Related
I need to calculate due date / end date for SLAs. As input values I have the start date and a timespan (in minutes). This calculation needs to take into account business hours, weekends, and holidays.
I've seen a lot of examples where the input is start date and end date, but have been struggling finding anything similar to the above input values.
Is there an elegant solution to this problem? Is there a way to calculate due date without using a loop? I can't think of a way to do the calculation without doing something similar to the following terrible algorithm:
Create a return variable "due date" and set it to input variable
"start date"
Create a control variable "used minutes" and set it to 0
Create a loop with the condition "used minutes" <= "input timespan"
Inside the loop, add a second to the "due date" return variable
Inside the loop, check if the second is within hours of operation
(checking business hours, weekends, and holidays). If so, increment
control variable "used minutes" by 1.
Upon exiting the loop, return variable "due date"
You need a table with valid business hours, with the weekends and holidays excluded (or marked as weekend/holiday so you can skip them.) Each row represents one day and the number of working hours for that day. Then you query the business hours table from your start date to the first (min) date where the sum(hours*60) is greater than your minutes parameter, excluding marked weekend/holiday rows. That gives you your end date.
Here's the day table:
CREATE TABLE [dbo].[tblDay](
[dt] [datetime] NOT NULL,
[dayOfWk] [int] NULL,
[dayOfWkInMo] [int] NULL,
[isWeekend] [bit] NOT NULL,
[holidayID] [int] NULL,
[workingDayCount] [int] NULL,
CONSTRAINT [PK_tblDay] PRIMARY KEY CLUSTERED
(
[dt] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
here's how I populate the table with days:
CREATE PROCEDURE [dbo].[usp_tblDay]
AS
BEGIN
SET NOCOUNT ON;
DECLARE
#Dt datetime ,
#wkInMo int,
#firstDwOfMo int,
#holID int,
#workDayCount int,
#weekday int,
#month int,
#day int,
#isWkEnd bit
set #workDayCount = 0
SET #Dt = CONVERT( datetime, '2008-01-01' )
while #dt < '2020-01-01'
begin
delete from tblDay where dt = #dt
set #weekday = datepart( weekday, #Dt )
set #month = datepart(month,#dt)
set #day = datepart(day,#dt)
if #day = 1 -- 1st of mo
begin
set #wkInMo = 1
set #firstDwOfMo = #weekday
end
if ((#weekday = 7) or (#weekday = 1))
set #isWkEnd = 1
else
set #isWkEnd = 0
if #isWkEnd = 0 and (#month = 1 and #day = 1)
set #holID=1 -- new years on workday
else if #weekday= 6 and (#month = 12 and #day = 31)
set #holID=1 -- holiday on sat, change to fri
else if #weekday= 2 and (#month = 1 and #day = 2)
set #holID=1 -- holiday on sun, change to mon
else if #wkInMo = 3 and #weekday= 2 and #month = 1
set #holID = 2 -- mlk
else if #wkInMo = 3 and #weekday= 2 and #month = 2
set #holID = 3 -- President’s
else if #wkInMo = 4 and #weekday= 2 and #month = 5 and datepart(month,#dt+7) = 6
set #holID = 4 -- memorial on 4th mon, no 5th
else if #wkInMo = 5 and #weekday= 2 and #month = 5
set #holID = 4 -- memorial on 5th mon
else if #isWkEnd = 0 and (#month = 7 and #day = 4)
set #holID=5 -- July 4 on workday
else if #weekday= 6 and (#month = 7 and #day = 3)
set #holID=5 -- holiday on sat, change to fri
else if #weekday= 2 and (#month = 7 and #day = 5)
set #holID=5 -- holiday on sun, change to mon
else if #wkInMo = 1 and #weekday= 2 and #month = 9
set #holID = 6 -- Labor
else if #isWkEnd = 0 and (#month = 11 and #day = 11)
set #holID=7 -- Vets day on workday
else if #weekday= 6 and (#month = 11 and #day = 10)
set #holID=7 -- holiday on sat, change to fri
else if #weekday= 2 and (#month = 11 and #day = 12)
set #holID=7 -- holiday on sun, change to mon
else if #wkInMo = 4 and #weekday= 5 and #month = 11
set #holID = 8 -- thx
else if #holID = 8
set #holID = 9 -- dy after thx
else if #isWkEnd = 0 and (#month = 12 and #day = 25)
set #holID=10 -- xmas day on workday
else if #weekday= 6 and (#month = 12 and #day = 24)
set #holID=10 -- holiday on sat, change to fri
else if #weekday= 2 and (#month = 12 and #day = 26)
set #holID=10 -- holiday on sun, change to mon
else
set #holID = null
insert into tblDay select #dt,#weekday,#wkInMo,#isWkEnd,#holID,#workDayCount
if #isWkEnd=0 and #holID is null
set #workDayCount = #workDayCount + 1
set #dt = #dt + 1
if datepart( weekday, #Dt ) = #firstDwOfMo
set #wkInMo = #wkInMo + 1
end
END
I also have a holiday table, but everyone's holidays are different:
holidayID holiday rule description
1 New Year's Day Jan. 1
2 Martin Luther King Day third Mon. in Jan.
3 Presidents' Day third Mon. in Feb.
4 Memorial Day last Mon. in May
5 Independence Day 4-Jul
6 Labor Day first Mon. in Sept
7 Veterans' Day Nov. 11
8 Thanksgiving fourth Thurs. in Nov.
9 Fri after Thanksgiving Friday after Thanksgiving
10 Christmas Day Dec. 25
HTH
This is the best I could do, still uses a loop but uses date functions instead of incrementing a minutes variable. Hope you like it.
