Autofill SQL table field with Datetime value based on input parameter - sql

I have a datetime field in my SQL table. I have created a procedure that takes count as a variable and generates records for the table. If the count is 5 it will generate 5 records.The logic i want is that when i provide 5 as an input parameter the datetime field in the table should be autofilled with values
12/20/2015 9:00
12/20/2015 11:00
12/20/2015 13:00
12/20/2015 15:00
12/20/2015 17:00
So every time a record is inserted into a table,the 2 hours of time should be added.

Recursive CTEs are one way to create records on the fly. The key here is to create an anchor (this is the first SELECT inside the CTE, which is your starting point). And an exit check (which is the WHERE clause).
Read up on MAXRECURSION if you want to create more than 100 records at a time.
Example
DECLARE #RecordsRequired INT = 5;
DECLARE #BaseDateTime SMALLDATETIME = GETDATE();
WITH [Sample] AS
(
/* This CTE uses recursion to create the required number of
* records.
*/
SELECT
1 AS RowNumber,
#BaseDateTime AS [DateTime]
UNION ALL
SELECT
RowNumber + 1 AS RowNumber,
DATEADD(HOUR, 2, [DateTime]) AS [DateTime]
FROM
[Sample]
WHERE
RowNumber < #RecordsRequired
)
SELECT
RowNumber,
[DateTime]
FROM
[Sample]
;
You could also look into WHILE blocks.

Use this code:
------------------ INPUT ------------------------
declare #start_date datetime = '01/01/2000 14:00'
declare #loops int = 5
-------------------------------------------------
declare #i int = 0
while (#i < #loops) begin
select dateadd(hour, #i * 2, #start_date)
set #i = #i + 1
end

Try this without LOOP
Declare #count int = 5,
#incrementer int =2 -- in case if you want to change the incrementer
SELECT Dateadd(hh, num * #incrementer, dates)
FROM (SELECT Cast(CONVERT(VARCHAR(20), Dateadd(dd, 1, Getdate()), 111)
+ ' 9:00 AM' AS DATETIME) AS Dates,
num
FROM (VALUES(0),(1),(2),(3),(4),(5)) TC (num)) A
WHERE num <= #count - 1
SQL FIDDLE DEMO

Please find the sample code below, it contains the logic that you needed. Hope it helps!!
--Create a temp table for sample output
CREATE TABLE #temp
(
CreatedDate datetime
)
--Declaring variables
DECLARE #Count int
DECLARE #TimeCounter int
--intializing values
SET #Count=5
SET #TimeCounter=0
WHILE(#Count>0)
BEGIN
--SELECT getdate()+1
insert into #temp(#temp.CreatedDate) Select DATEADD(hour,#TimeCounter,getdate())
SET #TimeCounter=#TimeCounter+2
SET #Count=#Count-1
END
--Final values
SELECT * FROM #temp tmp
--Dropping table
DROP TABLE #temp

This is one of those problems that's best solved with a numbers table / function. Much less code than recursion or loops, usually faster for anything non-trivial and more reusable too.
The core code you want is
CREATE PROCEDURE usp_PopulateAppointments
(
#StartDateTime datetime2(3),
#Records int,
#Interval int = 120 --Time between appointment slots in minutes. Default to 2h if not manually specified.
)
INSERT INTO Appointments
SELECT
DATEADD(m, #Interval * Number, #StartDateTime)
FROM dbo.udfNumbers(0, #Recs)
I've assumed in this a numbers function that takes #StartAt and #NumberResults. I use one derived from Adam's final code in the comments on http://dataeducation.com/you-require-a-numbers-table/ - in my experience it's faster than a real table, and takes less space too.

