I have two temp tables (below), the first marks one of five conditions. The second pulls from that table and does a sum and a count based on the condition. How could I get the second table to work with this, or a similar format?
select ID
,sum_value
,condition_field
,'condition_1' = case when condition_type in (1,2) then 1 else 0 end
,'condition_2' = case when condition_type in (3,4) then 1 else 0 end
--etc...
into #temp
from my_table
select ID
,sum_value
,'1_amt' = SUM(sum_value) from #temp where condition_1 = 1
,'1_cnt' = COUNT(ID) from #temp where condition_1 = 1
,'2_amt' = SUM(sum_value) from #temp where condition_2 = 1
,'2_cnt' = COUNT(ID) form #temp where condition_2 = 2
from #temp
You want something more like this:
SUM(CASE WHEN condition_1=1 THEN sum_value ELSE 0 END) AS 1_amt
Related
I have table:
Id Value
1 79868
2 79868
3 79868
4 97889
5 97889
Now, I want to make next select with bool variable that check if table contains difrent values at table column Value. Something like this:
select
v= (select case when exists(...)
then 1
else 0
end)
Table contais Values: 79868, 97889 so v should return 1 in other case 0.
How to write select iniside select case??
You can compare the min and max values:
select (case when (select min(value) from t) = (select max(value) from t)
then 1 else 0
end) as all_same
With an index on (value), this should be quite fast.
The above solution assumes that there are no null values or that NULL values should be ignored.
You might try this:
SELECT CASE COUNT(*)
WHEN 1 THEN 1
ELSE 0
END AS all_equal
FROM (SELECT DISTINCT Value FROM my_table);
If I get your question correct, you want to check if value column contains more than 1 distinct values. You can achieve this using,
select (case when count(value) > 1 then 1 else 0 end) as out
from (select value from table group by value) temp
May this is better:
SELECT CASE COUNT(DISTINCT value) WHEN 1 THEN 1
ELSE 0
END AS all_equal
FROM my_table;
So, you just need one case expression with two Boolean variable
declare #bit1 bit = 1, #bit0 bit = 0
select
(case when min(value) = max(value) then #bit1 else #bit0 end) as v
from table t
where value is not null
This is a the same as another answers
But is has some test data
declare #T table(pk int identity primary key, val int not null);
insert into #T (val) values (79868), (79868), (79868);
select case when count(distinct(val)) = 1 then 0 else 1 end as dd
from #t t;
select case when min(val) = max(val) then 0 else 1 end as dd
from #t t;
insert into #T (val) values (97889), (97889);
select case when count(distinct(val)) = 1 then 0 else 1 end as dd
from #t t;
select case when min(val) = max(val) then 0 else 1 end as dd
from #t t;
I like the min max answer from Gordon best
The following SQL (on SQL Server) returns an error of:
Incorrect syntax near '*'
Is there something inherently wrong with using the following SELECT statement?:
SELECT
COUNT(CASE WHEN <conditions> THEN * ELSE NULL END) as conditionalcountall
FROM TABLE
I tried this variation which also failed:
SELECT
CASE WHEN <conditions> THEN COUNT(*) ELSE NULL END as conditionalcountall
FROM TABLE
I tend to like sum()
SELECT
SUM(CASE WHEN <conditions> THEN 1 ELSE 0 END) as conditionalcountall
FROM TABLE
Try This, it is Tested
SELECT
CASE WHEN 1 = 1 THEN COUNT(*) ELSE NULL END as conditionalcountall
FROM TABLE
1 = 1is example conditions
Demo:-
Create table #temp (id int , col1 varchar (10))
go
insert into #temp values (1 , 'aaaa')
insert into #temp values (2 , 'bbbb')
insert into #temp values (3 , 'cccc')
SELECT
CASE WHEN 1 = 1 THEN COUNT(*) ELSE NULL END as conditionalcountall
FROM #temp
Result:
In Case Condation like that id = 1 you should select Count(*) in CASE cluse in your query
like this:
SELECT
CASE WHEN id = 1 THEN (select COUNT(*) from #temp) ELSE NULL END as conditionalcountall
FROM #temp
Result:-
Note: if You used Count(*) directly, you counted the id column, so you should use group by as next:
SELECT
CASE WHEN id = 1 THEN COUNT(*) ELSE NULL END as conditionalcountall
FROM #temp
group by id
Result:
SELECT
CASE WHEN X THEN Y
ELSE Z
END *NEW COLUMN NAME*
, COUNT(*)
FROM
TABLE
GROUP BY
*NEW COLUMN NAME*
This should return two columns, one with the buckets/case statement and one with the count of the columns for each one of your buckets
This method was the most straightforward for myself
If you REALLY, REALLY want to use COUNT, then you can do this:
SELECT
COUNT(*)
FROM table
WHERE <conditions>
I am have a table with data and now i need to return zero in select statement if there is no records in table for example. I need to use it in Stored Procedure.