--set up our source data
declare #business_hours table
(
work_day varchar(10),
open_time varchar(8),
close_time varchar(8)
)
insert into #business_hours values ('Monday', '08:30:00', '17:00:00')
insert into #business_hours values ('Tuesday', '08:30:00', '17:00:00')
insert into #business_hours values ('Wednesday', '08:30:00', '17:00:00')
insert into #business_hours values ('Thursday', '08:30:00', '17:00:00')
insert into #business_hours values ('Friday', '08:30:00', '18:00:00')
insert into #business_hours values ('Saturday', '09:00:00', '14:00:00')
declare #holidays table
(
holiday varchar(10)
)
insert into #holidays values ('2015-01-01')
insert into #holidays values ('2015-01-02')
--Im going to assume the SLA of 2 standard business days (0900-1700) = 8*60*2 = 960
declare #start_date datetime = '2014-12-31 16:12:47'
declare #time_span int = 960-- time till due in minutes
declare #true bit = 'true'
declare #false bit = 'false'
declare #due_date datetime --our output
--other variables
declare #date_string varchar(10)
declare #today_closing datetime
declare #is_workday bit = #true
declare #is_holiday bit = #false
--Given our timespan is in minutes, lets also assume we dont care about seconds in start or due dates
set #start_date = DATEADD(ss,datepart(ss,#start_date)*-1,#start_date)
while (#time_span > 0)
begin
set #due_date = DATEADD(MINUTE,#time_span,#start_date)
set #date_string = FORMAT(DATEADD(dd, 0, DATEDIFF(dd, 0, #start_date)),'yyyy-MM-dd')
set #today_closing = (select convert(datetime,#date_string + ' ' + close_time) from #business_hours where work_day = DATENAME(weekday,#start_date))
if exists((select work_day from #business_hours where work_day = DATENAME(weekday,#start_date)))
set #is_workday = #true
else
set #is_workday = #false
if exists(select holiday from #holidays where holiday = #date_string)
set #is_holiday = #true
else
set #is_holiday = #false
if #is_workday = #true and #is_holiday = #false
begin
if #due_date > #today_closing
set #time_span = #time_span - datediff(MINUTE, #start_date, #today_closing)
else
set #time_span = #time_span - datediff(minute, #start_date, #due_date)
end
set #date_string = FORMAT(DATEADD(dd, 1, DATEDIFF(dd, 0, #start_date)),'yyyy-MM-dd')
set #start_date = CONVERT(datetime, #date_string + ' ' + isnull((select open_time from #business_hours where work_day = DATENAME(weekday,convert(datetime,#date_string))),''))
end
select #due_date
Sql to Calculate due date excluding holidays and considering business hour as below :- < note : - It's working correctly Business hour (8-5) Maintain holiday table
CREATE TABLE [dbo].[holiday](
[id] [int] IDENTITY(1,1) NOT NULL,
[region] [nvarchar](10) NULL,
[Hdate] [date] NULL,
)
>
declare #start datetime= getdate()
declare #slamins int =960 --- SLA time in mins
declare #Country varchar(2)='NA'
declare #start_hour int = 8 -- business start hour
declare #end_hour int = 17 -- business end hour
declare #true bit = 'true'
declare #false bit = 'false'
declare #is_workday bit = #true
declare #is_holiday bit = #false
declare #due_date datetime
declare #today_closing datetime
declare #temp int = 0
declare #holidays table (HDate DateTime) -- Table variable to hold holidayes
---- Get country holidays from table based on the country code (Feel free to remove this or modify as per your DB schema)
Insert Into #Holidays (HDate) Select date from HOLIDAY Where region=#Country and Hdate>=DateAdd(dd, DateDiff(dd,0,#start), 0)
--check for weekends
set #start = case(datepart(dw,#start)+##datefirst-1)%7
when 0 then Convert(dateTime,CONVERT(varchar,#start+1,101)+' 08:00:00')
when 6 then Convert(dateTime,CONVERT(varchar,#start+2,101)+' 08:00:00')
else #start end
-- check if start time is before business hour
if datepart(hh, #start) < #start_hour set #start = Convert(dateTime,CONVERT(varchar,#start,101)+' 08:00:00')
-- check if start time is after business hour
if datepart(hh, #start) >= #end_hour set #start = Convert(dateTime,CONVERT(varchar,#start+1,101)+' 08:00:00')
-- loop start
while (#slamins > 0)
begin
-- prepared closing date time based on start date
set #today_closing = Convert(dateTime,CONVERT(varchar,#start,101)+' 17:00:00')
set #due_date = #start
-- calculate number of Minute between start date and closing date
set #temp = DATEDIFF(N, #start , #today_closing);
--check for weekends
if (DATEPART(dw, #start)!=1 AND DATEPART(dw, #start)!=7)
set #is_workday = #true
else
set #is_workday = #false
--check for holidays
if (Select Count(*) From #Holidays Where HDATE=DateAdd(dd, DateDiff(dd,0,#start), 0)) = 0
set #is_holiday =#false
else
set #is_holiday = #true
if #is_workday = #true and #is_holiday = #false
begin
if(#temp < #slamins)
begin
set #slamins = #slamins - #temp
end
else
begin
set #due_date = DATEADD(MINUTE,#slamins,#start)
set #slamins = 0
print #due_date
end
end
set #start = Convert(dateTime,CONVERT(varchar,#start+1,101)+' 08:00:00')
end
select #due_date
Here is an option using a WorkSchedule table, which will contain the business hours that are available to count towards the SLA. To account for weekends and holidays, just do not insert records for these days into the WorkSchedule table.
This solution also uses a "Tally" table aka numbers table in the due date calc. I also included debug output to help you see what is going on, so just comment out or uncomment any debug sections to see less/more info.
I used SQL temp tables in this example so that you can run it without messing up your current database schema, but you should replace with physical tables if you use this solution.
Test Data setups:
CREATE TABLE #WorkSchedule(WorkStart datetime not null primary key, WorkEnd datetime not null);
GO
CREATE TABLE #Tally (N int not null primary key);
GO
--POPULATE TEST DATA
--populate Tally table
insert into #Tally (N)
select top 10000 N = row_number() over(order by o.object_id)
from sys.objects o cross apply sys.objects o2
;
go
--POPULATE WITH DUMMY TEST DATA
INSERT INTO #WorkSchedule(WorkStart, WorkEnd)
SELECT
workStart = dateadd(hour, 8, t.workDate)
, workEnd = dateadd(hour, 17, t.workDate)
FROM (
SELECT top 10000 workDate = dateadd(day, row_number() over(order by o.object_id), '2000-01-01')
FROM sys.objects o cross apply sys.objects o2
) t
--Exclude weekends from work schedule
WHERE datename(weekday, t.workDate) not in ('Saturday','Sunday')
;
GO
Code to calculate Due Date:
SET NOCOUNT ON;
DECLARE #startDate datetime;
DECLARE #SLA_timespan_mins int;
DECLARE #workStartDayOne datetime;
DECLARE #SLA_Adjusted int;
DECLARE #dueDate datetime;
--SET PARAM VALUES HERE FOR TESTING TO ANY DATE/SLA TIMESPAN YOU WANT:
SET #startDate = '2014-01-04 05:00'; --Saturday
SET #SLA_timespan_mins = 10 * 60 ; --10 hrs.
--get the info day 1, since your start date might be after the work start time.
select top 1 #workStartDayOne = s.WorkStart
--increase the SLA timespan mins to account for difference between work start and start time
, #SLA_Adjusted = case when #startDate > s.WorkStart then datediff(minute, s.WorkStart, #startDate) else 0 end + #SLA_timespan_mins
from #WorkSchedule s
where s.WorkEnd > #startDate
and s.WorkStart <> s.WorkEnd
order by s.WorkStart asc
;
--DEBUG info:
select 'Debug Info' as DebugInfo, #startDate AS StartDate, #workStartDayOne as workStartDayOne, #SLA_timespan_mins as SLA_timespan_mins, #SLA_Adjusted as SLA_Adjusted;
--now sum all the non work hours during that period and determine the additional mins that need added.
