding loop main.0 iteration 9 file /tmp/in1_1524461553_1936466587.c line 9 function main thread 0
Unwinding loop main.0 iteration 10 file /tmp/in1_1524461553_1936466587.c line 9 function main thread 0
Unwinding loop main.0 iteration 11 file /tmp/in1_1524461553_1936466587.c line 9 function main thread 0
Unwinding loop main.0 iteration 12 file /tmp/in1_1524461553_1936466587.c line 9 function main thread 0
Unwinding loop main.0 iteration 13 file /tmp/in1_1524461553_1936466587.c
I guess symex hasn't been smart enough to see that the condition on the loop will always be false beyond a certain iteration. It tries to simplify expressions a bit as it goes along, but not all that much. When this is converted to a formula and passed to the SAT solver, the SAT solver will quickly see that the conditions for those iterations of the loop can never be satisfied and discard those parts of the formula, so it shouldn't affect correctness (though of course it may mean that CBMC takes a long time to run).
I am parsing Type3 glyphs fonts from Pdf to postscript. The input file have inline image with data streams flate decode filter applied.the filter has predictor 15.
Any body can help how I take the image streams form pdf to postscript.
This is how the input stream is given in pdf
32 0 obj
<<
/Length 342
>>
stream
37 0 4 -52 33 -1 d1
0.01 0 0 0.01 0 0 concat
gsave 2900 0 0 -5100 400 -100 concat
BI
/IM true
/W 29
/H 51
/BPC 1
/D[1
0]
/F/Fl
/DP<</Predictor 15
/Columns 29>>
ID xœ=Ì¡
Â`ÅñÿeÂLθ n`0>Ù`ñ
f[¦DŒF_ÁhC1ì%Ä)¶o.¢Ÿ"†ßá†s®àì]^ÏŠÅS³tFËÂÚ3sç'Æi èÐÇ:j‹¹¨åìOTÿ ª•ÉÙÕÅŸ¨‡¹Ó$°ÆΚWèÁ!¯Cê
÷0&f µtðV ©Ë÷iôíتÄ~Ø•Œöí&´« +ro#Ê‚ûÏÅùlßG'
EI gRestore
endstream
endobj
And here is what i am trying to write in output in Postscript
/g21 {
37 0 4 -52 33 -1 setcachedevice
q
[0.01 0 0 0.01 0 0] concat
q
[2900 0 0 -5100 400 -100] concat
[ xœ…ѱNÃ0à3©p'l` ¢abä*‰'#‚W`KP¡00öQ`d# ¨CWž€u`‰štj4Ü]# /ù¤œíÿ| ÂìÊüå7úŠ‰V'‚ª¦zò¡9à*´º
m1Õ`ñ—íü‹‡½Gù#ãÝAVxc¥Ž®"6oFܬJHÃB3(æod¾…xFP†o$!v±Ã»·0—gØY÷J$û„`´#zÊ
Oí¼œÑ¸é`Ê}ü…ñ.Z¯›cF4\¡*O¤ÑPÒYòî¦/éG‘qÑç¼2>öq<Üœ<
B˜5‚²¢ºÎ/èqUTUàoÓ9͔Π܉ä²z ‡S×ÛÙC(PA²š7èT¾ŽCGÈRaLéåksnˆÃ0z<zø:ž=
]
0
<<
/ImageType 1
/Width 29
/Height 51
/ImageMatrix [29 0 0 -51 0 51]
/BitsPerComponent 1
/Decode [1 0]
/DataSource { 2 copy get exch 1 add exch }
<</Predictor 15
/Columns 29
>>
/FlateDecode filter
>>
imagemask
pop pop
gRestore
gRestore
} def
PostScript has mostly the same filters as PDF. You don't need to decompress the data, just use the FlateDecode filter in PostScript and leave the compressed data untouched.
Note you'll need Language Level 3 for Predictor 15 (or any other PNG predictor) but that shouldn't be a problem, level 3 has been the standard for 18 years.
Otherwise you'll need to implement a version of the FlateDecode filter which supports the PNG Predictor. I believe zlib is quite capable of this.
[EDIT]
Your 'PostScript output' is incomplete, you are using PDF operators (q and Q) which you have not provided a definition for. Apart from anything else this makes it impossible to run the code through an interpreter. Kindly supply a complete simple example file, as requested. Not pasted code, I'm not inclined to go and create a file myself, and besides, binary doesn't cut and paste at all well.
Off the top of my head from desk checking I can't immediately see a problem, but since I can't run the code, I could easily be missing something.
