I require a SQL query to work out every product combination.
I have three product categories (game, accessory, upgrade) and products assigned to each of these three categories:
+----+------------+-----------+------------+
| id | category | product | prod_code |
+----+------------+-----------+------------+
| 1 | game | GTA | 100 |
| 2 | game | GTA1 | 200 |
| 3 | game | GTA2 | 300 |
| 4 | accessory | Play Pad | 400 |
| 5 | accessory | Xbox Pad | 500 |
| 6 | upgrade | Memory | 600 |
| 6 | upgrade | drive | 700 |
+----+------------+-----------+------------+
I want to take one product from each of the categories and work out every single combination:
+----+--------------+
| id | combinations |
+----+--------------+
| 1 | 100,400,600 |
| 2 | 100,500,600 |
| 3 | 100,400,700 |
| 4 | 100,500,700 |
| ? | etc |
+----+--------------+
How would I go about doing this?
Thanks in advance, Stuart
Use a CROSS JOIN:
SELECT CONCAT(t1.[prod_code], ',',
t2.[prod_code], ',',
t3.[prod_code])
FROM (
SELECT [prod_code]
FROM mytable
WHERE category = 'game') AS t1
CROSS JOIN (
SELECT [prod_code]
FROM mytable
WHERE category = 'accessory') AS t2
CROSS JOIN (
SELECT [prod_code]
FROM mytable
WHERE category = 'upgrade') AS t3
ORDER BY t1.[prod_code], t2.[prod_code], t3.[prod_code]
CROSS JOIN of derived tables, one for each category, produces the following cartesian product: 'game' products x 'accessory' products x 'upgrade' products
Demo here
Related
I have 2 tables as such:
cars: contains price of some parts for each car
| Car | Parts | Price |
| -------- | -------------- | -------|
| A | Windshield | 100 |
| A | Rims | 50 |
| B | Bumper | 200 |
| B | Rims | 60 |
parts: contains all possible parts for a car
| Parts |
|--------------|
| Windshield |
| Rims |
| Bumper |
| Headlights |
I want each car in cars to have every entry in parts. The end result should look like this:
| Car | Parts | Price |
| -------- | -------------- | -------|
| A | Windshield | 100 |
| A | Rims | 50 |
| A | Bumper | 0 |
| A | Headlights | 0 |
| B | Bumper | 200 |
| B | Rims | 60 |
| B | Windshield | 0 |
| B | Headlights | 0 |
Any ideas on how I could do this?
PS: The order matters less
You may use a calendar table approach:
SELECT c.Car, p.Parts, COALESCE(t.Price, 0) AS Price
FROM (SELECT DISTINCT Car FROM cars) c
CROSS JOIN parts p
LEFT JOIN cars t
ON t.Car = c.Car AND t.Parts = p.Parts
ORDER BY c.Car, p.Parts;
But as #Larnu has correctly pointed out in his comment, your schema should have a separate table containing all cars. This would avoid the distinct select I have in my answer above.
If you want to insert the additional rows into cars, then the code would look like:
insert into cars (car, parts, price)
select c.car, p.part, 0
from (select distinct car from cars) c cross join
parts p
where not exists (select 1
from cars c2
where c2.car = c.car and c2.part = c.part
);
This generates all combinations of cars and parts. It then filters out the ones that don't already exist in cars.
Note that left join and not exists are pretty much the same in this context. In an insert query, though, I usually use not exists because I think the intention is clearer.
I have two tables. Like this.
select * from extrafieldvalues;
+----------------------------+
| id | value | type | idItem |
+----------------------------+
| 1 | 100 | 1 | 10 |
| 2 | 150 | 2 | 10 |
| 3 | 101 | 1 | 11 |
| 4 | 90 | 2 | 11 |
+----------------------------+
select * from items
+------------+
| id | name |
+------------+
| 10 | foo |
| 11 | bar |
+------------+
I need to make a query and get something like this:
+--------------------------------------+
| idItem | valtype1 | valtype2 | name |
+--------------------------------------+
| 10 | 100 | 150 | foo |
| 11 | 101 | 90 | bar |
+--------------------------------------+
The quantity of types of extra field values is variable, but every item ALWAYS uses every extra field.
