I have texts like "DBName_TemplateDB_TESTDB01234_document" and "DBName_TemplateDB_TESTDB01234678_document". From both texts need to extract string between second underscore() and last underscore() like "TESTDB01234" and "TESTDB01234678".
Can you please help how to string in SQL Server using SUBSTRING and CHARINDEX?
Example:
Input Text: 'DBName_TemplateDB_TESTDB01234_document'
Output: TESTDB01234
Input Text: 'DBName_TemplateDB_TESTDB01234678_document'
Output: TESTDB01234678
I tried to extract and it's working only from the first underscore like below.
declare #Dbname varchar(max) = '#new#-TESTDB01234_document'
select substring( LEFT(#DbName,charindex('_',#DbName)-1),charindex('TEST',#DbName),len(LEFT(#DbName,charindex('_',#DbName)))-1)
Will this work for you?
--OPTION ONE: SUBSTRING
DECLARE #Start INT = CHARINDEX('TEST', #Dbname);
DECLARE #End INT = LEN(#Dbname) - (CHARINDEX('_', REVERSE(#Dbname)) - 1) - #Start;
SELECT SUBSTRING(#Dbname, #Start, #End) AS [Name]
--OPTION TWO: DOUBLE REPLACE
SELECT REPLACE(REPLACE(#Dbname, 'DBName_TemplateDB_', ''), '_document', ''); AS [Name]
--OPTION THREE: STRING_SPLIT
SELECT TOP 1 value AS [Name]
FROM STRING_SPLIT(#Dbname, '_')
WHERE value LIKE 'Test%'
I added a few options, sorry if its outside the scope of the question.
Using charindex
declare #Dbname varchar(max) = 'DBName_TemplateDB_TESTDB01234678_document'
select right(left(#DbName,third - 1), third - second - 1)
from (
select charindex('_',#DbName,charindex('_',#DbName) + 1) second,
charindex('_',#DbName,charindex('_',#DbName,charindex('_',#DbName) + 1) + 1) third
) t
If you are looking for data between the second and the last underscore, I will give the following approach as there might be more underscores between these ones:
declare #Dbname varchar(max) = 'DBName_TemplateDB_TESTDB01234678_1_2_3_document'
DECLARE #DbnameXML XML = '<a>' + REPLACE(#Dbname, '_', '</a><a>') + '</a>';
SELECT STRING_AGG([value], '_') WITHIN GROUP (ORDER BY [value_id])
FROM
(
SELECT ROW_NUMBER() OVER (ORDER BY T.c) - 1
,T.c.value('.', 'VARCHAR(128)')
,COUNT(1) OVER()
FROM #DbnameXML.nodes('a') T(c)
) DS ([value_id], [value], [values_count])
WHERE [value_id] > 1
AND [value_id] + 1 < [values_count]
I have a sample string like below and this string always contains the word "Inventory Charge[0.00068]"
DECLARE #Text NVARCHAR(MAX) = 'Materials Discount[0] ) + Inventory Charge[0.00068] Second gfggfdgfd gfgfgfgf'
would like to get value in between brackets for Inventory Charge.
Required output: 0.00068
I have tried with substring but not able to get the desired result. Please help.
DECLARE #Text NVARCHAR(MAX) = 'Materials Discount[0] ) + Inventory Charge[0.00068] Second'
SELECT SUBSTRING(#Text, CHARINDEX('Inventory Charge[', #Text) +
LEN('Inventory Charge[') + 1, CHARINDEX(']',#Text)
- (CHARINDEX('Inventory Charge[', #Text) + 2 + LEN('Inventory Charge[')) )
I find this type of thing easier to work out when breaking it down. It also helps avoid repeating the initial search for the starting substring location:
declare #text NVARCHAR(MAX) = 'Materials Discount[0] ) + Inventory Charge[0.00068] Second'
declare #leftSearchStr nvarchar(20) = 'Inventory Charge['
declare #rightSearchStr nvarchar(20) = ']'
declare #startPos int = charindex(#leftSearchStr, #text, 1) + LEN(#leftSearchStr)
declare #endPos int = charindex(#rightSearchStr, #text, #startPos)
SELECT SUBSTRING(#text, #startPos, #endPos - #startPos)
I solved it like this. Surely there is a better way to solve this, but this works.
