i am trying convert the row data into column in SQL, here is the data i have in my table
ID NAME DATE STATUS
1 A 1/1/15 START
1 A 1/20/15 END
I want result as
ID NAME START_DATE END_DATE
1 A 1/1/15 1/20/15
Any help will be appreciated
Check out Pivot.. Seems to be what you are looking to do.
https://technet.microsoft.com/en-us/library/ms177410(v=sql.105).aspx
Related
I would like to get the output for the over lapping date records
> Data: Id Open_date Closed_Date
> 1 2016-01-01 2017-01-01
**> 1 2016-12-31 2018-21-01
> 1 2016-01-01 2018-01-01**
> 2 2017-01-01 2018-02-02
Here, you see the second & 3rd records are starting with date than the closed_Date of their previous records. Here i need to identify those type of records
As you question is not much clear, I am assuming that you are looking for min of open date and max of close date.
If this is not the requirement edit the question to provide more details.
select id, min(Open_date), max(Closed_Date)
from table
group by id
Looks like you want to normalize a Slowly Changing Dimension Type 2. Of course the best way to handle them would be using Temporal tables using either Teradata or ANSI syntax.
There's a nice syntax in Teradata to get your expected result based on the Period data type, but it's imple to cast your begin/end dates to a period:
SELECT id,
-- split the period back into seperate dates
Begin(pd) AS Open_date,
End(pd) AS Closed_Date
FROM
(
SELECT NORMALIZE -- magic keyword :-)
id, PERIOD(Open_date, Closed_Date) AS pd
FROM tab
) AS dt
I am use ADO SQL in VBA to try and need the solution to the following example:
Table
ID Effective Date of Documentation
1 1/1/2015
2 6/1/2015
3 1/1/2016
4 6/1/2016
In the example above the documentation for the ID 1 is in effective from 1/1/2015 through 5/31/2015, for ID 2 its in effect from 6/1/2015 through 12/31/2015, and so forth. So if I have a date say 8/1/2015, then I need to return the record which the documentation is in effect for. So in this example the record for ID 2 would be returned. I need some SQL to accomplish this and I cant figure out how! Any ideas? Is this possible to do with this structure or do I need to create some artificial column first for the end date and query that?
You can do this by doing:
select t.*
from table t
where effdate < #date
order by effdate desc
fetch first 1 row only;
This is the SQL standard syntax. Different databases might have different syntax for selecting one row.
EDIT:
In MS Access you would do:
select TOP 1 t.*
from t
where effdate < #date
order by effdate desc;
I am writing a query and am having trouble filtering data as I would like. In the table, there is a date field and an ItemCode field. I would like to return one record per ItemCode with the earliest date that is after today.
If today is 6/6/2017 and my data looks like:
ItemCode Date
1 6/1/2017
1 6/7/2017
1 6/10/2017
2 6/2/2017
2 6/8/2017
2 6/15/2017
I would want the result to be
ItemCode Date
1 6/7/2017
2 6/8/2017
My query so far is:
SELECT PO_PurchaseOrderDetail.ItemCode, Min(PO_PurchaseOrderDetail.RequiredDate) AS NextPO
FROM PO_PurchaseOrderDetail
GROUP BY PO_PurchaseOrderDetail.ItemCode
HAVING (((Min(PO_PurchaseOrderDetail.RequiredDate))>=Now()));
The problem is that the Min function fires first and grabs the earliest dates per ItemCode, which are before today. Then the >=Now() is evaluated and because the min dates are before today, the query returns nothing.
I've tried putting the >=Now() inside the min function in the HAVING part of the query but it does not change the result.
My structure is wrong and I would appreciate any advice. Thanks!
I would approach like this for standard SQL, Access approach may vary
select PO_PurchaseOrderDetail.ItemCode,
min(PO_PurchaseOrderDetail.RequiredDate) as NextPO
from PO_PurchaseOrderDetail
where PO_PurchaseOrderDetail.RequiredDate >= Now()
group by PO_PurchaseOrderDetail.ItemCode;
Put the date condition in the where clause (not the having clause):
select ItemCode, min(Date) as NextPO
from PO_PurchaseOrderDetail
where Date > '6/6/2017'
group by ItemCode
Sorry if this is too general a question, but I couldn't find much material on this.
I'm wondering if there is any way in SQL or Tableau to always include certain records despite changes in a date range?
For example, I have 200 records that range from 1940-2004 and want 2 or 3 of these records to always be returned in the query (which includes a date range statement) is there a known method?
I'd like to avoid altering the date attributes based on the date range statement itself is possible.
Initial data:
Person_ID | Group | Date
ID 1 2 1-1-2003
ID 2 1 1-1-1994
ID 3 1 1-1-1985
ID 4 1 1-1-1992
ID 5 2 1-1-1991
ID 6 2 1-1-2002
ID 7 1 1-1-2003
ID 8 2 1-1-2005
ID 9 2 1-1-1999
ID 10 1-1-2002
ID 11 1-1-1989
For my results, I want it to be possible so that no matter the daterange I select, ID 10 and ID 11 are included.
SELECT Person_ID
FROM table
WHERE DATE BETWEEN date1 AND date2
Will always yield ID 10 and ID 11 no matter the dates inputted.
I don't know much about tableau but you can try this...
SELECT Person_ID
FROM table
WHERE (DATE BETWEEN date1 AND date2) OR Person_ID = 10 OR Person_ID = 11
If you want help on figuring out queries try and say what you want as literal as possible using sql words. So in this case you could say "I want to select the person_id from table where the date is between date1 and date2 or if the person_id is 10 or if the person_id is 11". If you ever say but (ex: date between date1 and date2 but if their id is 10 then also do it) then most likely you can put an or there : ). So if I were to do it without the or it sound more normal (in my opinion at least -> "where the date is between date1 and date2 but if the person_id is 10 or 11 also include it"). Hope that helps!
Say I have a table:
ID DATE
1 2/1/12
2 3/1/12
3 1/1/12
4 4/1/12
How would I go about selecting the first date found when decrementing from a given date.
Example: Find the last entry before 4/1/12, by date. Return entry at SQL ID 2.
If this was added:
ID DATE
5 3/2/12
Than the above example would return the entry at SQL ID 5.
How would I represent what I need in SQL?
Select top 1 ID, DATE
from table
where DATE < '4/1/12'
order by DATE DESC
other ideas: (in addition to Gratzy's)
select the MAX date where the date is less than the target date.
use a LAG function.