If you have only two fields, then left join is an option for this:
select i.*, efv1.value as value_1, efv2.value as value_2
from items i left join
extrafieldvalues efv1
on efv1.iditem = i.id and
efv1.type = 1 left join
extrafieldvalues efv2
on efv1.iditem = i.id and
efv1.type = 2 ;
In terms of performance, two joins are probably faster than an aggregation -- and it makes it easier to bring in more columns from items. One the other hand, conditional aggregation generalizes more easily and the performance changes by little as more columns from extrafieldvalues are added to the select.
Use conditional aggregation
select iditem,
max(case when type=1 then value end) as valtype1,
max(case when type=2 then value end) as valtype2,name
from extrafieldvalues a inner join items b on a.iditem=b.id
group by iditem,name
Problem description
Let the tables C and V have those values
>> Table V <<
| UnID | BillID | ProductDesc | Value | ... |
| 1 | 1 | 'Orange Juice' | 3.05 | ... |
| 1 | 1 | 'Apple Juice' | 3.05 | ... |
| 1 | 2 | 'Pizza' | 12.05 | ... |
| 1 | 2 | 'Chocolates' | 9.98 | ... |
| 1 | 2 | 'Honey' | 15.98 | ... |
| 1 | 3 | 'Bread' | 3.98 | ... |
| 2 | 1 | 'Yogurt' | 8.55 | ... |
| 2 | 1 | 'Ice Cream' | 7.05 | ... |
| 2 | 1 | 'Beer' | 9.98 | ... |
| 2 | 2 | 'League of Legends RP' | 40.00 | ... |
>> Table C <<
| UnID | BillID | ClientName | ... |
| 1 | 1 | 'Alexander' | ... |
| 1 | 2 | 'Tom' | ... |
| 1 | 3 | 'Julia' | ... |
| 2 | 1 | 'Tom' | ... |
| 2 | 2 | 'Alexander' | ... |
Table C have the values of each product, which is associated with a bill number. Table V has the relationship between the client name and the bill number. However, the bill number has a counter that is dependent on the UnId, which is the store unity ID. That being said, each store has it`s own Bill number 1, number 2, etc. Also, the number of bills from each store are not equal.
Solution description
I'm trying to make select between the C left join V without sucess. Because each BillID is dependent on the UnID, I have to make the join considering the concatenation between those two columns.
I've used this script, but it gives me an error.
SELECT
SUM(C.Value),
V.ClientName
FROM
C
LEFT JOIN
V
ON
CONCAT(C.UnID, C.BillID) = CONCAT(V.UnID, V.BillID)
GROUP BY
V.ClientName
and SQL server returns me this 'CONCAT' is not a recognized built-in function name.
I'm using Microsoft SQL Server 2008 R2
Is the use of CONCAT wrong? Or is it the way I tried to SELECT? Could you give me a hand?
[OBS: The tables I've present you are just for the purpose of explaining my difficulties. That being said, if you find any errors in the explanation, please let me know to correct them.]
You should be joining on the equality of the UnID and BillID columns in the two tables:
SELECT
c.ClientName,
COALESCE(SUM(v.Value), 0) AS total
FROM C c
LEFT JOIN V v
ON c.UnID = v.UnID AND
c.BillID = v.BillID
GROUP BY
c.ClientName;
In theory you could try joining on CONCAT(UnID, BillID). However, you could run into problems. For example, UnID = 1 with BillID = 23 would, concatenated together, be the same as UnID = 12 and BillID = 3.
Note: We wrap the sum with COALESCE, because should a given client have no entries in the V table, the sum would return NULL, which we then replace with zero.
concat is only available in sql server 2012.
Here's one option.
SELECT
SUM(C.Value),
V.ClientName
FROM
C
LEFT JOIN
V
ON
cast(C.UnID as varchar(100)) + cast(C.BillID as varchar(100)) = cast(V.UnID as varchar(100)) + cast(V.BillID as varchar(100))
GROUP BY
V.ClientName
I am stuck in the following situations.