[EDIT 2]
And that file, unsurprisingly, works fine.
You haven't supplied the PostScript file that you are creating. Its rather hard for me to tell what's wrong with the PostScript you created by looking at the PDF file you started with.
You could, of course, use Ghostscript (and I see you've used it to create the PDF file) to create a PostScript file, and then look at what that contains. If you set -dCompressFonts=false then the output font won't even be compressed.
For example:
37 0 4 -52 33 -1 d1
0.01 0 0 0.01 0 0 cm
q 2900 0 0 -5100 400 -99.9998 cm
BI
/IM true
/W 29
/H 51
/BPC 1
/D[1
0]
/F[/A85
/CCF]
/DP[null
<</K -1
/Columns 29>>]
ID
-D=,M5m+t^0_>op8\HM"Du]KKrr2rthqG/5qU_ik]$f$TlUslD91qoN93j0%dckk:ld^*DV25!+
!WX>~>
EI Q
Of course you'll need to look at the prolog to see how all the procedures used there are defined, but you can do that yourself, you certainly don't need me to do it. Notice that the imagemask uses the CCITTFax and ASCII85 decode filters, its trivial to add additional filters. Since the data is guaranteed to be 'monochrome' (its a mask) the CCITT filter generally gives superior compression to Flate.
Note that if you are really using Ghostscript 9.05 then you should upgrade, that is 6 years old.
It might possibly help if you were to explain why you want to take an ugly, bitmapped, type 3 font from PDF and make an ugly, bitmapped type 3 PostScript font from it.
[EDIT 3]
well looking at your PostScript file, the definition of the glyphs does not match what you've put in your question. The actual content looks like this:
/g10135{
88 0 4 -70 82 8 setcachedevice
q
[
0.01 0 0 0.01 0 0 ] M
q
[7800 0 0 -7800 400 800 ]M
<<
/ImageType 1
/Width 78
/Height 78
/ImageMatrix [ 78 0 0 -78 0 78]
/BitsPerComponent 1
/Decode [1
0]
/DataSource ....binary data.....
<< /Predictor 15
/Columns 78
/BitsPerComponent 1>>
/FlateDecode filter def
>> imagemask
Q
Q
}bind def
You have not supplied either a file, procedure or string source as a value for the DataSource key in the dictionary. Essentially, the PostScript interpreter reads and tokenises the /DataSource key, and then proceeds to process the binary as PostScript. Unsurprisingly this causes an error 'syntaxerror in (binary token, type=156)' when processed with Ghostscript.
If you had got past that then you would have discovered that the filter operator takes a data source as well and you haven't supplied one for that either.
So you need to create a data source for your binary data. Up to you how you do that but currentfile is one way. Or readstring given that you know the string length.
So something like:
<<
/ImageType 1
/Width 29
/Height 51
/ImageMatrix [29 0 0 -51 0 51]
/BitsPerComponent 1
/Decode [1 0]
/DataSource
<length> string dup
currentfile exch readstring
.....binary data.....
<<
/Predictor 15
/Columns 29
>> /FlateDecode filter
>> imagemask
Obviously you'll have to fill in yourself by knowing the string length. The dictionary argument to FlateDecode looks to me like it shouldn't be needed.
[Edit 4]
I notice that this is appears to be intended for commercial use. Nothing wrong with that, but I'm not going to do all your homework for you, if its your job its up to you to learn the language well enough to do the job.
I'm skipping lightly over the actual implementation details below in an attempt to outline where you are going wrong. In practice things are a little more complex, I haven't discussed how the procedure stored in the CharStrings dictionary is created, or the difference with early name binding (which is an important concept in PostScript).
Your existing code is:
/g10135{
88 0 4 -70 82 8 setcachedevice
q
[
0.01 0 0 0.01 0 0 ] M
q
[7800 0 0 -7800 400 800 ]M
<<
/ImageType 1
/Width 78
/Height 78
/ImageMatrix [ 78 0 0 -78 0 78]
/BitsPerComponent 1
/Decode [1
0]
/DataSource {417 string dup
currentfile exch readstring}
...binary data....
<< /Predictor 15
/Columns 78
>>/FlateDecode filter def
>> imagemask
Q
Q
}bind def
So, the PostScript interpreter reads those bytes one at a time, and converts them into tokens. This either results in an executable token, which is executed, or an operation on one of the stacks.