;with cteWorkMins as
(
SELECT TOP (#SLA_Adjusted)
s.WorkStart, s.WorkEnd
, WorkMinute = dateadd(minute, t.N, cast(s.WorkStart as datetime))
, t.N as MinuteOfWorkDay
, RowNum = row_number() over(order by s.WorkStart, t.N)
FROM #WorkSchedule s
INNER JOIN #Tally t
ON t.N between 1 and datediff(minute, s.WorkStart, s.WorkEnd)
WHERE s.WorkStart >= #workStartDayOne
ORDER BY s.WorkStart, t.N
)
/**/
SELECT #dueDate = m.WorkMinute
FROM cteWorkMins m
WHERE m.RowNum = #SLA_Adjusted
--*/
/**
--DEBUG: this query will show every minute that is accounted for during the Due Date calculation.
SELECT m.*
FROM cteWorkMins m
--WHERE m.RowNum = #SLA_Adjusted
ORDER BY m.WorkMinute
--*/
;
select #dueDate as DueDate;
GO
Test Cleanup:
IF object_id('TEMPDB..#WorkSchedule') IS NOT NULL
DROP TABLE #WorkSchedule;
GO
IF object_id('TEMPDB..#Tally') IS NOT NULL
DROP TABLE #Tally;
GO
as I understood from your question, what you need is as follow
You have given start date and number of minutes added to it, then you need to get the due date
To get the due date, you need to exclude the holidays and the due date should be during business day
here is what you can do
declare #start datetime,
#min int,
#days int
set #start= '28 Dec 2014'
set #min = 2200
-- get the number of days
set #days=datediff(day,#start,dateadd(minute,#min,#start))
-- get the due date
select max(Date)
from
(select row_number() over( order by t.Id)-1 as Id,t.Date
from DateMetadata t
inner join BusinessDays b on Day(t.Date) = b.Day
where t.Date > = #start and not exists(select 1 from Holidays h
where h.Day=Day(t.Date)
and h.Month=Month(t.Date))) as p
where p.Id < #days
Note :that DateMetadata table you will setup it in your database once
the setup for the above code :
create table Holidays(Id int identity(1,1),
Name nvarchar(50),
Day int,
Month int)
create table BusinessDays(Id int identity(1,1),
Name nvarchar(20),
Day int)
-- i am putting some days that are known,
-- it depends on you to define which holidays you want
insert into Holidays (Name,Day,Month) values('Christmas',25,12)
insert into Holidays(Name,Day,Month) values('New Year',31,12)
insert into Holidays(Name,Day,Month) values('Valentine',14,2)
insert into Holidays(Name,Day,Month) values('Mothers day',21,3)
insert into Holidays(Name,Day,Month) values('April fools day',1,4)
-- i am assuming that the business days are from monday till friday and
-- saturday and sunday are off days
insert into BusinessDays(Name,Day) values ('Monday',1)
insert into BusinessDays(Name,Day) values('Tuesday',2)
insert into BusinessDays(Name,Day) values('Wednesday',3)
insert into BusinessDays(Name,Day) values('Thursday',4)
insert into BusinessDays(Name,Day) values('Friday',5)
this table is needed and you will setup it once
-- set up a table that contains all dates from now till 2050 for example
-- and you can change the value of 2050 depending on your needs
-- this table you will setup it once
create table DateMetadata(Id int identity(1,1),
Date datetime)
declare #date datetime
set #date='01 Jan 2014'
while #date < '31 Dec 2050'
begin
insert into DateMetadata(Date) values(#date)
set #date = #date + 1
end
here a working DEMO
if you need any explanation, i am ready
hope it will help you
I created a function to calculate due date from the table, once it's populated as per Beth's and others' approaches (various similar methods for doing this, as you can see -- it only took me about an hour to think about all the UK holidays and populate the table including Easter dates up to 2029 without using these exact guides).
Note that my table contains SLA in business hours (8 hours in a normal day, 5 days in a normal week), your business hours may vary but you can amend this easily, just make sure your business hours are set the same for both the SLA table and the function below.
Code below is T-SQL (written in SSMS v17.8.1)
CREATE FUNCTION [JIRA].[Fn_JIRA_Due_Date] (
#CreatedDate DATETIME, #SLA_Business_Hours INTEGER
) RETURNS DATETIME
AS
-- SELECT [JIRA].[Fn_JIRA_Due_Date]('2019-12-28 08:00:00', 24)
/*
baldmosher™
2019-03-25
* Function returns the DueDate for a JIRA ticket, based on the CreatedDate and the SLA (based on the Issue Type, or the Epic for Tasks) and business hours per date (set in [JIRA].[Ref_JIRA_Business_Hours])
* Called by IUP to store this at the time the ticket is loaded
* Can only consider SLA in Business Hours:
* <24hrs calendar = <8hrs business
* =24hrs calendar = 8hrs business
* >24hrs calendar = 8hrs business * business days
*/
BEGIN
IF #CreatedDate IS NULL OR #SLA_Business_Hours IS NULL RETURN NULL;
DECLARE #SLA_Hours_Remaining SMALLINT = #SLA_Business_Hours;
--SET DATEFIRST 1;
DECLARE #DueDate DATETIME;
DECLARE #BusHrsStart DECIMAL(18,10) = 8 ; -- start of Business Hours (8am)
DECLARE #BusHrsClose DECIMAL(18,10) = 16 ; -- close of Business Hours (4pm)
--DECLARE #WkndStart DECIMAL(18,10) = 6 ; -- start of weekend (Sat)
DECLARE #Hours_Today SMALLINT ; -- # hours left in day to process ticket
-- PRINT 'Created ' + CAST(CAST(#CreatedDate AS DATE) AS VARCHAR(10)) + ' ' + CAST(CAST(#CreatedDate AS TIME) AS VARCHAR(8))
--!!!! extend to the next whole hour just to simplify reporting -- need to work on fixing this eventually
SET #CreatedDate = DATEADD(MINUTE,60-DATEPART(MINUTE,#CreatedDate),#CreatedDate)
-- PRINT 'Rounded ' + CAST(CAST(#CreatedDate AS DATE) AS VARCHAR(10)) + ' ' + CAST(CAST(#CreatedDate AS TIME) AS VARCHAR(8))
--check if created outside business hours and adjust CreatedDate to start the clock first thing at the next business hours start of day (days are checked next)
IF DATEPART(HOUR,#CreatedDate) < #BusHrsStart
--created before normal hours, adjust #CreatedDate later to #BusHrsStart same day
BEGIN
SET #CreatedDate = DATEADD(HOUR,#BusHrsStart,CAST(CAST(#CreatedDate AS DATE) AS DATETIME))
END
IF DATEPART(HOUR,#CreatedDate) >= #BusHrsClose
--created after normal hours, adjust #CreatedDate to #BusHrsStart next day
BEGIN
SET #CreatedDate = DATEADD(HOUR,#BusHrsStart,CAST(CAST(#CreatedDate+1 AS DATE) AS DATETIME))