I have two tables Products and Postage:
Postage table
+----------------------------------+
| Weight_GM | Postal Charges ($) |
+----------------------------------+
| 20 | 1 |
| 40 | 1.5 |
| 50 | 1.7 |
+----------------------------------+
Products table
+-------------------------------+
| SKU | Title | Weight_GM |
+-------------------------------+
| ABC | Shose | 17 |
| JKL | Camera | 27 |
| XYZ | IPad | 48 |
+-------------------------------+
I want to create a relationship to take appropriate postal charge from Postage table based on the Weight defined in both tables.
The desired result would be like this:
+---------------------------------------------------+
| SKU | Title | Weight_GM | Postal Charges |
+---------------------------------------------------+
| ABC | Shose | 17 | 1 |
| JKL | Camera | 27 | 1.5 |
| XYZ | IPad | 48 | 1.7 |
+---------------------------------------------------+
Note: I have been through many similar questions but there was not solution to my problem.
Thanks in advance.
This should work -- just use GROUP BY and MIN:
SELECT DISTINCT Pr.SKU, Pr.Title, Pr.Weight_GM, MIN(PO.Postal_Charges) as PO_Charges
FROM Products Pr
JOIN Postage Po ON Pr.Weight_GM <= Po.Weight_GM
GROUP BY Pr.SKU, Pr.Title, Pr.Weight_GM
And the Fiddle.
This should do it
;With WeightNumber AS
(
SELECT Weight_GM, Postal_Charge, ROW_NUMBER() OVER (ORDER BY Weight_GM) AS Num
FROM Postage
)
WeightRange AS
(
SELECT ISNULL(Prec.Weight_GM - 1, 0) AS START_WEIGHT, CurrentRow.Weight_GM AS END_WEIGHT, CurrentRow.Postal_Charge
FROM WeightNumber CurrentRow
LEFT JOIN WeightNumber Prec
ON Prec.Num=CurrentRow.Num - 1
)
SELECT *
FROM Products p
JOIN WeightRange w
ON p.Weight_GM BETWEEN w.START_WEIGHT AND w.END_WEIGHT
You can do this with the following code
The inner join will join the two tables with the key Weight_GM
select a.SKU, b.Postal Charges from Products a
inner join Postage b on a.Weight_GM = b.Weight_GM
try this:
select SKU,Title,prds.Weight_GM b,pst.Weight_GM a,Postal_charges
from Postage pst ,Products prds
where prds.Weight_GM < pst.Weight_GM
group by prds.Weight_GM;
here's the demo : demo link
I have two tables:
1. Master
| ID | Name | Amount |
|-----|--------|--------|
| 1 | a | 5000 |
| 2 | b | 10000 |
| 3 | c | 5000 |
| 4 | d | 8000 |
2. Detail
| ID |MasterID| PID | Qty |
|-----|--------|-------|------|
| 1 | 1 | 1 | 10 |
| 2 | 1 | 2 | 20 |
| 3 | 2 | 2 | 60 |
| 4 | 2 | 3 | 10 |
| 5 | 3 | 4 | 100 |
| 6 | 4 | 1 | 20 |
| 7 | 4 | 3 | 40 |
I want to select sum(Amount) from Master which joins to Deatil where Detail.PID in (1,2,3)
So I execute the following query:
SELECT SUM(Amount) FROM Master M INNER JOIN Detail D ON M.ID = D.MasterID WHERE D.PID IN (1,2,3)
Result should be 20000. But I am getting 40000
See this fiddle. Any suggestion?
You are getting exactly double the amount because the detail table has two occurences for each of the PIDs in the WHERE clause.
See demo
Use
SELECT SUM(Amount)
FROM Master M
WHERE M.ID IN (
SELECT DISTINCT MasterID
FROM DETAIL
WHERE PID IN (1,2,3) )
What is the requirement of joining the master table with details when you have all your columns are in Master table.
Also, isnt there any FK relationhsip defined on these tables. Looking at your data it seems to me that there should be FK on detail table for MasterId. If that is the case then you do not need join the table at all.
Also, in case you want to make sure that you have records in details table for the records for which you need sum and there is no FK relationship. Then you could give a try for exists instead of join.