I dont know who to return what I wrote before, apologise. vowejin firnefk rneqkln qrecjinrelqkjnr klwencirowejncienfvenciernicnreinc ikrenicernircniwncikwnkwjnkcjwnkjnckjncwkjnwckjnweknckejnckwjnckjnwekcjnwekjnckwjenckjwenkcjnwekjnckwenckwjenklwneocnwocnowencoejnkjwencojnwekojcnwekjcnkwejnckejcnkwejnckjwenkcjnwkjcnwkn:)
Using TOP:
SELECT TOP 1
PID, NAME, AGE
FROM (
SELECT
p.*, h.HID
FROM Performer p
INNER JOIN Concert c
ON c.PID = p.PID
INNER JOIN Hall h
ON h.HID = c.HID
INNER JOIN Tickets t
ON t.CID = c.CID
GROUP BY p.PID, p.NAME, p.AGE, h.HID, h.CAPACITY
HAVING COUNT(t.TID) = h.CAPACITY
) t
GROUP BY PID, NAME, AGE
ORDER BY COUNT(*) DESC
This should return expected result
;with Cte1 AS (
select C.CID, P.Name AS PerformerName, H.Name AS HallName, H.Capacity, H.HID
from #Performer P
inner join #Concert C on C.PID = P.PID
inner join #Hall H on H.HID = C.HID
)
, Cte2 AS (
select C.CID, H.HID, COUNT(*) SellCount
from #Concert C
inner join #Hall H on H.HID = C.HID
inner join #Tickets T on T.CID = C.CID
group by C.CID, H.HID
)
select Cte1.CID, Cte1.PerformerName, Cte1.HallName, Cte2.SellCount
from Cte1 inner join Cte2 on Cte2.CID = Cte1.CID AND Cte2.HID = Cte1.HID
where Cte1.Capacity = Cte2.SellCount
Related
I have been trying to query each city's popular genre. I am only trying to get the rows that I have highlighted. I tried using MAX() on a group by but gave me a syntax error.
My CTE query is as follows, its based on the dbeaver sample dataset:
with q_table
as
( select City, Genre, count(*) as counts
from
(select c.City, g.Name as Genre
from bus5dwr.dbeaver_sample.Customer c
inner join bus5dwr.dbeaver_sample.Invoice i
on i.CustomerId = c.CustomerId
inner join bus5dwr.dbeaver_sample.InvoiceLine il
on il.InvoiceId = i.InvoiceId
inner join bus5dwr.dbeaver_sample.track t
on t.TrackId = il.TrackId
inner join bus5dwr.dbeaver_sample.Genre g
on g.GenreId = t.GenreId
where Country = 'USA'
) as t2
group by City, Genre)
I tried the following query.
I don't have a dataset to test this on, but you should be able to just add a ROW_NUMBER() function to your CTE to get the values you are looking for. Such as:
with q_table
as
( select City, Genre, count(*) as counts,
,ROW_NUMBER() OVER(partition by City order by count(*) desc) RN
from
(select c.City, g.Name as Genre
from bus5dwr.dbeaver_sample.Customer c
inner join bus5dwr.dbeaver_sample.Invoice i
on i.CustomerId = c.CustomerId
inner join bus5dwr.dbeaver_sample.InvoiceLine il
on il.InvoiceId = i.InvoiceId
inner join bus5dwr.dbeaver_sample.track t
on t.TrackId = il.TrackId
inner join bus5dwr.dbeaver_sample.Genre g
on g.GenreId = t.GenreId
where Country = 'USA'
) as t2
group by City, Genre)
SELECT City, Genre, Counts
from q_table
WHERE RN=1
Order BY City
This use of MAX should work.
Edit; Added inner join. Thanks to Gordon Linoff for the observation that my original answer didn't actually achieve anything.