Create Table dates
(
datetimefield datetime not null
)
go
Create Procedure FillDateTimeField
#insertxrows int
AS
begin
Declare #LastDateTimeInserted as datetime
set #LastDateTimeInserted = (select isnull(max(datetimefield),getdate()) from Dates)
;WITH norows AS (
SELECT 1 as num, Dateadd(hour,2,#LastDateTimeInserted) as FirstRecord
UNION ALL
SELECT num + 1, dateadd(hour,2,firstrecord) FROM
norows
WHERE num < #insertxrows
)
insert into dates
select firstrecord from norows
end

Related

update field every hour in SQL Server

I have the following query in a job, it is scheduled to run every hour of L-V.
All the records that are made in the table in the FCH_FIN field have an exact time, for example: 7:00:00 to 19:00:00.
Then I create a temporary table and pass the data from my original table, and I want to go through my temporary table to get the difference in time between the system time using GETDATE () and the time of the record in the FCH_FIN field, if this is less then update active to 0.
Query:
DECLARE #count INT;
DECLARE #fch2 DATETIME;
DECLARE #seconds INT;
CREATE table #Suple
(
ID INT PRIMARY KEY NOT NULL,
ACTIVO NCHAR(10) NOT NULL,
FCH_INICIO DATETIME NOT NULL,
FCH_FIN DATETIME NOT NULL
);
INSERT INTO #Suple
SELECT *
FROM Original
WHERE ACTIVO = 1
AND CONVERT(DATE, FCH_FIN) = CONVERT(DATE, GETDATE());
SELECT #count = COUNT(*) FROM #Suple;
WHILE #count > 0
BEGIN
SELECT
#seconds = DATEDIFF(S, GETDATE(),FCH_FIN)
FROM
#Suple
WHERE
ACTIVO = 1
AND CONVERT(DATE, FCH_FIN) = CONVERT(DATE, GETDATE())
IF (#seconds < 3)
UPDATE Original
SET ACTIVO = 0
DELETE TOP(1) FROM #Suple
SET #count = (SELECT COUNT(*) FROM #Suple);
END
DROP TABLE #Suple
This query does not update anything
Table:
Can someone help me?
Why are you doing this in a loop in the first place? But look at your update statement. You are updating every single row in Original every iteration of the loop. But this should not be using a loop at all. Your ENTIRE code block here can be reduced to a single statement. You don't need temp tables or loops for this.
Also using shorthand in date functions is a challenge.
Update Original
where ACTIVO = 0
AND CONVERT(DATE, FCH_FIN) = CONVERT(DATE, GETDATE())
and DATEDIFF(Second, GETDATE(),FCH_FIN) < 3

Add a record for every Week-Day of the year to a blank table

I have a blank table that has two columns [ID] and [MyDate].
I would like to populate that table with all of the days of the current year MINUS weekends.
Is there a way to do this with a SQL query?
In this case I am using MSSQL T-SQL
I do not have any example code, as I am at a loss on where to get started for this scenario.
Using a numbers (Tally) table helps you to avoid using loops.
If you don't already have a numbers table, you can use this script to create it:
SELECT TOP 10000 IDENTITY(int,0,1) AS Number
INTO Tally
FROM sys.objects s1
CROSS JOIN sys.objects s2
ALTER TABLE Tally ADD CONSTRAINT PK_NumbersTest PRIMARY KEY CLUSTERED (Number)
For more information about the creation of a numbers table, read this SO post.
Now that you have a numbers table, you can use a cte to generate the dates you want. I've used DATEFROMPARTS and GETDATE() to get Jauary 1st of the current year, if you are using a version of sql server below 2012 you need to use other methods for that:
DECLARE #StartDate Date,
#EndDate Date
SELECT #StartDate = DATEFROMPARTS(YEAR(GetDate()), 1, 1)
SELECT #EndDate = DATEADD(Year, 1, #StartDate)
Now, create a CTE to get the dates required using the numbers table, and insert the records from the cte to the table:
;WITH CTE AS
(
SELECT DATEADD(Day, Number, #StartDate) As TheDate
FROM Tally
WHERE DATEADD(Day, Number, #StartDate) < #EndDate
)
INSERT INTO WeekDays
SELECT TheDate
FROM CTE
WHERE DATEPART(WeekDay, TheDate) BETWEEN 2 AND 6
See a live demo on rextester.
This will do it. Here the 1 and the 7 represents Sunday and Saturday
CREATE TABLE T (
ID INT NOT NULL IDENTITY(1,1),
MyDate DATE NOT NULL)
DECLARE #Start DATE
DECLARE #End DATE
SET #Start = '20170101'
SET #End = '20171231'
WHILE #Start <= #End
BEGIN
IF (DATEPART(DW, #Start) NOT IN (1,7))
BEGIN
INSERT INTO T (MyDate) VALUES (#Start)
END
SET #Start = DATEADD(DAY, 1, #Start)
END
SELECT * FROM T
Here's my quick attempt at your problem. Just use your table instead
select
CAST('2017-03-15' as datetime) as datestuff
into #test
Delete from #test
DECLARE #Y datetime = CAST('2017-12-31' AS DATE)
while #y != '2017-01-01'
begin
if DATENAME(DW, #y) not IN ('SUNDAY', 'SATURDAY')
BEGIN
INSERT INTO #test
SELECT #y
END
SET #Y = DATEADD(DD, -1, #Y)
end
select * from #test

