I've written the code below and keep getting an error for incorrect syntax
It said at line 10 near the , - so this line:
values(1, 'Stolz', 'Ted', 25000, NULL), )
If I only try to insert the first row of data it works fine, it's when I try to do multiple. Am I missing something really simple?
Drop Table #TPerson
CREATE TABLE #TPerson
(
personid int PRIMARY KEY NOT NULL,
lastname varchar(50) NULL,
firstname varchar(50) NULL,
salary money NULL,
managerid int NULL
);
Insert Into #TPerson(Personid, lastname, firstname, salary, managerid)
values (1, 'Stolz', 'Ted', 25000, NULL),
(2, 'Boswell', 'Nancy', 23000, 1),
(3, 'Hargett', 'Vincent', 22000, 1),
(4, 'Weekley', 'Kevin', 22000, 3),
(5, 'Metts', 'Geraldine', 22000, 2),
(6, 'McBride', 'Jeffrey', 21000, 2),
(7, 'Xiong', 'Jay', 20000, 3)
You can write something like this:
Insert Into #TPerson(Personid,lastname,firstname,salary,managerid)
select 1,'Stolz','Ted',25000,NULL
union all select 2,'Boswell','Nancy',23000,1
union all select 3,'Hargett','Vincent',22000,1
union all select 4,'Weekley','Kevin',22000,3
union all select 5,'Metts','Geraldine',22000,2
union all select 6,'McBride','Jeffrey',21000,2
union all select 7,'Xiong','Jay',20000,3
Related
I have these tables below along with the definition. I want to find top 10 products sold in a year after finding counts and without using aggregation and in an optimized way. I want to know if aggregation is still needed or I can accomplish it without using aggregation. Below is the query. Can anyone suggest a better approach.
CREATE TABLE Customer (
id int not null,
first_name VARCHAR(30),
last_name VARCHAR(30),
Address VARCHAR(60),
State VARCHAR(30),
Phone text,
PRIMARY KEY(id)
);
CREATE TABLE Product (
ProductId int not null,
name VARCHAR(30),
unitprice int,
BrandID int,
Brandname varchar(30),
color VARCHAR(30),
PRIMARY KEY(ProductId)
);
Create Table Sales (
SalesId int not null,
Date date,
Customerid int,
Productid int,
Purchaseamount int,
PRIMARY KEY(SalesId),
FOREIGN KEY (Productid) REFERENCES Product(ProductId),
FOREIGN KEY (Customerid) REFERENCES Customer(id)
)
Sample Data:
insert into
Customer(id, first_name, last_name, address, state, phone)
values
(1111, 'andy', 'johnson', '123 Maryland Heights', 'MO', 3211451234),
(1112, 'john', 'smith', '237 Jackson Heights', 'TX', 3671456534),
(1113, 'sandy', 'fleming', '878 Jersey Heights', 'NJ', 2121456534),
(1114, 'tony', 'anderson', '789 Harrison Heights', 'CA', 6101456534)
insert into
Product(ProductId, name, unitprice, BrandId, Brandname)
values
(1, 'watch',200, 100, 'apple'),
(2, 'ipad', 429, 100, 'apple'),
(3, 'iphone', 799, 100, 'apple'),
(4, 'gear', 300, 110, 'samsung'),
(5, 'phone',1000, 110, 'samsung'),
(6, 'tab', 250, 110, 'samsung'),
(7, 'laptop', 1300, 120, 'hp'),
(8, 'mouse', 10, 120, 'hp'),
(9, 'monitor', 400, 130, 'dell'),
(10, 'keyboard', 40, 130, 'dell'),
(11, 'dvddrive', 100, 130, 'dell'),
(12, 'dvddrive', 90, 150, 'lg')
insert into
Sales(SalesId, Date, CustomerID, ProductID, Purchaseamount)
values (30, '01-10-2019', 1111, 1, 200),
(31, '02-10-2019', 1111, 3, 799),
(32, '03-10-2019', 1111, 2, 429),
(33, '04-10-2019', 1111, 4, 300),
(34, '05-10-2019', 1111, 5, 1000),
(35, '06-10-2019', 1112, 7, 1300),