--adjust CreatedDate to start the clock the next day with >0 business hours (i.e. extend if it falls on a weekend or holiday)
SET #CreatedDate = CAST(#CreatedDate AS DATE)
StartNextWorkingDay:
IF (SELECT TOP(1) [Business_Hours] FROM [JIRA].[Ref_JIRA_Business_Hours] b WHERE b.[Date] = #CreatedDate ORDER BY [Date]) = 0
BEGIN
SET #CreatedDate = DATEADD(DAY,1,#CreatedDate)
GOTO StartNextWorkingDay
END
--DATEADD(DAY, DATEDIFF(DAY,0,#CreatedDate+7)/7*7,0); -- midnight, Monday next week
SET #CreatedDate = DATEADD(HOUR,#BusHrsStart,#CreatedDate); -- BusHrsStart
END
-- PRINT 'Started ' + CAST(CAST(#CreatedDate AS DATE) AS VARCHAR(10)) + ' ' + CAST(CAST(#CreatedDate AS TIME) AS VARCHAR(8))
--third, check the business hours for each date from CreatedDate onwards to determine the relevant DueDate
SET #DueDate = #CreatedDate
-- PRINT 'SLA Hrs ' + CAST(#SLA_Hours_Remaining AS VARCHAR(2))
SET #Hours_Today = #BusHrsStart + (SELECT TOP(1) [Business_Hours] FROM [JIRA].[Ref_JIRA_Business_Hours] b WHERE b.[Date] = CAST(#DueDate AS DATE) ORDER BY [Date]) - DATEPART(HOUR, #CreatedDate)
-- PRINT 'Hrs Today ' + CAST(#Hours_Today AS VARCHAR(2))
DueNextWorkingDay:
IF #SLA_Hours_Remaining > #Hours_Today
BEGIN
-- PRINT 'Due another day'
SET #SLA_Hours_Remaining = #SLA_Hours_Remaining - #Hours_Today --adjust remaining time after today's hours
SET #Hours_Today = (SELECT TOP(1) [Business_Hours] FROM [JIRA].[Ref_JIRA_Business_Hours] b WHERE b.[Date] = CAST(#DueDate AS DATE) ORDER BY [Date])
-- PRINT 'SLA Hrs ' + CAST(#SLA_Hours_Remaining AS VARCHAR(2))
-- PRINT 'Hrs Today ' + CAST(#Hours_Today AS VARCHAR(2))
SET #DueDate = DATEADD(DAY,1,DATEADD(HOUR,#BusHrsStart,CAST(CAST(#DueDate AS DATE) AS DATETIME))) --adjust DueDate to first thing next day
END
IF #SLA_Hours_Remaining <= #Hours_Today
BEGIN
-- PRINT 'Due today'
SET #DueDate = DATEADD(HOUR,#SLA_Hours_Remaining,#DueDate)
END
ELSE
BEGIN
GOTO DueNextWorkingDay
END
-- PRINT 'DueDate ' + CAST(CAST(#DueDate AS DATE) AS VARCHAR(10)) + ' ' + CAST(CAST(#DueDate AS TIME) AS VARCHAR(8))
RETURN #DueDate
END
GO
Table for SLAs:
CREATE TABLE [JIRA].[Ref_JIRA_SLAs](
[SLA_SK] [SMALLINT] IDENTITY(1,1) NOT NULL,
[Project] [VARCHAR](20) NULL,
[Issue_Type] [VARCHAR](50) NULL,
[Epic_Name] [VARCHAR](50) NULL,
[SLA_Business_Hours] [SMALLINT] NULL,
[Comments] [VARCHAR](8000) NULL
) ON [PRIMARY] WITH (DATA_COMPRESSION = PAGE)
GO
I have a table that has the following column (with some sample entries provided):
COLUMN NAME: pt_age_old
20 Years 8 Months 3 Weeks
1 Year 3 Months 2 Weeks
58 Years 7 Months
1 Year
7 Years 11 Months 2 Weeks
26 Years 6 Months
56 Years 6 Months
48 Years 6 Months 4 Weeks
29 Years 11 Months
4 Years 3 Months
61 Years 8 Months 4 Weeks
I have tried to cast it to datetime, of course this did not work. Same with convert.
Keep getting the following message:
Msg 241, Level 16, State 1, Line 2
Conversion failed when converting date and/or time from character string.
Main 2 questions are:
Is this type of conversion even possible with this existing string format?
If so, can you steer me in the right direction so I can make this happen?
Thanks!
This could be done using custom code such as below - I've assumed the values you're using are people's ages, and you're trying to work out their date of birth given their age today.
You can see the below code in action here: http://sqlfiddle.com/#!3/c757c/2
create function dbo.AgeToDOB(#age nvarchar(32))
returns datetime
as
begin
declare #pointer int = 0
, #pointerPrev int = 1
, #y nvarchar(6)
, #m nvarchar(6)
, #w nvarchar(6)
, #d nvarchar(6)
, #result datetime = getutcdate() --set this to the date we're working to/from
--convert various ways of expressing units to a standard
set #age = REPLACE(#age,'Years','Y')
set #age = REPLACE(#age,'Year','Y')
set #age = REPLACE(#age,'Months','M')
set #age = REPLACE(#age,'Month','M')
set #age = REPLACE(#age,'Weeks','W')
set #age = REPLACE(#age,'Week','W')
set #age = REPLACE(#age,'Days','D')
set #age = REPLACE(#age,'Day','D')
set #pointer = isnull(nullif(CHARINDEX('Y',#age),0),#pointer)
set #y = case when #pointer > #pointerprev then SUBSTRING(#age,#pointerprev,#pointer - #pointerprev) else null end
set #pointerPrev = #pointer + 1
set #pointer = isnull(nullif(CHARINDEX('M',#age),0),#pointer)
set #m = case when #pointer > #pointerprev then SUBSTRING(#age,#pointerprev,#pointer - #pointerprev) else null end
set #pointerPrev = #pointer + 1
set #pointer = isnull(nullif(CHARINDEX('W',#age),0),#pointer)
set #w = case when #pointer > #pointerprev then SUBSTRING(#age,#pointerprev,#pointer - #pointerprev) else null end
set #pointerPrev = #pointer + 1
set #pointer = isnull(nullif(CHARINDEX('D',#age),0),#pointer)
set #d = case when #pointer > #pointerprev then SUBSTRING(#age,#pointerprev,#pointer - #pointerprev) else null end
set #result = dateadd(YEAR, 0 - isnull(cast(#y as int),0), #result)
set #result = dateadd(MONTH, 0 - isnull(cast(#m as int),0), #result)
set #result = dateadd(Week, 0 - isnull(cast(#w as int),0), #result)
set #result = dateadd(Day, 0 - isnull(cast(#d as int),0), #result)
return #result
end
go
select dbo.AgeToDOB( '20 Years 8 Months 3 Weeks')
NB: there's a lot of scope for optimisation here; I've left it simple above to help keep it clear what's going on.
Technically it is possible to convert the relative time label into a datetime, but you will need a reference date though (20 Years 8 Months 3 Weeks as of '2013-10-16'). The reference date is most likely today (using GETDATE() or CURRENT_TIMESTAMP), but there is a chance it is a different date. You will have to parse the label, convert it to a duration, and then apply the duration to the reference time. This will be inherently slow.
There are at least two possible ways of doing this, write a FUNCTION to parse and convert the relative time label or use a .NET extended function to do the conversion. You would need to identify all of the possible labels otherwise the conversion will fail. Keep in mind that the reference date is important since 2 months is not a constant number of days (Jan-Feb = either 58 or 59 days).
