I have a table in my Postgres database where I forgot to insert a unique index. because of that index that i have now duplicated values. How to remove the duplicated values? I want to add a unique index on the fields translationset_Id and key.
I think you are asking for this:
DELETE FROM tablename
WHERE id IN (SELECT id
FROM (SELECT id,
ROW_NUMBER() OVER (partition BY column1, column2, column3 ORDER BY id) AS rnum
FROM tablename) t
WHERE t.rnum > 1);
It appears that you only want to delete records which are duplicate with regard to the translationset_id column. In this case, we can use Postgres' row number functionality to discern between duplicate rows, and then to delete those duplicates.
WITH cte AS
(
SELECT t.*, ROW_NUMBER() OVER (PARTITION BY translationset_id, key) AS rnum
FROM yourTable t
)
DELETE FROM yourTable
WHERE translationset_id IN (SELECT translationset_id FROM cte WHERE rnum > 1)
I think the most efficient way to do this is below.
DELETE FROM
table_name a
USING table_name b
WHERE
a.id < b.id and
a.same_column = b.same_column;
delete from mytable
where exists (select 1
from mytable t2
where t2.name = mytable.name and
t2.address = mytable.address and
t2.zip = mytable.zip and
t2.ctid > mytable.ctid
);
I need to remove duplicate rows from a fairly large SQL Server table (i.e. 300,000+ rows).
The rows, of course, will not be perfect duplicates because of the existence of the RowID identity field.
MyTable
RowID int not null identity(1,1) primary key,
Col1 varchar(20) not null,
Col2 varchar(2048) not null,
Col3 tinyint not null
How can I do this?
Assuming no nulls, you GROUP BY the unique columns, and SELECT the MIN (or MAX) RowId as the row to keep. Then, just delete everything that didn't have a row id:
DELETE FROM MyTable
LEFT OUTER JOIN (
SELECT MIN(RowId) as RowId, Col1, Col2, Col3
FROM MyTable
GROUP BY Col1, Col2, Col3
) as KeepRows ON
MyTable.RowId = KeepRows.RowId
WHERE
KeepRows.RowId IS NULL
In case you have a GUID instead of an integer, you can replace
MIN(RowId)
with
CONVERT(uniqueidentifier, MIN(CONVERT(char(36), MyGuidColumn)))
Another possible way of doing this is
;
--Ensure that any immediately preceding statement is terminated with a semicolon above
WITH cte
AS (SELECT ROW_NUMBER() OVER (PARTITION BY Col1, Col2, Col3
ORDER BY ( SELECT 0)) RN
FROM #MyTable)
DELETE FROM cte
WHERE RN > 1;
I am using ORDER BY (SELECT 0) above as it is arbitrary which row to preserve in the event of a tie.
To preserve the latest one in RowID order for example you could use ORDER BY RowID DESC
Execution Plans
The execution plan for this is often simpler and more efficient than that in the accepted answer as it does not require the self join.
This is not always the case however. One place where the GROUP BY solution might be preferred is situations where a hash aggregate would be chosen in preference to a stream aggregate.
The ROW_NUMBER solution will always give pretty much the same plan whereas the GROUP BY strategy is more flexible.
Factors which might favour the hash aggregate approach would be
No useful index on the partitioning columns
relatively fewer groups with relatively more duplicates in each group
In extreme versions of this second case (if there are very few groups with many duplicates in each) one could also consider simply inserting the rows to keep into a new table then TRUNCATE-ing the original and copying them back to minimise logging compared to deleting a very high proportion of the rows.
There's a good article on removing duplicates on the Microsoft Support site. It's pretty conservative - they have you do everything in separate steps - but it should work well against large tables.
I've used self-joins to do this in the past, although it could probably be prettied up with a HAVING clause:
DELETE dupes
FROM MyTable dupes, MyTable fullTable
WHERE dupes.dupField = fullTable.dupField
AND dupes.secondDupField = fullTable.secondDupField
AND dupes.uniqueField > fullTable.uniqueField
The following query is useful to delete duplicate rows. The table in this example has ID as an identity column and the columns which have duplicate data are Column1, Column2 and Column3.