-- If no records exists in below select statement
SELECT ID,Text,Date FROM tblData WHERE ID = 12
IF (##ROWCOUNT = 0)
BEGIN
SELECT -5 AS ID
END
Output:
ID Text Date
ID
-5
Expected output
ID
-5
If you want to return 1 row even when there is no match, you can use aggregation:
SELECT (CASE WHEN COUNT(*) = 0 THEN -5 ELSE MAX(ID) END) as ID
FROM tblData
WHERE ID = 12;
I always use an Exists statment.
if exists(SELECT ID FROM tblData WHERE ID = 12)
select 0 as RowsExist
else
select 1 as RowsExist
For a single scalar value you could use something like;
SELECT ISNULL((SELECT ID FROM tblData WHERE ID = 12), 0) as ID
Rhys
SELECT (CASE WHEN Ta.ID IS NULL THEN TBL.ID
ELSE Ta.ID END) AS ID,Ta.Text,Ta.Date
FROM (VALUES(-5)) AS TBL(ID)
LEFT JOIN
(
SELECT ID,Text,Date FROM tblData WHERE ID = 12
)
AS Ta ON Ta.ID = Ta.ID
I have the following SQL (example):
SET #Return_Value = = (SELECT Top 1
(CASE WHEN .... THEN ColumValue1 ELSE ColumValue2 END)
FROM TableA WHERE (Lots of AND Statements)
AND
(
(bla1)
OR
(bla2)
OR
(bla3)
)
The bla1, etc are logic to retrieve colum values from TableA. How can I return the values from bla1 if they were found without executing bla2 or bla3 because those might overwrite what I'm looking for? In other words I only want to execute OR statements if the previous one didn't find data, all this within a function.
You can use a case expression as :
SET #Return_Value = (SELECT Top 1
(CASE WHEN .... THEN ColumValue1 ELSE ColumValue2 END)
FROM TableA WHERE (Lots of AND Statements)
AND
( 1 = case when condition1 then 1
case when condition2 then 1
case when condition3 then 1
end
);
you can use order by, like
select Top 1
CASE WHEN .... THEN ColumValue1 ELSE ColumValue2 END
FROM TableA
WHERE
(Lots of AND Statements) AND
(
(bla1) OR
(bla2) OR
(bla3)
)
order by
case
when (bla1) then 1
when (bla2) then 2
when (bla3) then 3
else 999
end
Or you can try to simplify it (but you have to check performance):
select Top 1
CASE WHEN .... THEN ColumValue1 ELSE ColumValue2 END
FROM TableA
outer apply (
select
case
when (bla1) then 1
when (bla2) then 2
when (bla3) then 3
end as T
) as C
WHERE
(Lots of AND Statements) and
C.T is not null
order by C.T
or, for example, you can use union, something like this:
with cte as (
select Top 1
CASE WHEN .... THEN ColumValue1 ELSE ColumValue2 END as data
FROM TableA
WHERE
(Lots of AND Statements)
), cte2 as (
select top 1 data, 1 as c from cte where (bla1)
union all
select top 1 data, 2 as c from cte where (bla2)
union all
select top 1 data, 3 as c from cte where (bla3)
)
select top 1 data
from cte2
order by c
I have a inventory table with a condition i.e. new, used, other, and i am query a small set of this data, and there is a possibility that all the record set contains only 1 or all the conditions. I tried using a case statement, but if one of the conditions isn't found nothing for that condition returned, and I need it to return 0
This is what I've tried so far:
select(
case
when new_used = 'N' then 'new'
when new_used = 'U' then 'used'
when new_used = 'O' then 'other'
end
)as conditions,
count(*) as count
from myDB
where something = something
group by(
case
when New_Used = 'N' then 'new'
when New_Used = 'U' then 'used'
when New_Used = 'O' then 'other'
end
)
This returns the data like:
conditions | count
------------------
new 10
used 45
I am trying to get the data to return like the following:
conditions | count
------------------
new | 10
used | 45
other | 0
Thanks in advance
;WITH constants(letter,word) AS
(
SELECT l,w FROM (VALUES('N','new'),('U','used'),('O','other')) AS x(l,w)
)
SELECT
conditions = c.word,
[count] = COUNT(x.new_used)
FROM constants AS c
LEFT OUTER JOIN dbo.myDB AS x
ON c.letter = x.new_used
AND something = something
GROUP BY c.word;
try this -
DECLARE #t TABLE (new_used CHAR(1))
INSERT INTO #t (new_used)
SELECT t = 'N'
UNION ALL
SELECT 'N'
UNION ALL
SELECT 'U'
SELECT conditions, ISNULL(r.cnt, 0) AS [count]
FROM (
VALUES('U', 'used'), ('N', 'new'), ('O', 'other')
) t(c, conditions)
LEFT JOIN (
SELECT new_used, COUNT(1) AS cnt
FROM #t
--WHERE something = something
GROUP BY new_used
) r ON r.new_used = t.c
in output -
new 2
used 1
other 0
You can do it as a cross-tab:
select
sum(case when new_used = 'N' then 1 else 0 end) as N,
sum(case when new_used = 'U' then 1 else 0 end) as U,
sum(case when new_used = 'O' then 1 else 0 end) as Other
from myDB
where something = something