DECLARE #Text NVARCHAR(MAX) = 'Materials Discount[0] ) + Inventory Charge[0.00068] Second',
#Trim1 NVARCHAR(MAX),
#Trim2 NVARCHAR(MAX)
SET #Trim1 = SUBSTRING(#Text, CHARINDEX('[', #Text) + 1,LEN(#Text))
SET #Trim2 = SUBSTRING(#Trim1, CHARINDEX('[', #Trim1) + 1, LEN(#Trim1))
SELECT LEFT(#Trim2, LEN(#Trim2) - CHARINDEX(']', #Trim2) - 3)
If you know that the string you want to select is the Last bracketed selection, then we can simply use REVERSE and then find the first bracketed value.
If you have to do this in a single operation, I find it easier to incorporate a CROSS APPLY to calculate the steps in between:
DECLARE #Text NVARCHAR(MAX) = 'Materials Discount[0] ) + Inventory Charge[0.00068] Second'
SELECT Reverse(SubString(RevText, [RLeft], [RRight]-[RLeft]))
FROM ( SELECT REVERSE(#Text) as RevText) text
OUTER APPLY (SELECT CHARINDEX(']', RevText) + 1 as [RLeft],
CHARINDEX('[', revText) as [RRight]) Calcs
If you don't know for sure that the search term is the first or last bracket, then we just need to search on the prefix first, and use that as the start location for the CharIndex function:
SELECT SubString([Text], [Left], [Right]-[Left])
FROM ( SELECT #Text as [Text], 'Inventory Charge[' as prefix ) inputs
OUTER APPLY (SELECT CHARINDEX(prefix, [Text]) + LEN(prefix) as [Left]) Calcs1
OUTER APPLY (SELECT CHARINDEX(']', [Text], [Left]) as [Right]) Calcs2
You can get a little bit fancy using STRING_SPLIT to tokenize the input for you too, note that you need to split by the close bracket so that the value and the field prefix are in the same result:
This solution uses REVERSE again because we know the token is at the end of the line, so we can use LEFT logic to save an index lookup
SELECT Reverse(LEFT(REVERSE(value), CHARINDEX('[', REVERSE(value))-1))
FROM String_Split(#Text, ']') s
WHERE s.value LIKE '%Inventory Charge%'
Or you can use SUBSTRING again:
SELECT SUBSTRING(value,[LEFT],[Length] - [Left] + 1)
FROM String_Split(#Text, ']') s
CROSS APPLY (SELECT CHARINDEX('[', value) + 1 as [LEFT], LEN(value) as [Length]) calcs
WHERE s.value LIKE '%Inventory Charge%'
I got the following entry in my database:
images/test.jpg
I want to trim the entry so I get: test
So basically, I want everything after / and before .
How can I solve it?
use the following function
left(#test, charindex('/', #test) - 1)
If you want to get this out of your table using SQL, take a look at the following functions that will help you: SUBSTRING and CHARINDEX. You can use those to trim your entries.
A possible query will look like this (where col is the name of the column that contains your image directories:
SELECT SUBSTRING(col, LEN(SUBSTRING(col, 0, LEN(col) - CHARINDEX ('/', col))) + 1,
LEN(col) - LEN(SUBSTRING(col, 0, LEN(col) - CHARINDEX ('/', col))) - LEN(SUBSTRING(
col, CHARINDEX ('.', col), LEN(col))));
Bit of an ugly beast. It also depends on the standard format of 'dir/name.ext'.
Edit:
This one (inspired by praveen) is more generic and deals with extensions of different length:
SELECT SUBSTRING(col, LEN(LEFT(col, CHARINDEX ('/', col))) + 1, LEN(col) - LEN(LEFT(col,
CHARINDEX ('/', col))) - LEN(RIGHT(col, LEN(col) - CHARINDEX ('.', col))) - 1);
Before
SELECT SUBSTRING(ParentBGBU,0,CHARINDEX('/',ParentBGBU,0)) FROM dbo.tblHCMMaster;
After
SELECT SUBSTRING(ParentBGBU,CHARINDEX('-',ParentBGBU)+1,LEN(ParentBGBU)) FROM dbo.tblHCMMaster
----select characters before / including /
select SUBSTRING ('abcde/wxyz',0,CHARINDEX('/','abcde/wxyz')+1)
--select characters after / including /
select SUBSTRING('abcde/wxyz',CHARINDEX('/','abcde/wxyz'),LEN('abcde/wxyz'))
declare #T table
(
Col varchar(20)
)
insert into #T
Select 'images/test1.jpg'
union all
Select 'images/test2.png'
union all
Select 'images/test3.jpg'
union all
Select 'images/test4.jpeg'
union all
Select 'images/test5.jpeg'
Select substring( LEFT(Col,charindex('.',Col)-1),charindex('/',Col)+1,len(LEFT(Col,charindex('.',Col)-1))-1 )
from #T
I have made a method which is much more general :
so :
DECLARE #a NVARCHAR(MAX)='images/test.jpg';
--Touch here
DECLARE #keysValueToSearch NVARCHAR(4000) = '/'
DECLARE #untilThisCharAppears NVARCHAR(4000) = '.'