DELETE FROM TableName
WHERE ID NOT IN (SELECT MAX(ID)
FROM TableName
GROUP BY Column1,
Column2,
Column3
/*Even if ID is not null-able SQL Server treats MAX(ID) as potentially
nullable. Because of semantics of NOT IN (NULL) including the clause
below can simplify the plan*/
HAVING MAX(ID) IS NOT NULL)
The following script shows usage of GROUP BY, HAVING, ORDER BY in one query, and returns the results with duplicate column and its count.
SELECT YourColumnName,
COUNT(*) TotalCount
FROM YourTableName
GROUP BY YourColumnName
HAVING COUNT(*) > 1
ORDER BY COUNT(*) DESC
delete t1
from table t1, table t2
where t1.columnA = t2.columnA
and t1.rowid>t2.rowid
Postgres:
delete
from table t1
using table t2
where t1.columnA = t2.columnA
and t1.rowid > t2.rowid
DELETE LU
FROM (SELECT *,
Row_number()
OVER (
partition BY col1, col1, col3
ORDER BY rowid DESC) [Row]
FROM mytable) LU
WHERE [row] > 1
This will delete duplicate rows, except the first row
DELETE
FROM
Mytable
WHERE
RowID NOT IN (
SELECT
MIN(RowID)
FROM
Mytable
GROUP BY
Col1,
Col2,
Col3
)
Refer (http://www.codeproject.com/Articles/157977/Remove-Duplicate-Rows-from-a-Table-in-SQL-Server)
I would prefer CTE for deleting duplicate rows from sql server table
strongly recommend to follow this article ::http://codaffection.com/sql-server-article/delete-duplicate-rows-in-sql-server/
by keeping original
WITH CTE AS
(
SELECT *,ROW_NUMBER() OVER (PARTITION BY col1,col2,col3 ORDER BY col1,col2,col3) AS RN
FROM MyTable
)
DELETE FROM CTE WHERE RN<>1
without keeping original
WITH CTE AS
(SELECT *,R=RANK() OVER (ORDER BY col1,col2,col3)
FROM MyTable)
DELETE CTE
WHERE R IN (SELECT R FROM CTE GROUP BY R HAVING COUNT(*)>1)
To Fetch Duplicate Rows:
SELECT
name, email, COUNT(*)
FROM
users
GROUP BY
name, email
HAVING COUNT(*) > 1
To Delete the Duplicate Rows:
DELETE users
WHERE rowid NOT IN
(SELECT MIN(rowid)
FROM users
GROUP BY name, email);
Quick and Dirty to delete exact duplicated rows (for small tables):
select distinct * into t2 from t1;
delete from t1;
insert into t1 select * from t2;
drop table t2;
I prefer the subquery\having count(*) > 1 solution to the inner join because I found it easier to read and it was very easy to turn into a SELECT statement to verify what would be deleted before you run it.
--DELETE FROM table1
--WHERE id IN (
SELECT MIN(id) FROM table1
GROUP BY col1, col2, col3
-- could add a WHERE clause here to further filter
HAVING count(*) > 1
--)
SELECT DISTINCT *
INTO tempdb.dbo.tmpTable
FROM myTable
TRUNCATE TABLE myTable
INSERT INTO myTable SELECT * FROM tempdb.dbo.tmpTable
DROP TABLE tempdb.dbo.tmpTable
I thought I'd share my solution since it works under special circumstances.
I my case the table with duplicate values did not have a foreign key (because the values were duplicated from another db).
begin transaction
-- create temp table with identical structure as source table
Select * Into #temp From tableName Where 1 = 2
-- insert distinct values into temp
insert into #temp
select distinct *
from tableName
-- delete from source
delete from tableName
-- insert into source from temp
insert into tableName
select *
from #temp
rollback transaction
-- if this works, change rollback to commit and execute again to keep you changes!!
PS: when working on things like this I always use a transaction, this not only ensures everything is executed as a whole, but also allows me to test without risking anything. But off course you should take a backup anyway just to be sure...
