SQL self join pairwise - sql

Question

Suppose I have a table consisting of entries like
ID Arrival Date Arrival City Departure Date Departure City
1 Jun 27 2015 Berlin Jun 20 2015 Paris
1 Jul 1 2015 Rome Jun 29 2015 Berlin
1 Jul 30 2015 Vienna Jul 15 2015 Rome
2 Jun 28 2015 Prague Jun 23 2015 Vienna
2 Jul 1 2015 Rome Jun 29 2015 Prague
2 Jul 30 2015 Vienna Jul 15 2015 Moscow
...
and for each ID I want to join this data on itself such that observations with subsequent Departure Date and Arrival Date are grouped pairwise - i.e. a departure is paired with the previous arrival for each ID.
In the example above (where the observations are sorted for convenience) the 2nd row would be appended to the 1st, the 3rd to the 2nd, the 5th to the 4th and the 6th to the 5th (thus producing 4 rows with fields ID Arrival Date Arrival City Departure Date Departure City Arrival Date2 Arrival City2 Departure Date2 Departure City2).
There could potentially be more than three departures for each ID so a general approach is required. Also please note that there can be holes in the data where Arrival City and Departure City does not match - e.g. the Arrival City of the 5th row is not the Departure City of the 6th row but they should still be merged. In fact a major goal is to get a better view of how many holes there are in the data.

Answer 1

A solution is to use a CTE and consider that the difference between two consecutive rows (identified by the rowno) is 1 all the time (and also consider the dates):
;WITH CTE AS (
SELECT
rownum = ROW_NUMBER() OVER (ORDER BY t.ID, t.arrivalDate),
t.ID,
t.arrivalDate,
t.arrivalCity,
t.departureDate,
t.departureCity
FROM #test t
)
SELECT *
FROM CTE c1
JOIN CTE c2
ON c1.ID = c2.ID
AND c2.departureDate > c1.arrivalDate
AND c2.rownum - c1.rownum = 1
GO
-- structure of the #test table
CREATE TABLE #test (
ID int,
arrivalDate date,
arrivalCity varchar(30),
departureDate date,
departureCity varchar(30)
)
SQL fiddle here: SQLFiddle

Answer 2

Try this:
SELECT a.id
,a.arrival_date
,a.arrival_city
,a.departure_date
,a.departure_city
,b.arrival_date arrival_date_2
,b.arrival_city arrival_city_2
,b.departure_date departure_date_2
,b.departure_city departure_city_2
FROM triptable a
JOIN triptable b ON a.id = b.id
AND a.departure_date = (SELECT min(departure_date) FROM so34815894 x WHERE x.departure_date > b.arrival_date AND x.id = b.id)
Edited based on your comment to:
find the record with the earliest departure date after the previous record's
arrival date, and
ignore the fact that the sample data's 6th record has a different
departure city than the 5th record's arrival city.

Answer 3

Not entirely sure what result set your looking for.. but I thought I'd give this a shot and see if any of these help you out.
drop table #t1
create table #t1 (id int, ArrivalDate datetime, ArrivalCity varchar(50), Departuredate datetime, DepartureCity varchar(50))
insert into #t1
values (1, 'Jun 27 2015', 'Berlin', 'Jun 20 2015','Paris'),
(1, 'Jul 1 2015', 'Rome','Jun 29 2015','Berlin'),
(1, 'Jul 30 2015', 'Vienna','Jul 15 2015','Rome'),
(2, 'Jun 28 2015','Prague','Jun 23 2015','Vienna'),
(2, 'Jul 1 2015','Rome','Jun 29 2015','Prague'),
(2, 'Jul 30 2015','Vienna','Jul 15 2015','Moscow')
select *, case when lead(departurecity) over (partition by id order by Arrivaldate) = ArrivalCity or lead(departurecity) over (partition by id order by Arrivaldate) is null then 1 else 0 end as PairID into #t2 from #t1
update #t2
set PairID = id
where pairid != id
and pairid != 0
This is the code to start up..
select * from #t2
will result in:
id ArrivalDate ArrivalCity Departuredate DepartureCity PairID
1 2015-06-27 Berlin 2015-06-20 Paris 1
1 2015-07-01 Rome 2015-06-29 Berlin 1
1 2015-07-30 Vienna 2015-07-15 Rome 1
2 2015-06-28 Prague 2015-06-23 Vienna 2
2 2015-07-01 Rome 2015-06-29 Prague 0
2 2015-07-30 Vienna 2015-07-15 Moscow 2
Any location where the pair id = 0 ... you have a gap/baddata however you want to put it..
You could also:
select *, lead(departurecity) over (partition by ID order by ArrivalDate) as PreviousDepartureCity, lead(Departuredate) over (partition by ID order by ArrivalDate) as PreviousDepartureDate from #t2
This will add previous departure city and date.. and you can do what you want with the nulls.. they will signify the first flight.. or a gap if the subsequent pair id = 0 ...
The select options become endless.... if null and lag(pairid) = 0 then you have the row with the gap.. if null and pair id = id.. and lag(pairid) = id then you have your first flight..
I mean I can keep going.. and give you more details but I'm not sure this is what your looking for.. Hope it helped anyway..
Good luck!
P.S Didn't see why you needed to join the table to itself .. maybe I missed the whole point..lol..sorry if that's the case..