Here is a sample of what the function might look like:
-- Test data
DECLARE #test varchar(50)
, #ref_date datetime
SET #test = '20 Years 8 Months 3 Weeks'
SET #ref_date = '2013-10-16' -- or use GETDATE() / CURRENT_TIMESTAMP
-- Logic in function
DECLARE #pos int
, #ii int
, #val int
, #label varchar(50)
, #result datetime
SET #pos = 0
SET #result = #ref_date
WHILE (#pos <= LEN(#test))
BEGIN
-- Parse the value first
SET #ii = NULLIF(CHARINDEX(' ', #test, #pos), 0)
SET #label = RTRIM(LTRIM(SUBSTRING(#test, #pos, #ii - #pos)))
SET #val = CAST(#label AS int)
SET #pos = #ii + 1
-- Parse the label next
SET #ii = NULLIF(CHARINDEX(' ', #test, #pos), 0)
IF (#ii IS NULL) SET #ii = LEN(#test) + 1
SET #label = RTRIM(LTRIM(SUBSTRING(#test, #pos, #ii - #pos)))
SET #pos = #ii + 1
-- Apply the value and offset
IF (#label = 'Days') OR (#label = 'Day')
SET #result = DATEADD(dd, -#val, #result)
ELSE IF (#label = 'Weeks') OR (#label = 'Week')
SET #result = DATEADD(ww, -#val, #result)
ELSE IF (#label = 'Months') OR (#label = 'Month')
SET #result = DATEADD(mm, -#val, #result)
ELSE IF (#label = 'Years') OR (#label = 'Year')
SET #result = DATEADD(yy, -#val, #result)
END
SELECT #result
-- So if this works correctly,
-- 20 Years 8 Months 3 Weeks from 2013-10-16 == 1993-01-26
Make a function to split it up:
create function f_tst
(
#t varchar(200)
) returns date
begin
declare #a date = current_timestamp
;with split1 as
(
select 1 start, charindex(' ', #t + ' ', 4)+1 stop
where #t like '% %'
union all
select stop, charindex(' ', #t + ' ', stop + 4)+1
from split1
where charindex(' ', #t, stop) > 0
), split2 as
(
select cast(left(x.sub, charindex(' ', x.sub)) as int) number,
substring(x.sub, charindex(' ', x.sub) + 1, 1) unit
from split1
cross apply (select substring(#t, start, stop - start) sub) x
)
select #a = case unit when 'W' then dateadd(ww, -number, #a)
when 'Y' then dateadd(yy, -number, #a)
when 'M' then dateadd(mm, -number, #a)
end
from split2
return #a
end
Test function:
select dbo.f_tst(age)
from (values('20 Years 8 Months 3 Weeks'),('1 Month') ) x(age)
Result:
1993-01-27
2013-09-17
No, date time type presents actual date, like YYYY-MM-DD HH:MM, your strings are not DATE fields, they are age, to have date time you need date of birth and them somehow add this age to it
The following is my stored procedure for setting workingday between two dates
Create procedure [dbo].[sp_workingdays](#startdate date,#enddate date,#createddatetime datetime,#adminid int)
as
declare #start date,#end date
declare #day varchar(50)
declare #timeid int
declare #daypare int
declare #workingdaytype varchar(20)
begin
set #start=#startdate
set #end=#enddate
while (#start<=#end)
begin
if #start not in (select Date from Generalholyday_details)
begin
select #day= DATENAME(dw,#start)
select #workingdaytype =case (DATEPART(DW,#start)+##DATEFIRST)%7 when 1 then 'Leave Day' when 2 then 'Full Day' when 3 then 'Full Day' when 4 then 'Full Day'when 5 then 'Full Day' when 6 then 'Full Day' when 0 then 'Half Day' end
select #timeid=Time_id from Workingdaytimesetting_details where Workingday_type=#workingdaytype
insert into Workingday_details(Working_date,working_day,Time_id) values(#start,#day,#timeid)
update Workingday_details set createddatetime=#createddatetime where createddatetime is null
update Workingday_details set adminid=#adminid where adminid is null
end
set #start=DATEADD(day,1,#start)
end
end
GO
In datepart line 1 is for sunday. but actually when i run the stored procedure, i got 1 for Saturday. how can i set 1 for sunday.In my previous system i got 1 for sunday in same procedure.
Have a look at SET DATEFIRST (Transact-SQL)
Sets the first day of the week to a number from 1 through 7.
To see the current setting of SET DATEFIRST, use the ##DATEFIRST
function.
The setting of SET DATEFIRST is set at execute or run time and not at
parse time.
Specifying SET DATEFIRST has no effect on DATEDIFF. DATEDIFF always
uses Sunday as the first day of the week to ensure the function is
deterministic.
Try this one -
SET DATEFIRST 7
DATEFIRST - MSDN
Also try this query after small refactor:
CREATE PROCEDURE [dbo].[sp_workingdays]
(
#startdate DATE
, #enddate DATE
, #createddatetime DATETIME
, #adminid INT
)
AS BEGIN
DECLARE
#start DATE
, #end DATE
, #day VARCHAR(50)
, #timeid INT
, #workingdaytype VARCHAR(20)
SELECT
#start = #startdate
, #end = #enddate
WHILE (#start <= #end) BEGIN
IF NOT EXISTS(
SELECT 1
FROM Generalholyday_details
WHERE #start = [Date]
) BEGIN
SELECT
#day = DATENAME(dw, #start)
, #workingdaytype =
CASE WHEN dt = 1 THEN 'Leave Day'
WHEN dt IN (2,3,4,5,6) THEN 'Full Day'
ELSE 'Half Day'
END
FROM (
SELECT dt = (DATEPART(DW, #start) + ##DATEFIRST) % 7
) t
SELECT #timeid = Time_id
FROM Workingdaytimesetting_details
WHERE Workingday_type = #workingdaytype
INSERT INTO Workingday_details (Working_date, working_day, Time_id)
VALUES (#start, #day, #timeid)
UPDATE Workingday_details
SET createddatetime = #createddatetime
WHERE createddatetime IS NULL
UPDATE Workingday_details
SET adminid = #adminid
WHERE adminid IS NULL
END
SET #start = DATEADD(DAY, 1, #start)
END
END
GO
I am using this query to get time taken.
SELECT DATEDIFF(dd, ActualStartDate, ActualCompletionDate) AS TimeTaken
FROM TableName
Now I want to exclude weekends and only include Mon-Fri as days counted.
Example query below, here are some details on how I solved it.
Using DATEDIFF(WK, ...) will give us the number of weeks between the 2 dates. SQL Server evaluates this as a difference between week numbers rather than based on the number of days. This is perfect, since we can use this to determine how many weekends passed between the dates.
So we can multiple that value by 2 to get the number of weekend days that occurred and subtract that from the DATEDIFF(dd, ...) to get the number of weekdays.
This doesn't behave 100% correctly when the start or end date falls on Sunday, though. So I added in some case logic at the end of the calculation to handle those instances.