DECLARE #keysValueToSearchPattern NVARCHAR(4000) = '%' + #keysValueToSearch + '%'
--Nothing to touch here
SELECT SUBSTRING(
#a,
PATINDEX(#keysValueToSearchPattern, #a) + LEN(#keysValueToSearch),
CHARINDEX(
#untilThisCharAppears,
#a,
PATINDEX(#keysValueToSearchPattern, #a) + LEN(#keysValueToSearch)
) -(PATINDEX(#keysValueToSearchPattern, #a) + LEN(#keysValueToSearch))
)
SELECT Substring('ravi1234#gmail.com', 1, ( Charindex('#', 'ravi1234#gmail.com')
- 1 ))
Before,
RIGHT('ravi123#gmail.com', ( Charindex('#', 'ravi123#gmail.com') + 1 ))
After
I just did this in one of my reports and it was very simple.
Try this:
=MID(Fields!.Value,8,4)
Note: This worked for me because the value I was trying to get was a constant not sure it what you are trying to get is a constant as well.
I know this has been a while.. but here is an idea
declare #test varchar(25) = 'images/test.jpg'
select
#test as column_name
, parsename(replace(#test,'/','.'),1) as jpg
,parsename(replace(#test,'/','.'),2) as test
,parsename(replace(#test,'/','.'),3) as images
I found Royi Namir's answer useful but expanded upon it to create it as a function. I renamed the variables to what made sense to me but you can translate them back easily enough, if desired.
Also, the code in Royi's answer already handled the case where the character being searched from does not exist (it starts from the beginning of the string), but I wanted to also handle cases where the character that is being searched to does not exist.
In that case it acts in a similar manner by starting from the searched from character and returning the rest of the characters to the end of the string.
CREATE FUNCTION [dbo].[getValueBetweenTwoStrings](#inputString
NVARCHAR(4000), #stringToSearchFrom NVARCHAR(4000), #stringToSearchTo
NVARCHAR(4000))
RETURNS NVARCHAR(4000)
AS
BEGIN
DECLARE #retVal NVARCHAR(4000)
DECLARE #stringToSearchFromSearchPattern NVARCHAR(4000) = '%' +
#stringToSearchFrom + '%'
SELECT #retVal = SUBSTRING (
#inputString,
PATINDEX(#stringToSearchFromSearchPattern, #inputString) + LEN(#stringToSearchFrom),
(CASE
CHARINDEX(
#stringToSearchTo,
#inputString,
PATINDEX(#stringToSearchFromSearchPattern, #inputString) + LEN(#stringToSearchFrom))
WHEN
0
THEN
LEN(#inputString) + 1
ELSE
CHARINDEX(
#stringToSearchTo,
#inputString,
PATINDEX(#stringToSearchFromSearchPattern, #inputString) + LEN(#stringToSearchFrom))
END) - (PATINDEX(#stringToSearchFromSearchPattern, #inputString) + LEN(#stringToSearchFrom))
)
RETURN #retVal
END
Usage:
SELECT dbo.getValueBetweenTwoStrings('images/test.jpg','/','.') AS MyResult
I got some invalid length errors. So i made this function, this should not give any length problems. Also when you do not find the searched text it will return a NULL.
CREATE FUNCTION [FN].[SearchTextGetBetweenStartAndStop](#string varchar(max),#SearchStringToStart varchar(max),#SearchStringToStop varchar(max))
RETURNS varchar(max)
BEGIN
SET #string = CASE
WHEN CHARINDEX(#SearchStringToStart,#string) = 0
OR CHARINDEX(#SearchStringToStop,RIGHT(#string,LEN(#string) - CHARINDEX(#SearchStringToStart,#string) + 1 - LEN(#SearchStringToStart))) = 0
THEN NULL
ELSE SUBSTRING(#string
,CHARINDEX(#SearchStringToStart,#string) + LEN(#SearchStringToStart) + 1
,(CHARINDEX(#SearchStringToStop,RIGHT(#string,LEN(#string) - CHARINDEX(#SearchStringToStart,#string) + 1 - LEN(#SearchStringToStart)))-2)
)
END
RETURN #string
END
if Input= pg102a-wlc01s.png.intel.com and Output should be pg102a-wlc01s
we can use below query :
select Substring(pc.name,0,charindex('.',pc.name,0)),pc.name from tbl_name pc
You can try this:
Declare #test varchar(100)='images/test.jpg'
Select REPLACE(RIGHT(#test,charindex('/',reverse(#test))-1),'.jpg','')
Below query gives you data before '-'
Ex- W12345A-4S
SELECT SUBSTRING(Column_Name,0, CHARINDEX('-',Column_Name)) as 'new_name'
from [abc].
