I have a table like following
id id_a id_b uds
--------------------------
1 1 3 20
1 2 8 17
2 1 3 5
3 1 1 32
3 2 1 6
What I would need is to get the row with minimum "uds" for each "id". So the result would be:
id id_a id_b uds
--------------------------
1 2 8 17
2 1 3 5
3 2 1 6
Thank you in advance...
Use Min with a group by clause:
select id, id_a, id_b, min(uds) as uds
from table1
group by id, id_a, id_b
order by id, id_a, id_b;
However, I should mention this is going to get you all of the items, you need to also specify an aggregate on the other columns, or do not include them.
select id, min(uds) as uds
from table1
group by id
order by id;
Judging by your desired output though, the following may be what you want:
select id, max(id_a) as id_a, max(id_b) as id_b, min(uds) as uds
from table1
group by id
order by id;
Most databases support the ANSI standard window functions. An easy way to do what you want:
select t.*
from (select t.*, row_number() over (partition by id order by uds) as seqnum
from t
) t
where seqnum = 1;
you have to set condition with minimum uds value or you have to decides how many numbers of records you want with minimum uds
More one way:
select
a.*
from
#temp a inner join (select id, min(uds) minUds from #temp group by id) b on
a.id = b.id
and a.uds = b.minUds
Related
I have this select:
"Select * from table" that return:
Id
Value
1
1
1
1
2
10
2
10
My goal is create a sum from each Value group by id like this:
Id
Value
Sum
1
1
2
1
1
2
2
10
20
2
10
20
I Have tried ways like:
SELECT Id,Value, (SELECT SUM(Value) FROM Table V2 WHERE V2.Id= V.Id GROUP BY IDRNC ) FROM Table v;
But the is not grouping by id.
Id
Value
Sum
1
1
1
1
1
1
2
10
10
2
10
10
Aggregation aggregates rows, reducing the number of records in the output. In this case you want to apply the result of a computation to each of your records, task carried out by the corresponding window function.
SELECT table.*, SUM(Value) OVER(PARTITION BY Id) AS sum_
FROM table
Check the demo here.
Your attempt looks correct.
Can you try the below query :
It works for me :
SELECT Id, Value,
(SELECT SUM(Value) FROM Table V2 WHERE V2.Id= V.Id GROUP BY ID) as sum
FROM Table v;
You can do it using inner join to join with selection grouped by id :
select t.*, sum
from _table t
inner join (
select id, sum(Value) as sum
from _table
group by id
) as s on s.id = t.id
You can check it here
Your select is ok if you adjust it just a little:
SELECT Id,Value, (SELECT SUM(Value) FROM Table V2 WHERE V2.Id= V.Id GROUP BY IDRNC ) FROM Table v;
GROUP BY IDRNC is a mistake and should be GROUP BY ID
you should give an alias to a sum column ...
subquery selecting the sum does not have to have self table alias to be compared with outer query that has one (this is not a mistake - works either way)
Test:
WITH
a_table (ID, VALUE) AS
(
Select 1, 1 From Dual Union All
Select 1, 1 From Dual Union All
Select 2, 10 From Dual Union All
Select 2, 10 From Dual
)
SELECT ID, VALUE, (SELECT SUM(VALUE) FROM a_table WHERE ID = v.ID GROUP BY ID) "ID_SUM" FROM a_table v;
ID VALUE ID_SUM
---------- ---------- ----------
1 1 2
1 1 2
2 10 20
2 10 20
I have table T1
ID Size
A 1
A 2
A 3
B 3
B 4
C 2
C 4
I want to group by ID and filter the smallest size for each ID
Desired outcome:
A 1
B 3
C 2
I tried doing something like this:
SELECT ID, Size
FROM T1
WHERE ID IN (SELECT DISTINCT ID FROM T1)
You want a basic GROUP BY query:
SELECT ID, MIN(Size) AS Size
FROM T1
GROUP BY ID;
SELECT T1.id, MIN(T1.SIZE) AS MinimumSize FROM T1 GROUP BY T1.ID
may be you can find your solution.