(36, '07-10-2019', 1112, 9, 400),
(37, '08-10-2019', 1113, 5, 2000),
(38, '09-10-2019', 1113, 4, 300),
(39, '10-10-2019', 1113, 3, 799),
(40, '11-10-2019', 1113, 2, 858),
(41, '01-10-2020', 1111, 1, 400),
(42, '02-10-2020', 1111, 2, 429),
(43, '03-10-2020', 1112, 7, 1300),
(44, '04-10-2020', 1113, 7, 2600),
(45, '05-10-2020', 1114, 7, 1300),
(46, '06-10-2020', 1114, 7, 1300),
(47, '07-10-2020', 1114, 9, 800)
Tried this:
SELECT PCY.Name, PCY.Year, PCY.SEQNUM
FROM (SELECT P.Name AS Name, Extract('Year' from S.Date) AS YEAR, COUNT(P.Productid) AS CNT,
RANK() OVER (PARTITION BY Extract('Year' from S.Date) ORDER BY COUNT(P.Productid) DESC) AS RANK
FROM Sales S inner JOIN
Product P
ON S.Productid = P.Productid
) PCY
WHERE PCY.RANK <= 10;
I am seeing this error:
ERROR: column "p.name" must appear in the GROUP BY clause or be used in an aggregate function
LINE 2: FROM (SELECT P.Name AS Name, Extract('Year' from S.Date) AS ...
^
SQL state: 42803
Character: 52
I don't understand why you don't want to use an aggregate function when you have to aggregate over your data. This query works fine, without any issues on the GROUP BY:
WITH stats AS (
SELECT EXTRACT
( YEAR FROM DATE ) AS y,
P.productid,
P.NAME,
COUNT ( * ) numbers_sold,
RANK ( ) OVER ( PARTITION BY EXTRACT ( YEAR FROM DATE ) ORDER BY COUNT ( * ) DESC ) r
FROM
product
P JOIN sales S ON S.Productid = P.Productid
GROUP BY
1,2
)
SELECT y
, name
, numbers_sold
FROM stats
WHERE r <= 10;
This works because the productid is the primary key that has a functional dependency to the product name.
By the way, tested on version 12, but it should work on older and newer versions as well.
Please help me with an SQL query. Here go test tables with data:
CREATE TABLE "Cats"
(
"CatId" SERIAL PRIMARY KEY,
"Name" character varying NOT NULL
);
CREATE TABLE "Measures"
(
"MeasureId" SERIAL PRIMARY KEY,
"CatId" integer NOT NULL REFERENCES "Cats",
"Weight" double precision NOT NULL,
"MeasureDay" integer NOT NULL
);
INSERT INTO "Cats" ("Name") VALUES
('A'), ('B'), ('C')
;
INSERT INTO "Measures" ("CatId", "Weight", "MeasureDay") VALUES
(1, 5.0, 1),
(1, 5.3, 2),
(1, 6.1, 5),
(2, 3.2, 1),
(2, 3.5, 2),
(2, 3.8, 3),
(2, 4.0, 4),
(2, 4.0, 5),
(3, 6.6, 1),
(3, 6.9, 2),
(3, 7.0, 3),
(3, 6.9, 4)
;
How do I select those CatId that have measures for ALL 5 days (MeasureDay takes all values in (1, 2, 3, 4, 5)) ?
On this test data, the query should return 2 since only Cat with CatId = 2 has measures for all days (1, 2, 3, 4, 5).
I assume that I should use GROUP BY "CatId" and HAVING clauses, but what kind of query should be inside HAVING?
try like this using group by
select CatId
from Measures
where MeasureDay in (1, 2, 3, 4, 5)
group by CatId
having count(distinct MeasureDay) = 5;
You can use aggregation and a having clause:
select m.CatId
from measures m
group by m.CatId
having count(distinct measureDay) = 5;
I'm trying to create a calculated column in SQL. Basically I need to get a set of distinct dates and determine how many customers there are in the population on that particular date. The result should be something like:
Date______| Customers
2016-01-01 | 1
2016-01-01 | 2
2016-01-05 | 3
2016-02-09 | 4
etc.
