I have two columns called
1ST column Calendar Date:
16/02/2015
2nd Column Previous Day:
Yes
Formula I am currently using:
if([calendar Date])=today-1,"YES","NO").
The 2nd column returns value based on the 1st column.
However , the problem I am getting is when I run the data on monday when we have calendar date (day on friday). So it is showing "NO" as formula only returns data for previous day.
So I want something like this
Only when I run on Monday it should give me if([calendar Date])=today-3,"YES","NO").And all other workdays if([calendar Date])=today-1,"YES","NO")
Can you please help me on this.
If you cell A2 has the calender date then try with below formula.
=IF(WEEKDAY(A2)=6,(IF(A2=TODAY()-3,"YES","NO")),(IF(A2=TODAY()-1,"YES","NO")))
=IF(WEEKDAY(TODAY())=2,IF(TODAY()-3 = A12, "YES", "NO"), IF(TODAY()-1 = A12, "YES", "NO"))
first, identify whether the date today is monday or the other day of the week.
IF(WEEKDAY(TODAY())=2
If today is monday, then you can create the condition that the previous day must be friday [today()-3].
IF(TODAY()-3 = A12, "YES", "NO")
If today is not monday, then create the condition that the previous day is the date yesterday [today()-1].
IF(TODAY()-1 = A12, "YES", "NO")
To disregard weekends and holidays, you will want either the NETWORKDAYS or
NETWORKDAYS.INTL¹ function. Not only can you skip a conventional Sat/Sun weekend but you can add a reference to a list of holidays to be discounted as well. The newer NETWORKDAYS.INTL has a large selection of built-in non-standard 'weekend' formats or you can write your own. e.g. "0000011" is a standard Sat/Sun weekend and "0101000" is a Tue and Thu 'weekend'.
Both NETWORKDAYS and NETWORKDAYS.INTL count the number of days inclusively so you are looking for a value of 2, not 1.
For the following example, I've reset the computer's system date to Tue 19-Jan-2016 (the day after Martin Luther King Day, 2016).
=IF(NETWORKDAYS.INTL([#[calendar Date]], TODAY(), "0000011", Z$2:Z$11)=2, "Yes", "No")
If you wanted to get a little more elaborate, just use the NETWORKDAYS.INTL function with a custom number format of [=2]\Y\e\s;\No;\No. This allows you to retain the actual underlying value of the NETWORKDAYS.INTL formula while displaying Yes or No.
The results from the image above clearly show that both the weekend and holiday were discarded from consideration and that Fri 15-Jan-2016 is considered the previous day.
¹ The NETWORKDAYS.INTL function was introduced with Excel 2013. It is not available in earlier versions.
Related
I want to format a date as follows: Y17W15, but there is no option to set the start of the year. However, there is no consistent way of calculating this. I cannot just subtract a month (other times I will need to show the month too), and I cannot just add 4 or 5 to the week field due to leap years, etc.
Our year starts on a Saturday that is closest to December 1. This means if November 30 is on a Saturday, the Fiscal Year will start on November 30.
Currently what I have is below, which works fine except it shows Y17W10. The easiest option in my head is to have a way to actually set the start of a fiscal year, but if I have to go through a bunch of if statements it's okay as long as it works.
MsgBox(Format(Now, """Y""yy""W""mm"""))
Thanks for your time!
I am aware that: Given a 4-5-4 calendar and a date, how do I determine what fiscal week that date falls in? exists but I am looking for an answer that isn't as hard-coded.
Michael
I have an SQL query I need to run once a month.
The data set the query produces always has to be from the 11th of the month before to the 10th of the current month.
I now manualy run the query in the fews days after the 11th day of the month manually adjusting the date range in my where statement:
for example...
Where Column A is greater than 10/10/2015 and less than 12/11/15
I was hoping there would be a statement I could add to my query to automatically find the 11th day of the last month and the 10th of the current month. This way I could schedule the query and automatically email the results.
You should be able to use the following within your query: -
CONVERT(date,FORMAT(GETDATE(),'yyyy-MM')+'-10')
(for the 10th of this month)
and
CONVERT(date,FORMAT(DATEADD(m,-1,GETDATE()),'yyyy-MM')+'-11')
(for the 11th of last month).
Try to look out the MONTH() function in your working DBMS. In MySQL and MSSQL it returns a number (1 been january) corresponding to the current month that your system is (you may check if it's date is updated).
With this function you can subtract 1 to get the last month, having to do some logic when the current one is January, hence 1. Since now you should get 12 (december) intead of 0 (an error).
Cheers, mate!
I have a workbook that I am using the NOW function to return today's date and then I have another cell to convert to WEEKNUM that I use to MATCH on with a different tab. I need to be able to create a formula to read today's date and always return the previous Saturday. Example: Today is 6-8-2015. I want this formula to return 6-6-2015. Any ideas on how to make this work. I am struggling here.
How about:
=NOW()-(WEEKDAY(NOW(),1))
This will return the time 'now' minus the number of days from Saturday where Sunday = 1, Monday = 2 etc.
