separate values from a string using SQL - sql

Question

I have this requirement where we need to separate values from a string the format of the is like
{Feature1=Value1} | {Feature2=Value2} | .. | {FeatureN=ValueN}
{12345=Gold}|{12346=Silver}
so need to separate features and values from the given srting..
To separate PIPE separated values i am using..
select *
from xmltable('r/c' passing xmltype('<r><c>' || replace('{12345=Gold}|{12346=Silver}','|','</c><c>') || '</c></r>')
columns new_str varchar2(30) path '.');
NEW_STR
------------------------------
{12345=Gold}
{12346=Silver}
I am writing a PLSQL block which iterate through each pipe separate values using above query.
I can store these values in PLSQL variable.
Now another task here is to get features and values from two above strings for this i write below SQL
select substr ('{12345=Gold}',2, instr('{12345=Gold}', '=')-2) features from dual;
FEATURES
----------------------
12345
SELECT SUBSTR('{12345=Gold}', instr('{12345=Gold}', '=')+1, LENGTH(substr ('{12345=Gold}', instr('{12345=Gold}', '=')+1, INSTR('{12345=Gold}', '}', 2)))-1) value FROM DUAL;
VALUE
--------------
Gold
So here i am able to get the features and values from a string......
I am looking for another or alternate SQL for my SQL's specially for the last one i find it complex function use so if you have any better idea for the above scenario then please Post !
Please ask if the scenario is not clear
MY DB is --
Oracle Database 12c Enterprise Edition Release 12.1.0.2.0 - 64bit Production

Answer 1

with line as (
select '{12345=Gold}|{12346=Silver}|{12399=Copper}' str from dual)
select substr (parse, 2, instr(parse,'=')-2) as feature
,substr (parse, instr(parse,'=')+1, length(parse)-instr(parse,'=')-1 ) as value
from
(select distinct regexp_substr(str, '[^|]+', 1, level) as parse
from line
connect by regexp_substr(str, '[^|]+', 1, level) is not null)

Answer 2

Here is a way using types and a handy built-in package called apex_util:
create type keyval_t is object (key varchar2(10), value varchar2(100));
/
create type keyval_tab_t is table of keyval_t;
/
create or replace package test_pkg is
function keyval_tab (p_keyval_string varchar2) return keyval_tab_t;
end;
/
create or replace package body test_pkg is
function keyval_tab (p_keyval_string varchar2) return keyval_tab_t
is
l_tab apex_application_global.vc_arr2;
l_tab2 apex_application_global.vc_arr2;
l_keyval_tab keyval_tab_t := keyval_tab_t();
l_str long;
begin
-- Split string at pipe delimiters
l_tab := apex_util.string_to_table (p_keyval_string, '|');
-- For each {key=value} pair
for i in 1..l_tab.count loop
l_str := l_tab(i);
-- Remove the {}
l_str := ltrim (l_str, '{ ');
l_str := rtrim (l_str, '} ');
-- Split string into key and value
l_tab2 := apex_util.string_to_table (l_str, '=');
if l_tab2.count = 2 then
l_keyval_tab.extend;
l_keyval_tab(i) := keyval_t (l_tab2(1), l_tab2(2));
else
-- ?? invalid string
null;
end if;
end loop;
return l_keyval_tab;
end;
end;
/
Now you can query:
SQL> select value from table(test_pkg.keyval_tab ('{12345=Gold}|{12346=Silver}'))
2* where key='12346';
VALUE
--------------------------------------------------------------------------------
Silver
SQL> select key from table(test_pkg.keyval_tab ('{12345=Gold}|{12346=Silver}'))
2 where value='Gold';
KEY
----------
12345

Answer 3

Use this query to get your expected output. Sorry if there are too many replace functions. But this is quite easier.
select EXTRACTVALUE (COLUMN_VALUE, '/row/Code') code,
EXTRACTVALUE (COLUMN_VALUE, '/row/Value') Value
from TABLE(XMLSEQUENCE(EXTRACT(XMLTYPE('<rowset><row>'||replace(replace(replace(replace('{12345=Gold}|{12346=Silver}','}|{','</Value></row><row><Code>'),'{','<Code>'),'=','</Code><Value>'),'}','</Value>')||'</row></rowset>'),'/rowset/row')));

Answer 4

If you already have separated columns into rows the work to do is fairly simple with REGEXP_REPLACE function.
Considering that your cols now is:
NEW_STR
--------------
{12345=Gold}
{12346=Silver}
You can do this sql to transform it into two different columns:
select regexp_replace( col, '\{(\d+)=\w+\}', '\1' ) as feature,
regexp_replace( col, '\{\d+=(\w+)\}', '\1' ) as value
from testTable
Transform that into a view and then just select with columns as you like:
create or replace view testView as
select regexp_replace( col, '\{(\d+)=\w+\}', '\1' ) as feature,
regexp_replace( col, '\{\d+=(\w+)\}', '\1' ) as value
from testTable
Then just do:
select * from testView where feature = '12345'
Or
Select * from testView where value = 'Gold'
If you like to transform the feature value as a number just use the to_number function on that column as:
to_number(regexp_replace( col, '\{(\d+)=\w+\}', '\1' ))
Remember that in order to do this you must be absolute sure that it is only numbers on that, otherwise you will have conversion errors

Answer 5

You can also use a pivot table and REGEXP_SUBSTR
with MyStrings as
(select '{Feature1=Value1}|{Feature2=Value2}|{FeatureN=ValueN}' Str from dual
union all
select '{12345=Gold}|{12346=Silver}' from dual
)
,pivot as (
Select Rownum Pnum
From dual
Connect By Rownum <= 100
)
SELECT rownum rn
,REGEXP_SUBSTR (ms.Str,'[^|]+',1,pv.pnum) TXT
FROM MyStrings ms
,pivot pv
where REGEXP_SUBSTR (ms.Str,'[^|]+',1,pv.pnum) is not null