You may also want to consider whether or not the DATEDIFF should be fully inclusive. e.g. Is the difference between 9/10 and 9/11 1 day or 2 days? If the latter, you'll want to add 1 to the final product.
declare #d1 datetime, #d2 datetime
select #d1 = '9/9/2011', #d2 = '9/18/2011'
select datediff(dd, #d1, #d2) - (datediff(wk, #d1, #d2) * 2) -
case when datepart(dw, #d1) = 1 then 1 else 0 end +
case when datepart(dw, #d2) = 1 then 1 else 0 end
I found when i used this there was a problem when d1 fell on saturday. Below is what i used to correct this.
declare #d1 datetime, #d2 datetime
select #d1 = '11/19/2011' , #d2 = '11/28/2011'
select datediff(dd, #d1, #d2) +case when datepart(dw, #d1) = 7 then 1 else 0 end - (datediff(wk, #d1, #d2) * 2) -
case when datepart(dw, #d1) = 1 then 1 else 0 end +
case when datepart(dw, #d2) = 1 then 1 else 0 end
BEGIN
DECLARE #totaldays INT;
DECLARE #weekenddays INT;
SET #totaldays = DATEDIFF(DAY, #startDate, #endDate)
SET #weekenddays = ((DATEDIFF(WEEK, #startDate, #endDate) * 2) + -- get the number of weekend days in between
CASE WHEN DATEPART(WEEKDAY, #startDate) = 1 THEN 1 ELSE 0 END + -- if selection was Sunday, won't add to weekends
CASE WHEN DATEPART(WEEKDAY, #endDate) = 6 THEN 1 ELSE 0 END) -- if selection was Saturday, won't add to weekends
Return (#totaldays - #weekenddays)
END
This is on SQL Server 2014
declare #d1 datetime, #d2 datetime
select #d1 = '4/19/2017', #d2 = '5/7/2017'
DECLARE #Counter int = datediff(DAY,#d1 ,#d2 )
DECLARE #C int = 0
DECLARE #SUM int = 0
WHILE #Counter > 0
begin
SET #SUM = #SUM + IIF(DATENAME(dw,
DATEADD(day,#c,#d1))IN('Sunday','Monday','Tuesday','Wednesday','Thursday')
,1,0)
SET #Counter = #Counter - 1
set #c = #c +1
end
select #Sum
If you hate CASE statements as much as I do, and want to be able to use the solution inline in your queries, just get the difference of days and subtract the count of weekend days and you'll have the desired result:
declare #d1 datetime, #d2 datetime, #days int
select #d1 = '2018/10/01', #d2 = '2018/11/01'
SET #days = DateDiff(dd, #d1, #d2) - DateDiff(ww, #d1, #d2)*2
print #days
(The only caveat--or at least point to keep in mind--is that this calculation is not inclusive of the last date, so you might need to add one day to the end date to achieve an inclusive result)
I just want to share the code I created that might help you.
DECLARE #MyCounter int = 0, #TempDate datetime, #EndDate datetime;
SET #TempDate = DATEADD(d,1,'2017-5-27')
SET #EndDate = '2017-6-3'
WHILE #TempDate <= #EndDate
BEGIN
IF DATENAME(DW,#TempDate) = 'Sunday' OR DATENAME(DW,#TempDate) = 'Saturday'
SET #MyCounter = #MyCounter
ELSE IF #TempDate not in ('2017-1-1', '2017-1-16', '2017-2-20', '2017-5-29', '2017-7-4', '2017-9-4', '2017-10-9', '2017-11-11', '2017-12-25')
SET #MyCounter = #MyCounter + 1
SET #TempDate = DATEADD(d,1,#TempDate)
CONTINUE
END
PRINT #MyCounter
PRINT #TempDate
If you do have a holiday table, you can also use that so that you don't have to list all the holidays in the ELSE IF section of the code. You can also create a function for this code and use the function whenever you need it in your query.
I hope this might help too.
Using https://stackoverflow.com/a/1804095 and JeffFisher30's answer above (https://stackoverflow.com/a/14572370/6147425) and my own need to have fractional days, I wrote this:
DateDiff(second,Start_Time,End_Time)/86400.0
-2*DateDiff(week, Start_Time, End_Time)
-Case When (DatePart(weekday, Start_Time)+##DateFirst)%7 = 1 Then 1 Else 0 End
+Case When (DatePart(weekday, End_Time)+##DateFirst)%7 = 1 Then 1 Else 0 End
Use this function to calculate the number of business days excluding Saturday and Sunday. Also it will exclude start date and it will include end date.
-- Select [dbo].[GetBussinessDays] ('02/18/2021', '03/06/2021') -- 11 days
CREATE or ALTER FUNCTION [dbo].[GetBussinessDays] (
#StartDate DATETIME,
#EndDate DATETIME
)
returns INT AS
BEGIN
DECLARE #tempStartDate DATETIME= #StartDate;
DECLARE #tempEndDate DATETIME = #EndDate;
IF(#tempStartDate IS NULL
OR
#tempEndDate IS NULL)
BEGIN
RETURN NULL;
END
--To avoid negative values reverse the date if StartDate is grater than EndDate
IF(#StartDate > #EndDate)
BEGIN
SET #StartDate = #tempEndDate;
SET #EndDate = #tempStartDate;
END
DECLARE #Counter INT = Datediff(day,#StartDate ,#EndDate);
DECLARE #TempCounter INT = 0;
DECLARE #TotalBusinessDays INT = 0;
WHILE #Counter >= 0
BEGIN
IF(#TempCounter > 0 OR #Counter = 1) -- To ignore first day's calculation
Begin
SET #TotalBusinessDays = #TotalBusinessDays + Iif(Datename(dw, Dateadd(day,#TempCounter,#StartDate)) IN('Monday',
'Tuesday',
'Wednesday',
'Thursday',
'Friday'),1,0)
END
SET #Counter = #Counter - 1
SET #TempCounter = #TempCounter +1
END
RETURN #TotalBusinessDays;
END
Using #Derek Kromm answer (Current Marked Answer)
I have modified so it IS tolerant of any localisations that may be on the target server.
DECLARE #d1 DATETIME, #d2 DATETIME
SELECT #d1 = '10/01/2022', #d2 = '10/28/2022'
SELECT (datediff(dd, #d1, #EndQuery)+1) - (datediff(wk, #d1, dateadd(dd,1,#d2)) * 2)
- CASE WHEN DateName(WEEKDAY, #d1) = 'Sunday' THEN 1 ELSE 0 END -- This includes for start date edge case
+ CASE WHEN DateName(WEEKDAY, #d2) = 'Saturday' THEN 1 ELSE 0 END -- This includes for end date edge case.
This is with the end date being innclusive.