I created a sample database & data (using MySQL as I don't have permission to create tables in our Oracle dbs) with the following script:
create database customer_example;
use customer_example;
create table customers (
customer_id int not null primary key,
customer_name varchar(255) not null,
term_date DATE);
create table employee (
employee_id int not null primary key,
employee_name varchar(255) not null);
create table cust_emp (
ce_id int not null AUTO_INCREMENT,
emp_id int not null,
cust_id int not null,
start_date date,
end_date date,
deleted_yn boolean,
primary key (emp_id, cust_id, ce_id),
foreign key (cust_id) references customers(customer_id),
foreign key (emp_id) references employee(employee_id));
insert into customers (customer_id, customer_name)
values (1, 'Bobby Tables'), (2, 'Grover Cleveland'), (3, 'Chester Arthur'), (4, 'Jan Bush'), (5, 'Emanuel Porter'), (6, 'Darren King'), (7, 'Casey Mcguire'), (8, 'Robin Simpson'), (9, 'Robin Tables'), (10, 'Mitchell Arnold');
insert into customers (customer_id, customer_name, term_date)
values (11, 'Terrell Graves', '2017-01-01'), (12, 'Richard Wagner', '2016-10-31'), (13, 'Glenn Saunders', '2016-11-19'), (14, 'Bruce Irvin', '2016-03-11'), (15, 'Glenn Perry','2016-06-06'), (16, 'Hazel Freeman', '2016-07-10'),
(17, 'Martin Freeman', '2016-02-11'), (18, 'Morgan Freeman', '2017-02-01'), (19, 'Dirk Drake', '2017-01-12'), (20, 'Fraud Fraud', '2016-12-31');
insert into employee (employee_id, employee_name)
values (1000, 'Cedrick French'), (1001, 'Jane Phillips'), (1002, 'Brian Green'), (1003, 'Shawn Brooks'), (1004, 'Clarence Thomas');
insert into cust_emp (emp_id, cust_id, start_date, end_date)
values (1000, 1, '2016-01-01', '2016-02-01'), (1000, 1, '2016-02-01', '2016-02-01'), (1000, 2,'2016-01-05', '2016-01-16'),(1000, 3,'2016-02-09', '2016-03-14'),(1000, 4,'2016-03-20', '2016-04-23'),
(1000, 5,'2016-01-01', '2016-01-16'),(1000, 6,'2016-01-01', '2016-01-16'),(1004, 7, '2016-01-14', '206-01-16'),
(1004, 8, '2016-01-13', '2016-01-16'),(1004, 9, '2016-01-05', '2016-01-16'), (1003, 12, '2016-04-21', '2016-11-30');
insert into cust_emp (emp_id, cust_id, start_date, deleted_yn)
values (1002, 11, '2016-04-10', TRUE),(1003, 10, '2016-01-16', FALSE), (1004, 12, '2016-04-20', TRUE), (1004, 12, '2016-04-19', FALSE), (1003, 13, '2016-06-06', TRUE), (1002, 14, '2016-06-10', TRUE),
(1004, 15, '2016-03-25', TRUE), (1004, 17, '2016-01-02', TRUE), (1004, 18, '2017-01-01', TRUE), (1004, 19, '2016-11-13', TRUE), (1004, 20, '2016-03-10', TRUE), (1004, 16, '2016-05-13', TRUE);
insert into cust_emp (emp_id, cust_id, start_date)
values (1002, 1, '2016-02-01'), (1004, 2, '2016-01-16'),(1003, 3, '2016-03-14'),(1002, 4, '2016-04-23'),(1004, 5, '2016-01-16'),(1002, 6, '2016-01-16'),(1004, 7, '2016-01-16'),
(1004, 8, '2016-01-16'),(1002, 9, '2016-01-16'), (1004, 10, '2016-01-16');
The following SQL works fine in MySQL but when I try it in Oracle, I get an 'invalid identifier' on 'dates':
select distinct(ce.start_date) as dates,
(select count(distinct(c.customer_id))
from customers c
inner join cust_emp ce on c.customer_id = ce.cust_id
where ce.start_date < dates
and (ce.end_date > dates or (ce.deleted_yn = false or ce.deleted_yn is null))
and (c.term_date > dates or c.term_date is null)
)
from cust_emp as ce;
It seems as though this is because the dates is too far in a subquery. I've tried a CTE as well, but that seems to have the same issue as it gave the same error. How can I re-write this so that I can assess how many customers were there for each date in Oracle?