Generate random records for datetime columns by stored procedure in SQL

I want to generate 5 random records from a field which is a datetime column and contains several records of (OrderDate) for a given date range using stored procedure for the table named Orders
CREATE PROCEDURE test
#StartDate DATETIME = NULL,
#EndDate DATETIME = NULL,
AS
BEGIN
SELECT OrderDate = DATEADD(......)
FROM Orders
END
May I get some help!
A while loop works ok for this purpose, especially if you're concerned with limiting your randomness to a bounded date range.
The downside is that potentially many insert queries get executed vs. a single insert for a recursive CTE as in the other answer.
create procedure dbo.spGenDates2
#MinDate datetime,
#MaxDate datetime,
#RecordCount int = 5
as
SET NOCOUNT ON;
DECLARE #Range int, #DayOffset int, #Cnt int
SET #Range = DATEDIFF(dd, #MinDate, #MaxDate)
SET #Cnt = 1
WHILE #Cnt <= #RecordCount
BEGIN
SET #DayOffset = RAND() * (#Range + 1)
INSERT INTO _test (Dt) VALUES(DATEADD(dd, #DayOffset, #MinDate))
SET #Cnt = #Cnt + 1
END
Based on your syntax I'm assuming you're using SQL Server...
Note that you cannot reliably use the sql random number generator function RAND() within the context of a single query because it does not get reseeded per row so you end up receiving the same, single random number for each row result. Instead, an approach using NEWID() converted into a numeric does the trick when generating random values within the execution of a single query.
Here's a procedure that will give you n number of sample dates in the near past.
create procedure dbo.spGenDates
#MaxDate datetime,
#RecordCount int = 5
as
WITH dates as (
SELECT DATEADD(MILLISECOND, ABS(CHECKSUM(NEWID())) * -1, #MaxDate) D,
1 as Cnt
UNION ALL
SELECT DATEADD(MILLISECOND, ABS(CHECKSUM(NEWID())) * -1, #MaxDate) D,
x.Cnt + 1 as Cnt
FROM dates x
WHERE x.Cnt < #RecordCount
)
INSERT INTO _test (Dt)
SELECT D
FROM dates
The wording of the question has been clarified (see comments on another answer) to be a desire to SELECT 5 random sample dates within a bounded range from a table.
A query like this will yield the desired result.
SELECT TOP (5) OrderDate
FROM Orders
WHERE OrderDate >= #StartDate
AND OrderDate < #EndDate
ORDER BY NEWID()

How can I generate a temporary table filled with dates in SQL Server 2000?

