I have this crazy array.
ReDim arrayDeCeldas(filas - 1, columnas - 1)
For i = 0 To filas - 1
For j = 0 To columnas - 1
arrayDeCeldas(i, j) = i & j
Debug.Write(arrayDeCeldas(i, j) & " ")
Next j
Debug.WriteLine("")
Next i
And I'm trying to link it to a number of conditions and is not well to do
I'm trying to try to get 6 index from array
The number can't repeat and it are pick horizontally or vertically randomly
0 1 2 3 4 5 6 7
10 11 12 13 14 15 16 17
20 21 22 23 24 25 26 27
30 31 32 33 34 35 36 37
40 41 42 43 44 45 46 47
This example about i'm try.
It can be seen, there are a total of 6 items with different sizes
Actually my code, it's getting huge
Private Sub setBarco()
Dim numeroRandom As New System.Random()
Dim indiceA, indiceB As Integer
For b = 1 To barcos
Randomize()
Dim value As Integer = CInt(Int((2 * Rnd() + 1)))
indiceA = numeroRandom.Next(0, filas)
indiceB = numeroRandom.Next(0, columnas)
Select Case b
Case 1
If arrayDeCeldas(indiceA, indiceB) = 0 Then
arrayDeCeldas(indiceA, indiceB) = b & 1
End If
Case 2
Select Case value
Case 1
For c = 0 To 1
If indiceB + c < columnas Then
If arrayDeCeldas(indiceA, indiceB + c) = 0 Then
arrayDeCeldas(indiceA, indiceB + c) = b & c
End If
Else
If arrayDeCeldas(indiceA, indiceB - c) = 0 Then
arrayDeCeldas(indiceA, indiceB - c) = b & c
End If
End If
Next
Case 2
For c = 0 To 1
If indiceA + c < filas Then
If arrayDeCeldas(indiceA + c, indiceB) = 0 Then
arrayDeCeldas(indiceA + c, indiceB) = b & c
Else
End If
Else
End If
Next
End Select
Case 3
Case 4
Case 5
Case 6
End Select
Next b
End Sub
Based on your comment-reply, I understand the program must:
Pick at random any six elements from a 2D-array, and each element or value must be selected only once.
That's fairly straightforward: here's a pseudo-code implementation:
Perform some initial computation:
Get the bounds of the 2D array
Seed a random number generator:
Create a HashSet instance
Get six pairs of coordinates:
Loop continuously until HashSet has 6 elements in it:
Generate a coordinate pair within the bounds of the array found in Step 1.
Get the value from the coordinate pair
Check to see if we've seen the value before (by looking at the HashSet). If we've not seen it before, then add it to the HashSet and continue, otherwise ignore it and try again.
Return the contents of the HashSet
In C# this would be:
Int32[,] numbers = new Int32[] { ... };
Int32 maxY = numbers.GetUpperBound(0); // y-axis in dimension 0
Int32 maxX = numbers.GetUpperBound(1); // x-axis in dimension 1
Random rng = new Random();
HashSet<Int32> values = new HashSet<Int32>();
while( values.Count < 6 ) {
Int32 x = rng.Next( maxX + 1 ); // Random.Next is upperbound exclusive, hence +1
Int32 y = rng.Next( maxY + 1 );
Int32 value = numbers[ y, x ];
if( !values.Contains( value ) ) values.Add( value );
}
return values.ToArray();
Note that by keeping track of observed values, instead of coordinates, we can simultaneously avoid duplicate values and duplicate coordinates: as duplicate coordinates will give you duplicate values anyway.
Related
I'm trying to list all numbers with 3 digits where the individual digits sum to a given number.
So far I can return a list of all numbers using this Visual Basic code:
target = 17
i = 1
j = 1
k = 1
Do While i < 10
Do While j < 10
Do While k < 10
r = i + j + k
If r = target Then
If i <> j And j <> k And k <> i Then
lsNumbers.Add(i & j & k )
End If
End If
k += 1
Loop
If k = 10 Then k = 1
j += 1
Loop
If j = 10 Then j = 1
i += 1
Loop
But I want only unique, non repeating combinations.
For example for the target number 17:
179, 197, 269, 278, 287...
I want to be able to test the current number before I add it to the list, to check if it is a combination of a number already in the list - so 197 would fail because of 179, and 287 would fail because of 278
Observations
Just curious, is excluding the 0 digit on purpose?
To iterate through the possible digits, a well suited instruction pair is FOR NEXT. Definitely simpler than the DO WHILE that you used.
Loop
If k = 10 Then k = 1
Loop
If j = 10 Then j = 1
Upon loop completion, the iterator is sure to contain 10. The IF is redundant.