I want to know what id_b exist the most times in each id_A. I have this table
id_A id_B
1 1
2 1
2 1
3 1
3 3
3 3
And I need a sql command that puts the table like this:
id_A id_B
1 1
2 1
3 3
Technically, this is called the "mode" of (the distribution of) the values.
If you only want one, then use can use the ANSI standard function row_number() with conditional aggregation:
select id_A, id_B as mode_id_B
from (select id_A, id_B, count(*) as cnt,
row_number() over (partition by id_A order by count(*) desc) as seqnum
from t
group by id_A, id_B
) ab
where seqnum = 1;
I want to add an extra column, where the max values of each group (ID) will appear.
Here how the table looks like:
select ID, VALUE from mytable
ID VALUE
1 4
1 1
1 7
2 2
2 5
3 7
3 3
Here is the result I want to get:
ID VALUE max_values
1 4 7
1 1 7
1 7 7
2 2 5
2 5 5
3 7 7
3 3 7
Thank you for your help in advance!
Your previous questions indicate that you are using SQL Server, in which case you can use window functions:
SELECT ID,
Value,
MaxValue = MAX(Value) OVER(PARTITION BY ID)
FROM mytable;
Based on your comment on another answer about first summing value, you may need to use a subquery to actually get this:
SELECT ID,
Date,
Value,
MaxValue = MAX(Value) OVER(PARTITION BY ID)
FROM ( SELECT ID, Date, Value = SUM(Value)
FROM mytable
GROUP BY ID, Date
) AS t;
There is no need to use GROUP BY in subselect.
select ID, VALUE,
(select MAX(VALUE) from mytable where ID = t.ID) as MaxValue
from mytable t
Use this query.
SELECT ID
,value
,(
SELECT MAX(VALUE)
FROM GetMaxValue gmv
WHERE gmv.ID = gmv1.ID
GROUP BY ID
) as max_value
FROM GetMaxValue gmv1
ORDER BY ID
Try it with a sub select and group by, then grab the MAX of this group:
select
ID,
VALUE,
(select MAX(VALUE)
from mytable
group by ID
having ID = t.ID
) as max_values
from mytable t
Edit:
I built a SQL fiddle, which shows that my solution works, but also VDohnal is correct and doesn't need the group by, so I'll upvote his answer.
If I have a table which is of the following format:
ID NAME NUM TIMESTAMP BOOL
1 A 5 09:50 TRUE
1 B 6 13:01 TRUE
1 A 1 10:18 FALSE
2 A 3 12:20 FALSE
1 A 1 05:30 TRUE
1 A 12 06:00 TRUE
How can I get the ID, NAME and NUM for each unique ID, NAME pair with the latest Timestamp and BOOL=TRUE.
So for the above table the output should be:
ID NAME NUM
1 A 5
1 B 6
I tried using Group By but I cannot seem to get around that either I need to put an aggregator function around num (max, min will not work when applied to this example) or specifying it in group by (which will end up matching on ID, NAME, and NUM combined). Both as far as I can think will break in some case.
PS: I am using SQL Developer (that is the SQL developed by Oracle I think, sorry I am a newbie at this)
If you're using at least SQL-Server 2005 you can use the ROW_NUMBER function:
WITH CTE AS
(
SELECT ID, NAME, NUM,
RN = ROW_NUMBER()OVER(PARTITION BY ID, NAME ORDER BY TIMESTAMP DESC)
FROM Table
WHERE BOOL='TRUE'
)
SELECT ID, NAME, NUM FROM CTE
WHERE RN = 1
Result:
ID NAME NUM
1 A 5
1 B 6
Here's the fiddle: http://sqlfiddle.com/#!3/a1dc9/10/0
select t1.* from table as t1 inner join
(
select NAME, NUM, max(TIMESTAMP) as TIMESTAMP from table
where BOOL='TRUE'
) as t2
on t1.name=t2.name and t1.num=t2.num and t1.timestamp=t2.timestamp
where t1.BOOL='TRUE'
select t1.*
from TABLE1 as t1
left join
TABLE1 as t2
on t1.name=t2.name and t1.TIMESTAMP>t2.TIMESTAMP
where t1.BOOL='TRUE' and t2.id is null
should do it for you.