I am using the gnuplot scrip command set key autotitle columnhead to make the lables for my data. The only issue is, the column head data is numeric and so it doesnt really mean much on its own.
Is there a way to add a fixed string to the autotitle, eg "Year " + columnhead, or alternatively, give my key a title?
String concatenation using . operator with columnhead() works in gnuplot v4.6 (documentation):
set terminal pngcairo enhanced truecolor size 480,320 fontscale 0.8
set output 'autotitle.png'
set key left Left
plot for [i=2:4] 'data.txt' u 1:i w l t 'f(x) = '.columnhead(i)
Also, yes, you can set a title for the key instead, like this: set key title 'f(x)'.
Input file data.txt used in this example:
x 100x x^3 2^x
1 100 1 2
2 200 8 4
3 300 27 8
4 400 64 16
5 500 125 32
6 600 216 64
7 700 343 128
8 800 512 256
9 900 729 512
10 1000 1000 1024
Related
So I have a datatable that looks something like that following. ID represents an object, bin represents how I am segmenting the data, and percent is how much of a data falls into that bin.
id bin percent
2 8 0.20030698388
2 16 0.14504988488
2 24 0.12356101304
2 32 0.09976976208
2 40 0.09056024558
2 48 0.07137375287
2 56 0.04067536454
2 64 0.03914044512
2 72 0.02916346891
2 80 0.16039907904
3 8 0.36316695352
3 16 0.03958691910
3 24 0.11876075731
3 32 0.13253012048
3 40 0.03098106712
3 48 0.07228915662
3 56 0.07745266781
3 64 0.02581755593
3 72 0.02065404475
3 80 0.11876075731
I am looking for a function to turn this dataset into a cdf partitioning id. I have tried cume_dist and percent_rank, but they do not appear to work.
I am facing a similar problem and found this great tutorial for doing exactly that:
https://dwaincsql.com/2015/05/14/excel-in-t-sql-part-2-the-normal-distribution-norm-dist-density-functions/
It tries to rebuild the Excel function NORM.DIST function which gives you either the PDF if you set the cummulative flag as FALSE and the CDF if you set it as TRUE. I assumed that CUME_DIST would do the exact same thing in SQL. However, it turns out that the latter distributes by counting the elements whereas Excel uses the relative differences in the values.
I tried parsing a common string depiction of ranges (e.g. 1-9) into actual ranges (e.g. 1 .. 9), but often got weird results when including two digit numbers. For example, 1-10 results in the single value 1 instead of a list of ten values and 11-20 gave me four values (11 10 21 20), half of which aren't even in the expected numerical range:
put get_range_for('1-9');
put get_range_for('1-10');
put get_range_for('11-20');
sub get_range_for ( $string ) {
my ($start, $stop) = $string.split('-');
my #values = ($start .. $stop).flat;
return #values;
}
This prints:
1 2 3 4 5 6 7 8 9
1
11 10 21 20
Instead of the expected:
1 2 3 4 5 6 7 8 9
1 2 3 4 5 6 7 8 9 10
11 12 13 14 15 16 17 18 19 20
(I figured this out before posting this question, so I have answered below. Feel free to add your own answer if you'd like to elaborate).
The problem is indeed that .split returns Str rather than Int, which the original answer solves. However, I would rather implement my "get_range_for" like this:
sub get_range_for($string) {
Range.new( |$string.split("-")>>.Int )
}
This would return a Range object rather than an Array. But for iteration (which is what you most likely would use this for), this wouldn't make any difference. Also, for larger ranges the other implementation of "get_range_for" could potentially eat a lot of memory because it vivifies the Range into an Array. This doesn't matter much for "3-10", but it would for "1-10000000".
Note that this implementation uses >>.Int to call the Int method on all values returned from the .split, and then slips them as separate parameters with | to Range.new. This will then also bomb should the .split return 1 value (if it couldn't split) or more than 2 values (if multiple hyphens occurred in the string).
