I have a query with 5 columns. I want to add 1 column that defines the number of times the value in column 2 (ItemCode) occurs in the results.
This is my query:
SELECT
Items.Description_0 AS [Items.Description],
Items.ItemCode,
warehouse_location,
Stock.Quantity AS StockQty,
Stock.warehouse
FROM
((SELECT gbkmut.artcode, gbkmut.warehouse, ISNULL(gbkmut.warehouse_location,'') AS warehouse_location,
SUM(gbkmut.aantal) AS Quantity FROM gbkmut
INNER JOIN Items ON Items.ItemCode = gbkmut.artcode
INNER JOIN voorrd ON voorrd.artcode=gbkmut.artcode
AND voorrd.magcode=gbkmut.warehouse
INNER JOIN ItemUnits ON ItemUnits.Unit = Items.PackageDescription
WHERE gbkmut.reknr = Items.GLAccountDistribution
AND (( gbkmut.transtype IN ('N', 'C', 'P', 'X')
AND gbkmut.datum BETWEEN {d '2000-01-09'} AND {d '2031-02-08'} ) )
AND (gbkmut.warehouse='MAG1' )
AND Items.Type IN ('S','B')
AND NOT (Items.GLAccountAsset IS NOT NULL AND Items.IsSerialNumberItem=1) AND NOT (Items.Type = 'S' AND ItemUnits.UnitType = 'T')
GROUP BY gbkmut.artcode, gbkmut.warehouse, ISNULL(gbkmut.warehouse_location,'')
HAVING SUM(gbkmut.aantal) > 0)) Stock
INNER JOIN Items ON Items.ItemCode=Stock.artcode
WHERE Items.ItemCode like '10.27021%'
ORDER BY Items.ItemCode
Lazy version, use a common table expression (cte):
with cte as
(
[your huge select]
)
select t1.*, t2.codecount
from cte t1
join (select ItemCode, count(*) as codecount from cte group by ItemCode) as t2
ON t2.ItemCode = t1.ItemCode
Related
This is my SQL query:
SELECT DISTINCT(ItemId), TCode, PartNumber,ModelNumber, ItemUOM
FROM #Results
This query returns:
ItemId TCode Source PartNumber ModelNumber ItemUOM
-----------------------------------------------------------------
1024 1000 NULL NULL EA
1024 1000 FLEX FLEX EA
#Result is a temp table I have used left join in that query
Why does SELECT DISTINCT return the same ItemID 1024 twice?
SELECT DISTCINT(I.ItemId),
(DENSE_RANK() OVER(ORDER BY I.ItemId ASC)) AS RowNumber,
(I.TCode), E.Name AS Source,
I.GoldenRecordNumber AS GoldenRecordNo, I.ItemCode AS MMRefNo,
I.ShortDescription AS ShortText, I.LongDescription AS POText,
Suppliers.Description AS Manufacturer, Suppliers.Name AS ManufacturerCode,
Suppliers.Abbreviation AS ManufacturerAbbr,
ItemSuppliers.ReferenceNo AS PartNumber, ItemSuppliers.ReferenceNo AS ModelNumber,
UOM.Name AS ItemUOM, MG.Name AS PSGC,
NM.Noun AS ClassName, NM.LongAbbrevation AS ClassDescription
INTO
#Results
FROM
Items I
LEFT JOIN
ItemSuppliers ON I.ItemId = ItemSuppliers.ItemsId
LEFT JOIN
Suppliers ON ItemSuppliers.ManufacturerId = Suppliers.SupplierId
LEFT JOIN
UnitOfMeasurement UOM ON UOM.UOMId = I.UOMId
LEFT JOIN
MaterialGroup MG ON MG.MaterialGroupId = I.MaterialGroupId
LEFT JOIN
NounModifiers NM ON NM.NounModifierId = I.NounModifierId
LEFT JOIN
AutoClass AC ON AC.ClassName = NM.Noun
LEFT JOIN
ERP E ON E.ERPId = I.ERPName
LEFT JOIN
NounModifierAttributes NMA ON NMA.NounModifierId =
NM.NounModifierId
LEFT JOIN
Attributes A ON A.AttributeId = NMA.AttributeId
LEFT JOIN
ItemAttributes IA ON IA.ItemId = I.ItemId
WHERE
(I.ItemCode LIKE '%'+'2001010088'+'%' )
SELECT 'Int' = COUNT(distinct(ItemId))
FROM #Results
WHERE (TCode IS NOT NULL OR MMRefNo IS NOT NULL)
SELECT DISTINCT(ItemId),
TCode, Source, GoldenRecordNo, MMRefNo, ShortText, POText,
Manufacturer, ManufacturerCode, ManufacturerAbbr, PartNumber, ModelNumber,
ItemUOM, PSGC, ClassName, ClassDescription
FROM
#Results
WHERE
(TCode IS NOT NULL OR MMRefNo IS NOT NULL)
AND RowNumber BETWEEN (1-1)*100 + 1 AND (((1-1) * 100 + 1) + 100) - 1
DROP TABLE #Results
if you are convinced the rows which are selected can be grouped together then it should work fine.