I need to make a temporary table that holds of range of dates, as well as a couple of columns that hold placeholder values (0) for future use. The dates I need are the first day of each month between $startDate and $endDate where these variables can be several years apart.
My original sql statement looked like this:
select dbo.FirstOfMonth(InsertDate) as Month, 0 as Trials, 0 as Sales
into #dates
from customer
group by dbo.FirstOfMonth(InsertDate)
"FirstOfMonth" is a user-defined function I made that pretty much does what it says, returning the first day of the month for the provided date with the time at exactly midnight.
This produced almost exactly what I needed until I discovered there were occasionally gaps in my dates where I had a few months were there were no records insert dates. Since my result must still have the missing months I need a different approach.
I have added the following declarations to the stored procedure anticipating their need for the range of the dates I need ...
declare $startDate set $startDate = select min(InsertDate) from customer
declare $endDate set $endDate = select max(InsertDate) from customer
... but I have no idea what to do from here.
I know this question is similar to this question but, quite frankly, that answer is over my head (I don't often work with SQL and when I do it tends to be on older versions of SQL Server) and there are a few minor differences that are throwing me off.
I needed something similar, but all DAYS instead of all MONTHS.
Using the code from MatBailie as a starting point, here's the SQL for creating a permanent table with all dates from 2000-01-01 to 2099-12-31:
CREATE TABLE _Dates (
d DATE,
PRIMARY KEY (d)
)
DECLARE #dIncr DATE = '2000-01-01'
DECLARE #dEnd DATE = '2100-01-01'
WHILE ( #dIncr < #dEnd )
BEGIN
INSERT INTO _Dates (d) VALUES( #dIncr )
SELECT #dIncr = DATEADD(DAY, 1, #dIncr )
END
This will quickly populate a table with 170 years worth of dates.
CREATE TABLE CalendarMonths (
date DATETIME,
PRIMARY KEY (date)
)
DECLARE
#basedate DATETIME,
#offset INT
SELECT
#basedate = '01 Jan 2000',
#offset = 1
WHILE (#offset < 2048)
BEGIN
INSERT INTO CalendarMonths SELECT DATEADD(MONTH, #offset, date) FROM CalendarMonths
SELECT #offset = #offset + #offset
END
You can then use it by LEFT joining on to that table, for the range of dates you require.
I would probably use a Calendar table. Create a permanent table in your database and fill it with all of the dates. Even if you covered a 100 year range, the table would still only have ~36,525 rows in it.
CREATE TABLE dbo.Calendar (
calendar_date DATETIME NOT NULL,
is_weekend BIT NOT NULL,
is_holiday BIT NOT NULL,
CONSTRAINT PK_Calendar PRIMARY KEY CLUSTERED (calendar_date)
)
Once the table is created, just populate it once in a loop, so that it's always out there and available to you.
Your query then could be something like this:
SELECT
C.calendar_date,
0 AS trials,
0 AS sales
FROM
dbo.Calendar C
WHERE
C.calendar_date BETWEEN #start_date AND #end_date AND
