Using Column value as foldername when exporting images MSSQL - sql

Question

When exporting images using MSSQL, is there a way to specify a columns value as a new folder name?
For example, I have a field called ReportID that I would like a folder to be created inside my already created "images" folder if it doesn't already exist, (multiple records could hold the same ReportID).
My script is as follows: (the correct file path is being written, but no images are being saved, and I assume it's not creating folders properly)
sp_configure 'show advanced options', 1;
GO
RECONFIGURE;
GO
sp_configure 'Ole Automation Procedures', 1;
GO
RECONFIGURE;
GO
DECLARE #file int,
#FilePath varchar(80),
#hr INT,
#FK_ReferenceID INT,
#FK_FieldID INT,
#Value VARBINARY(MAX),
#Extension varchar(4),
#ReportID INT;
DECLARE imgs CURSOR
FOR SELECT FK_ReferenceID, FK_FieldID, Value, Extension, ReportID FROM dbo.ImageValues
FOR UPDATE OF FilePath;
OPEN imgs;
FETCH NEXT FROM imgs INTO #FK_ReferenceID, #FK_FieldID, #Value, #Extension, #ReportID;
WHILE ##FETCH_STATUS = 0
BEGIN
SELECT #FilePath = 'E:\Reports\images\' + CAST(#ReportID AS VARCHAR(10)) + '\' + CAST(#FK_ReferenceID AS VARCHAR(10)) + '-f' + CAST(#FK_FieldID AS VARCHAR(10)) + '.' + CAST(#Extension AS VARCHAR(4));
EXEC sp_OACreate 'ADODB.Stream', #file OUT;
EXEC sp_OASetProperty #file, 'Type', 1;
EXEC sp_OAMethod #file, 'Open';
EXEC sp_OAMethod #file, 'Write', NULL, #Value;
EXEC sp_OAMethod #file, 'SaveToFile', NULL, #FilePath, 2;
EXEC sp_OAMethod #file, 'Close';
EXEC sp_OADestroy #file;
UPDATE dbo.ImageValues SET FilePath = #FilePath WHERE CURRENT OF imgs;
FETCH NEXT FROM imgs INTO #FK_ReferenceID, #FK_FieldID, #Value, #Extension, #ReportID;
END
CLOSE imgs;
DEALLOCATE imgs;
GO
sp_configure 'Ole Automation Procedures', 0;
GO
RECONFIGURE;
GO

Answer 1

One way to do this is to break this into 2 steps, (1) create the folders first anyways and (2) then the file. You would need to check for exceptions in both steps, in the first step you would ignore if the exception that folder already exists. Alternatively you could first check if the folder exists and then create it and then the file. As far as I know, SQL automatically would not do such checks for you.