So /g10135 is terminated by the { character, because that's a reserved character. The / introduces a name object, so we end up with the name object g10135 which we push on to the operand stack. The { character introduces an executable array so we put a mark on the operand stack.
Next we read 88, terminated by a white space character. That's a numeric so we store that on the operand stack, likewise the other numbers. The operand stack now contains:
/g10135
mark
88
0
4
-70
82
8
We then read setcachedevice, which is terminated by a white space. That isn't a standard token so the interpreter starts looking through the dictionaries on the dictionary stack, looking for a definition. Since it is a standard operator, we find it in systemdict and execute it. That consumes 6 operands from the operand stack, it has no other effects (actually it does, but this is a bit special because we are executing inside a font, but we'll ignore that for now).
Next we encounter a q, again this is looked up in every dictionary on the dictionary stack to find a definition. This is defined in your own prolog as a gsave, so it takes no operands and returns no operands, it simply saves the graphics state, incrementing the save depth by 1.
I'm not going to go through the rest it would be tedious, however, eventually we reach your /DataSource, this is a name, so we push it on the operand stack. The next thing we encounter is a { that's a procedure definition so we push a mark on the operand stack. We then encounter a 417 so we push that, string, dup, currentfile, exch and readstring, so our stack looks like:
/DataSource
mark
417
string
dup
currentfile
exch
readstring
Then we get the character } That is the closing mark for an executable array, so we create the array and push it onto the operand stack:
/DataSource
{....}
Then we return to the procedure and continue executing it. The next thing we find is some binary data so we try to execute that as PostScript binary tokens. Because it isn't valid the interpreter throws an error.
Just creating an executable array is not sufficient to actually execute it. If you look at the outline code I posted at the end of edit 3 above you will note that I did not put the readstring and so on in an executable array, I simply allowed the interpreter to execute that code immediately.
By doing so the readstring acts on currentfile (the actual PostScript program in this case) and reads bytes of data from the current point in that file. The current point will be immediately after consuming the white space which terminates the readstring, ie the actual binary data. The readstring operator reads enough bytes from the file to fill the string, leaving the string on the operand stack. The file pointer has moved on to the byte after the binary data, and the interpreter resumes token scanning at that point. So it then creates the FilterParams dictionary puts the /FlateDecode name on the stack and then executes the filter operator which consumes the name, the dictionary and the string operands, returning a file object. That file object then becomes the value associated with the DataSource key in the image dictionary which is passed to the imagemask operator.
While I haven't tested that code, its basically correct. There are of course other ways to achieve the same aim.
That's basically about as far as I'm prepared to go with this, you need to go and look at what I've written and compare it with your own program.
Note that the simplest way to investigate this is to take the contents of the CharProc (excluding the setcachedevice) and just run that as a PostScript program.
I want to convert this PDF file compiled with LaTeX (XeLaTeX engine so that to use an Arabic font) and I want to upload it to the web and prevent copy and paste of its content.
Since I am looking for a freeware to do that, I came across two powerful beasts to do this job, namely, ImageMagick and Ghostscript. All what I need is to convert one text PDF to image PDF in one go, preferably with batch processing if possible (to convert many PDFs in one go).
I run this code in command line and it works fine for English-written PDFs:
convert someenglish.pdf output.pdf
Now when I do the same for an Arabic PDF I get this error:
convert.exe: PDFDelegateFailed `[ghostscript library] -q -dQUIET -dSAFER -dBATCH
-dNOPAUSE -dNOPROMPT -dMaxBitmap=500000000 -dAlignToPixels=0 -dGridFitTT=2 "-sD
EVICE=pngalpha" -dTextAlphaBits=4 -dGraphicsAlphaBits=4 "-r72x72" "-sOutputFile
=C:/Users/doctorate/AppData/Local/Temp/magick-65203BNMxTDhXtkF%d" "-fC:/Users/doctorate/Ap
pData/Local/Temp/magick-65206AK54hOoKA62" "-fC:/Users/doctorate/AppData/Local/Temp/ma
gick-6520hDn-KMyTyxy2"': **** Error reading a content stream. The page may be
incomplete.