This query showed very good performance for me:
DELETE tbl
FROM
MyTable tbl
WHERE
EXISTS (
SELECT
*
FROM
MyTable tbl2
WHERE
tbl2.SameValue = tbl.SameValue
AND tbl.IdUniqueValue < tbl2.IdUniqueValue
)
it deleted 1M rows in little more than 30sec from a table of 2M (50% duplicates)
Using CTE. The idea is to join on one or more columns that form a duplicate record and then remove whichever you like:
;with cte as (
select
min(PrimaryKey) as PrimaryKey
UniqueColumn1,
UniqueColumn2
from dbo.DuplicatesTable
group by
UniqueColumn1, UniqueColumn1
having count(*) > 1
)
delete d
from dbo.DuplicatesTable d
inner join cte on
d.PrimaryKey > cte.PrimaryKey and
d.UniqueColumn1 = cte.UniqueColumn1 and
d.UniqueColumn2 = cte.UniqueColumn2;
Yet another easy solution can be found at the link pasted here. This one easy to grasp and seems to be effective for most of the similar problems. It is for SQL Server though but the concept used is more than acceptable.
Here are the relevant portions from the linked page:
Consider this data:
EMPLOYEE_ID ATTENDANCE_DATE
A001 2011-01-01
A001 2011-01-01
A002 2011-01-01
A002 2011-01-01
A002 2011-01-01
A003 2011-01-01
So how can we delete those duplicate data?
First, insert an identity column in that table by using the following code:
ALTER TABLE dbo.ATTENDANCE ADD AUTOID INT IDENTITY(1,1)
Use the following code to resolve it:
DELETE FROM dbo.ATTENDANCE WHERE AUTOID NOT IN (SELECT MIN(AUTOID) _
FROM dbo.ATTENDANCE GROUP BY EMPLOYEE_ID,ATTENDANCE_DATE)
This is the easiest way to delete duplicate record
DELETE FROM tblemp WHERE id IN
(
SELECT MIN(id) FROM tblemp
GROUP BY title HAVING COUNT(id)>1
)
Use this
WITH tblTemp as
(
SELECT ROW_NUMBER() Over(PARTITION BY Name,Department ORDER BY Name)
As RowNumber,* FROM <table_name>
)
DELETE FROM tblTemp where RowNumber >1
Here is another good article on removing duplicates.
It discusses why its hard: "SQL is based on relational algebra, and duplicates cannot occur in relational algebra, because duplicates are not allowed in a set."
The temp table solution, and two mysql examples.
In the future are you going to prevent it at a database level, or from an application perspective. I would suggest the database level because your database should be responsible for maintaining referential integrity, developers just will cause problems ;)
I had a table where I needed to preserve non-duplicate rows.
I'm not sure on the speed or efficiency.
DELETE FROM myTable WHERE RowID IN (
SELECT MIN(RowID) AS IDNo FROM myTable
GROUP BY Col1, Col2, Col3
HAVING COUNT(*) = 2 )
Oh sure. Use a temp table. If you want a single, not-very-performant statement that "works" you can go with:
DELETE FROM MyTable WHERE NOT RowID IN
(SELECT
(SELECT TOP 1 RowID FROM MyTable mt2
WHERE mt2.Col1 = mt.Col1
AND mt2.Col2 = mt.Col2
AND mt2.Col3 = mt.Col3)
FROM MyTable mt)
Basically, for each row in the table, the sub-select finds the top RowID of all rows that are exactly like the row under consideration. So you end up with a list of RowIDs that represent the "original" non-duplicated rows.
The other way is Create a new table with same fields and with Unique Index. Then move all data from old table to new table. Automatically SQL SERVER ignore (there is also an option about what to do if there will be a duplicate value: ignore, interrupt or sth) duplicate values. So we have the same table without duplicate rows. If you don't want Unique Index, after the transfer data you can drop it.
Especially for larger tables you may use DTS (SSIS package to import/export data) in order to transfer all data rapidly to your new uniquely indexed table. For 7 million row it takes just a few minute.
