I want to use the today() function as a dynamic filter to show MM/YYYY as number format
So i want my filter to show =201601
But with my function i get 20161: input(CATS(Year(TODAY()),Month(TODAY())), 6.) =20161
Does anybody know how to show 201601 instead of 20161?
There is a format that will display a data in YYYYMM format.
put(today(),yymmn6.)
Did you intend to convert to a number instead of a character string? If so then you could use the INPUT function as in your example.
input(put(today(),yymmn6.),6.)
You could even use the YYMMDDN format if YYMMN doesn't work for you, just read the first 6 digits.
input(put(today(),yymmddn8.),6.)
Or you could build the number arithmetically.
year(today())*100+month(today())
Here's the proper function:
put(today(), yymmn6.)
Related
I want to extract the decimal part of a number and use it as a column name. For example, extract “001“ from 0.001. Can I use decimalFormat for this?
Please refer to the script below using DolphinDB:
x=1.001
decimalFormat(x - floor(x), "0.000").substr(2)
The result is 001.
Snowflake documentation says to use TO_DATE('2022-01-01', 'YYYYMM'), however, when running that I receive the error message:
"Error: too many arguments for function [TO_DATE("policy_effective_date", 'YYYYMM')] expected 1, got 2"
Any help is appreciated.
I was expecting to see 2022-01-01 turn into 202201. Even if I need to bring in DD that's fine too, I can just capture the LEFT 6 digits, but regardless the system is saying it's too many arguments.
TO_DATE() function accepts string/varchar format date and converts to Date Data type. For that we need to pass existing String date type format to parse. To Convert to the required format we need to use to_varchar as given in the documentation. https://docs.snowflake.com/en/sql-reference/functions-conversion.html
I have tried everything that I can think of to get the right date format. Can anybody help with this RPA-problem in UiPath. I have used the 'get text' activity to get the folder date and after that tried to use the
Datetime.ParseExact(Str variable,"dd/MM/yyyy", System.Globalization.CultureInfo.InvariantCulture).
It gives me the error:
Assign: String was not recognized as a valid DateTime.
Your help is much appreciated.
edit: I have now sought help from a friend who figured it out. The error was in the string, which could not be seen, because there was an invisible character in the string that I extracted through 'get text' activity. The solution is in 2 steps:
assign another variable to the exact same date and use an if statement to find out if these two strings are equal and you will find out that they are not.
Now use a regex to capture only digits and slash/hyphen which will get rid of the invisible character.
Try to use "dd_MM_yyyy" instead of "dd/MM/yyyy".
The reason is because UiPath/VB.Net has a habit of using US date formatting even though you're using Culture Info...It's a real pain
Try this:
pDateString = "21/02/2020"
Assign a Date type variable = Date.ParseExact(pDateString,"dd/MM/yyyy",nothing)
Here we're telling the parser to use English format date...The Date type returned will be in US format but you can simply convert back to uk IF needed by using something like:
pDateString("dd/MM/yyyy")
I am trying to take the following value and making it into a date format of dd-MMM-yy
For example: 110412 turns into 04-NOV-12
My formula as of right now is:
(CONCATENATE(MID(E14,3,2),"-",(TEXT(LEFT(E14,2),"MMM")),"-",RIGHT(E14,2)))
It is giving me 04-Jan-12.
Please note that I would like the month to be in all caps.
Try using the "UPPER(foo)" function as a wrapper to make the result all caps.
UPPER((CONCATENATE(MID(E14,3,2),"-",(TEXT(LEFT(E14,2),"MMM")),"-",RIGHT(E14,2))))
or better still:
=MID(E14,3,2)&"-"&UPPER(TEXT(DATE(MID(E14,5,2),MID(E14,1,2),MID(E14,3,2)),"MMM"))&"-"&RIGHT(E14,2)
I got a date of the type SYDATUM and wondering how to format it in a format like m/d/y.
I've found some snippets on the web, but they were not really helpful.
-thanks yor your help.
You should be more specific - what exactly do you want to do with the date (use type D internally, it's shorter and does the same thing).
Do you want to WRITE it to a list screen? Use the formatting options described in the documentation and online help:
WRITE l_my_date MM/DD/YYYY.
Do you want to convert it to a text variable? Very similar:
WRITE l_my_date TO l_my_text MM/DD/YYYY.
To set the date format in a SAPscript form, see the SET DATE MASK command.
To print the formatted date in a SmartForm, use the WRITE command and a temporary variable (yes, ugly, I know...)
Most controls (ALV Grid for example) should take care of the format automatically.
However - be careful when hard-coding the format into your application. Usually you don't have to do this because the system automatically uses the format specified in the user master data. This ensures that every user will see the date formatted according to their locale settings.
Normally it's better to export the date into the plant level country specific date format:
if w_country is initial.
select single LAND1
from T001W
into w_country
where WERKS eq w_the_plant.
endif.
SET COUNTRY w_country.
write w_the_date to w_export.
for example 03/04/2002 could be different date in different country.
You can try the keyword TRANSLATE. Alternatively suggest you could have a look at this link