**** Incorrect object count in object stream.
Error: /rangecheck in resolveobjectstream
Operand stack:
78424 10 1 10 --dict:7/15(L)-- 26 --nostringval-- 35 --nostri
ngval-- --dict:2/2(L)-- --dict:2/2(L)-- --dict:2/2(L)-- --dict:2/2(L)--
--dict:4/4(L)-- --dict:4/4(L)-- --dict:4/4(L)-- --dict:4/4(L)-- --dict
:4/4(L)-- --dict:3/3(L)-- --dict:2/2(L)-- --nostringval-- --dict:7/7(L)-
- --dict:10/10(L)-- --nostringval-- --nostringval-- Type Font Subtyp
e CIDFontType2 BaseFont MYCROL+(AH
Execution stack:
%interp_exit .runexec2 --nostringval-- --nostringval-- --nostringval-
- 2 %stopped_push --nostringval-- --nostringval-- --nostringval-- fa
lse 1 %stopped_push 1983 1 3 %oparray_pop 1982 1 3 %oparray_
pop 1966 1 3 %oparray_pop --nostringval-- --nostringval-- --nostri
ngval-- --nostringval-- --nostringval-- --nostringval-- --nostringval--
--nostringval-- --nostringval--
Dictionary stack:
--dict:1193/1684(ro)(G)-- --dict:1/20(G)-- --dict:82/200(L)-- --dict:82
/200(L)-- --dict:116/127(ro)(G)-- --dict:280/300(ro)(G)-- --dict:24/32(L)-
-
Current allocation mode is local
GPL Ghostscript 9.15: Unrecoverable error, exit code 1
# error/pdf.c/InvokePDFDelegate/263.
convert.exe: no images defined `test.pdf' # error/convert.c/ConvertImageCommand/
3210.
Question
What am I missing here? I am not a programmer, so please consider this in your answer. I am very grateful if you could show how to do this in batch process.
Notes
Windows 7 32bit
Ghostscript version 9.15
Quality of image is not an issue for me even 72dpi will be fine
I want to strike a balance between size of the output and clarity of text. I just want the text to be readable on the web and not to do some OCR processing with it, so image doesn't need to be very sharp. Size of output is more important, the less the better and honestly I am clueless as to what might works better; to convert the PDF file into PNG or into JPEG in this case.
I don't want to burst a PDF into multiple serially named PNGs or JPEGs, simply one PDF to another PDF but as images inside and no more copy&paste-prone text.
Update
I tried to make a minimal working example PDF to mimic the original PDF and found that problem arises by including a certain Arabic font called (AH) Manal Black. Running pdffonts from command line on this MWE PDF gives:
Syntax Error (18062): Illegal character ')'
Syntax Error (18076): Dictionary key must be a name object
Syntax Error (18085): Dictionary key must be a name object
Syntax Error (18248): Illegal character ')'
Syntax Error (18248): Dictionary key must be a name object
Syntax Error (18253): Dictionary key must be a name object
Syntax Error (18599): Illegal character ')'
Syntax Error (18599): Dictionary key must be a name object
Syntax Error (18607): Dictionary key must be a name object
name type emb sub uni object ID
------------------------------------ ----------------- --- --- --- ---------
GAKHDJ+(AH CID TrueType yes yes yes 5 0
HTCSVQ+Amiri-Regular CID TrueType yes yes yes 7 0
By excluding this Arabic font when compiling the document using LaTeX/XeTeX engine, the convert command works just fine like in other English PDFs. So most probably this problem is linked to parsing of the fonts.
Update: A minimally working example is here: https://www.dropbox.com/s/qdeuzips0ivas4q/mwe_ar.pdf?dl=0
The minimally working example has PDF object no. 10 as an ObjStm (object stream), where this part can be found (I edited the whitespace formatting for improved readability):
<< /Type /Font
/Subtype /Type0
/BaseFont /GAKHDJ+#28AH)#20Manal#20Black
/Encoding /Identity-H
/DescendantFonts [4 0 R]
/ToUnicode 12 0 R
>>
So the font name, (AH) Manal Black, has properly hex-escaped the blanks as #20 and the opening parenthesis ( as #28, but it hasn't hex-escaped the closing parenthesis ) as #29, as it should.
Without knowing more about the PDF generating process, I guess that the Creator/Producer combo as given through the file's metadata,
Creator: XeTeX output 2015.05.01:1207
Producer: xdvipdfmx (20140317)
is to be blamed. This is a bug in the PDF generating software...
Update
Maybe I should reveal how I dissected and uncompressed the MWE PDF:
Trying it with QPDF didn't work:
qpdf --qdf --object-streams=disable mwe_ar.pdf qdf.pdf
object stream 10 (file position 585): unexpected )
Trying it with pdftk didn't work either:
pdftk mwe_ar.pdf cat pdftk.pdf uncompress
Error: Unable to find file.
Error: Failed to open PDF file:
mwe_ar.pdf
Errors encountered. No output created.