Solution
In order to check if a number, that obeys the condition, is unique in the sense that it is not composed of the same 3 digits as an already validated number, you could consult a 3-D array. If the new number corresponds to a non-zero element in this array, it means that the new number would be using the same digits as an earlier number. That's reason to reject it.
Next code runs in QBasic. You'll have no trouble rewriting it for Visual BASIC.
DIM r%(1 TO 9, 1 TO 9, 1 TO 9)
FOR i% = 1 TO 9
FOR j% = 1 TO 9
FOR k% = 1 TO 9
r%(i%, j%, k%) = 0
NEXT
NEXT
NEXT
target% = 17
FOR i% = 1 TO 9
FOR j% = 1 TO 9
FOR k% = 1 TO 9
IF i% + j% + k% = target% THEN
IF r%(i%, j%, k%) = 0 THEN
PRINT i% * 100 + j% * 10 + k%; " ";
r%(i%, j%, k%) = 1 ' Could do without this one because of the ascending order
r%(i%, k%, j%) = 1
r%(j%, i%, k%) = 1
r%(j%, k%, i%) = 1
r%(k%, i%, j%) = 1
r%(k%, j%, i%) = 1
END IF
END IF
NEXT
NEXT
NEXT
This is my output of valid numbers:
179 188 269 278 359 368 377 449 458 467 557 566
I previously have a Excel sheet with VBA coding that fills column, row 1 to 10 with the number 1, row 11 to 20 with number 2 and so on. The code I've used is as follows:
Sub fill()
Dim ID
ID = 1
For c = 1 To 34
ActiveWorkbook.Sheets("Sheet1").Cells(c, 1) = ID
ActiveWorkbook.Sheets("Sheet1").Cells(c + 1, 1) = ID
c = c + 1
If (c Mod 10) = 0 Then
ID = ID + 1
End If
Next c
End Sub
Now I want to change it so that the code starts at row 3 onwards. Meaning row 3 to 12 = 1, row 13 to 22 = 2 and so on. So I changed the 'For' statement to:
For c = 3 To 34
But what happens is that the number 1 appears from row 3 to row 10, and then continues with number 2 in row 11 to 20. Not what I was expecting.
Therefore, what would be the best method of changing the code?
If you want exactly the same output but two rows lower, you can use:
Sub fill()
Dim ID
ID = 1
For c = 1 To 34
ActiveWorkbook.Sheets("Sheet1").Cells(c + 2, 1) = ID
ActiveWorkbook.Sheets("Sheet1").Cells(c + 3, 1) = ID
c = c + 1
If (c Mod 10) = 0 Then
ID = ID + 1
End If
Next c
End Sub
If you still only want to go to row 34 but start in row 3, change the 34 to 32 in the above code.
You can also do it without looping and this is easier to adjust the parameters:
Sub fill()
Const NUMBER_OF_ROWS As Long = 34
Const START_ROW As Long = 3
Const ID As Long = 1
Const NUMBER_IN_GROUP As Long = 10
With ActiveWorkbook.Sheets("Sheet1").Cells(START_ROW, 1).Resize(NUMBER_OF_ROWS)
.Value = .Parent.Evaluate("INDEX(INT((ROW(" & .Address & ")-" & START_ROW & ")/" & _
NUMBER_IN_GROUP & ")+" & ID & ",)")
End With
End Sub
When i understand you write, this should work:
You can use the loop how you did at the beginning. and just add plus 2 to c in the ActiveWorkbook.Sheets("Tabelle1").Cells(c + 2, 1) = ID
Sub fill()
Dim ID
ID = 1
For c = 1 To 34
ActiveWorkbook.Sheets("Tabelle1").Cells(c + 2, 1) = ID
ActiveWorkbook.Sheets("Tabelle1").Cells(c + 3, 1) = ID
c= c+1
If (c Mod 10) = 0 Then
ID = ID + 1
End If
Next c
End Sub
something like that should be the simplest way:
Sub fill()
Dim i As Integer
Dim j As Integer
For i = 1 To 4
For j = 1 To 10
ActiveWorkbook.Sheets("Sheet1").Cells(j + (i - 1) * 10 + 2, 1) = i
Next j
Next i
End Sub
EDIT:
No, the simplest way would be type formula into A3:
=ROUNDDOWN(((ROW()-3))/10,0)+1
end drag it donw.
Function convertToText(ByVal data As String) As String
Dim result As String = Nothing
Dim i As Integer = 0
Dim j As Integer = 0
For Each c As Char In data.ToCharArray
j *= 2
If c = "1"c Then j += 1
i += 1
If i = 8 Then
i = 0
result &= Chr(j)
j = 0
End If
Next
Return result
End Function
It converts binary to text but its a bit difficult for me to understand the logic behind it.