with q_table
as
( select City, Genre, count(*) as counts
from
(select c.City, g.Name as Genre
from bus5dwr.dbeaver_sample.Customer c
inner join bus5dwr.dbeaver_sample.Invoice i
on i.CustomerId = c.CustomerId
inner join bus5dwr.dbeaver_sample.InvoiceLine il
on il.InvoiceId = i.InvoiceId
inner join bus5dwr.dbeaver_sample.track t
on t.TrackId = il.TrackId
inner join bus5dwr.dbeaver_sample.Genre g
on g.GenreId = t.GenreId
where Country = 'USA'
) as t2
group by City, Genre)
SELECT a.City, a.Genre, a.counts
FROM q_table a
INNER JOIN (
SELECT City, MAX(counts) counts
FROM q_table
GROUP BY City
) b ON a.City = b.City AND a.counts = b.counts;
try this
with q_table
as
(select * from (
( select City, Genre, count(*) as counts
from
(select c.City, g.Name as Genre
from bus5dwr.dbeaver_sample.Customer c
inner join bus5dwr.dbeaver_sample.Invoice i
on i.CustomerId = c.CustomerId
inner join bus5dwr.dbeaver_sample.InvoiceLine il
on il.InvoiceId = i.InvoiceId
inner join bus5dwr.dbeaver_sample.track t
on t.TrackId = il.TrackId
inner join bus5dwr.dbeaver_sample.Genre g
on g.GenreId = t.GenreId
where Country = 'USA'
) as t2
group by City, Genre)) as t3 where count in (select max(count) count from t3 group by city)
I have two tables in Oracle DB
Person (
id
)
Bill (
id,
date,
amount,
person_id
)
I need to get person and amount from last bill if exist.
I trying to do it this way
SELECT
p.id,
b.amount
FROM Person p
LEFT JOIN Bill b
ON b.person_id = p.id AND b.date = (SELECT MAX(date) FROM Bill WHERE person_id = 1)
WHERE p.id = 1;
But this query works only with INNER JOIN. In case of LEFT JOIN it throws ORA-01799 a column may not be outer-joined to a subquery
How can I get amoun from the last bill using left join?
Please try the below avoiding sub query to be outer joined
SELECT
p.id,
b.amount
FROM Person p
LEFT JOIN(select * from Bill where date =
(SELECT MAX(date) FROM Bill b1 WHERE person_id = 1)) b ON b.person_id = p.id
WHERE p.id = 1;
What you are looking for is a way to tell in bills, for each person, what is the latest record, and that one is the one to join with. One way is to use row_number:
select * from person p
left join (select b.*,
row_number() over (partition by person_id order by date desc) as seq_num
from bills b) b
on p.id = b.person_id
and seq_num = 1
You cannot have a subquery inside an ON statement.
Instead you need to convert your LEFT JOIN statement into a whole subquery.
Not tested but this should work.
SELECT
p.id,
b.amount
FROM Person p
LEFT JOIN (
SELECT id FROM Bill
WHERE person_id = p.id
AND date = (SELECT date FROM Bill WHERE person_id = 1)) b
WHERE p.id = 1;
I'm not quite sure why you would want to filter for the date though.
Simply filtering for the person_id should do the trick
you should join Person and Bill to the result for max date in bill related to person_id
select Person.id, bill.amount
from Person
left join bill on bill.person_id = person.id
left join (
select person_id, max(date) as max_date
from bill
group by person_id ) t on t.person_id = Person.id and b.date = t.max_date
Hey you can do like this
SELECT
p.id,
b.amount
FROM Person p
LEFT JOIN Bill b
ON b.person_id = p.id AND b.date = (SELECT max(date) FROM Bill WHERE person_id = 1)
WHERE p.id = 1
SELECT
p.id,
b.amount
FROM Person p
LEFT JOIN Bill b
ON b.person_id = p.id
WHERE (SELECT max(date) FROM bill AS sb WHERE sb.person_id=p.id LIMIT 1)=b.date;
SELECT
p.id,
c.amount
FROM Person p
LEFT JOIN (select b.person_id as personid,b.amount as amount from Bill b where b.date1= (select max(date1) from Bill where person_id=1)) c
ON c.personid = p.id
WHERE p.id = 1;
try this
select * from person p
left join (select MAX(id) KEEP (DENSE_RANK FIRST ORDER BY date DESC)
from bills b) b
on p.id = b.person_id
I use GREATEST() function in join condition:
SELECT
p.id,
b.amount
FROM Person p
LEFT JOIN Bill b
ON b.person_id = p.id
AND b.date = GREATEST(b.date)
WHERE p.id = 1
This allows you to grab the whole row if necessary and grab the top x rows
SELECT p.id
,b.amount
FROM person p
LEFT JOIN
(
SELECT * FROM
(
SELECT date
,ROW_NUMBER() OVER (PARTITION BY person_id ORDER BY date DESC) AS row_num
FROM bill
)
WHERE row_num = 1
) b ON p.id = b.person_id
WHERE p.id = 1
;
Here is my query that I have:
SELECT CG.Id, CG.Name, CG.IsToggled, COUNT(*) AS TotalWordCount
FROM CategoryGroup AS CG
JOIN Category AS C ON CG.Id = C.GroupId
JOIN Phrase AS P ON C.Id = P.CategoryId
GROUP BY CG.Id
ORDER BY CG.Name
What I need to do is to get a total of the TotalWordCount column where CG.IsToggled = 1
Is this possible in the same query or is there a way I can do this with two queries. Two SQL statements would be okay if they do come up with the same value as all the TotalWordCount added together.