By useing below query we can able to delete duplicate records based on the single column or multiple column. below query is deleting based on two columns. table name is: testing and column names empno,empname
DELETE FROM testing WHERE empno not IN (SELECT empno FROM (SELECT empno, ROW_NUMBER() OVER (PARTITION BY empno ORDER BY empno)
AS [ItemNumber] FROM testing) a WHERE ItemNumber > 1)
or empname not in
(select empname from (select empname,row_number() over(PARTITION BY empno ORDER BY empno)
AS [ItemNumber] FROM testing) a WHERE ItemNumber > 1)
Create new blank table with the same structure
Execute query like this
INSERT INTO tc_category1
SELECT *
FROM tc_category
GROUP BY category_id, application_id
HAVING count(*) > 1
Then execute this query
INSERT INTO tc_category1
SELECT *
FROM tc_category
GROUP BY category_id, application_id
HAVING count(*) = 1
Another way of doing this :--
DELETE A
FROM TABLE A,
TABLE B
WHERE A.COL1 = B.COL1
AND A.COL2 = B.COL2
AND A.UNIQUEFIELD > B.UNIQUEFIELD
I would mention this approach as well as it can be helpful, and works in all SQL servers:
Pretty often there is only one - two duplicates, and Ids and count of duplicates are known. In this case:
SET ROWCOUNT 1 -- or set to number of rows to be deleted
delete from myTable where RowId = DuplicatedID
SET ROWCOUNT 0
From the application level (unfortunately). I agree that the proper way to prevent duplication is at the database level through the use of a unique index, but in SQL Server 2005, an index is allowed to be only 900 bytes, and my varchar(2048) field blows that away.
I dunno how well it would perform, but I think you could write a trigger to enforce this, even if you couldn't do it directly with an index. Something like:
-- given a table stories(story_id int not null primary key, story varchar(max) not null)
CREATE TRIGGER prevent_plagiarism
ON stories
after INSERT, UPDATE
AS
DECLARE #cnt AS INT
SELECT #cnt = Count(*)
FROM stories
INNER JOIN inserted
ON ( stories.story = inserted.story
AND stories.story_id != inserted.story_id )
IF #cnt > 0
BEGIN
RAISERROR('plagiarism detected',16,1)
ROLLBACK TRANSACTION
END
Also, varchar(2048) sounds fishy to me (some things in life are 2048 bytes, but it's pretty uncommon); should it really not be varchar(max)?
DELETE
FROM
table_name T1
WHERE
rowid > (
SELECT
min(rowid)
FROM
table_name T2
WHERE
T1.column_name = T2.column_name
);
CREATE TABLE car(Id int identity(1,1), PersonId int, CarId int)
INSERT INTO car(PersonId,CarId)
VALUES(1,2),(1,3),(1,2),(2,4)
--SELECT * FROM car
;WITH CTE as(
SELECT ROW_NUMBER() over (PARTITION BY personid,carid order by personid,carid) as rn,Id,PersonID,CarId from car)
DELETE FROM car where Id in(SELECT Id FROM CTE WHERE rn>1)
I you want to preview the rows you are about to remove and keep control over which of the duplicate rows to keep. See http://developer.azurewebsites.net/2014/09/better-sql-group-by-find-duplicate-data/
with MYCTE as (
SELECT ROW_NUMBER() OVER (
PARTITION BY DuplicateKey1
,DuplicateKey2 -- optional
ORDER BY CreatedAt -- the first row among duplicates will be kept, other rows will be removed
) RN
FROM MyTable
)
DELETE FROM MYCTE
WHERE RN > 1
I'm testing something in Oracle and populated a table with some sample data, but in the process I accidentally loaded duplicate records, so now I can't create a primary key using some of the columns.
How can I delete all duplicate rows and leave only one of them?
Use the rowid pseudocolumn.
DELETE FROM your_table
WHERE rowid not in
(SELECT MIN(rowid)
FROM your_table
GROUP BY column1, column2, column3);
Where column1, column2, and column3 make up the identifying key for each record. You might list all your columns.
From Ask Tom
delete from t
where rowid IN ( select rid
from (select rowid rid,
row_number() over (partition by
companyid, agentid, class , status, terminationdate
order by rowid) rn
from t)
where rn <> 1);
(fixed the missing parenthesis)
From DevX.com:
DELETE FROM our_table
WHERE rowid not in
(SELECT MIN(rowid)
FROM our_table
GROUP BY column1, column2, column3...) ;
Where column1, column2, etc. is the key you want to use.