Someone please help.
The code seems to convert a text containing a binary number representing 8 bit character codes to a string containing these characters.
The for each loop loops over all binary digits ("0" or "1") of the input. The code of each result character is computed and after every 8 input characters the code is considered to be complete and the new character whose code was determined is added to the result (result &= Chr(j) is the same as result = result & Chr(j). Chr(j) converts an Integer containing a character code into a character). The variable i counts the bits.
The variable j holds the character code. If a bit is "1", then 1 is added to j (j += 1 is the same as j = j + 1), but not if it is "0".
A "1" in the right most bit position has a (decimal) value of 1. The next to its left a value of 2. The next 4 and so on. The value doubles for each position until it reaches 128 for the left most bit of an 8 bit number. Therefore j is doubled on each loop (j *= 2 is the same as j = j * 2).
Example with just 4 bits:
data = "1010"
The binary number 1010 means
1 * 8 + 0 * 4 + 1 * 2 + 0 * 1 = (decimal)10
The code does this
j = 0 => 0
j *= 2 => 0
j += 1 => 1 'since c = "1"
j *= 2 => 2
'no += 1 since c = "0"
j *= 2 => 4
j += 1 => 5 'since c = "1"
j *= 2 => 10
'no += 1 since c = "0"
The first 1 we added is doubled 3 times and becomes 8. The second 1 we added is doubled only once and becomes 2. 8 + 2 = 10.
As an example. I want to randomly hand out 100 chocolates to 25 kids. I cannot give any kid more than 10 chocolates.
So here m = 100, n = 25, x = 1 and y = 12.
I have checked these questions.
Dividing a number into m parts uniformly randomly
Dividing a number into random unequal parts
They do give some idea but in these questions x and y are not specified.
So basically,
1) Total No. of Chocolates = 100
2) I can only give minimum 1 and maximum 12 chocolates to each kid
3) Chocolates should be distributed between 25 kids
4) I do not want any distribution (uniform or normal) - it should be purely random. (I am willing to exclude this condition if all else fails.)
Private Function divideUniformlyRandomly(n As Integer, m As Integer) As Integer()
Dim rRandom As New Random
Dim fences As Integer() = New Integer(m - 2) {}
For i As Integer = 0 To m - 3
fences(i) = rRandom.Next(0, n - 1)
Next
[Array].Sort(fences)
Dim result As Integer() = New Integer(m - 1) {}
result(0) = fences(0)
For i As Integer = 1 To m - 3
result(i) = fences(i + 1) - fences(i)
Next
result(m - 1) = n - 1 - fences(m - 2)
Return result
End Function
This does work but I get 0 and 13 as well. I cannot ensure x and y here.
Give each child x chocolate. This will leave you with m - (n * x) to distribute randomly. Keep distributing to children that have less than y chocolates, until there are no more chocolates.
Private Function divideUniformlyRandomly(n As Integer, m As Integer, x As Integer, y As Integer) As Integer()
Dim rRandom As New Random
Dim aResult As Integer() = New Integer(n - 1) {}
Dim i As Integer = 0
Dim remaining As Integer = m
' Every n must have a min of x.
For i = 0 To n - 1
aResult(i) = x
remaining -= x
Next
' distribute the remaining m over the children randomly
While remaining > 0
' pick a child randomly
i = rRandom.Next(0, n)
' if the child has less than y, give them one
If aResult(i) < y Then
aResult(i) += 1
remaining -= 1
End If
End While
' Debug
Dim sum As Integer = 0
For i = 0 To n - 1
Console.WriteLine("{0}: {1}", i, aResult(i))
sum += aResult(i)
Next
Console.WriteLine("Sum: {0}", sum)
divideUniformlyRandomly = aResult
End Function
I'm very new to VBA and programming, so this might be a dumb question. I have written the following code:
Function central(X)
Dim xc(300, 10), xa(200)
m = X.Rows.Count
n = X.Columns.Count
For j = 1 To n
xa(j) = 0
For i = 1 To m
xa(j) = xa(j) + X(i, j)
Next i
xa(j) = xa(j) / m
For i = 1 To m
xc(i, j) = X(i, j) - xa(j)
Next i
Next
central = xc()
End Function
This should output a matrix whose elements are subtracted from the average value of their columns.
My problem is that the output is shifted with one row and column. So for example for this table:
1 1 1
2 2 2
3 3 3
it gives me:
0 0 0
0 -1 -1
0 0 0
Thanks in advance!