1. but if rows are having different data then distinct will not help.
2. use ltrim,rtrim to remove leading and trailing spaces.
example: distinct(ltrim(rtrim(ItemId)))
this will help if it due to spaces or for junk values
The behavior of DISTINCT works as expected. For instance, you could use GROUP BY clause to group them by ItemId, TCode to get top most records
SELECT
ItemId, TCode,
MAX(PartNumber) PartNumber, MAX(ModelNumber) ModelNumber,
MAX(ItemUOM), ...
FROM #Results
GROUP BY ItemId, TCode
In case any failure in GROUP BY clause use ranking function to assign the rank and get the record based on rank value.
select
store, sum(value)
from
rms.sa_tran_head
where
store_day_seq_no in (select store_day_seq_no
from rms.sa_store_day
where store in (3003)
and business_date = '01-JAN-2015')
and tran_type in ('SALE', 'RETURN')
group by
store;
How to write the above query using JOINS..
SELECT
sd.store,
SUM(TH.VALUE) AS GROSS ,
SUM(ti.qty) AS QTY
FROM rms.sa_tran_head AS th
JOIN rms.sa_store_day AS sd
ON th.store_day_seq_no = sd.store_day_seq_no
JOIN rms.sa_tran_item AS ti
ON ti.tran_seq_no = th.tran_seq_no
WHERE sd.store in (3003) --in (3003) use in if more than 1 value
AND sd.business_date = '01-JAN-2015'
AND th.tran_type IN ('SALE','RETURN')
GROUP BY
sd.store;
When I add other columns of another table it is showing different values...
I assumed store_day_seq_no is FK for the table rms.sa_store_day and the query with JOIN like this,
SELECT
sd.store,
SUM(sd.value) AS [Sum]
FROM rms.sa_tran_head AS th
JOIN rms.sa_store_day AS sd
ON th.store_day_seq_no = sd.store_day_seq_no
WHERE
sd.store = 3003 --in (3003) use in if more than 1 value
AND sd.business_date = '01-JAN-2015'
AND th.tran_type IN ('SALE','RETURN')
GROUP BY
sd.store;
I think this is ok.
SELECT
t1.store,
SUM(t1.Value) AS Sum_Value
FROM rms.sa_tran_head t1
INNER JOIN sa_store_day t2 ON t1.store_day_seq_no = t2.store_day_seq_no
WHERE t2.store IN ( 3003 )
AND t2.business_date = '01-JAN-2015'
AND t1.tran_type IN ( 'SALE' , 'RETURN' )
GROUP BY t1.store
I'm not a DBA so please don't yell at me. Trying to do an inner join and Group By using a concatenated column. The ON statement is producing a syntax error. I do not have access to the original tables and am trying to normalize this into another table, I know its ugly. Not overly worried about performance, just need to work. Cant use functions either.
SELECT DISTINCT A.[carrier_code],[carrier_name], [carrier_grouping], A.[collector_name], [dataset_loaded], [docnum], [envoy_payer_id], [loc], [market], [master_payor_grouping], [plan_class], [plan_name], A.[resp_ins],A.[resp_ind], A.[resp_payor_grouping], A.[Resp_Plan_Type], A.[rspphone], A.[state], A.[sys],A.[resp_ins]+A.[resp_payor_grouping]+A.[carrier_code]+A.[state]+A.[Collector_Name] as ExtId
FROM [Table1] A
INNER JOIN
(SELECT [resp_ins]+[resp_payor_grouping]+[carrier_code]+[state]+[Collector_Name] as Extid
FROM [Table1]
WHERE [resp_ind] = 'Insurance'
GROUP BY [resp_ins]+[resp_payor_grouping]+[carrier_code]+[state]+[Collector_Name]) B
ON A.[resp_ins]+A.[resp_payor_grouping]+A.[carrier_code]+A.[state]+A.[Collector_Name] = B.[resp_ins]+B.[resp_payor_grouping]+B.[carrier_code]+B.[state]+B.[Collector_Name];
My ON and Group By statements are eventually the primary key in new table.
Your alias B hasn't columns as you mentioned. It has just on column Extid.
