SQL Numerator from 0-Z - sql

Question

Is there a simple an elegant way to create a numerator in SQL the do the following:
Three digit number
Each digit can can have a number from 0-Z : Min 000, Max ZZZ
for example let's take : 129, After increasing by 1, the new number will be 12A
When number is 15Z, after increasing by one it will turn into 160 and so on.
I can only use SQL, no code behind !!.
I only need an enumerator and not a conversion between bases like other have suggested.
Can someone help me write a UDF.
I got an excellent and elegant answer which I marked below.
Who ever marked my question as negative please reconsider because this is a real problem and not a theoratic one and it saved me a lot of workarounds.
Thanks in advance.

Answer 1

Produce cartesian and take the first that is greater then input value:
declare #v varchar(10) = '129'
;with cte as(select * from (values('0'),('1'),('2'),('3'),('4'),('5'),('6'),('7'),('8'),('9')
,('A'),('B'),('C'),('D'),('E'),('F'),('G'),('H'),('I'),('J'),('K')
,('L'),('M'),('N'),('O'),('P'),('Q'),('R'),('S'),('T'),('U'),('V')
,('W'),('X'),('Y'),('Z')) t(n))
select top 1 c1.n + c2.n + c3.n as n
from cte c1
cross join cte c2
cross join cte c3
where c1.n + c2.n + c3.n > #v
order by n

Answer 2

You should store the values numeric and then convert them when needed to your format.
Here is a script to add one to the strange format. The script is not checking for overflow nor invalid data in the original value:
DECLARE #original char(3) = '129'
DECLARE #val int =
CASE WHEN RIGHT(#original, 1) > '9' THEN ASCII(RIGHT(#original, 1)) - 55
ELSE RIGHT(#original, 1) END
+CASE WHEN SUBSTRING(#original, 2,1) > '9'
THEN ASCII(SUBSTRING(#original, 2,1)) - 55 ELSE SUBSTRING(#original, 2,1) END * 36
+CASE WHEN LEFT(#original, 1) > '9'
THEN ASCII(LEFT(#original, 1)) - 55 ELSE LEFT(#original, 1) END * 36 * 36
+1 -- increase 1
SELECT
CHAR(CASE WHEN #val / 36 / 36 > 9 THEN #val / 36 / 36 + 55
ELSE #val / 36 / 36+48 END)+
CHAR(CASE WHEN (#val / 36) % 36 > 9 THEN (#val / 36) % 36 + 55
ELSE (#val / 36) % 36+48 END)+
CHAR(CASE WHEN #val % 36 % 36 > 9 THEN #val % 36 % 36 + 55
ELSE #val % 36 % 36+48 END)
Result:
12A

Answer 3

I suggest you create this table in your DB with this query
;WITH Ch AS
( select i,C=CASE WHEN i<=10 THEN Char(47+i) ELSE CHAR(54+i) END FROM (SELECT TOP 36 row_number() over(order by object_id) i from sys.objects) t )
SELECT row_number() over(order by Ch.c,Ch2.c,Ch3.c) i,
Ch.c + Ch2.c + Ch3.c C INTO B36 FROM Ch CROSS JOIN Ch Ch2 CROSS JOIN Ch Ch3
So you can do indexes in the i & C columns
Then you do queries from this table for conversions with index seeking fastest speed and optimized as follows:
SELECT C FROM B36 WHERE i=3728
Reverse encoding with
SELECT i FROM B36 WHERE C='AG7'

Answer 4

Function that converts bigint to Base36
CREATE FUNCTION dbo.fnBase36
(
#Val BIGINT
)
RETURNS VARCHAR(13)
AS
BEGIN
DECLARE #Result VARCHAR(13) = ''
IF (#Val <= 0)
BEGIN
RETURN '0'
END
WHILE (#Val > 0)
BEGIN
SELECT #Result = CHAR(#Val % 36 + CASE WHEN #Val % 36 < 10 THEN 48 ELSE 55 END) + #Result,
#Val = FLOOR(#Val/36)
END
RETURN #Result
END
GO
select dbo.fnBase36(321)
--returns 8X

Answer 5

I can give you a converter like this:
char(48 + (i / (36 * 36)) + CASE WHEN (i / (36 * 36)) > 9 THEN 7 ELSE 0 END) +
char(48 + (i / 36) % 36 + CASE WHEN (i / 36) % 36 > 9 THEN 7 ELSE 0 END) +
char(48 + i % 36 + CASE WHEN i % 36 > 9 THEN 7 ELSE 0 END)
that can convert an int value to what you want.
[SQL Fiddle Demo]
Edit
I also can give you inversion of above converter like this:
(E.g.: #t varchar(max) = '12Z')
(ASCII(LEFT(#t, 1)) - 48 - CASE WHEN ASCII(LEFT(#t, 1)) > ASCII('9') THEN 7 ELSE 0 END) * 36 * 36 +
(ASCII(SUBSTRING(#t,2,1)) - 48 - CASE WHEN ASCII(SUBSTRING(#t,2,1)) > ASCII('9') THEN 7 ELSE 0 END) * 36 +
(ASCII(RIGHT(#t, 1)) - 48 - CASE WHEN ASCII(RIGHT(#t, 1)) > ASCII('9') THEN 7 ELSE 0 END)