how do I create a file of the form .zpl to be used with SCIP? Do I write my problem in a notepad and save it as .zpl?
Yes. That is exactly what you have to do.
Related
I wonder there is any way to splitting some variables in VSCode?
my example will explain my question better:
I have an exe file in such path C:\path\to\workspace\main\project\project.exe
my cpp source path that will create exe file is this C:\path\to\workspace\main\project\test.cpp
I want to create a task in tasks.json but my oder of variables does not give me the right path
as you understand:
${workspaceFolder} is C:\path\to\workspace
${fileDirname} returns C:\path\to\workspace\main\project
and ${relativeFileDirname}.exe returns main\project.exe
and combination of "${fileDirname}\\${relativeFileDirname}.exe" as a command will return C:\path\to\workspace\main\project\main\project.exe that is wrong.
so I wanted to know there is any other variable that just return the parent of current file or not?
if not can we split variables with \ ?
I hope it makes some sense
thanks
Add new fileDirnameBasename variable
see https://github.com/microsoft/vscode/commit/551db7ec94f02a4bdc8999092cf8bef642b3992d
${fileDirnameBasename} is being added to vscode v1.52 which I believe is what you are looking for.
You can use the extension Command Variable
Use the commands:
extension.commandvariable.file.fileDirBasename
extension.commandvariable.file.fileDirBasename1Up
extension.commandvariable.file.fileDirBasename2Up
btw, as an workaround, this worked for me
"${fileDirname}\\*.exe"
but need a variable for getting parent folder of current open file
any idea?
i am programming with eiffel and every time i open a file and start writing into it, it deletes its content and starts writing into it like it's an empty file, is there a way to do it without deleting the previouse content?
Here is a example of code
local
f: PLAIN_TEXT_FILE
do
create f.make_open_write("C://myName/desktop//myfile.txt")
f.put_integer(3)
and now the file will contain 3 and all the previouse data will be lost!
Creation procedure make_open_append should be used in this case:
create f.make_open_append ("C:/myName/desktop/myfile.txt")
f.put_integer(3)
If you want to append text at the end of the file, use make_open_append like that:
f.make_open_append("C://myName/desktop//myfile.txt")
If you want to rewrite from the beginning of the file (like in your example, replacing the first character of the file with 3), you can open in read write mode and write to it like this:
f.make_open_read_write("C://myName/desktop//myfile.txt")
f.put_integer(3)
i'm trying to create a Sifteo game able to detect accelerometer data and write them on a file.txt;
I know that several methods exist that allow to visualize data on the shell (but it need to connect the base on the pc) or storing them in a StoredObject, but i'd like to create a text file.
In the documentation of sifteo sdk I found something about script lua.
I didn't understand it, Can you help me???
Thanks
If you're simply asking for how to make a .txt file in a lua script it should be something like
file = io.open("FileName.txt","w")
file:write("Information")
file:close()
If you're new to lua you can also insert information from a variable or a table by replacing it with the string "Information".
Hope this helped.
i try to rename a file using vb.net in this way:
my.computer.filesyste.rename(oldname,newname)
But if i use a software to recover files deleted, i find a file named :"_ldname", and if i recovery the file "_ldname" i have, in this way, two files equals.
Can i do this without have a duplicate of my file?
Best regards
Sebastiano
You cannot, this is a windows filesystem limitation and nothing to do with programming. Two files cannot have the same name in the same location.
The recovery software should be forcing a rename to Myfile(1).txt or something like that to distinguish between the two files.
You could always use:
If File.Exists(path) = False Then
To make sure the file doesn't already exists. Then if it does exist you could add a "(1)" to the file name.
By default AutoCAD installs a text based file called acad2010.lsp at the set location below
Dim FILE_NAME As String = "C:\Program Files\AutoCAD 2010\Support\acad2010.lsp"
However it my be that the user/ administrator/ or third party has changed the location of this file. Is it possible to then locate it using the following
Dim FILE_NAME As String = "C:\*\acad2010.lsp"
In other words search the entire c:\ drive for file acad2010.lsp?
If this doesn't work can you please let me know what would?
You could search for it with an FSO. It's not going to be fast however you do it but this is the fastest way I can think of.
http://www.microbion.co.uk/developers/fso.htm should give you a rough idea of how it's done.
Your solution will not work. Is not possible to locate it using *. (BTW is possible in ms-builds scripts). The only way of doing it is:
1- Create a FindFile function (check for example
http://xlvba.3.forumer.com/index.php?showtopic=125)
2- Use it to locate the exact path of the file. (It could be really time
consuming)
3- From this point your code is the same...
Unfortunately, you can't use wildcards in a filepath. You have two options:
Prompt the user for the file location using the "Open File" dialog. The code to do this varies based on which Office product you are using. In Excel, you would use the Application.FindFile method (more info here).
Write your own function to search the filesystem for the file. Microsoft provides an example here.
If that file is used by internal functions of the application, the installer will have recorded a registry key for the file's location.
Open regedit.exe and search for the file name and path.
You can read a registry entry using this VBA one-liner:
CreateObject("WScript.Shell").RegRead(strRegPath)
You may need a terminating backslash on the key address, but that's a safe and simple registry access method. More details on the MSDN site:
https://msdn.microsoft.com/en-us/library/x05fawxd%28v=vs.84%29.aspx