I have to query a nested object using Nest, however the query is built in dynamic way. Below is code that demonstrate using query on nested "books" in a static way
QueryContainer qry;
qry = new QueryStringQuery()
{
DefaultField = "name",
DefaultOperator = Operator.And,
Query = "salman"
};
QueryContainer qry1 = null;
qry1 = new RangeQuery() // used to search for range ( from , to)
{
Field = "modified",
GreaterThanOrEqualTo = Convert.ToDateTime("21/12/2015").ToString("dd/MM/yyyy"),
};
QueryContainer all = qry && qry1;
var results = elastic.Search<Document>(s => s
.Query(q => q
.Bool(qb => qb
.Must(all)))
.Filter(f =>
f.Nested(n => n
.Path("books")
.Filter(f3 => f3.And(
f1 => f1.Term("book.isbn", "122"),
f2 => f2.Term("book.author", "X"))
)
)
)
);
The problem is that i need to combine multiple queries (using And,OR operators) for "books" in dynamic fashion. For example, get the books that satisfy these set of conditions:
Condition 1: Books that has Author "X" and isbn "1"
Condition 2: Books that has Author "X" and isbn "2"
Condition 3: Books that has Author "Z" and isbn "3"
Other Condtions: .....
Now, the filter in the nested Query should retrieve books if:
Condition 1 AND Condition 2 Or Condition 3
Suppose that i have class name FilterOptions that contains the following attributes:
FieldName
Value
Operator (which will combine the next filter)
I am going to loop on the given FilterOptions array to build the query.
Question:
What should i use to build the nested query? Is it a FilterDesciptor and how to combine them add the nested query to the Search Method?
Please, recommend any valuable link or example?
I agree with paweloque, it seems your first two conditions are contradictory and wouldn't work if AND-ed together. Ignoring that, here's my solution. I've implemented this in such a way that allows for more than the three specific conditions you have. I too feel it would fit better in a bool statement.
QueryContainer andQuery = null;
QueryContainer orQuery = null;
foreach(var authorFilter in FilterOptions.Where(f=>f.Operator==Operator.And))
{
andQuery &= new TermQuery
{
Field = authorFilter.FieldName,
Value = authorFilter.Value
};
}
foreach(var authorFilter in FilterOptions.Where(f=>f.Operator==Operator.Or))
{
orQuery |= new TermQuery
{
Field = authorFilter.FieldName,
Value = authorFilter.Value
};
}
After that, in the .Nested call I would put:
.Path("books")
.Query(q=>q
.Bool(bq=>bq
.Must(m=>m.MatchAll() && andQuery)
.Should(orQuery)
))
In the specific case of the Condition 1 and Condition 2 you'd probably not get any results because these are exclusive conditions. But I assume now, that you want to get results which match either of those conditions. You've chosen nested which is definitely the way to go. With the nested type you can combine parameters for a single book.
Combining nested queries
For your use case I'd use bool query type with must or should clauses.
A query to get books for either Condition 1 or Condition 2 would be:
POST /books/_search
{
"query": {
"bool": {
"should": [
{
"nested": {
"path": "books",
"query": {
"bool": {
"must": [
{
"match": {
"books.isbn": "2"
}
},
{
"match": {
"books.author": "X"
}
}
]
}
}
}
},
{
"nested": {
"path": "books",
"query": {
"bool": {
"must": [
{
"match": {
"books.isbn": "1"
}
},
{
"match": {
"books.author": "X"
}
}
]
}
}
}
}
]
}
}
}
Can you explain, why are your books nested? Without nesting them in a top structure but indexing directly as a top level object in an index/type you could simplify your queries.
Not-Analyzed
There is another caveat that you have to remind: If you want to have an exact match on the author and the ISBN you have to make sure that the ISBN and author fields are set to not_analyzed. Otherwise they get analyzed and splitted into parts and your match would'n work very well.
E.g. if you have a ISBN Number with dashes, then it would get split into parts:
978-3-16-148410-0
would become indexed as:
978
3
16
148410
0
And a search with exactly the same ISBN number would give you all the books which have one of the sub-numbers in their ISBN number. If you want to prevent this, use the not_analyzed index-type and Multi-fields:
"isbn": {
"type": "string",
"fields": {
"raw": {
"type": "string",
"index": "not_analyzed"
}
}
}
Then to address the not_analyzed isbn field you'd have to call it:
books.isbn.raw
Hope this helps.
Related
I'm trying to filter items by relation using a knex query. I'm almost there (I think) but struggling a little and could use some help as this is new to me.
I have a list of users who are following people and have followers. I'm trying to return a list of users who I'm not already following. Below is my code so far:
const users = await knex("users-permissions_user").whereNotExists(
function () {
this.select("*")
.from("users_followers__users_followings")
.where("user_id", "users-permissions_user.id")
.where("follower_id", id);
}
);
This returns a list of users who currently have no followers and users where I'm the only follower. Any users who I follow and also have more followers are still returned. I thought like would achieve this type of filter but I must be doing it wrong.
Here is how the table for the followers/following relation appears in my db:
And here is the data that would be returned from the above query:
[
{
"id": "138",
"followers": [
{
"id": "143"
}
]
},
{
"id": "140",
"followers": [
{
"id": "160"
},
{
"id": "136"
}
]
},
{
"id": "135",
"followers": []
},
{
"id": "136",
"followers": []
}
]
As you can see, users with no followers are returned as are users who I'm not already following but users who have multiple followers, including me (ID 160), are returned when they should be omitted.
Any advice would be greatly appreciated!
So the reason that users like 140 are being returned even though they are following you (160) is because they are following at least one other person who isn't you, which means your where clause will match them.