Answer 4

It sounds to me like you're wanting to pivot the results and put the results in additional columns. I used ROW_NUMBER() for the ordering. I concatenated the columns in a row prior to the pivot, pivoted, then used a function to reverse the concatenation.
SELECT
p.ID,
dbo.SplitString(p.[1], CHAR(13), 1) AS arrivalDate1,
dbo.SplitString(p.[1], CHAR(13), 2) AS arrivalCity1,
dbo.SplitString(p.[1], CHAR(13), 3) AS departureDate1,
dbo.SplitString(p.[1], CHAR(13), 4) AS departureCity1,
*
FROM
(
SELECT *
FROM
(
SELECT
ID,
ROW_NUMBER() OVER (PARTITION BY ID ORDER BY arrivalDate) RowNum,
CAST(arrivalDate AS VARCHAR(MAX)) + CHAR(13)
+ arrivalCity + CHAR(13)
+ CAST(departureDate AS VARCHAR(MAX)) + CHAR(13)
+ departureCity TripDetails
FROM trip t
) t
PIVOT (MIN(t.TripDetails) FOR t.RowNum IN ([1], [2], [3], [4], [5] /* , ... */)) p
) p;
using this SplitString function
CREATE FUNCTION dbo.SplitString (
#stringToSplit VARCHAR(MAX),
#delim VARCHAR(255),
#occurence INT )
RETURNS VARCHAR(MAX) AS
BEGIN
DECLARE #name NVARCHAR(255);
DECLARE #pos INT;
DECLARE #orderNum INT;
SET #orderNum=0;
WHILE CHARINDEX(#delim, #stringToSplit) > 0
BEGIN
SELECT #orderNum=#orderNum+1;
SELECT #pos = CHARINDEX(#delim, #stringToSplit) ;
SELECT #name = SUBSTRING(#stringToSplit, 1, #pos-1);
IF #orderNum = #occurence
BEGIN
RETURN #name;
END
SELECT #stringToSplit = SUBSTRING(#stringToSplit, #pos+1, LEN(#stringToSplit)-#pos)
END
SELECT #orderNum=#orderNum+1;
IF #orderNum = #occurence
BEGIN
RETURN #stringToSplit;
END
RETURN NULL;
END

Answer 5

This should work:
with cte as(select *, row_number() over(partition by id order by date) rn from table)
select * from cte c1
join cte c2 on c1.id = c2.id and c1.rn = c2.rn - 1

Answer 6

try this,
declare #t table(ID int,ArrivalDate datetime, ArrivalCity varchar(50)
,DepartureDate datetime,DepartureCity varchar(50))
insert into #t values
(1, 'Jun 27 2015', 'Berlin', 'Jun 20 2015', 'Paris ')
,(1, 'Jul 1 2015 ', 'Rome ', 'Jun 29 2015', 'Berlin ')
,(1, 'Jul 30 2015', 'Vienna', 'Jul 15 2015', 'Rome ')
,(2, 'Jun 28 2015', 'Prague', 'Jun 23 2015', 'Vienna ')
,(2, 'Jul 1 2015 ', 'Rome ', 'Jun 29 2015', 'Prague ')
,(2 , 'Jul 30 2015', 'Vienna', 'Jul 15 2015', 'Moscow ')
;WITH CTE
AS (
SELECT *
,ROW_NUMBER() OVER (
ORDER BY id
,arrivaldate
) rn
FROM #t
)
SELECT A.arrivaldate
,a.arrivalcity
,a.DepartureDate
,a.DepartureCity
,b.arrivaldate
,b.arrivalcity
,b.DepartureDate
,b.DepartureCity
FROM CTE A
LEFT JOIN CTE b ON a.rn + 1 = b.rn