SELECT DISTINCT A.[carrier_code],[carrier_name], [carrier_grouping], A.[collector_name], [dataset_loaded], [docnum], [envoy_payer_id], [loc], [market], [master_payor_grouping], [plan_class], [plan_name], A.[resp_ins],A.[resp_ind], A.[resp_payor_grouping], A.[Resp_Plan_Type], A.[rspphone], A.[state], A.[sys],A.[resp_ins]+A.[resp_payor_grouping]+A.[carrier_code]+A.[state]+A.[Collector_Name] as ExtId
FROM [Table1] A
INNER JOIN
(SELECT [resp_ins]+[resp_payor_grouping]+[carrier_code]+[state]+[Collector_Name] as Extid
FROM [Table1]
WHERE [resp_ind] = 'Insurance'
GROUP BY [resp_ins]+[resp_payor_grouping]+[carrier_code]+[state]+[Collector_Name]) B
ON A.[resp_ins]+A.[resp_payor_grouping]+A.[carrier_code]+A.[state]+A.[Collector_Name] = B.Extid;
Try this, I didn't put all the column in result, you can manage yourself.
select A.*
from
(
select [carrier_code],[carrier_name], [sys],[resp_ins]+[resp_payor_grouping]+[carrier_code]+[state]+[Collector_Name] as ExtId
FROM [Table1]
) A
inner join
(
select distinct Extid
from
(
SELECT [resp_ins]+[resp_payor_grouping]+[carrier_code]+[state]+[Collector_Name] as ExtId
FROM [Table1]
WHERE [resp_ind] = 'Insurance'
) ins
) B on (A.ExtId = B.ExtId)
You don't need to concatenate the values - you can GROUP BY and JOIN on multiple columns.
SELECT DISTINCT
...
FROM
[Table1] A
INNER JOIN
(
SELECT
[resp_ins],
[resp_payor_grouping],
[carrier_code],
[state],
[Collector_Name]
FROM
[Table1]
WHERE
[resp_ind] = 'Insurance'
GROUP BY
[resp_ins],
[resp_payor_grouping],
[carrier_code],
[state],
[Collector_Name]
) B
ON
(
A.[resp_ins] = B.[resp_ins]
Or
(A.[resp_ins] Is Null And B.[resp_ins] Is Null)
)
And
(
A.[resp_payor_grouping] = B.[resp_payor_grouping]
Or
(A.[resp_payor_grouping] Is Null And B.[resp_payor_grouping] Is Null)
)
And
(
A.[carrier_code] = B.[carrier_code]
Or
(A.[carrier_code] Is Null And B.[carrier_code] Is Null)
)
And
(
A.[state] = B.[state]
Or
(A.[state] Is Null And B.[state] Is Null)
)
And
(
A.[Collector_Name] = B.[Collector_Name]
Or
(A.[Collector_Name] Is Null And B.[Collector_Name] Is Null)
)
;
I have to do an self join on a table. I am trying to return a list of several columns to see how many of each type of drug test was performed on same day (MM/DD/YYYY) in which there were at least two tests done and at least one of which resulted in a result code of 'UN'.
I am joining other tables to get the information as below. The problem is I do not quite understand how to exclude someone who has a single result row in which they did have a 'UN' result on a day but did not have any other tests that day.
Query Results (Columns)
County, DrugTestID, ID, Name, CollectionDate, DrugTestType, Results, Count(DrugTestType)
I have several rows for ID 12345 which are correct. But ID 12346 is a single row of which is showing they had a row result of count (1). They had a result of 'UN' on this day but they did not have any other tests that day. I want to exclude this.
I tried the following query
select
c.desc as 'County',
dt.pid as 'PID',
dt.id as 'DrugTestID',
p.id as 'ID',
bio.FullName as 'Participant',
CONVERT(varchar, dt.CollectionDate, 101) as 'CollectionDate',
dtt.desc as 'Drug Test Type',
dt.result as Result,
COUNT(dt.dru_drug_test_type) as 'Count Of Test Type'
from
dbo.Test as dt with (nolock)
join dbo.History as h on dt.pid = h.id
join dbo.Participant as p on h.pid = p.id
join BioData as bio on bio.id = p.id
join County as c with (nolock) on p.CountyCode = c.code
join DrugTestType as dtt with (nolock) on dt.DrugTestType = dtt.code
inner join
(
select distinct
dt2.pid,
CONVERT(varchar, dt2.CollectionDate, 101) as 'CollectionDate'
from
dbo.DrugTest as dt2 with (nolock)
join dbo.History as h2 on dt2.pid = h2.id
join dbo.Participant as p2 on h2.pid = p2.id
where
dt2.result = 'UN'
and dt2.CollectionDate between '11-01-2011' and '10-31-2012'
and p2.DrugCourtType = 'AD'
) as derived
on dt.pid = derived.pid
and convert(varchar, dt.CollectionDate, 101) = convert(varchar, derived.CollectionDate, 101)
group by
c.desc, dt.pid, p.id, dt.id, bio.fullname, dt.CollectionDate, dtt.desc, dt.result
order by
c.desc ASC, Participant ASC, dt.CollectionDate ASC
This is a little complicated because the your query has a separate row for each test. You need to use window/analytic functions to get the information you want. These allow you to do calculate aggregation functions, but to put the values on each line.