/*
EXAMPLE:
/MONDAY/
SET DATEFIRST 1
SELECT dbo.FUNC_GETDATEDIFFERENCE_WO_WEEKEND('2019-02-01','2019-02-12')
*/
CREATE FUNCTION FUNC_GETDATEDIFFERENCE_WO_WEEKEND
(
#pdtmaLastLoanPayDate DATETIME,
#pdtmaDisbursedDate DATETIME
)
RETURNS BIGINT
BEGIN
DECLARE
#mintDaysDifference BIGINT
SET #mintDaysDifference = 0
WHILE CONVERT(NCHAR(10),#pdtmaLastLoanPayDate,121) <= CONVERT(NCHAR(10),#pdtmaDisbursedDate,121)
BEGIN
IF DATEPART(WEEKDAY,#pdtmaLastLoanPayDate) NOT IN (6,7)
BEGIN
SET #mintDaysDifference = #mintDaysDifference + 1
END
SET #pdtmaLastLoanPayDate = DATEADD(DAY,1,#pdtmaLastLoanPayDate)
END
RETURN ISNULL(#mintDaysDifference,0)
END
I am sure somebody has worked out to simulate Excel networkdays function in other programming language.
I'd appreciate if you could share.
Thanks
The idea is to calculate the weekdays between the start of each date's week then applying various offsets.
Find the number of days between the Saturday before each date
Divide by 7 and multiply by 5 to get the number of weekdays
Offset the total for whether the start date is after the end date
Offset again for whether the start is after the end and the start is a Saturday
Again for whether the start is after and the end is Sunday
Again for whether the start is not after and the start is a Sunday
Again for whether the start is not after and the end is a Saturday
Add some random dates into a table.
declare #t table ([start] datetime, [end] datetime)
insert into #t values ('2088-01-14 11:56:23','2011-11-10 03:34:09')
insert into #t values ('2024-09-24 10:14:29','2087-09-16 15:52:06')
Then calcuate NETWORKDAYS for those dates.
select [start],[end]
,((datediff(day,0,[end])-datepart(dw,[end]))-(datediff(day,0,[start])-datepart(dw,[start])))/7*5 --[weekdays]
+ datepart(dw,[end]) - datepart(dw,[start]) --[weekday diff]
+ case when datediff(day,0,[start]) > datediff(day,0,[end]) then -1 else 1 end --[start after]
+ case when datediff(day,0,[start]) > datediff(day,0,[end]) and datepart(dw,[start]) = 7 then 1 else 0 end --[start after and start saturday]
+ case when datediff(day,0,[start]) > datediff(day,0,[end]) and datepart(dw,[end]) = 1 then 1 else 0 end --[start after and end sunday]
+ case when datediff(day,0,[start]) <= datediff(day,0,[end]) and datepart(dw,[start]) = 1 then -1 else 0 end --[start not after and start sunday]
+ case when datediff(day,0,[start]) <= datediff(day,0,[end]) and datepart(dw,[end]) = 7 then -1 else 0 end --[start not after and end saturday]
as [networkdays]
from #t
A SQL solution as per SO question "Equivalent of Excel’s NETWORKDAYS function with Jet ADO"
Hope this helps someone out there but this works for me. Requires you to create a dbo.FederalHolidays table (which can be easily populated with online date sources).
Cleanest way I could come up with that is easily scalable.
--Simulate Excel Formula =NETWORKDAYS() excludes weekend days and federal holidays. Requires a Federal Holiday Table, easy to create.
DECLARE #d1 date, #d2 date
SET #d1 = '4/12/2019'
SET #d2 = '4/23/2019'
SELECT
DATEDIFF(dd,#d1,#d2) +1 --First calculate regular date difference +1 to count the start date; does not exclude weekends/holidays.
- (SELECT COUNT(*) --Calculate number of holidays between the date range and subtract it from DATEDIFF().
FROM [dbo].[FederalHolidays]
WHERE DATE BETWEEN #d1 AND #d2)
- (SELECT (DATEDIFF(wk, #d1, #d2) * 2) --Calculate number of weekend days between the date range and subtract it from DATEDIFF().
+(CASE WHEN DATENAME(dw, #d1) = 'Sunday' THEN 1 ELSE 0 END)
+(CASE WHEN DATENAME(dw, #d2) = 'Saturday' THEN 1 ELSE 0 END)) as NetWorkDays
For what it's worth, I created the following function for mysql that assumes Mon-Fri are business days:
DROP FUNCTION IF EXISTS BusinessDays;
DELIMITER //
CREATE FUNCTION BusinessDays (startDate DATE, endDate DATE)
RETURNS INT
DETERMINISTIC
BEGIN
DECLARE startWeekDay INT;
DECLARE allDays INT;
DECLARE fullWeekCount INT;
DECLARE remainderDays INT;
DECLARE maxPossibleRemainderWeekendDays INT;
DECLARE soloSundays INT;
DECLARE totalBusinessDays INT;
SET startWeekDay = WEEKDAY(startDate);
SET allDays = ABS(DATEDIFF(endDate, startDate)) + 1;
SET fullWeekCount = FLOOR(allDays/7);
SET remainderDays = allDays - (fullWeekCount * 7);
SET maxPossibleRemainderWeekendDays = ROUND(2*(startWeekDay+remainderDays-6)/(ABS(2*(startWeekDay+remainderDays-6))+1))+1;
SET soloSundays = ROUND(2*(startWeekDay-6)/(ABS(2*(startWeekDay-6))+1))+1;
SET totalBusinessDays = allDays - (fullWeekCount * 2) - maxPossibleRemainderWeekendDays + soloSundays;
RETURN totalBusinessDays;
END //
DELIMITER ;
Perhaps this will also help, I created a formula (in Excel) that will simulate the NETWORKDAYS function:
= 1 + ( ( B1 - A1) * 5 - ( WEEKDAY(A1) - WEEKDAY(B1) ) * 2 ) / 7 + IF(A1<=B1,IF(WEEKDAY(B1)=7,-1,0) + IF(WEEKDAY(A1)=1,-1,0), IF(WEEKDAY(B1)<>1,-1,0) + IF(WEEKDAY(A1)<>7,-1,0) )
NOTE: WEEKDAY() has Sunday as 0 to Saturday as 6
I have been looking for this capability for quite some time, so went ahead and just created it on my own.
Usage: This is a function you can create in SQL. You can easily modify this to work outside a function if needed, but I prefer functions to take care of these types of calculations.
I added quite a few comments in case anyone was wondering how it worked. What this does is take two inputs:
#startDate - the beginning date you want to add workday to.
#addDays - the whole number of days you want to add to the #startDate.
Calculation process:
It loops repeatedly until the # of working days has been reached. For example, if you enter 365 days, it will cycle around 500 times before it's able to predict the # of working days to add. I've added #weekendCount in case anyone needs to know the # of weekend days excluded before reaching the final end date.
Once completed, the integer #recCounter essentially is the # of days that must be added to the #startDate before the number of working days is reached. I am sure someone can write this better than I, or perhaps someone can make use of this. Hope this helps! :)
CREATE FUNCTION [dbo].[addNetworkDays](#startDate AS DATETIME, #addDays AS Int)
RETURNS DATETIME
AS
BEGIN
DECLARE #recCounter Int
SET #recCounter = 0
DECLARE #weekendCount Int
SET #weekendCount = 0
DECLARE #workdayCount Int
SET #workdayCount = 0
DECLARE #newDate DateTime
WHILE #addDays > #workdayCount
BEGIN
-- Add another day to the start date
SET #recCounter = #recCounter + 1
-- Cumuluate the weekend vs. workday counter, based on the day of the week. This loop will repeat until #workdayCount has reached the #addDays.