If you want to return only users who are not following you, you could achieve this by replacing your left join and where clause with a where not exists clause. In knex that would look something like:
qb.whereNotExists(function() {
this.select(1)
.from('users_followers__users_followings')
.where('users_followers__users_followings.user_id', knex.ref('users-permissions_user.id'))
.where('users_followers__users_followings.follower_id', id);
});
I am new to MongoDB. I need to convert this SQL code to MongoDB
select TOP 5 r.regionName, COUNT(c.RegionID)
from region as r,
company as c
where c.RegionID = r._id
group by r.regionName
order by COUNT(c.RegionID) DESC;
Option 1. You can use the aggregation framework with $lookup, $group, $project , $sort and $limit stages, but this seems like a wrong approach since the true power to change relation database with mongoDB is the denormalization and avoidance of join ($lookup) like queries.
Option 2. You convert your multi-table relational database schema to document model and proceed with simple $group, $project, $sort and $limit stage aggregation query for the above task.
Since you have not provided any mongodb document examples it is hard to provide how your queries will look like ...
Despite of my comment I try to give a translation (not tested):
db.region.aggregate([
{
$lookup: // left outer join collections
{
from: "company",
localField: "_id",
foreignField: "RegionID",
as: "c"
}
},
{ $match: { c: { $ne: [] } } }, // remove non-matching documents (i.e. INNER JOIN)
{ $group: { _id: "$regionName", regions: { $addToSet: { "$c.RegionID" } } } }, // group and get distinct regions
{ $project: { regionName: "$_id", count: { $size: "$regions" } , _id: 0} } // some cosmetic and count
{ $sort: { regionName: 1 } }, // order result
{ $limit: 5 } // limit number or returned documents
])
How can I return all documents which have parameter.code = "123", given this document structure, using CosmosDB SQL query? Is it necessary to use a UDF? (If so, how?)
{
"batch_id": "abc",
"samples": [
{
"sample_id": "123",
"tests": [
{
"parameter": {
"code": "123", // <- target
}
}
]
}
]
}
No need to use UDF(User Defined Function),just use cosmos db query sql with double JOIN.
SQL:
SELECT c.batch_id FROM c
join samples in c.samples
join tests in samples.tests
where tests.parameter.code = "123"
Output:
Considering this query written in sql server how would I efficiently convert it to mongodb:
select * from thetable where column1 = column2 * 2
You can use below aggregation.
You project a new field comp to calculate the expression value followed by $match to keep the docs with eq(0) value and $project with exclusion to drop comp field.
db.collection.aggregate([
{ $addFields: {"comp": {$cmp: ["$column1", {$multiply: [ 2, "$column2" ]} ]}}},
{ $match: {"comp":0}},
{ $project:{"comp":0}}
])
If you want to run your query in mongo Shell,
try below code,
db.thetable .find({}).forEach(function(tt){
var ttcol2 = tt.column2 * 2
var comapreCurrent = db.thetable.findOne({_id : tt._id,column1 : ttcol2});
if(comapreCurrent){
printjson(comapreCurrent);
}
});
I liked the answer posted by #Veeram but it would also be possible to achieve this using $project and $match pipeline operation.
This is just for understanding the flow
Assume we have the below 2 documents stored in a math collection
Mongo Documents
{
"_id" : ObjectId("58a055b52f67a312c3993553"),
"num1" : 2,
"num2" : 4
}
{
"_id" : ObjectId("58a055be2f67a312c3993555"),
"num1" : 2,
"num2" : 6
}
Now we need to find if num1 = 2 times of num2 (In our case the document with _id ObjectId("58a055b52f67a312c3993553") will be matching this condition)
Query:
db.math.aggregate([
{
"$project": {
"num2": {
"$multiply": ["$num2",1]
},
"total": {
"$multiply": ["$num1",2]
},
"doc": "$$ROOT"
}
},
{
"$project": {
"areEqual": {"$eq": ["$num2","$total"]
},
doc: 1
}
},
{
"$match": {
"areEqual": true
}
},
{
"$project": {
"_id": 1,
"num1": "$doc.num1",
"num2": "$doc.num2"
}
}
])
Pipeline operation steps:-
The 1st pipeline operation $project calculates the total
The 2nd pipeline operation $project is used to check if the total
matches the num2. This is needed as we cannot use the comparision
operation of num2 with total in the $match pipeline operation
The 3rd pipeline operation matches if areEqual is true
The 4th pipeline operation $project is just used for projecting the fields
Note:-
In the 1st pipeline operation I have multiplied num2 with 1 as num1 and num2 are stored as integers and $multiply returns double value. So incase I do not use $mutiply for num2, then it tries to match 4 equals 4.0 which will not match the document.
Certainly no need for multiple pipeline stages when a single $redact pipeline will suffice as it beautifully incorporates the functionality of $project and $match pipeline steps. Consider running the following pipeline for an efficient query:
db.collection.aggregate([
{
"$redact": {
"$cond": [
{
"$eq": [
"$column1",
{ "$multiply": ["$column2", 2] }
]
},
"$$KEEP",
"$$PRUNE"
]
}
}
])
In the above, $redact will return all documents that match the condition using $$KEEP and discards those that don't match using the $$PRUNE system variable.
I'm hoping to create a query where it will filter out IDs containing a wildcard. For instance, I would like to search for something everywhere except where the ID contains the word current. Is this possible?
Yes it is possible using Regex Filter/Regex Query. I could not figure a way to directly do it using the Complement option hence I've used bool must_not to solve your problem for the time being. I'll refine the answer later if possible.
POST <index name>/_search
{
"query": {
"match_all": {}
},
"filter": {
"bool": {
"must_not": [
{
"regexp": {
"ID": {
"value": ".*current.*"
}
}
}
]
}
}
}