DELETE FROM tablename a
WHERE a.ROWID > ANY (SELECT b.ROWID
FROM tablename b
WHERE a.fieldname = b.fieldname
AND a.fieldname2 = b.fieldname2)
Solution 1)
delete from emp
where rowid not in
(select max(rowid) from emp group by empno);
Solution 2)
delete from emp where rowid in
(
select rid from
(
select rowid rid,
row_number() over(partition by empno order by empno) rn
from emp
)
where rn > 1
);
Solution 3)
delete from emp e1
where rowid not in
(select max(rowid) from emp e2
where e1.empno = e2.empno );
create table t2 as select distinct * from t1;
You should do a small pl/sql block using a cursor for loop and delete the rows you don't want to keep. For instance:
declare
prev_var my_table.var1%TYPE;
begin
for t in (select var1 from my_table order by var 1) LOOP
-- if previous var equal current var, delete the row, else keep on going.
end loop;
end;
To select the duplicates only the query format can be:
SELECT GroupFunction(column1), GroupFunction(column2),...,
COUNT(column1), column1, column2...
FROM our_table
GROUP BY column1, column2, column3...
HAVING COUNT(column1) > 1
So the correct query as per other suggestion is:
DELETE FROM tablename a
WHERE a.ROWID > ANY (SELECT b.ROWID
FROM tablename b
WHERE a.fieldname = b.fieldname
AND a.fieldname2 = b.fieldname2
AND ....so on.. to identify the duplicate rows....)
This query will keep the oldest record in the database for the criteria chosen in the WHERE CLAUSE.
Oracle Certified Associate (2008)
create table abcd(id number(10),name varchar2(20))
insert into abcd values(1,'abc')
insert into abcd values(2,'pqr')
insert into abcd values(3,'xyz')
insert into abcd values(1,'abc')
insert into abcd values(2,'pqr')
insert into abcd values(3,'xyz')
select * from abcd
id Name
1 abc
2 pqr
3 xyz
1 abc
2 pqr
3 xyz
Delete Duplicate record but keep Distinct Record in table
DELETE
FROM abcd a
WHERE ROWID > (SELECT MIN(ROWID) FROM abcd b
WHERE b.id=a.id
);
run the above query 3 rows delete
select * from abcd
id Name
1 abc
2 pqr
3 xyz
This blog post was really helpful for general cases:
If the rows are fully duplicated (all values in all columns can have copies) there are no columns to use! But to keep one you still need a unique identifier for each row in each group.
Fortunately, Oracle already has something you can use. The rowid.
All rows in Oracle have a rowid. This is a physical locator. That is, it states where on disk Oracle stores the row. This unique to each row. So you can use this value to identify and remove copies. To do this, replace min() with min(rowid) in the uncorrelated delete:
delete films
where rowid not in (
select min(rowid)
from films
group by title, uk_release_date
)
The Fastest way for really big tables
Create exception table with structure below:
exceptions_table
ROW_ID ROWID
OWNER VARCHAR2(30)
TABLE_NAME VARCHAR2(30)
CONSTRAINT VARCHAR2(30)
Try create a unique constraint or primary key which will be violated by the duplicates. You will get an error message because you have duplicates. The exceptions table will contain
the rowids for the duplicate rows.
alter table add constraint
unique --or primary key
(dupfield1,dupfield2) exceptions into exceptions_table;
Join your table with exceptions_table by rowid and delete dups
delete original_dups where rowid in (select ROW_ID from exceptions_table);
If the amount of rows to delete is big, then create a new table (with all grants and indexes) anti-joining with exceptions_table by rowid and rename the original table into original_dups table and rename new_table_with_no_dups into original table
create table new_table_with_no_dups AS (
select field1, field2 ........