Done. Input errors, so no output created.
Trying it with MuPDF's mutool also failed:
mutool clean -d mwe_ar.pdf mutool.pdf
warning: lexical error (unexpected ')')
error: invalid key in dict
error: cannot parse dict
error: cannot open object stream (10 0 R)
error: cannot load object stream containing object (1 0 R)
warning: cannot load object (1 0 R) into cache
warning: lexical error (unexpected ')')
error: invalid key in dict
error: cannot parse dict
error: cannot open object stream (10 0 R)
error: cannot load object stream containing object (4 0 R)
error: cannot load object (4 0 R) into cache
Finally, as a last resort, PeePDF.py to the rescue:
$ cat peepdf-commands.txt
object 10
$ peepdf.py -s peepdf-commands.txt
<< /Length 1000
/N 13
/Type /ObjStm
/Filter /FlateDecode
/First 84 >>
stream
9 0 3 72 11 133 2 197 1 312 15 343 4 446 14 625 19 876 6 1344 18 1514 5 1758 7 1886 <</Font<</F1 5 0 R/F2 7 0 R>>/ProcSet[/PDF/Text/ImageC/ImageB/ImageI]>>
<</Resources 9 0 R/Type/Page/Parent 11 0 R/Contents[8 0 R]>>
<</Type/Pages/Count 1/Kids[3 0 R]/MediaBox[0 0 595.28 841.89]>>
<</Creator( XeTeX output 2015.05.01:1207)/Producer(xdvipdfmx \(20140317\))/CreationDate(D:20150501120749+01'00')>>
<</Pages 11 0 R/Type/Catalog>>
[417[251]421[257]424[368]443[470]445[355]450[380]480[322]498[480 233]505[461]508[256]514[326]520[264]]
<</Type/Font/Subtype/CIDFontType2/BaseFont/GAKHDJ+#28AH)#20Manal#20Black/FontDescriptor 14 0 R/CIDSystemInfo<</Registry(Adobe)/Ordering(Identity)/Supplement 0>>/DW 199/W 15 0 R>>
<</Type/FontDescriptor/Ascent 529/Descent -415/StemV 109/CapHeight 529/AvgWidth 392/FontBBox[-112 -321 1006 1137]/ItalicAngle 0/Flags 6/Style<</Panose<000000000000000000000000>>>/FontName/GAKHDJ+#28AH)#20Manal#20Black/FontFile2 16 0 R/CIDSet 17 0 R>>
[39[693]41[522]51[535]108[415]124[415]388[218 926]402[1213]406[541]446[586]1886[317]1992[229]2016[366]2021[366]2105[244]2108[244]2139[1006]2150[295]2162[378]2227[379 452]2272[589]2294[176]2300[198]2308[389]2339[343]2356[723]2359[1079]2397[552]2413[346]2457[177]2491[299]2912[349]2952[219]2969[209]2973[148]2976[302]2981[341]3027[168]3149[550]3297[259]3325[292]3726[248]3732[319]3853[411]3893[179]4021[55]4323[104]4627[560]5068[238]5106[476]5322[159]5328[222]6366[93]]
<</Type/Font/Subtype/CIDFontType2/BaseFont/HTCSVQ+Amiri-Regular/FontDescriptor 18 0 R/CIDSystemInfo<</Registry(Adobe)/Ordering(Identity)/Supplement 0>>/DW 190/W 19 0 R>>
<</Type/FontDescriptor/Ascent 1123/Descent -635/StemV 87/CapHeight 1123/AvgWidth 685/FontBBox[-581 -900 11467 1815]/ItalicAngle 0/Flags 6/Style<</Panose<000000000500000000000000>>>/FontName/HTCSVQ+Amiri-Regular/FontFile2 20 0 R/CIDSet 21 0 R>>
<</Type/Font/Subtype/Type0/BaseFont/GAKHDJ+#28AH)#20Manal#20Black/Encoding/Identity-H/DescendantFonts[4 0 R]/ToUnicode 12 0 R>>
<</Type/Font/Subtype/Type0/BaseFont/HTCSVQ+Amiri-Regular/Encoding/Identity-H/DescendantFonts[6 0 R]/ToUnicode 13 0 R>>
endstream
The more often I use PeePDF.py, the more I love it. Thanks, Jose Miguel, for this wonderful tool!
I usually use pdftocairo to fix that:
pdftocairo corruptedinfile.pdf -pdf outfile.pdf
After that, ghostscript can handle it properly.