Huh?
Isn't this what you want?
select ce.dates as dates, count(distinct c.customer_id)
from cust_emp ce join
customers c
on c.customer_id = ce.cust_id
where ce.start_date < ce.dates and
(ce.end_date > ce.dates or ce.deleted_yn = false or ce.deleted_yn is null) and
(c.term_date > ce.dates or c.term_date is null)
group by ce.dates
order by ce.dates;
I don't really understand the use of the subquery with select distinct. The logic you describe is more easily understood as a simple aggregation.
I'm not sure where dates comes from. It is not in your data model, but it is in your sample query.
I've got a table with almost 10 million views and would to run this query on the latest million or hundred thousand or so.
Here's a SQL fiddle with example data and input/output: http://sqlfiddle.com/#!9/340a41
Is this even possible?
CREATE TABLE object (`id` int, `name` varchar(7), `value` int);
INSERT INTO object (`id`, `name`, `value`)
VALUES
(1, 'a', 1),
(2, 'b', 2),
(3, 'c', 100),
(4, 'a', 1),
(5, 'b', 2),
(6, 'c', 200),
(7, 'a', 2),
(8, 'b', 2),
(9, 'c', 300),
(10, 'a', 2),
(11, 'b', 2),
(12, 'a', 2),
(13, 'b', 2),
(14, 'c', 400)
;
-- Want:
-- name, max(id), count(id)
-- 'a', 4, 2
-- 'b', 14, 5
-- 'a', 12, 3
If you want the latest and the id is implemented sequentially, then you can do this using limit or top. In SQL Server:
select top 100000 o.*
from object o
order by id desc;
In MySQL, you would use limit:
select o.*
from object o
order by id desc
limit 100000
select name, count(id) cnt, max(id) max_id, max(value) max_v
from
(select
top 1000000 -- MS SQL Server
id,name,value
from myTable
limit 1000000 --mySQL
order by id desc)
group by name
remove line which doesn't match your server.
I made an SQL Fiddle and what I would like to do is join these two queries by using the departmentid.
What I would like to show is the departmentname and not_approved_manager.
Would it be best to use a union or join in this case?
Tables
create table cserepux
(
status int,
comment varchar(25),
departmentid int,
approveddate datetime
);
insert into cserepux (status, comment, departmentid, approveddate)
values (1, 'testing1', 1, NULL), (1, 'testing2', 1, NULL),
(1, 'testing2', 2, NULL), (0, 'testing2', 1, NULL),
(0, 'tesitng2', 1, NULL), (0, 'testing2', 1, NULL),
(0, 'tesitng2', 1, NULL), (0, 'testing3', 2, NULL),
(0, 'testing3', 3, NULL);
create table cseDept
(
departmentid int,
department_name varchar(25)
);
insert into cseDept (departmentid,department_name)
values (1, 'department one'), (2, 'department two'),
(3, 'department three'), (4, 'department four');
Query
select
departmentid,
COUNT(*) AS 'not_approved_manager'
from
cserepux
where
approveddate is null
group by
departmentid
SELECT * FROM cseDept
You need to do a join. A union will not get you what you want.
select d.department_name, COUNT(*) AS 'not_approved_manager'
from cserepux c
inner join cseDept d on c.departmentid = d.departmentid
where approveddate is null
group by d.department_name
Do you need just a join and a correct group by
select dep.department_name, COUNT(*) AS 'not_approved_manager'
from cseDept dep
join cserepux cs on cs.departmentid = dep.departmentid
where approveddate is null
group by dep.department_name
Fiddle: http://sqlfiddle.com/#!3/5cf4e/30
Since joins and group by are really basic things in SQL I can suggest you do take a look on some tutorials to get a bit more proficiency whit it. You can try SQL Server Central stairway articles series