from original_dups t1
where not exists ( select null from exceptions_table T2 where t1.rowid = t2.row_id )
)
Using rowid-
delete from emp
where rowid not in
(select max(rowid) from emp group by empno);
Using self join-
delete from emp e1
where rowid not in
(select max(rowid) from emp e2
where e1.empno = e2.empno );
Solution 4)
delete from emp where rowid in
(
select rid from
(
select rowid rid,
dense_rank() over(partition by empno order by rowid
) rn
from emp
)
where rn > 1
);
1. solution
delete from emp
where rowid not in
(select max(rowid) from emp group by empno);
2. sloution
delete from emp where rowid in
(
select rid from
(
select rowid rid,
row_number() over(partition by empno order by empno) rn
from emp
)
where rn > 1
);
3.solution
delete from emp e1
where rowid not in
(select max(rowid) from emp e2
where e1.empno = e2.empno );
4. solution
delete from emp where rowid in
(
select rid from
(
select rowid rid,
dense_rank() over(partition by empno order by rowid
) rn
from emp
)
where rn > 1
);
5. solution
delete from emp where rowid in
(
select rid from
(
select rowid rid,rank() over (partition by emp_id order by rowid)rn from emp
)
where rn > 1
);
DELETE from table_name where rowid not in (select min(rowid) FROM table_name group by column_name);
and you can also delete duplicate records in another way
DELETE from table_name a where rowid > (select min(rowid) FROM table_name b where a.column=b.column);
DELETE FROM tableName WHERE ROWID NOT IN (SELECT MIN (ROWID) FROM table GROUP BY columnname);
delete from dept
where rowid in (
select rowid
from dept
minus
select max(rowid)
from dept
group by DEPTNO, DNAME, LOC
);
For best performance, here is what I wrote :
(see execution plan)
DELETE FROM your_table
WHERE rowid IN
(select t1.rowid from your_table t1
LEFT OUTER JOIN (
SELECT MIN(rowid) as rowid, column1,column2, column3
FROM your_table
GROUP BY column1, column2, column3
) co1 ON (t1.rowid = co1.rowid)
WHERE co1.rowid IS NULL
);
Check below scripts -
1.
Create table test(id int,sal int);
2.
insert into test values(1,100);
insert into test values(1,100);
insert into test values(2,200);
insert into test values(2,200);
insert into test values(3,300);
insert into test values(3,300);
commit;
3.
select * from test;
You will see here 6-records.
4.run below query -
delete from
test
where rowid in
(select rowid from
(select
rowid,
row_number()
over
(partition by id order by sal) dup
from test)
where dup > 1)
select * from test;
You will see that duplicate records have been deleted.
Hope this solves your query.
Thanks :)
I didn't see any answers that use common table expressions and window functions.
This is what I find easiest to work with.
DELETE FROM
YourTable
WHERE
ROWID IN
(WITH Duplicates
AS (SELECT
ROWID RID,
ROW_NUMBER()
OVER(
PARTITION BY First_Name, Last_Name, Birth_Date)
AS RN
SUM(1)
OVER(
PARTITION BY First_Name, Last_Name, Birth_Date
ORDER BY ROWID ROWS BETWEEN UNBOUNDED PRECEDING
AND UNBOUNDED FOLLOWING)
AS CNT
FROM
YourTable
WHERE
Load_Date IS NULL)
SELECT
RID
FROM
duplicates
WHERE
RN > 1);
Somethings to note:
1) We are only checking for duplication on the fields in the partition clause.
2) If you have some reason to pick one duplicate over others you can use an order by clause to make that row will have row_number() = 1
3) You can change the number duplicate preserved by changing the final where clause to "Where RN > N" with N >= 1 (I was thinking N = 0 would delete all rows that have duplicates, but it would just delete all rows).
4) Added the Sum partition field the CTE query which will tag each row with the number rows in the group. So to select rows with duplicates, including the first item use "WHERE cnt > 1".
solution :
delete from emp where rowid in
(
select rid from
(
select rowid rid,
row_number() over(partition by empno order by empno) rn
from emp
)
where rn > 1
);
create or replace procedure delete_duplicate_enq as
cursor c1 is
select *
from enquiry;
begin
for z in c1 loop
delete enquiry
where enquiry.enquiryno = z.enquiryno
and rowid > any
(select rowid
from enquiry
where enquiry.enquiryno = z.enquiryno);
end loop;
end delete_duplicate_enq;
This is similar to the top answer but gives me a much better explain plan:
delete from your_table
where rowid in (
select max(rowid)
from your_table
group by column1, column2, column3
having count(*) > 1
);