You can solve this with a window function
SELECT CG.Id, CG.Name, CG.IsToggled, COUNT(*) AS TotalWordCount,
COUNT(*) OVER (PARTITION BY CG.id) as TotalTotalWordCount
FROM CategoryGroup AS CG
JOIN Category AS C ON CG.Id = C.GroupId
JOIN Phrase AS P ON C.Id = P.CategoryId
GROUP BY CG.Id
ORDER BY CG.Name
Assuming this is actually Microsoft SQL Server (which means the original query posted would error out because it doesn't CG.Name in your GROUP BY).
What I need to do is to get a total of the TotalWordCount column where CG.IsToggled = 1
You cannot do a total of a total (aggregate of an aggregate) in the same query. But, you can do it in a subquery like this :
SELECT CG.Id, CG.Name, CG.IsToggled, SUM(c2.TotalWordCount) AS TotalWordCount
FROM CategoryGroup AS CG
INNER JOIN
(
SELECT Id, Name, COUNT(*) AS TotalWordCount
FROM CategoryGroup
WHERE IsToggled = 1
GROUP BY Id, Name
) AS c2 ON c2.Id = CG.Id AND c2.Name = CG.Name
JOIN Category AS C ON CG.Id = C.GroupId
JOIN Phrase AS P ON C.Id = P.CategoryId
GROUP BY CG.Id, CG.Name, CG.IsToggled
ORDER BY CG.Name
Note that: You might need to use LEFT JOIN to include those with IsToggled = 0 in the query as well:
SELECT CG.Id, CG.Name, CG.IsToggled, SUM(COALESCE(c2.TotalWordCount, 0)) AS TotalWordCount
FROM CategoryGroup AS CG
JOIN Category AS C ON CG.Id = C.GroupId
JOIN Phrase AS P ON C.Id = P.CategoryId
LEFT JOIN
(
SELECT Id, Name, COUNT(*) AS TotalWordCount
FROM CategoryGroup
WHERE IsToggled = 1
GROUP BY Id, Name
) AS c2 ON c2.Id = CG.Id AND c2.Name = CG.Name
GROUP BY CG.Id, CG.Name, CG.IsToggled
ORDER BY CG.Name
This subquery produces the correct table. But now I want to get the average of the averages, and I'm getting an error "Missing FROM-clause entry for table "c"".
SELECT
c.name,
AVG(avgvalue)
FROM
(
SELECT
c.name,
p.name,
AVG(a."value") AS avgvalue
FROM answers a INNER JOIN survey_responses sr ON sr.id = a.survey_response_id AND a.question_id = 13
INNER JOIN answers category_answer ON category_answer.survey_response_id = sr.id AND category_answer.question_id = 264
INNER JOIN answers_categories ac ON category_answer.id = ac.answer_id
INNER JOIN categories c ON c.id = ac.category_id
INNER JOIN products p ON p.id = a.product_id
WHERE c.name IN ('Accounting')
GROUP BY c.name, p."name"
HAVING count(p.name)>10
) as ProductAverages
GROUP BY c.name;
You are naming the ProductAverages, so your table aliases should reference it, not c - which can be used only in the inner query:
SELECT
name, -- Here
AVG(avgvalue)
FROM
(
SELECT
c.name,
p.name,
AVG(a."value") AS avgvalue
FROM answers a INNER JOIN survey_responses sr ON sr.id = a.survey_response_id AND a.question_id = 13
INNER JOIN answers category_answer ON category_answer.survey_response_id = sr.id AND category_answer.question_id = 264
INNER JOIN answers_categories ac ON category_answer.id = ac.answer_id
INNER JOIN categories c ON c.id = ac.category_id
INNER JOIN products p ON p.id = a.product_id
WHERE c.name IN ('Accounting')
GROUP BY c.name, p."name"
HAVING count(p.name)>10
) as ProductAverages
GROUP BY name; -- and here
I have a table which has several one to many relationships with other tables. Let's say the main table is a person, and the other tables represent pets, cars and children. I would like a query that returns details of the person,the number of pets, cars and children they have e.g.
Person.Name Count(cars) Count(children) Count(pets)
John Smith 3 2 4
Bob Brown 1 3 0
What is the best way to do this?