-- Note that #weekendCount is not used in any capacity, can be used if you need to know how many weekend days there are.
IF DATEPART(dw, DATEADD(d, #recCounter, #startDate)) IN (1, 7) SET #weekendCount = #weekendCount + 1
IF DATEPART(dw, DATEADD(d, #recCounter, #startDate)) IN (2, 3, 4, 5, 6) SET #workdayCount = #workdayCount + 1
END
-- At this point, the script has completed the cycle, stopping when the detected # of workdays has reached the count of days the user specified.
-- Calculate the new date, based on the # of cycles *days* detected above.
SET #newDate = DATEADD(d, #recCounter, #startDate)
-- If the new/adjusted date falls on a Saturday or Sunday, add additional days to compensate.
IF DATEPART(dw, #newDate) = 1 SET #newDate = DATEADD(d, 1, #newDate)
IF DATEPART(dw, #newDate) = 7 SET #newDate = DATEADD(d, 1, #newDate)
RETURN CAST(#newDate AS DATETIME)
NETWORKDAYS for Australia
WITH PH_NET_WORKDAY AS
(
----BUILD UNDERLYING WORKDAY DATA TABLE
SELECT
DT,
STATE,
CASE
WHEN WORKDAY-PUBLIC_HOLIDAY <0
THEN 0
ELSE WORKDAY-PUBLIC_HOLIDAY
END AS WORKDAY
FROM
(
SELECT
DT,
STATE,
WORKDAY,
----PUBLIC HOLIDAY INFORMATION HERE
CASE
WHEN STATE = 'NSW'
THEN
CASE
WHEN DT IN (
'01-Oct-2018',
'25-Dec-2018',
'26-Dec-2018',
'01-Jan-2019',
'28-Jan-2019',
'19-Apr-2019',
'20-Apr-2019',
'21-Apr-2019',
'22-Apr-2019',
'25-Apr-2019',
'10-Jun-2019',
'07-Oct-2019',
'25-Dec-2019',
'26-Dec-2019'
)
THEN 1
ELSE 0
END
WHEN STATE = 'SA'
THEN
CASE
WHEN DT IN (
'01-Oct-2018',
'24-Dec-2018',
'25-Dec-2018',
'26-Dec-2018',
'31-Dec-2018',
'01-Jan-2019',
'28-Jan-2019',
'11-Mar-2019',
'19-Apr-2019',
'20-Apr-2019',
'22-Apr-2019',
'25-Apr-2019',
'10-Jun-2019',
'07-Oct-2019',
'24-Dec-2019',
'25-Dec-2019',
'26-Dec-2019'
)
THEN 1
ELSE 0
END
WHEN STATE = 'QLD'
THEN
CASE
WHEN DT IN (
'01-Oct-2018',
'25-Dec-2018',
'26-Dec-2018',
'01-Jan-2019',
'28-Jan-2019',
'19-Apr-2019',
'20-Apr-2019',
'21-Apr-2019',
'22-Apr-2019',
'25-Apr-2019',
'06-May-2019',
'07-Oct-2019',
'25-Dec-2019',
'26-Dec-2019'
)
THEN 1
ELSE 0
END
WHEN STATE = 'VIC'
THEN
CASE
WHEN DT IN (
'28-Sep-2018',
'06-Nov-2018',
'25-Dec-2018',
'26-Dec-2018',
'01-Jan-2019',
'28-Jan-2019',
'11-Mar-2019',
'19-Apr-2019',
'20-Apr-2019',
'21-Apr-2019',
'22-Apr-2019',
'25-Apr-2019',
'10-Jun-2019',
'05-Nov-2019',
'25-Dec-2019',
'26-Dec-2019'
)
THEN 1
ELSE 0
END
WHEN STATE = 'TAS'
THEN
CASE
WHEN DT IN (
'25-Dec-2018',
'26-Dec-2018',
'01-Jan-2019',
'28-Jan-2019',
'11-Mar-2019',
'19-Apr-2019',
'22-Apr-2019',
'23-Apr-2019',
'25-Apr-2019',
'10-Jun-2019',
'25-Dec-2019',
'26-Dec-2019'
)
THEN 1
ELSE 0
END
ELSE 0
END AS PUBLIC_HOLIDAY
FROM
(
SELECT
DT.*,
ST.*
FROM
(
SELECT
TRUNC (TO_DATE('01-JAN-2021','DD-MON-YYYY') - ROWNUM) AS DT,
TRIM(TO_CHAR( TRUNC (TO_DATE('01-JAN-2021','DD-MON-YYYY') - ROWNUM) , 'DAY')) AS WEEK_DAY,
CASE
WHEN TRIM(TO_CHAR( TRUNC (TO_DATE('01-JAN-2021','DD-MON-YYYY') - ROWNUM) , 'DAY')) = 'SATURDAY'
THEN 0
WHEN TRIM(TO_CHAR( TRUNC (TO_DATE('01-JAN-2021','DD-MON-YYYY') - ROWNUM) , 'DAY')) = 'SUNDAY'
THEN 0
----BUILD STATE PUBLIC HOLIDAY DATE SET HERE, WE CAN EXCLUDE PUBLIC HOLIDAYS
ELSE 1
END AS WORKDAY
FROM DUAL CONNECT BY ROWNUM < (365.25*8+1)
) DT
,
(
SELECT 'NSW' AS STATE FROM DUAL
UNION
SELECT 'QLD' AS STATE FROM DUAL
UNION
SELECT 'SA' AS STATE FROM DUAL
UNION
SELECT 'ACT' AS STATE FROM DUAL
UNION
SELECT 'VIC' AS STATE FROM DUAL
UNION
SELECT 'ACT' AS STATE FROM DUAL
) ST
)
)
),
----A SAMPLE DATA SET FOR SAME DATES BETWEEN DIFFERENT STATE TO TEST PUBLIC HOLIDAY DIFFERENCES
SAMPLE_DATA AS
(
SELECT
'01-FEB-2019' AS D1,
'11-FEB-2019' AS D2,
'NSW' AS STATE
FROM DUAL
UNION
SELECT
'01-FEB-2019' AS D1,
'11-FEB-2019' AS D2,
'SA' AS STATE
FROM DUAL
UNION
SELECT
'19-APR-2019' AS D1,
'26-APR-2019' AS D2,
'NSW' AS STATE
FROM DUAL
)
----SELECT WORKDAYS FROM PH TABLE AND INSERT INTO SAPLE TABLE
SELECT
SAMPLE_DATA.*,
(
SELECT SUM(WORKDAY)
FROM PH_NET_WORKDAY
WHERE
STATE = SAMPLE_DATA.STATE
AND DT>=SAMPLE_DATA.D1
AND DT<=SAMPLE_DATA.D2
)
AS WORKDAYS
FROM SAMPLE_DATA