Note, this does include the timestamp along with the day (eg. 6/6/2015 14:48). If you want just the date you could daisy-chain a text function around it.
I am trying to convert column with GMT hour to the specified time zones from the user.
I get an error when VBA attempts to subtract 18000 secs (GMT-5) from 01:00.
Selected_GMT = -18000
CellValue = "1/0/00 01:00"
New_Time = DateAdd("s", Selected_GMT,CellValue)
Is this error happening because VBA is unable to determine the hours before 00:00?
I have figured out the seconds for Selected_GMT, how can I use that to determine New_Time?
As ooo noted in a comment above, 1/0/00 is an invalid date code. However even if that was a typo in your question, the fact that the date uses a 2 digit year code begs the question "WHICH year 00?" Apologies if you already know this, but below I've extracted a recap of how Excel dates work from something that I've written elsewhere. The relevant part is "Day Zero And Before In Excel"; if the "00" actually represents *19*00 in the cell (as it will if you've just punched in "01:00 as the cell entry), you're going to run into problems subtracting from that. In which case, perhaps explicitly enter the date and time (perhaps using the current date) but hide the date component using formatting):
Excel uses a "date serial" system in which any date that you use in
calculations is represented as a positive integer value. That integer
value is calculated from an arbitrary starting date. Adding whole
numbers to a specific serial date moves you forward through the
calendar a day at a time, and subtracting whole numbers moves you
backwards... as long as you don't go past the starting date of the
serial number system and end up with a negative value. Times are
represented as fractions of a day; 0.25 for 6am, 0.5 for noon, 0.75
for 6pm and so on.
Excel Dates
In the case of Excel for Windows, the starting date is 1 January 1900. That is, if you enter the value 1 into a cell in Excel
and format it as a date, you'll see the value as 1 January 1900. 2
will be the 2nd of January 1900, 3 the 3rd of January, and so on. 367
represents 1 January 1901 because Excel treats 1900 as having been a
leap year with 366 days. In other words, every full day that passes
adds 1 to the serial date.
It's important to remember that the above relates to Excel only, and
not to Access, SQL Server or other database products (or Visual Basic,
for that matter). In Access, for example, the range of valid dates is
1 January 100 to 31 December 9999, the same range that can be stored
in a VB or VBA variable with a Date data type.
Excel And The Macintosh
Macintosh systems use a start date of 1 January 1904, neatly bypassing the 1900 leap year issue. However that
does mean that there's a 4 year discrepancy between the serial date
values in a workbook created in Excel for Windows, and one created in
Excel for the Mac. Fortunately under Tools -> Options-> Calculation
(on pre-2007 versions of Excel) you'll find a workbook option called
1904 Date System. If that's checked, Excel knows that the workbook
came from a Macintosh and will adjust its date calculations
accordingly.
Excel Times
As noted in the introduction, times are calculated as a
fraction of a day. For example 1.5 represents noon on 2 January 1900.
1.75 represents 6pm on 2 January 1900.
(Snipped a bit about the leap year bug in 1900)
From 1 March 1900 onward Excel's dates are correct, but if you format
the number 1 using the format dddd, mmmm dd, yyyy you'll get the
result Sunday, 1 January 1900. That is incorrect; 1 January 1900 was a
Monday, not a Sunday. This day of week error continues until you reach
1 March, which is the first truly correct date in the Excel calendar.
Day Zero And Before In Excel
If you use the value zero and display it
in date format you'll get the nonsense date Saturday 0 January 1900.
If you try to format a negative value as a date, you'll just get a
cell full of hash marks. Similarly if you try to obtain a date serial
number using Excel functions like DateValue, you can only do so for
dates on or after 1 January 1900. An attempt to specify an earlier
date will result in an error.
The 1904 (Macintosh) system starts from zero. (1 January 1904 has a
value of 0, not 1. Excel's on-line help describes the Mac system as
starting from January 2, but that's probably easier than explaining to
users why a serial date value of 0 works on the Mac but not Excel.)
Negative numbers won't generate an error, but the number will be
treated as absolute. That is, both 1 and -1 will be treated as 2
January 1904.
I need to run a report grouped by week. This could be done by using group by week(date) but the client wants to set the day of the week that marks the end of week. So it can be Tuesday, Wednesday etc. How can I work this into a group by query?
The datetime column type is unix timestamp.
The WEEK() function takes an optional second parameter to specify the start of the week:
This function returns the week number for date. The two-argument form of WEEK() enables you to specify whether the week starts on Sunday or Monday and whether the return value should be in the range from 0 to 53 or from 1 to 53.
However, it can only be set to Sunday or Monday.
UPDATE: Further to the comments below, you may want to consider adding a new column to your table to act as a grouping field, based on WEEK(DATE_ADD(date INTERVAL x DAY)), as suggested in the comments. You may want to create triggers to automatically generate this values whenever the date field is updated, and when new rows are inserted. You would then be able to create a usable index on this new field as required.