Yii2 - hasMany with custom query - yii

I am trying to create custom query in the hasMany function. I am not getting any error, but I am not getting any data from the table inside join statement. What's is wrong?
This is the function:
return $this->hasMany(UserKeys::classname(), ['user_id' => 'id'])
->select('licences.licenceName, userKeys.*')
->from('userKeys')
->innerJoin('licences', 'licences.id = userKeys.licence_id');

Try with following syntax. It may help you.
return $this->hasMany(UserKeys::classname(), ['user_id' => 'id'])
->select('licences.licenceName, userKeys.*')
->from(['userKeys' => UserKeys::classname()])
->viaTable('licences', ['licences.id = userKeys.licence_id']);

Related

How to make a SUM() with WHERE in HASMANY relationship on laravel? Any help is appreciated

Good evening friends, I'm having difficulty on get a SUM from a HASMANY relationship with a condition.
I was trying to do something like this:
$marketPlaces = ModelAccountMarketplace::with(['orders'])
->whereHas('orders', function ($query) use ($dates) {
$query->selectRaw('SUM(valor_frete) as somaFreteGratis')
->whereBetween('datetime', [$dates['dateStart'], $dates['dateEnd']]);
});
But when i try to get the value with: var_dump($marketPlace->somaFreteGratis);
I get a null value. I try to put the where inside the WITH() like:
$marketPlaces = ModelAccountMarketplace::with(['orders' => function ($query) {
$query->selectRaw('SUM(valor_frete) as somaFreteGratis')->where('tipo_frete', 'gratis');
}])
->whereHas('orders', function ($query) use ($dates) {
$query->whereBetween('datetime', [$dates['dateStart'], $dates['dateEnd']]);
});
But in every try i get a null value when i check with:
<?= var_dump($marketPlace->somaFreteGratis); ?>
Any help would be appreciated.
What you're trying to do can be accomplished using a withCount along with a Closure
$marketPlaces = ModelAccountMarketplace::withCount([
'orders as somaFreteGratis' => function ($query) use ($dates) {
$query->select(DB::raw('sum(valor_frete)')
->where('tipo_frete', 'gratis')
->whereBetween('datetime', [$dates['dateStart'], $dates['dateEnd']]);
}
])
->get();

Yii2 - hasMany relation with multiple columns

I have a table message_thread:
id
sender_id
recipient_id
I want to declare a relation in my User model that will fetch all message threads as follows:
SELECT *
FROM message_thread
WHERE sender_id = {user.id}
OR recipent_id = {user.id}
I have tried the following:
public function getMessageThreads()
{
return $this->hasMany(MessageThread::className(), ['sender_id' => 'id'])
->orWhere(['recipient_id' => 'id']);
}
But it generates an AND query. Does anyone know how to do this?
You cannot create regular relation in this way - Yii will not be able to map related records for eager loading, so it not supporting this. You can find some explanation int this answer and related issue on GitHub.
Depending on use case you may try two approach to get something similar:
1. Two regular relations and getter to simplify access
public function getSenderThreads() {
return $this->hasMany(MessageThread::className(), ['sender_id' => 'id']);
}
public function getRecipientThreads() {
return $this->hasMany(MessageThread::className(), ['recipient_id' => 'id']);
}
public function getMessageThreads() {
return array_merge($this->senderThreads, $this->recipientThreads);
}
In this way you have two separate relations for sender and recipient threads, so you can use them directly with joins or eager loading. But you also have getter which will return result ofboth relations, so you can access all threads by $model->messageThreads.
2. Fake relation
public function getMessageThreads()
{
$query = MessageThread::find()
->andWhere([
'or',
['sender_id' => $this->id],
['recipient_id' => $this->id],
]);
$query->multiple = true;
return $query;
}
This is not real relation. You will not be able to use it with eager loading or for joins, but it will fetch all user threads in one query and you still will be able to use it as regular active record relation - $model->getMessageThreads() will return ActiveQuery and $model->messageThreads array of models.
Why orOnCondition() will not work
orOnCondition() and andOnCondition() are for additional ON conditions which will always be appended to base relation condition using AND. So if you have relation defined like this:
$this->hasMany(MessageThread::className(), ['sender_id' => 'id'])
->orOnCondition(['recipient_id' => new Expression('id')])
->orOnCondition(['shared' => 1]);
It will generate condition like this:
sender_id = id AND (recipent_id = id OR shared = 1)
As you can see conditions defined by orOnCondition() are separated from condition from relation defined in hasMany() and they're always joined using AND.
For this query
SELECT *
FROM message_thread
WHERE sender_id = {user.id}
OR recipent_id = {user.id}
You Can use these
$query = (new \yii\db\Query)->from("message_thread")
$query->orFilterWhere(['sender_id'=>$user_id])->orFilterWhere(['recipent_id '=>$user_id]);

Yii 2 can rewrite WHERE condition from model?