Subquery Factoring (9i+):
WITH count_cars AS (
SELECT t.person_id
COUNT(*) num_cars
FROM CARS c
GROUP BY t.person_id),
count_children AS (
SELECT t.person_id
COUNT(*) num_children
FROM CHILDREN c
GROUP BY t.person_id),
count_pets AS (
SELECT p.person_id
COUNT(*) num_pets
FROM PETS p
GROUP BY p.person_id)
SELECT t.name,
NVL(cars.num_cars, 0) 'Count(cars)',
NVL(children.num_children, 0) 'Count(children)',
NVL(pets.num_pets, 0) 'Count(pets)'
FROM PERSONS t
LEFT JOIN count_cars cars ON cars.person_id = t.person_id
LEFT JOIN count_children children ON children.person_id = t.person_id
LEFT JOIN count_pets pets ON pets.person_id = t.person_id
Using inline views:
SELECT t.name,
NVL(cars.num_cars, 0) 'Count(cars)',
NVL(children.num_children, 0) 'Count(children)',
NVL(pets.num_pets, 0) 'Count(pets)'
FROM PERSONS t
LEFT JOIN (SELECT t.person_id
COUNT(*) num_cars
FROM CARS c
GROUP BY t.person_id) cars ON cars.person_id = t.person_id
LEFT JOIN (SELECT t.person_id
COUNT(*) num_children
FROM CHILDREN c
GROUP BY t.person_id) children ON children.person_id = t.person_id
LEFT JOIN (SELECT p.person_id
COUNT(*) num_pets
FROM PETS p
GROUP BY p.person_id) pets ON pets.person_id = t.person_id
you could use the COUNT(distinct x.id) synthax:
SELECT person.name,
COUNT(DISTINCT car.id) cars,
COUNT(DISTINCT child.id) children,
COUNT(DISTINCT pet.id) pets
FROM person
LEFT JOIN car ON (person.id = car.person_id)
LEFT JOIN child ON (person.id = child.person_id)
LEFT JOIN pet ON (person.id = pet.person_id)
GROUP BY person.name
I would probably do it like this:
SELECT Name, PersonCars.num, PersonChildren.num, PersonPets.num
FROM Person p
LEFT JOIN (
SELECT PersonID, COUNT(*) as num
FROM Person INNER JOIN Cars ON Cars.PersonID = Person.PersonID
GROUP BY Person.PersonID
) PersonCars ON PersonCars.PersonID = p.PersonID
LEFT JOIN (
SELECT PersonID, COUNT(*) as num
FROM Person INNER JOIN Children ON Children.PersonID = Person.PersonID
GROUP BY Person.PersonID
) PersonChildren ON PersonChildren.PersonID = p.PersonID
LEFT JOIN (
SELECT PersonID, COUNT(*) as num
FROM Person INNER JOIN Pets ON Pets.PersonID = Person.PersonID
GROUP BY Person.PersonID
) PersonPets ON PersonPets.PersonID = p.PersonID
Note, that it depends on your flavour of RDBMS, whether it supports nested selects like the following:
SELECT p.name AS name
, (SELECT COUNT(*) FROM pets e WHERE e.owner_id = p.id) AS pet_count
, (SELECT COUNT(*) FROM cars c WHERE c.owner_id = p.id) AS world_pollution_increment_device_count
, (SELECT COUNT(*) FROM child h WHERE h.parent_id = p.id) AS world_population_increment
FROM person p
ORDER BY p.name
IIRC, this works at least with PostgreSQL and MSSQL. Not tested, so your mileage may vary.
Using subselects not very good practice, but may be here it will be good
select p.name, (select count(0) from cars c where c.idperson = p.idperson),
(select count(0) from children ch where ch.idperson = p.idperson),
(select count(0) from pets pt where pt.idperson = p.idperson)
from person p
You could do this with three outer joins:
SELECT
Person.Name,
sum(case when cars.id is not null then 1 else 0 end) car_count,
sum(case when children.id is not null then 1 else 0 end) child_count,
sum(case when pets.id is not null then 1 else 0 end) pet_count
FROM
Person
LEFT OUTER JOIN
cars on
Person.id = cars.person_id
LEFT OUTER JOIN
children on
Person.id = children.person_id
LEFT OUTER JOIN
pets on
Person.id = pets.person_id
GROUP BY
Person.Name
I belive that Oracle now supports the case when syntax, but if not you could use a decode.
You'd need to include multiple count statements in the query. Off the top of my head,
SELECT p.Name, COUNT(DISTINCT t.Cars), COUNT(DISTINCT o.Children), Count(DISTINCT p.Pets)
FROM Person p
INNER JOIN Transport t ON p.ID = t.PersonID
LEFT JOIN Offspring o ON p.ID = o.PersonID
LEFT JOIN Pets p ON p.ID = o.OwnerID
GROUP BY p.Name
ORDER BY p.Name