DAY(C.calendar_date) = 1
You can join in the Customers table however you need to, outer joining on FirstOfMonth(InsertDate) = C.calendar_date if that's what you want.
You can also include a column for day_of_month if you want which would avoid the overhead of calling the DAY() function, but that's fairly trivial, so it probably doesn't matter one way or another.
This of course will not work in SQL-Server 2000 but in a modern database where you don't want to create a permanent table. You can use a table variable instead creating a table so you can left join the data try this. Change the DAY to HOUR etc to change the increment type.
declare #CalendarMonths table (date DATETIME, PRIMARY KEY (date)
)
DECLARE
#basedate DATETIME,
#offset INT
SELECT
#basedate = '01 Jan 2014',
#offset = 1
INSERT INTO #CalendarMonths SELECT #basedate
WHILE ( DATEADD(DAY, #offset, #basedate) < CURRENT_TIMESTAMP)
BEGIN
INSERT INTO #CalendarMonths SELECT DATEADD(HOUR, #offset, date) FROM #CalendarMonths where DATEADD(DAY, #offset, date) < CURRENT_TIMESTAMP
SELECT #offset = #offset + #offset
END
A starting point of a useful kludge to specify a range or specific list of dates:
SELECT *
FROM
(SELECT CONVERT(DateTime,'2017-1-1')+number AS [Date]
FROM master..spt_values WHERE type='P' AND number<370) AS DatesList
WHERE DatesList.Date IN ('2017-1-1','2017-4-14','2017-4-17','2017-12-25','2017-12-26')
You can get 0 to 2047 out of master..spt_values WHERE type='P', so that's five and a half year's worth of dates if you need it!
Tested below and it works, though it's a bit convoluted.
I assigned arbitrary values to the dates for the test.
DECLARE #SD smalldatetime,
#ED smalldatetime,
#FD smalldatetime,
#LD smalldatetime,
#Mct int,
#currct int = 0
SET #SD = '1/15/2011'
SET #ED = '2/02/2012'
SET #FD = (DATEADD(dd, -1*(Datepart(dd, #SD)-1), #sd))
SET #LD = (DATEADD(dd, -1*(Datepart(dd, #ED)-1), #ED))
SET #Mct = DATEDIFF(mm, #FD, #LD)
CREATE TABLE #MyTempTable (FoM smalldatetime, Trials int, Sales money)
WHILE #currct <= #Mct
BEGIN
INSERT INTO #MyTempTable (FoM, Trials, Sales)
VALUES
(DATEADD(MM, #currct, #FD), 0, 0)
SET #currct = #currct + 1
END
SELECT * FROM #MyTempTable
DROP TABLE #MyTempTable
For SQL Server 2000, this stackoverflow post looks promising for a way to temporarily generate dates calculated off of a start and end date. It's not exactly the same but quite similar. This post has a very in-depth answer on truncating dates, if needed.
In case anyone stumbles on this question and is working in PostgreSQL instead of SQL Server 2000, here is how you might do it there...
PostgreSQL has a nifty series generating function. For your example, you could use this series of all days instead of generating an entire calendar table, and then do groupings and matchups from there.
SELECT current_date + s.a AS dates FROM generate_series(0,14,7) AS s(a);
dates
------------
2004-02-05
2004-02-12
2004-02-19
(3 rows)
SELECT * FROM generate_series('2008-03-01 00:00'::timestamp,
'2008-03-04 12:00', '10 hours');
generate_series