The result of split is a Str, so you are accidentally creating a range of strings instead of a range of integers. Try converting $start and $stop to Int before creating the range:
put get_range_for('1-9');
put get_range_for('1-10');
put get_range_for('11-20');
sub get_range_for ( $string ) {
my ($start, $stop) = $string.split('-');
my #values = ($start.Int .. $stop.Int).flat; # Simply added .Int here
return #values;
}
Giving you what you expect:
1 2 3 4 5 6 7 8 9
1 2 3 4 5 6 7 8 9 10
11 12 13 14 15 16 17 18 19 20
I need to create spline programmatically. I've made something like:
0
SECTION
2
HEADER
9
$ACADVER
1
AC1006
0
ENDSEC
0
SECTION
2
TABLES
0
TABLE
2
LAYER
0
LAYER
2
shape
70
64
62
250
6
CONTINUOUS
0
LAYER
2
holes
70
64
62
250
6
CONTINUOUS
0
ENDTAB
0
ENDSEC
0
SECTION
2
ENTITIES
0
SPLINE
8
shape
100
AcDbSpline
210
0
220
0
230
1
70
4
71
3
72
11
73
4
74
4
42
0.0000001
43
0.0000001
44
0.0000000001
40
0
40
0
40
0
40
0
40
1
40
1
40
1
40
2
40
2
40
2
40
2
10
0
20
0
30
0
10
100
20
50
30
0
10
40
20
40
30
0
10
15
20
23
30
0
11
0
21
0
31
0
11
200
21
200
31
0
11
80
21
80
31
0
11
432
21
234
31
0
0
ENDSEC
0
EOF
When I'm trying to open it in Autodesk TrueView, I'm getting an error:
Undefined group code 210 for object on line 54.
Invalid or incomplete DXF input -- drawing discarded.
Where is the error? When I'm copying just SPLINE section to the DXF generated by AI everything works fine. So I think I need to add something in the header section or something.
This file is DXF version AC1006 which is older than DXF R12. The SPLINE entity
requires at least DXF version AC1012 DXF R13/R14. But with DXF version AC1012
the tag structure of DXF files is changed (OBJECTS and CLASSES sections, SubClassMarkers ...), so just editing the DXF version
does not work.
See also: http://ezdxf.readthedocs.io/en/latest/dxfinternals/filestructure.html#minimal-dxf-content
Also the SPLINE entity seems to be invalid, it has no handle (5) and no owner
tag (330), and the whole AcDbEntity subclass is missing.
Your spline is of degree 3 with 11 knots (0, 0,0,0,1,1,1,2,2,2,2) and 4 control points ( (0,0), (100,50),(40,40),(15,23) ). This might be the problem culprit. You should either have 4 control points and 8 knots or 7 control points and 11 knots.
You may need to assign a handle to the SPLINE, since you're specifying $ACADVER = AC1018 = AutoCAD 2004 where item handles are required.
Try adding a 5-code pair right before the layer designation, like so, where AAAA is a unique hex-encoded handle:
0
SPLINE
5 <-- add these two lines
AAAA <--
8
shape
100
AcDbSpline
I have a file like this
3 4 5 6 7 1
4 5 4 4 4 4
2 2 3 3 2 1
and I want to multiple every data point by a constant (e.g. 10) to get the following output
30 40 50 60 70 10
40 50 40 40 40 40
20 20 30 30 20 10
I have been trying to do it like this without success
awk '{i=1; while (i<=NF) print $i*10; i++}'
You are using a while loop, whereas a simple for would suffice:
$ awk '{for (i=1; i<=NF; i++) $i*=10}1' file
30 40 50 60 70 10
40 50 40 40 40 40
20 20 30 30 20 10
A while needs a finish condition and you are not providing none. Also, if the amount of loops to do is a fixed number, it is better to just use for.
Note that you were saying print, so that every field would be printed in a different line. By replacing each one of them and using 1 to print it afterwards, you keep the format.
I have a worked example of how to compute the capacity of a hard disk, could anyone explain where the BOLD figures came out of?
RPM: 7200
no of sectors: 400
no of platters: 6
no of heads: 12
cylinders: 17000
avg seek time: 10millisecs
time to move between adj cylinders: 1millisec
the first line of the answer given to me is:
12 x 17 x 4 x 512 x 10^5
I just want to know where the parts in bold came from.The 512 I dont know. The 10 is from the seek time but its power 5?
The answer is
heads x cylinder x sectors x 512 (typical size of one sector in bytes)
so this is
12 x 17000 x 400 x 512
which is the same as
12 x 17 x 1000 x 4 x 100 x 512
and
100 = 10^2
1000 = 10^3
10^2 x 10^3 = 10^5
As you want the capacity, you don't need any times here.
A reference for the 512 bytes can be found at Wikipedia, for example (and it also has a similar example with the same formula a bit below).