The following query starts with your query. It then calculates the number of UN results on each date for each participant and the total number of tests. It applies the appropriate filter to get what you want:
with base as (<your query here>)
select b.*
from (select b.*,
sum(isUN) over (partition by Participant, CollectionDate) as NumUNs,
count(*) over (partition by Partitipant, CollectionDate) as NumTests
from (select b.*,
(case when result = 'UN' then 1 else 0 end) as IsUN
from base
) b
) b
where NumUNs <> 1 or NumTests <> 1
Without the with clause or window functions, you can create a particularly ugly query to do the same thing:
select b.*
from (<your query>) b join
(select Participant, CollectionDate, count(*) as NumTests,
sum(case when result = 'UN' then 1 else 0 end) as NumUNs
from (<your query>) b
group by Participant, CollectionDate
) bsum
on b.Participant = bsum.Participant and
b.CollectionDate = bsum.CollectionDate
where NumUNs <> 1 or NumTests <> 1
If I understand the problem, the basic pattern for this sort of query is simply to include negating or exclusionary conditions in your join. I.E., self-join where columnA matches, but columns B and C do not:
select
[columns]
from
table t1
join table t2 on (
t1.NonPkId = t2.NonPkId
and t1.PkId != t2.PkId
and t1.category != t2.category
)
Put the conditions in the WHERE clause if it benchmarks better:
select
[columns]
from
table t1
join table t2 on (
t1.NonPkId = t2.NonPkId
)
where
t1.PkId != t2.PkId
and t1.category != t2.category
And it's often easiest to start with the self-join, treating it as a "base table" on which to join all related information:
select
[columns]
from
(select
[columns]
from
table t1
join table t2 on (
t1.NonPkId = t2.NonPkId
)
where
t1.PkId != t2.PkId
and t1.category != t2.category
) bt
join [othertable] on (<whatever>)
join [othertable] on (<whatever>)
join [othertable] on (<whatever>)
This can allow you to focus on getting that self-join right, without interference from other tables.
I have a table item_table like this:
item age
--------------
1 1
1 6
2 2
I have the other table price_table like this:
item pricetype price
--------------------------
1 O 5
1 P 6
1 V 7
2 O 8
2 P 9
2 V 10
So, I want to inner join above two tables.
select *
from item_table i
inner join price_table p
on ...
There are some conditions about the on:
if the average of age of an item is bigger than 3, then I do: inner join price_table on pricetype = 'O' or pricetype = 'P'
If not, then I do: inner join price_table on pricetype = 'O' or pricetype = 'P' or pricetype = 'V'
So there are conditions for on conditions.
I then write the query like this:
select i.item, i.type, p.pricetype, p.price
from item_table i
inner join price_table p on i.item = p.item
and (avg(i.age) >= 3 and p.pricetype in ('O', 'P'))
or (avg(i.age) < 3 and p.pricetype in ('O', 'P', 'V'))
The error is given: An aggregate cannot appear in an ON clause unless it is in a subquery contained in a HAVING clause or select list, and the column being aggregated is an outer reference.
I can't move the avg to Having because other conditions are depending on the avg.
How can I write the select query?
select *
from (
select item, avg(age) as AvgAge
from item_table
group by item
) ia
inner join price_table p on ia.item = p.item
and ((ia.AvgAge >= 3 and p.pricetype in ('O', 'P'))
or (ia.AvgAge < 3 and p.pricetype in ('O', 'P', 'V')))
SQL Fiddle Example 1
This can be simplified to:
select *
from (
select item, avg(age) as AvgAge
from item_table
group by item
) ia
inner join price_table p on ia.item = p.item
and (p.pricetype in ('O', 'P')
or (ia.AvgAge < 3 and p.pricetype = 'V'))
SQL Fiddle Example 2
Did you try placing the aggregation in a subquery, then you have the avg() value for use in the JOIN clause:
select i.item, i.type, p.pricetype, p.price
from
(
select avg(i.age) age, i.item, i.type -- not sure where type is coming from in your OP as it is not in the table you showed
from item_table i
group by i.item, i.type
) i
inner join price_table p
on i.item = p.item
and ((i.age>= 3 and p.pricetype in ('O', 'P'))
or (i.age < 3 and p.pricetype in ('O', 'P', 'V')))