---------------------
2008-03-01 00:00:00
2008-03-01 10:00:00
2008-03-01 20:00:00
2008-03-02 06:00:00
2008-03-02 16:00:00
2008-03-03 02:00:00
2008-03-03 12:00:00
2008-03-03 22:00:00
2008-03-04 08:00:00
(9 rows)
I would also look into date_trunc from PostgreSQL using 'month' for the truncator field to maybe refactor your original query to easily match with a date_trunc version of the calendar series.
select top (datediff(D,#start,#end)) dateadd(D,id-1,#start)
from BIG_TABLE_WITH_NO_JUMPS_IN_ID
declare #start datetime
set #start = '2016-09-01'
declare #end datetime
set #end = '2016-09-30'
create table #Date
(
table_id int identity(1,1) NOT NULL,
counterDate datetime NULL
);
insert into #Date select top (datediff(D,#start,#end)) NULL from SOME_TABLE
update #Date set counterDate = dateadd(D,table_id - 1, #start)
The code above should populate the table with all the dates between the start and end. You would then just join on this table to get all of the dates needed. If you only needed a certain day of each month, you could dateadd a month instead.
SELECT P.Id
, DATEADD ( DD, -P.Id, P.Date ) AS Date
FROM (SELECT TOP 1000 ROW_NUMBER () OVER (ORDER BY (SELECT NULL)) AS Id, CAST(GETDATE () AS DATE) AS Date FROM master.dbo.spt_values) AS P
This query returns a table calendar for the last 1000 days or so. It can be put in a temporary or other table.
Create a table variable containing a date for each month in a year:
declare #months table (reportMonth date, PRIMARY KEY (reportMonth));
declare #start date = '2018', #month int = 0; -- base 0 month
while (#month < 12)
begin
insert into #months select dateAdd(month, #month, #start);
select #month = #month + 1;
end
--verify
select * from #months;
This is by far the quickest method I have found (much quicker than inserting rows 1 by 1 in a WHILE loop):
DECLARE #startDate DATE = '1900-01-01'
DECLARE #endDate DATE = '2050-01-01'
SELECT DATEADD(DAY, sequenceNumber, #startDate) AS TheDate
INTO #TheDates
FROM (
SELECT ones.n + 10*tens.n + 100*hundreds.n + 1000*thousands.n + 10000*tenthousands.n AS sequenceNumber
FROM
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) ones(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) tens(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) hundreds(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) thousands(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) tenthousands(n)
WHERE ones.n + 10*tens.n + 100*hundreds.n + 1000*thousands.n + 10000*tenthousands.n <= DATEDIFF(day, #startDate, #endDate)
) theNumbers
SELECT *
FROM #TheDates
ORDER BY TheDate
The recursive answer:
DECLARE #startDate AS date = '20220315';
DECLARE #endDate AS date = '20230316'; -- inclusive
WITH cte_minutes(dt)
AS (
SELECT
DATEFROMPARTS(YEAR(#startDate), MONTH(#startDate), 1)
UNION ALL
SELECT
DATEADD(month, 1, dt)
FROM
cte_minutes
WHERE DATEADD(month, 1, dt) < #endDate
)
SELECT
dt
into #dates
FROM
cte_minutes
WHERE
dt >= #startDate
AND
dt <= #endDate
OPTION (MAXRECURSION 2000);
DROP TABLE dbo.#dates