Output - W12345A
Inspired by the work of Josien, I wondered about a simplification.
Would this also work? Much shorter:
SELECT SUBSTRING(col, CHARINDEX ('/', col) + 1, CHARINDEX ('.', col) - CHARINDEX ('/', col) - 1);
(I can't test right now because of right issues at my company SQL server, which is a problem in its own right)
Simply Try With LEFT ,RIGHT ,CHARINDEX
select
LEFT((RIGHT(a.name,((CHARINDEX('/', name))+1))),((CHARINDEX('.', (RIGHT(a.name,
((CHARINDEX('/', name))+1)))))-1)) splitstring,
a.name
from
(select 'images/test.jpg' as name)a
declare #searchStart nvarchar(100) = 'search ';
declare #searchEnd nvarchar(100) = ' ';
declare #string nvarchar(4000) = 'This is a string to search (hello) in this text ';
declare #startIndex int = CHARINDEX(#searchStart, #string,0) + LEN(#searchStart);
declare #endIndex int = CHARINDEX(#searchEnd, #string, #startIndex + 1);
declare #length int = #endIndex - #startIndex;
declare #sub nvarchar(4000) = SUBSTRING(#string, #startIndex, #length)
select #startIndex, #endIndex, #length, #sub
This is a little more legible than the one-liners in this answer which specifically answer the question, but not in a generic way that would benefit all readers. This could easily be made into a function as well with a slight modification.
If there are more than one or none occurences of given character use this:
DECLARE #rightidx int = CASE
WHEN 'images/images/test.jpg' IS NULL OR (CHARINDEX('.', 'images/images/test.jpg')) <= 0 THEN LEN('images/images/test.jpg')
ELSE (CHARINDEX('.', REVERSE('images/images/test.jpg')) - 1)
END
SELECT RIGHT('images/images/test.jpg', #rightidx)
This was the approach I took.
CREATE FUNCTION dbo.get_text_before_char(#my_string nvarchar(255),#my_char char(1))
RETURNS nvarchar(255)
AS
BEGIN;
return IIF(#my_string LIKE '%' + #my_char + '%',left (#my_string, IIF(charindex(#my_char, #my_string) - 1<1,1,charindex(#my_char, #my_string) - 1)),'');
END;
CREATE FUNCTION dbo.get_text_after_char(#my_string nvarchar(255),#my_char char(1))
RETURNS nvarchar(255)
AS
BEGIN;
return IIF ( #my_string LIKE '%' + #my_char + '%' ,RIGHT ( #my_string , IIF ( charindex ( #my_char ,reverse(#my_string) )-1 < 1 ,1 ,charindex ( #my_char ,reverse(#my_string) )-1 ) ) , '' )
END;
SELECT
dbo.get_text_before_char('foo-bar','-')
, dbo.get_text_after_char('foo-bar','-')
declare #test varchar(100)='images/test.jpg'
select right(left(#test, charindex('.', #test) - 1),4)
I have the following string.
Input
--------------
2030031469-NAI
To get the numeric part, I am using the following script
declare #str varchar(50)= '2030031469-NAI'
Select
#str
,SUBSTRING(#str, 1, NULLIF(CHARINDEX('-', #str) - 1, -1))
,Left(#str,PATINDEX('%-%',#str)-1)
to get the following output
Output:
----------
2030031469
Is there any other easy/elegant way of doing the same?
select left(#str, patindex('%[^0-9]%', #str+'.') - 1)
In case your string start with alphabet and end with number like ERT-123
you can use this query:
(select substring(#str,patindex('%[0-9]%', #str),len(#str)))
Please check with this, i used in my project for extracting phone numbers
CREATE Function [dbo].[RemoveNonNumericCharacters](#Temp VarChar(1000))
Returns VarChar(1000)
AS
Begin
While PatIndex('%[^0-9]%', #Temp) > 0
Set #Temp = Stuff(#Temp, PatIndex('%[^0-9]%', #Temp), 1, '')
Return #TEmp
End
To extract number from an unformatted string
DECLARE #Text NVARCHAR(100)= 'extract only 23124R integer ##%%'
SELECT SUBSTRING(#Text, PATINDEX('%[0-9]%',#Text), PATINDEX('%[^0-9]%',SUBSTRING(#Text, PATINDEX('%[0-9]%',#Text), LEN(#Text)))-1) [ONLY_INT]