I have some where condition in my model .
Its check is field active or no.
Now I need to write a join relation. But I need to remove where condition. Is it possible?
My model.
...
public static function find() {
return (new AssetgroupsQuery(get_called_class()))->active();
}
My relation
public function getAssetgroup(): \app\models\AssetgroupsQuery {
return $this->hasOne(Assetgroups::class, ['asg_id' => 'ass_group'])->andOnCondition(['asg_active' => '1'])
->viaTable('assets', ['ass_id' => 'log_ass_id',]);
}
I need to got all active assets and join, if asset is empty I need to got null fields, but
model where condition added to my current sql query and remove all fields which assets are null.
I try to add some where Condition to remove old where, but it don't work.
Can you help me?
You can reset existing conditions by using where(null).
On relation level:
public function getAssetgroup(): \app\models\AssetgroupsQuery {
return $this->hasOne(Assetgroups::class, ['asg_id' => 'ass_group'])
->andOnCondition(['asg_active' => '1'])
->where(null)
->viaTable('assets', ['ass_id' => 'log_ass_id',]);
}
Or directly on join:
$query = MyModel::find()
->joinWith([
'assetgroup' => function (ActiveQuery $query) {
$query->where(null);
},
])

CakePHP - HABTM find() don't make the JOIN to other tables

My title will look like naive but I have to say I read/searched/tested everything possible, but my find() method don't implement the JOIN to related tables in the SQL query. I used it several times in other projects without problems but here...
Here my 2 models (nothing special but the manual definition of the related model) :
class Pflanzen extends AppModel {
public $useTable = 'pflanzen';
public $hasAndBelongsToMany = array(
'Herbar' => array(
'order'=>'Herbar.order ASC',
'joinTable' => 'herbar_pflanzen',
'foreignKey' => 'pflanzen_id',
'associationForeignKey' => 'herbar_id')
);
}
class Herbar extends AppModel {
public $useTable = 'herbar';
public $hasAndBelongsToMany = array(
'Pflanzen' => array('joinTable' => 'herbar_pflanzen',
'foreignKey' => 'herbar_id',
'associationForeignKey' => 'pflanzen_id')
)
}
Here my query in the "Herbar" controller (can't be more normal...) :
$pflanzen = $this->Herbar->Pflanzen->find('all',array(
'fields'=>array('Herbar.name','Pflanzen.linkplatter'),
'conditions' => array('Pflanzen.linkplatter' => true),
'order' => 'Herbar.name',
'limit' => 10,
'recursive'=>2)
);
$this->set('pflanzen',$pflanzen);
and the resulting error in the view :
Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'Herbar.name' in 'field list'
SQL Query: SELECT `Herbar`.`name`, `Pflanzen`.`linkplatter`, `Pflanzen`.`id` FROM `burgerbib`.`platter_pflanzen` AS `Pflanzen` WHERE `Pflanzen`.`linkplatter` = '1' ORDER BY `Herbar`.`name` ASC LIMIT 10
You can see that their is no JOIN in the SQL. Why ?? What do I wrong ?
I would really appreciate your help as I'm searching for hours and do no more see any solutions and didn't find nothing using google. Thanks in advance !!
HABTM doesn't make joined queries, it makes a query for all base records and more queries as needed for each relationship to fill the array. Your condition assumes a join, hence the error.
You can force a join using the 'joins' parameter. http://book.cakephp.org/1.2/en/view/872/Joining-tables
In the End, the better way of doing this is using the containable behaviour. Force Join is only useful when the containable behavior don't respond to the need :
http://book.cakephp.org/2.0/fr/core-libraries/behaviors/containable.html#using-containable

LINQ to NHibernate: selecting entity which has a specific entity in a one to many association

I would like to make this query:
Session.Linq<User>().Where(u => u.Payments.Count(p => p.Date != null) > 0);
In plain English I want to get all the users that has at least one payment with the date specified.
When I run the sample code I get a System.ArgumentException with the message:
System.ArgumentException : Could not find a matching criteria info provider to: this.Id = sub.Id
Do you know a solution to this problem?
It would also be very helpful if someone could provide the same query with the NHibernate Query by Criteria API.
I'm not sure if this will work in your particular case, but I would use the .Any() extension to clean up the linq query a bit; for example:
Session.Linq<User>().Where(u => u.Payments.Any(p => p.Date != null));
I think something like it:
Customer customerAlias = null;
criteria = CurrentSession.CreateCriteria(typeof(User), () => customerAlias);
if (searchCriteria.OrdersNumber.HasValue)
{
ICriteria paymentsCriteria = criteria.CreateCriteria<Customer>(x => x.Payments);
DetachedCriteria paymentsCount = DetachedCriteria.For<Payment>();
paymentsCount.SetProjection(Projections.RowCount());
paymentsCount.Add(SqlExpression.NotNull<Payment>(x => x.Date));
paymentsCount.Add<Payment>(x => x.Customer.Id == customerAlias.Id);
paymentsCriteria.Add(Subqueries.Gt(1, paymentsCount));
}
return criteria.List<User>();