SQL first of every month

Supposing that I wanted to write table valued function in SQL that returns a table with the first day of every month between the argument dates, what is the simplest way to do this?
For example fnFirstOfMonths('10/31/10', '2/17/11') would return a one-column table with 11/1/10, 12/1/10, 1/1/11, and 2/1/11 as the elements.
My first instinct is just to use a while loop and repeatedly insert first days of months until I get to before the start date. It seems like there should be a more elegant way to do this though.
Thanks for any help you can provide.
Something like this would work without being inside a function:
DECLARE #LowerDate DATE
SET #LowerDate = GETDATE()
DECLARE #UpperLimit DATE
SET #UpperLimit = '20111231'
;WITH Firsts AS
(
SELECT
DATEADD(DAY, -1 * DAY(#LowerDate) + 1, #LowerDate) AS 'FirstOfMonth'
UNION ALL
SELECT
DATEADD(MONTH, 1, f.FirstOfMonth) AS 'FirstOfMonth'
FROM
Firsts f
WHERE
DATEADD(MONTH, 1, f.FirstOfMonth) <= #UpperLimit
)
SELECT *
FROM Firsts
It uses a thing called CTE (Common Table Expression) - available in SQL Server 2005 and up and other database systems.
In this case, I start the recursive CTE by determining the first of the month for the #LowerDate date specified, and then I iterate adding one month to the previous first of month, until the upper limit is reached.
Or if you want to package it up in a stored function, you can do so, too:
CREATE FUNCTION dbo.GetFirstOfMonth(#LowerLimit DATE, #UpperLimit DATE)
RETURNS TABLE
AS
RETURN
WITH Firsts AS
(
SELECT
DATEADD(DAY, -1 * DAY(#LowerLimit) + 1, #LowerLimit) AS 'FirstOfMonth'
UNION ALL
SELECT
DATEADD(MONTH, 1, f.FirstOfMonth) AS 'FirstOfMonth'
FROM
Firsts f
WHERE
DATEADD(MONTH, 1, f.FirstOfMonth) <= #UpperLimit
)
SELECT * FROM Firsts
and then call it like this:
SELECT * FROM dbo.GetFirstOfMonth('20100522', '20100831')
to get an output like this:
FirstOfMonth
2010-05-01
2010-06-01
2010-07-01
2010-08-01
PS: by using the DATE datatype - which is present in SQL Server 2008 and newer - I fixed the two "bugs" that Richard commented about. If you're on SQL Server 2005, you'll have to use DATETIME instead - and deal with the fact you're getting a time portion, too.
create function dbo.fnFirstOfMonths(#d1 datetime, #d2 datetime)
returns table as return
select dateadd(m,datediff(m,0,#d1)+v.number,0) as FirstDay
from master..spt_values v
where v.type='P' and v.number between 0 and datediff(m, #d1, #d2)
and dateadd(m,datediff(m,0,#d1)+v.number,0) between #d1 and #d2
GO
Notes
master..spt_values is a source for general purpose sequence numbers in SQL Server
dateadd(m, datediff(m is a technique for working out the first day of month for any date
+v.number is used to increase it by one month each time
0 and datediff(m, #d1, #d2) this condition gives us all the numbers we need to generate a first-of-month date for each month between #d1 and #d2, inclusive of both months
and dateadd(m,datediff(m,0,#d1)+v.number,0) between #d1 and #d2 the final filter to verify that the first-of-month date generated is between #d1 and #d2
Performance comparison against marc_s's code
Summary
8220 ms (CTE)
4173 ms (master..spt_values)
Test
declare #t table (dt datetime)
declare #d datetime
declare #i int
set nocount on
set #d = GETDATE()
set #i = 0
while #i < 10000
begin
insert #t select * from dbo.getfirstofmonth('20090102', '20100506')
delete #t
set #i = #i + 1
end
print datediff(ms, #d, getdate())
set #d = GETDATE()
set #i = 0
while #i < 10000
begin
insert #t select * from dbo.fnfirstofmonths('20090102', '20100506')
delete #t
set #i = #i + 1
end
print datediff(ms, #d, getdate())
Performante
It will loop just between the months involved (4 times in the example):
set dateformat mdy;
declare #date1 smalldatetime,#date2 smalldatetime,#i int
set #date1= '10-31-2010'
set #date2= '02-17-2011'
set #i=1
while(#i<=DATEDIFF(mm,#date1,#date2))
begin
select convert(smalldatetime,CONVERT(varchar(6),DATEADD(mm,#i,#date1),112)+'01',112)
set #i=#i+1
end
I realize this isn't a function, but I'm going to throw this into the mix anyway.
select cal_date from calendar
where day_of_month = 1
and cal_date between '2011-01-01' and '2012-01-01'
This calendar table runs on a PostgreSQL server at work. I'll port it to SQL Server tonight, and run some speed comparisons. (Why? Because this stuff is fun, that's why.)
Just in case anybody is still reading this ...
I cannot imaging that any of the aforementioned functions is faster than this:
declare #DatFirst date = '20101031', #DatLast date = '21110217';
declare #DatFirstOfFirstMonth date = dateadd(day,1-day(#DatFirst),#DatFirst);
select DatFirstOfMonth = dateadd(month,n,#DatFirstOfFirstMonth)
from (
select top (datediff(month,#DatFirstOfFirstMonth,#DatLast)+1)
n=row_number() over (order by (select 1))-1
from (values (1),(1),(1),(1),(1),(1),(1),(1)) a (n)
cross join (values (1),(1),(1),(1),(1),(1),(1),(1)) b (n)
cross join (values (1),(1),(1),(1),(1),(1),(1),(1)) c (n)
cross join (values (1),(1),(1),(1),(1),(1),(1),(1)) d (n)
) x